Re: [PHP-DB] Oracle-PHP (contd.)
Are you sure you need an environment variable to store that? if yes, this script should do the trick : putenv(TNS_ADMIN=/ora1/app/oracle/product/8.1.6/network/admin); --- $tns = getenv(TNS_ADMIN); echo $tns; Regards, Philippe Vandana [EMAIL PROTECTED] a écrit dans le message news: [EMAIL PROTECTED] With reference to my previous problem in connecting to the oracle database, I found out some additional information. I defined the TNS_ADMIN variable in the startup file and added this line to my php-script: putenv(TNS_ADMIN=/ora1/app/oracle/product/8.1.6/network/admin); and when I tried to echo this variable echo($TNS_ADMIN); The value is not being printed, it is not defined.When I tried the same thing at the command prompt the value was defined.What is the reason that the value of TNS_ADMIN is not being available to the php-script. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] submitbutton/imagebutton
I'm kind of new to php so there may be an obvious answer but I can't
find it for the moment.
What I want to do is change the 'type=submit' of a submit button to
'type=image' so I can control the looks of the button.
In pure HTML there is of course no problem, the image is still used as a
submit button but... the submit type is being passed on to a php script
( ...if ($submit) {...) that makes a qeary to a mysql database. When I
change the type=submit to type=image the script doesn't pick up the
submit value anymore, so nothing happens.
Am I overlooking something or is it just something that doesn't work?
IIRC you have to use something like $submit_x $submit_y, which is a bit
more longwinded.
Since I have started using buttons for submit, I now put a hidden field
called formname inside each form,and chekc for that and that the method of
the form is correct.
It makes it a little bit easier if you have more than one form per page.
HTH
M@
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[PHP-DB] managing variant data
Hi again, another conundrum. What is the best way to deal with the following situation? You have a group of common properties including a property that indicates a second group of common properties. For example, suppose you have this table: Officers Name Rank Age Height Weight Species The 'Species' property may have the following values: Vulcan, Human, Klingon, or Android. If (Species==Vulcan) then you want to store these additional properties: MindmeldCount and YearsOnVulcan If (Species==Klingon) then you want to store these additional properties: NumberofConcealedWeapons and RidgesOnForehead If (Species==Android) then you want to store these additional properties: PositronicBrain and MemoryJigas If (Species==Human) then you want to store these additional properties: AttendedStarfleetAcademy and BloodType The problems I want to avoid are: 1) placing all the properties for all species in the Officers table (as this would include unnecessary properties for each row) and 2) storing the properties in the Officers in four seperate tables (Klingons, Humans, Androids, and Vulcans) redundantly. Should additional tables be created: Vulcans, Klingons, Androids, Humans? If so, how should these tables be joined to Officers? In an object language I would solve a problem like this be creating a base class with the Officers properties and then deriving new classes from this base class using inheritance. How do I solve this problem in a database setting? Thanks in advance for your help, Jesse -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] access to a access db via php
Hello NG, it's the first time I use this NG and I'm not sure whether I'm I right here or not. The problem: I'm a beginner in php (just started to read the first introductions). I created a guestbook with FP2000. The entrys where safed in and shown from a db. FP 2000 nearly created it by itself using asp. The problem is that my provider doesn't support a db connection via asp. They told me that php3 is supported. My question: Can I use the created db (where my guestbook entrys are safed) and edit and show results via php? I think yes but all tutorials I found about it described a odbc connection and I think the provider I'm using doesn't support this , too. Is there any possibilty to work in an access DB without any odbc connection (cause then I need a server which supports DNS and so on and all Servers I knew are too expensive for me at the moment). Maybe I can access the db via php like a text file? There are many question I have, sorry if this description isn't precise enough. I'm glad about any hints, comments, suggestions, links or whatsoever that would help me. Thanks in advance to read and answer this long posting. MFG Matthias -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] Database access using ODBC
Hi,
Long time reader, first time poster! I am new to php coming from
a generally MS (unfortunately) background (Access, VB, SQLServer)
and I am looking to branch out a bit.
I have a client who wishes to have an internet front-end to an
Access database. I am using php with odbc to access this and (as
I am a newbie), I am having problems with the connection. After
I do an odbc_pConnect, when I call the odbc_exec, I get the usual
error, Warning: Supplied agrument is not a valid ODBC-Link resource.
The ODBC DSN is setup as standard (no default login etc). The
following code is being used for db access:
function DBRetrieve($pSQLStr)
{
global $DBConn, $DBQryID, $DBQryRows, $DBQryColumns;
$DBDsn='PHPTEST';
$DBUser='Admin';
$DBPassword ='';
#Open a persistent connection to the database
if (!$DBConn = (odbc_pConnect($DBDsn, $DBUser, $DBPassword) or die(Database
Execution Error: . odbc_Error() . . odbc_ErrorMsg(
{
echo \nError connecting to database\n;
return false;
}
#Send query to database
if (!$DBQryID=(odbc_Exec($DBConn, $pSQLStr) or die(Database Execution Error: .
odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_EXEC]\n;
DBDestroy();
return false;
}
#Get no of rows in recordset
if (!$DBQryRows=(odbc_num_rows($DBQryId) or die(Database Execution Error: .
odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_NUM_ROWS]\n;
DBDestroy();
return false;
}
#Get number of fields to display
if (!$DBQryColumns=(odbc_num_fields($DBQryId) or die(Database Execution Error: .
odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_NUM_FIELDS]\n;
DBDestroy();
return false;
}
return true;
}
Does this look ok to you more experienced guys? Am I missing
something or is there a better way?
Thanks.
Colum
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[PHP-DB] Re: MySQL: alphabetizing, skipping the , a
Hey all, I'm trying to generate a alphabetized list of items from my database, but I want to alphabetize the list, skipping the leading articles in the title for each item. some solutions suggest creating a 2nd (dummy name) column to alphabetize by, but I don't want to maintain two columns for my name field. but I've been using the following to ignore 'the ' and 'a ': $select = mysql_select_db(bases); $query = SELECT IF(left(nameE,2)='A ' or left(nameE,4)='The ', if(left(nameE,2)='A ',right(nameE,length(nameE)-2), right(nameE, length(nameE)-4)),nameE) as alphabet,nameE FROM principle order by alphabet; $result = mysql_query($query) but if I want to ignore third or fourth variable, on top of 'the ' and 'a ', what syntax would I use, to include these additional cases in my script above? the above query was built on a coding solution I found at http://www.bitmechanic.com/mail-archives/mysql/May1998/0713.html *mysql: select statements that ignore the * Cameron -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] upload problem ...
Steve, When you use input type=file the web server uploads the file to a temporary directory which it must have write access to, i.e. the user that the httpd process is run as must have write access to /php/tmp. To my knowledge there is no way of allowing the httpd process to write to that directory using your ftp users/password. Bear in mind that you could change the temporary upload directory from /php/tmp to /tmp. do you have full access to you box or only an account? hope this helps ciao Andre. Steve Brett wrote: hi, i have a site and need to write a script to upload / download files so the database can be updated / backed up. i've tried setting up an input type=file ... and this works fine on my machine but php gives an eror onthe server saying that the /php/tmp dir cannot be written to by, i assume, the nobody account within whihc the web server runs. i need to be bale to write to the httpd dir using php and then i can get the db to import the files. i have an ftp username and password but don't know how to get php to pass the authorisation the server. the site is already password protected just using a table of username / passowrds. many thanks in advance Steve -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] Cookies
How can I request a persistant cookie from the clients computer (to make a autologin) this doesnt work :echo $HTTP_COOKIE_VARS[nameCookie] code to set cookie: setcookie(newsLogin,$value,time()+ 3348000); if i ask from the same page I get the values I need but not from a different page... thx
Re: [PHP-DB] Database access using ODBC
Colum,
Did you check out www.php.net/odbc_Exec
One of the solutions posted in the comments was to download and install a
new ODBC driver from MSFT. Are you getting a valid integer returned to
$DBConn?
NOt worked with this, but I hope those are helpful suggestions - Miles Thompson
At 08:38 AM 6/25/01 -0400, [EMAIL PROTECTED] wrote:
Hi,
Long time reader, first time poster! I am new to php coming from
a generally MS (unfortunately) background (Access, VB, SQLServer)
and I am looking to branch out a bit.
I have a client who wishes to have an internet front-end to an
Access database. I am using php with odbc to access this and (as
I am a newbie), I am having problems with the connection. After
I do an odbc_pConnect, when I call the odbc_exec, I get the usual
error, Warning: Supplied agrument is not a valid ODBC-Link resource.
The ODBC DSN is setup as standard (no default login etc). The
following code is being used for db access:
function DBRetrieve($pSQLStr)
{
global $DBConn, $DBQryID, $DBQryRows, $DBQryColumns;
$DBDsn='PHPTEST';
$DBUser='Admin';
$DBPassword ='';
#Open a persistent connection to the database
if (!$DBConn = (odbc_pConnect($DBDsn, $DBUser, $DBPassword) or
die(Database Execution Error: . odbc_Error() . . odbc_ErrorMsg(
{
echo \nError connecting to database\n;
return false;
}
#Send query to database
if (!$DBQryID=(odbc_Exec($DBConn, $pSQLStr) or die(Database Execution
Error: . odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_EXEC]\n;
DBDestroy();
return false;
}
#Get no of rows in recordset
if (!$DBQryRows=(odbc_num_rows($DBQryId) or die(Database Execution
Error: . odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_NUM_ROWS]\n;
DBDestroy();
return false;
}
#Get number of fields to display
if (!$DBQryColumns=(odbc_num_fields($DBQryId) or die(Database
Execution Error: . odbc_Error() . . odbc_ErrorMsg(
{
echo \nError executing database request: [ODBC_NUM_FIELDS]\n;
DBDestroy();
return false;
}
return true;
}
Does this look ok to you more experienced guys? Am I missing
something or is there a better way?
Thanks.
Colum
Mail2Web - Check your email from the web at
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[PHP-DB] Is MySQL in 4.0.6?
Is MySQL included in the 406kb version of PHP 4.0.6? When I try to connect to MySQL (after adding localhost paswords to php.ini) using this version it says: Warning: Can't connect to MySQL server on 'localhost' (10061) in mysql_local_test.php on line 2 From what i've heard, MySQL is included in PHPbut why doesn't the connect work if it is included? -Adam Lundrigan CEO, VPU http://www.vpu-virtual.com/ ICQ # 73617446 [EMAIL PROTECTED]
