Re: [PHP-DB] strange link problem to a database item

2002-01-19 Thread chip

On Friday 18 January 2002 09:39 pm, Chris Lott banged out on the keys:
  In my code I have the following line:
 
  printf(td align=\center\a href=\%s\
  img src=\.xvpics/%s\/a/td\n, $row[name], $row[name]);
 
  When I view this web page I get I get, in-
  konqueror - all thumb images are fine
  netscape 6 - no thumb images, just a narrow verticle bar

 Can you make this available somewhere to look at?

Okay, try this:
a href=http://66.114.152.128/p/public_html/;
The following files are available for you to look at -
index.html.txt
index.tk.txt
index.pickups.txt
Just enter those file names after the above url to view the source code.
(of course you all already know that).
-- 
Chip

Windows 95/NT - 32 bit extensions and a graphical shell for a 16 bit patch
to an 8 bit operating system originally coded for a 4 bit microprocessor,
written by a 2 bit company that can't stand 1 bit of competition.


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Re: [PHP-DB] strange link problem to a database item

2002-01-19 Thread Jason Wong

On Saturday 19 January 2002 16:06, chip wrote:
 On Friday 18 January 2002 09:39 pm, Chris Lott banged out on the keys:
   In my code I have the following line:
  
   printf(td align=\center\a href=\%s\
   img src=\.xvpics/%s\/a/td\n, $row[name], $row[name]);
  
   When I view this web page I get I get, in-
   konqueror - all thumb images are fine
   netscape 6 - no thumb images, just a narrow verticle bar
 
  Can you make this available somewhere to look at?

 Okay, try this:
 a href=http://66.114.152.128/p/public_html/;
 The following files are available for you to look at -
 index.html.txt
 index.tk.txt
 index.pickups.txt
 Just enter those file names after the above url to view the source code.
 (of course you all already know that).

Interesting problem. It seems that your thumbnails are in an invalid format. 
Using Opera right-clicking on picture and selecting Image Properties 
reveals that the purported image dimensions are 0 x 0 pixels and Bits per 
pixel is also 0.

Saving the thumbnail and loading into IrfanView gives an invalid header error.

I think you'll have to look at re-doing your thumbnails.

hth
-- 
Jason Wong - Gremlins Associates - www.gremlins.com.hk

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[PHP-DB] Breaking up an array

2002-01-19 Thread Troy A. Delagardelle

I am trying to break this array up so that I can display each one of these
varibles independantly.  What PHP function will allow me to to this??  Or
what other way can I achieve this??  Thx  Troy




+--+---+-+-+-+
| username | Total | average | minimum | maximum |
+--+---+-+-+-+
| eric |52 |  52 | 52  | 52  |
| troy | 11436 | 84.7111 | 10  | 99  |
| wade |38 |  38 | 38  | 38  |
+--+---+-+-+-+


SELECT username, SUM(statusDuration) as 'Total',
- avg(statusDuration) as 'average',
- min(statusDuration) as 'minimum',
- max(statusDuration) as 'maximum' from workerLogs group by username;


Array ( [0] = eric [1] = eric [2] = 52 [3] = 52 [4] = 52 [5] = 52 [6]
= 52 [7] = 52 [8] = 52 [9] = 52 ) Array ( [0] = troy [1] = troy [2] =
35651 [3] = 35651 [4] = 176.4900990099 [5] = 176.4900990099 [6] = 10 [7]
= 10 [8] = 99 [9] = 99 ) Array ( [0] = wade [1] = wade [2] = 38 [3] =
38 [4] = 38 [5] = 38 [6] = 38 [7] = 38 [8] = 38 [9] = 38 )




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[PHP-DB] PHP Mysql on Win32 platform

2002-01-19 Thread Joni Järvinen

Hey.

I have apache, php and mysql installed on Win32 platform. Everything
works great but when I try to connect to mysql database with PHP,
I get the following error:

Warning: Access denied for user: 'ODBC@localhost' (Using password: YES) in
c:\dev\msgv2\index.php on line 15.

The line 15 contains the mysql_connect. It is using the user 'root' with
password.
The user exists in mysql's User table. Do I need to grant ODBC access
to mysql and if I do, how do I do it?

Thanks in advance.

// Joni



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Re: [PHP-DB] php/msql

2002-01-19 Thread DL Neil

Hi Mike

 while ($row = mysql_fetch_array($result)) {
  echo trtd.$row[0]./td\n;
  echo td.$row[1]./td\n;
  $formatted=sprintf($%s,$row[2]);
  echo td $formatted  /td/trbr;
 }

 I get an error in the last line where I want to put $formatted into the last
 cell of a table
 if I  // echo $formatted without the HTML tags it puts it at the top of the
 page.
 The error is : Parse error: parse error, expecting `','' or `';''
 also: what does the \n  mean at the end of the html tags?
 I am new to PHP and have no seen that before.

Welcome to our little band!
Tuxedo Junction does that mean that there is a dress code on the Internet in Canada?

The echo command outputs one or more strings: 
http://www.php.net/manual/en/function.echo.php.
If you have more than one string, they must be separated with commas.

Alternatively you could join the three strings together using the concatenation 
operator:
http://www.php.net/manual/en/language.operators.string.php

The \n question (newline character) is answered/illustrated in the first link above 
(and many other places -
try throwing it into the manual's search facility).

You sound as if you're just starting out. There are many PHP/MySQL tutorials on the 
web. Start at the host sites
and check out links, otherwise chuck a few of the key words at Google.

Regards,
=dn



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[PHP-DB] distinct - how to do

2002-01-19 Thread Barry Rumsey

I have the following query:
$query = SELECT  * FROM xp_topics, xp_stories WHERE xp_topics.topicid = 
xp_stories.topicid AND xp_topics.artistname='Faith Hill' ORDER BY topictext DESC LIMIT 
0,20; 
It returns the lot but a lot of doubles.
 I want to put a DISTINCT call the query, but if I put it after the select ( select 
distinct * from...) it returns nothing. How do you do a DISTINCT?



[PHP-DB] MySQL database

2002-01-19 Thread Morten Nielsen

Hi,

Could anybody explain to me how I should make a table with usernames and
passwords.
I want to make a site, where users can sign up and enter some values, which
is stored in a different table.
How do I grant the necessary acces to the tables, so users can enter values
into them?

Please help,
Morten



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Re: [PHP-DB] distinct - how to do

2002-01-19 Thread Paul DuBois

At 2:28 +1300 1/20/02, Barry Rumsey wrote:
I have the following query:
$query = SELECT  * FROM xp_topics, xp_stories WHERE 
xp_topics.topicid = xp_stories.topicid AND 
xp_topics.artistname='Faith Hill' ORDER BY topictext DESC LIMIT 
0,20;
It returns the lot but a lot of doubles.
  I want to put a DISTINCT call the query, but if I put it after the 
select ( select distinct * from...) it returns nothing. How do 
you do a DISTINCT?

That's how you do it (add DISTINCT after the SELECT keyword).
You must be doing something else wrong.

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Re: [PHP-DB] strange link problem to a database item

2002-01-19 Thread Steven Cayford

On 2002.01.18 23:00:16 -0600 chip wrote:
 On Friday 18 January 2002 08:09 pm, Steven Cayford banged out on the
 keys:
  Hello again.
 
  On 2002.01.18 18:48:36 -0600 chip wrote:
   In my code I have the following line:
  
   printf(td align=\center\a href=\%s\
   img src=\.xvpics/%s\/a/td\n, $row[name], $row[name]);
 
  Ok. So the name field in your table holds the filename of the image
 and
  you have a thumbnail image by the same name in the .xvpics folder? What
  does the html source look like in your browser? If you type the url for
  the image into the browser address bar directly do you get the image?
 
  -Steve
 
 In Konqueror it works, but when I enter the path into netscape and opera
 as
 suggested it does not work. I even made a differant directory, called
 thumbs,
 and copied the thumb-nail images into it and got the same results. I
 don't
 understand why Konqueror will display them but the other browsers will
 not.
 I was using the .xvpics folder because it was already made by XV, so why
 make
 another? Just seemed simpler. Doesn't PHP have a way of making thumbs
 from
 the larger images dynamically? Seems like I'd seen something about this
 somewhere...
 --
 chip

Strange. It sounds like the images themselves are in a format that only 
konquerer understands. Are they jpegs, gifs, pngs? Do they have the right 
file extensions? I don't know what else to recommend.

PHP does have image manipulation functions if it was compiled with gd 
support. See the manual at http://www.php.net/manual/en/ref.image.php. 
Alternatively you can call the ImageMagick programs from your script.

-Steve

 
 
   When I view this web page I get I get, in-
   konqueror - all thumb images are fine
   netscape 6 - no thumb images, just a narrow verticle bar
   opera 6 - a rectangle with the word image in it
   I tried from work on an nt machine and got broken image icons.
  
   I have verified all browsers are set to show all images. When I
   right-click
   and hit show image, so I would view the thumb itself, I don't get the
   image,
   instead I get the text url to the image.
   I've included the full code below.
   Any ideas what the cause might be?
  
   --
   Chip W
   
   Windows 95/NT - 32 bit extensions and a graphical shell for a 16 bit
   patch
   to an 8 bit operating system originally coded for a 4 bit
 microprocessor,
   written by a 2 bit company that can't stand 1 bit of competition.
   
  
   =
  
   html
   head
 titleChips Pics/title
   /head
   body
   table summary= border=0 align=center cellpadding=5
   cellspacing=5
   tr
 ?
  $pic = (int) $pic;
   if(! isset($pic))
   { $pic = 0; }
   $new_pic=$pic+24;
   $conn=mysql_connect(localhost, chip,carvin) or die (Could
 not
   get
   the databse);
 mysql_select_db(images, $conn) or die (Could not select the
   database);
 $num = mysql_query(select count(*) from misc) or
   die(mysql_error());
$sql=select * from misc limit $pic,24;
$result=mysql_query($sql) or die (The query didn't work,
 oops);
if (mysql_num_rows($result) == 0)
   {
   echo tr\ntd colspan=\6\
 align=\center\\nfont
   size=\+2\Oops, you've reached the end of the line.\nbr\na
   href=\../index.html\Home/a/font;
   }
else
   {
   while ($row=mysql_fetch_array($result))
   {
   printf(td align=\center\a href=\%s\img
   src=\thumbs/%s\/a/td\n, $row[name], $row[name]);
   $i++;
   if($i %6==0)
   {
   echo /tr\n;
   }
   }
   echo tr\ntd colspan=\6\ align=\center\\na
   href=\../index.html\Home/anbsp;\na
   href=\index.php?pic=$new_pic\Next/a\n/td\n/tr\n;
   echo tr\ntd colspan=\6\ align=\center\\nThere are 
   .mysql_result($num,0,0).  pics in the database/td\n/tr\n;
   }
 ?
   /table
   /body
   /html
  
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 Windows 95/NT - 32 bit extensions and a graphical shell for a 16 bit
 patch
 to an 8 bit operating system originally coded for a 4 bit microprocessor,
 written by a 2 bit company that can't stand 1 bit of competition.
 
 

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Re: [PHP-DB] Variable search help still needed - sorry :-(

2002-01-19 Thread Chris Payne

Hi there,

I made some of the changes you said below, and when I check the query I get
this:

The query is SELECT distinct description, email, url, country, category,
type, rating from search6 WHERE description LIKE '%word%'AND category =
'Automotive' AND country = 'Austria' AND type = 'Car Rental' ORDER BY
description


so to me it doesn't appear to be putting the array item in there, or am I
wrong?  I am confused, thanks for your help.

Regards

Chris


 On Saturday 19 January 2002 13:11, Chris Payne wrote:
  Hi there,
 
  I know this is probably a REALLY simple problem, but I can't get this to
  work.  I need to get it to cycle through each word and do a search, I
used
  this as sent from Beau Lebens (Thank you) but I can't get it to work.
It
  works on 1 word querie but if I enter more than 1 it says can't execute
  query, please help and tell me what i'm doing wrong :-)

 Anytime you're putting a query to a db and you're not getting the results
 expected you should echo the query to see what you're actually sending to
the
 db. You could also copy and paste the query into the mysql-client to see
what
 pops out.


  $words = explode( , $test);
 
  // create connection
  $connection = mysql_connect(Localhost,!!!,!!!) or die(Couldn't
make
  a connection.);
 
  // select database
  $db = mysql_select_db(tas, $connection)
   or die(Couldn't select database.);
 
  $sql = SELECT distinct description, email, url, country, category,
type,
  rating from search6  WHERE ; foreach ($words as $word) {
  $sql .= description LIKE '%word%';

 You should probably be using:

   $sql .=  description LIKE '%word%' OR ; # note the spaces


  }

 After the foreach loop you need to remove the trailing OR . That is you
 need to remove the last 3 characters from $sql.



  $sql .= AND category = '$category' AND country = '$country' AND type =
  '$type' ORDER BY description;

 This would be a good place to:

  echo(The query is $sqlbr);


  $sql = mysql_query($sql,$connection)
   or die(Couldn't execute query.);


 hth
 --
 Jason Wong - Gremlins Associates - www.gremlins.com.hk

 /*
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 you knowing nothing?
 -- Lloyd Cole and the Commotions
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Re: [PHP-DB] distinct - how to do

2002-01-19 Thread Miles Thompson

Barry,

Change --  xp_topics.topicid = xp_stories.topicid
to--- xp_stories.topicid = xp_topics.topicid
and see what your results are. Your primary selection is on xp_topics.

Then add DISTINCT following your SELECT.

That should do the trick - Miles

At 02:28 AM 1/20/2002 +1300, Barry Rumsey wrote:
I have the following query:
$query = SELECT  * FROM xp_topics, xp_stories WHERE xp_topics.topicid = 
xp_stories.topicid AND xp_topics.artistname='Faith Hill' ORDER BY 
topictext DESC LIMIT 0,20;
It returns the lot but a lot of doubles.
  I want to put a DISTINCT call the query, but if I put it after the 
 select ( select distinct * from...) it returns nothing. How do you do 
 a DISTINCT?


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Re: [PHP-DB] MySQL database

2002-01-19 Thread Miles Thompson

Morten,

What's your level of knowledge of both databases and PHP?  Please have a 
look at the Introductory Tutorial (Link at the top left of www.php.net). At 
the end of that tutorial, which is admittedly rudimentary, there are links 
to more advanced ones, including ones specifically for user authentication.

Regards - Miles Thompson

At 06:08 PM 1/19/2002 +0100, Morten Nielsen wrote:
Hi,

Could anybody explain to me how I should make a table with usernames and
passwords.
I want to make a site, where users can sign up and enter some values, which
is stored in a different table.
How do I grant the necessary acces to the tables, so users can enter values
into them?

Please help,
Morten



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Re: [PHP-DB] MySQL database

2002-01-19 Thread Miles Thompson

As Brian Clark just pointed out on php-general, in response to another 
issue ...
http://www.faqts.com/knowledge_base/index.phtml/fid/51/

Some very specific refernces. You'll find what you need there.

Miles

At 06:08 PM 1/19/2002 +0100, Morten Nielsen wrote:
Hi,

Could anybody explain to me how I should make a table with usernames and
passwords.
I want to make a site, where users can sign up and enter some values, which
is stored in a different table.
How do I grant the necessary acces to the tables, so users can enter values
into them?

Please help,
Morten



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Re: [PHP-DB] Variable search help still needed - sorry :-(

2002-01-19 Thread Jason Wong

On Sat, 19 Jan 2002, Chris Payne wrote:

 Hi there,
 
 I made some of the changes you said below, and when I check the query I get
 this:
 
 The query is SELECT distinct description, email, url, country, category,
 type, rating from search6 WHERE description LIKE '%word%'AND category =
 'Automotive' AND country = 'Austria' AND type = 'Car Rental' ORDER BY
 description
 
 
 so to me it doesn't appear to be putting the array item in there, or am I
 wrong?  I am confused, thanks for your help.
 
  You should probably be using:
 
$sql .=  description LIKE '%word%' OR ; # note the spaces


Missed this error the first time round. It should be:

  $sql .=  description LIKE '%$word%' OR ; # note the $!!


hth
-- 
Jason Wong


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[PHP-DB] Password help plz

2002-01-19 Thread Shelly Wilds

hi guys,
  i'm new to php/mysql :), so plz bare with me a bit.
i'm trying to figure out how to retrieve password un crypted to browser.

//
$result = mysql_query(SELECT * FROM auth WHERE 
username='$valid_user',$db);
$myrow = mysql_fetch_array($result);
?

form method=post action=?php echo $PHP_SELF?
input type=hidden name=id value=?php echo $myrow[id]?
Username:input type=Text name=username value=?php echo 
$myrow[username]?br
Userpass:input type=Text name=userpass value=?php echo 
$myrow[userpass]?br
Usermail:input type=Text name=usermail value=?php echo 
$myrow[usermail]?br
Userpriv:input type=Text name=userpriv value=?php echo 
$myrow[userpriv]?br
input type=Submit name=update value=Update information/form
//

i've tried this and no result...
Userpass:input type=Text name=userpass value=?php echo 
$myrow[userpass(password('userpass'))]?br

could someone plz help me out with this...tx

Shelly



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[PHP-DB] load data infile problem

2002-01-19 Thread rop30999

I have a called file cats.txt which count data that were solitary of a DB
Access.
I need to export these data for a table 'cats' inside of a DB done in MySql.

In MySql I can execute this procedure in the following way:

Load data local infile gatos.txt
into table gatos
fields
terminated by ','
enclosed by ''
(Id, Nome, Raça);

I need to know how I can accomplish this same operation but using PHP

Thank you

Paulo



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Re: [PHP-DB] Password help plz

2002-01-19 Thread Miles Thompson

Shelly,

Retrieve a decrypted password for display? Can't do it, MySQL's password() 
function is one way. Check this page of  the MySQL docs: 
http://www.mysql.com/doc/M/i/Miscellaneous_functions.html

You can display the password as encrypted by that function.

PHP doesn't have a password() function, that's a MySQL function, so your line
?php echo $myrow[userpass(password('userpass'))]?
won't work.

This isn't an altogether bad thing. There is a long-held belief that once 
passwords are set no one should be able to retrieve them, only reset them. 
This does make it very difficult to use the users table for mailing 
passwords to users. g

If you want to encrypt /decrypt passwords, have a look at the des_encrypt() 
and des_decrypt() functions on the above-referenced page.

If you want still more information on passwords there is a tutorial/article 
on line at www.zend.com

Regards - Miles Thompson

At 04:13 PM 1/19/2002 -0500, Shelly Wilds wrote:
hi guys,
  i'm new to php/mysql :), so plz bare with me a bit.
i'm trying to figure out how to retrieve password un crypted to browser.

//
$result = mysql_query(SELECT * FROM auth WHERE 
 username='$valid_user',$db);
 $myrow = mysql_fetch_array($result);
 ?

 form method=post action=?php echo $PHP_SELF?
 input type=hidden name=id value=?php echo $myrow[id]?
 Username:input type=Text name=username value=?php echo 
 $myrow[username]?br
 Userpass:input type=Text name=userpass value=?php echo 
 $myrow[userpass]?br
 Usermail:input type=Text name=usermail value=?php echo 
 $myrow[usermail]?br
 Userpriv:input type=Text name=userpriv value=?php echo 
 $myrow[userpriv]?br
 input type=Submit name=update value=Update information/form
//

i've tried this and no result...
Userpass:input type=Text name=userpass value=?php echo 
$myrow[userpass(password('userpass'))]?br

could someone plz help me out with this...tx

Shelly



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Re: [PHP-DB] load data infile problem

2002-01-19 Thread Miles Thompson

You running Windows or *nix?  File permissions will play a part in this, 
but use PHP's exec() function to execute MySQL's load data infile. The 
manual has a number of well annotated examples. The big problem may be that 
you'll be executing the command as whatever user the web server is running as.

But before you start reinventing the wheel,  search for MySQL import csv 
PHP, or something similar, and check out the script sites referred to in 
the links part of the manual. This isn't a new problem and has been 
addressed before.

HTH - Miles Thompson


At 09:13 PM 1/19/2002 +, rop30999 wrote:
I have a called file cats.txt which count data that were solitary of a DB
Access.
I need to export these data for a table 'cats' inside of a DB done in MySql.

In MySql I can execute this procedure in the following way:

Load data local infile gatos.txt
into table gatos
fields
terminated by ','
enclosed by ''
(Id, Nome, Raça);

I need to know how I can accomplish this same operation but using PHP

Thank you

Paulo



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