[PHP-DB] Firebird under Windows 2000

2003-09-25 Thread thejavo
Hi!:
I don't know if anybody tried PHP with Firebird, but I've got a really
curious problem. I've installed PHP 4.3.3 and work with Firebird 1.5 RC6 and
MS - IIS without any problems, but suddenly, and with no other advice or
error messages than the "ring" of a bell my PHP pages stop to work. I tried
everything but nothing seems to solve the problem.

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[PHP-DB] Sybase

2003-09-25 Thread Stephan van Beerschoten
Hi all,

As many, I'm forced to start my message too with the problem statement
that I can't connect to my sybase database. I have to be more honest
even in saying that I don't even know the difference in --enable-sybase
and --enable-sybase-ct (I have tried both). 

I'm by no means an SQL nitwit.. I just never had to work with sybase
before.
I don't have any clue when it comes to sybase.. never worked with
any, but I have to now. I have a login and can connect using isql
and the database definition 'CST_SYB' which comes straight out of the
sybase interfaces file.
However I can't seem to get any php connections working. I can flood you
with sybase_connect() examples, but they come straight from the manual.
What am I missing ? 

Oh btw, I compiled my php using the orignal sybase openclient package in
$SYBASE, but I also see people referring to 'freedts'? I assume this is
a substitute in case no original sybase libs are available, right?
Anyway, any pointers would be more then welcome.

/Stephan

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Re: [PHP-DB] large csv text file import into postgresql via PHP

2003-09-25 Thread Martin Marques
El Jue 25 Sep 2003 13:08, Dave [Hawk-Systems] escribió:
> we have a number of csv dumps that occasionally have to be used to update
> tables in a postgres database...
>
> normally this is done by uploading the file and whomever running a php
> based parser which opens the file into an array, does a split on the comma,
> then executes an insert or update to the database with the split array
> values.
>
> we have a new upload that involves a 143mb file, compared to previous
> upload sizes of 10k to 150k.  Is there a more efficient way to handle this
> rather than having PHP load the entire file into an array (which would have
> to be in memory during the operation, correct?).

I guess you are using file() to read the entire file. Try using fopen() and 
read line by line with fread().

-- 
Porqué usar una base de datos relacional cualquiera,
si podés usar PostgreSQL?
-
Martín Marqués  |[EMAIL PROTECTED]
Programador, Administrador, DBA |   Centro de Telematica
   Universidad Nacional
del Litoral
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[PHP-DB] Re: MySQL Very Slow Work.

2003-09-25 Thread Chris Berlioz
You can always try indexing your data, this will improve your query speeds.
Don't know how you are quering data, but would suggest using keys and
"optimized" query expressions.  You should also check your Win 2000 services
running and anything that might interfere with your setup (ie: antivir,
etc), just a thought! it might not have anything to do with your problem
though.

No concerning the list, but its interesting if you are Russian how you build
your sentences in English... just like orientals do, so the root of the
languages must be the same (russian and oriental dialects).

Christian.


"äÒÕÞÉË ëÉÒÉÌÌ" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> I have php 4.3.2, Apache 2.0.46 and MySQL 4.* on Windows 2000 SP4.
> And i have problem.
> When i make query from php to MySQL.
> This work wery slow.
> Every query 4-5 sec.
> What i can make.
> Sorry for error, i know english wery bad.
> Please HELP ME!

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Re: [PHP-DB] MySQL Very Slow Work.

2003-09-25 Thread George Patterson


On Sat, 20 Sep 2003 19:54:18 +0400
"äÒÕÞÉË ëÉÒÉÌÌ" <[EMAIL PROTECTED]> wrote:

> I have php 4.3.2, Apache 2.0.46 and MySQL 4.* on Windows 2000 SP4.
> And i have problem.
> When i make query from php to MySQL.
> This work wery slow.
> Every query 4-5 sec.
> What i can make.
> Sorry for error, i know english wery bad.
> Please HELP ME!
> 

Don't worry about your grammar errors. I'm sure my russian would be
worse. I am assuming you that are russian based on you email
address..but that is off topic for the list.

Firstly, You never said what processor and the amount of memory that is
in the machine that you have install that software.

How many records have you got in the database?? We have implemented a
project in which queries take 20-30 seconds.. about 1 million records,
I think..


George Patterson

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[PHP-DB] MySQL Very Slow Work.

2003-09-25 Thread äÒÕÞÉË ëÉÒÉÌÌ
I have php 4.3.2, Apache 2.0.46 and MySQL 4.* on Windows 2000 SP4.
And i have problem.
When i make query from php to MySQL.
This work wery slow.
Every query 4-5 sec.
What i can make.
Sorry for error, i know english wery bad.
Please HELP ME!

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[PHP-DB] large csv text file import into postgresql via PHP

2003-09-25 Thread Dave [Hawk-Systems]
we have a number of csv dumps that occasionally have to be used to update tables
in a postgres database...

normally this is done by uploading the file and whomever running a php based
parser which opens the file into an array, does a split on the comma, then
executes an insert or update to the database with the split array values.

we have a new upload that involves a 143mb file, compared to previous upload
sizes of 10k to 150k.  Is there a more efficient way to handle this rather than
having PHP load the entire file into an array (which would have to be in memory
during the operation, correct?).

thanks

Dave

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Re: [PHP-DB] parse error.

2003-09-25 Thread Steve Davies
Hi Micella

You need to either slash-escape your insert query or use single quotes:

$query="insert into dene (day,start_time) values (\"2003.09.25\",\"22:30\") " ;

or

$query="insert into dene (day,start_time) values ('2003.09.25','22:30') " ;

steve

M|cella Erdem Efe wrote:

I am a new programmer of PHP4.3.3 an MySql 3.23 .

When below script is executed
   "Parse error: parse error, unexpected T_DNUMBER in c:\program
files\apache group\apache\htdocs\ilkdeneme21.php on line 17"
is being seen.
This may be very simple but I could not solve it.Could you help me for this
error?
Thanks for your attention
[EMAIL PROTECTED]

mysql_connect("localhost","username");
if (mysql_select_db($dbname))
{ echo "connected";}
else
{ echo "not connected";}
$query="insert into dene (day,start_time) values ("2003.09.25","22:30") " ;
  $result=mysql_query($query);
  if ($result))
{ echo "data girildi";}
else
{ echo "data girilemedi";
 exit;}
?>

 

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Re: [PHP-DB] OUTFILE

2003-09-25 Thread Nitin
select  into OUTFILE  from 

Enjoy happy programming
Nitin


- Original Message - 
From: "Jonatan Pugliese." <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, September 25, 2003 6:59 PM
Subject: [PHP-DB] OUTFILE


> How to use OUTFILE function in mysql and linux?
> 
> 
> 
> Jonatan Pugliese
> Area Sistemas
> ACA - Automovil club Argentino
> 4808-4676 / 4663
> www.aca.org.ar  
> 
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> 

[PHP-DB] OUTFILE

2003-09-25 Thread Jonatan Pugliese.
How to use OUTFILE function in mysql and linux?



Jonatan Pugliese
Area Sistemas
ACA - Automovil club Argentino
4808-4676 / 4663
www.aca.org.ar  

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SV: [PHP-DB] parse error.

2003-09-25 Thread Henrik Hornemann
Hi,

There are at least two errors in your script:

$query="insert into dene (day,start_time) values ("2003.09.25","22:30") " ;
should be
$query="insert into dene (day,start_time) values ('2003.09.25','22:30') " ;

And
if ($result))
should be
if ($result)

regards Henrik Hornemann

> -Oprindelig meddelelse-
> Fra: Mücella Erdem Efe [mailto:[EMAIL PROTECTED]
> Sendt: 26. september 2003 00:52
> Til: [EMAIL PROTECTED]
> Emne: [PHP-DB] parse error.
> 
> 
> I am a new programmer of PHP4.3.3 an MySql 3.23 .
> 
> When below script is executed
> "Parse error: parse error, unexpected T_DNUMBER in c:\program
> files\apache group\apache\htdocs\ilkdeneme21.php on line 17"
>  is being seen.
> 
> This may be very simple but I could not solve it.Could you 
> help me for this
> error?
> Thanks for your attention
> [EMAIL PROTECTED]
> 
> 
>  $dbname = 'mycmpe';
> 
> mysql_connect("localhost","username");
> if (mysql_select_db($dbname))
> { echo "connected";}
> else
> { echo "not connected";}
> 
> $query="insert into dene (day,start_time) values 
> ("2003.09.25","22:30") " ;
>$result=mysql_query($query);
>if ($result))
> { echo "data girildi";}
> else
> { echo "data girilemedi";
>   exit;}
> 
> ?>
> 
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> To unsubscribe, visit: http://www.php.net/unsub.php
> 
> 

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[PHP-DB] parse error.

2003-09-25 Thread Mücella Erdem Efe
I am a new programmer of PHP4.3.3 an MySql 3.23 .

When below script is executed
"Parse error: parse error, unexpected T_DNUMBER in c:\program
files\apache group\apache\htdocs\ilkdeneme21.php on line 17"
 is being seen.

This may be very simple but I could not solve it.Could you help me for this
error?
Thanks for your attention
[EMAIL PROTECTED]




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Re: [PHP-DB] Re: Email Application

2003-09-25 Thread CPT John W. Holmes
From: <[EMAIL PROTECTED]>

> I am not so new in PHP but I have a problem.
> I am trying to create a webmail program for my penpal
> site. I cant retrieve and desplay e-mails from my mail
> server. Any one with ideas?

I have an idea.

---John Holmes...

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Re: [PHP-DB] Re: Email Application

2003-09-25 Thread George Patterson
On Thu, 25 Sep 2003 00:42:21 +0300
[EMAIL PROTECTED] wrote:

> Hey Guys,
> 
> I am not so new in PHP but I have a problem.
> I am trying to create a webmail program for my penpal
> site. I cant retrieve and desplay e-mails from my mail
> server. Any one with ideas?
> 

Unless you are trying to achive something different from the other open
source webmail packages, why re-invent the wheel?? 

I suggest that you find something that is close to what you want and
modify from there.

I'd suggest using IMp is for the mail server supports it.


George Patterson

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[PHP-DB] Record Selection

2003-09-25 Thread Kaan
I have a table that the user can select numerous address's, I then want them
to click submit and have a confirmation page that just shows the address's
they selected.


If you take a look at this you will see what I mean and where I have got to.

ttp://www.tbptestsite.com/kaantest/index.php
or download at
http://www.tbptestsite.com/kaantest/calloff.zip


on the 'ajr_calloff_selected.php' if the user does not add a quantity it
shouldn't go through to the confirmation page, making it so only ones with
quantities go to the confirmation page filtering out all the other records.


Please could someone help me on this, I am completely new to PHP so this is
all abit over my head.


Many thanks in advance,
Kaan.

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Re: [PHP-DB] Re: Email Application

2003-09-25 Thread Ignatius Reilly
If your mail server supports IMAP, you should use the PHP IMAP functions.
Very convenient.

Ignatius
_
- Original Message -
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, September 24, 2003 11:42 PM
Subject: [PHP-DB] Re: Email Application


> Hey Guys,
>
> I am not so new in PHP but I have a problem.
> I am trying to create a webmail program for my penpal
> site. I cant retrieve and desplay e-mails from my mail
> server. Any one with ideas?
>
> Regards,
>
> ~ Charles
>
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>
>

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Re: [PHP-DB] Re: Email Application

2003-09-25 Thread Jason Wong
On Thursday 25 September 2003 05:42, [EMAIL PROTECTED] wrote:

> I am not so new in PHP but I have a problem.
> I am trying to create a webmail program for my penpal
> site. I cant retrieve and desplay e-mails from my mail
> server. Any one with ideas?

With the limited amount of information give, I would say there is something 
wrong with your code.

-- 
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Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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[PHP-DB] Re: Email Application

2003-09-25 Thread mutie
Hey Guys,

I am not so new in PHP but I have a problem.
I am trying to create a webmail program for my penpal
site. I cant retrieve and desplay e-mails from my mail
server. Any one with ideas?

Regards,

~ Charles

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Re: [PHP-DB] Photo Gallery Comments.. NOT WORKING

2003-09-25 Thread Viorel Dragomir
Hi,

I see that you try to use $result, which is a resource [i think], as a
normal string.
Try to use the fetch data instead of the resource.


vio-
- Original Message - 
From: "Adam Symonds" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, September 23, 2003 9:14 AM
Subject: [PHP-DB] Photo Gallery Comments.. NOT WORKING


> Hi I have the following code which is a photo gallery, I have set it up so
> users
> can add comments to the photos, what I want to happen is in the gallery if
a
> user
> has posted a comment on the photo, I want it to say comments under the
photo
> in the gallery, I have tried doing this using  IN_ARRAY but I am getting
an
> error msg,
>
> Warning: in_array(): Wrong datatype for second argument
> on line 203
>
> line 203 is this: if(in_array($images[$i],$result))echo " class=blue>Comments";
> will have a play around with a few things and left yuo know if I suceed b4
> you get back.
>
> Can someone see what I am doing wrong with the in_array..
>
> Thanx In advance
> Adam
>
> ==
>
>  //start of comments selection...
>$mysql_access = mysql_connect("localhost", "username", "password") or
> DIE(mysql_error());
>mysql_select_db("database", $mysql_access) or DIE(mysql_error());
> $query = "SELECT * FROM comphotolink WHERE comphotolink.PhotoPath =
> $PathVar";
>$result = mysql_query($query, $mysql_access) or DIE(mysql_error());
> if ($result) {
> while ($r = mysql_fetch_array($result))
> { // Begin While
> extract($r);
> $PhotoName = $PhotoName;
> //echo "$PhotoName ";
> } //End While
> } else {
> echo "no comments";
> }
>
> //end of comments selection
>
> //page vars
> $total = count($images);
> $limit = 15;
> $page = $_GET['page'];
> $num_prow=3;
>
> //$offset = ($page - 1) * $limit;
>
> //$jpgs=0;
> $handle=opendir($PathVar);
> $index=0;
> $images;
> $last_updated;
>
> while($file=readdir($handle)){
>
> if($file!='.' && $file!='..'){
> $myfile=explode(".",$file);
>
> if($myfile[1]=='jpg' || $myfile[1]=='JPG'){
> $images[$index]=$file;
> //$size[$index]=filesize($file);
> //$date[$index]=filemtime($file);
> $thumb[$index]=$file;
> $index++;
> $jpgs++;
> }
> }
> }
>
> if(!$images){
> print "::Warning::This folder contains no allowed image
files.";
> exit;
> }
>
> $total=count($images);
>
> $numPages = ceil($total / $limit);
>
>
> $j=0;
>
> // Set first set of pictures
> if(!isset($pics)){$pics=$page * $limit;}
>
> //$pics = $page * $limit;
>
>
> $from = $pics-$limit;
> $pp = $pics+$limit;
> // =OUTPUT=
>
> $query2 = "SELECT * FROM eventlistings WHERE PhotoPath = $PathVar";
>$result2 = mysql_query($query2, $mysql_access) or DIE(mysql_error());
> if ($result2) {
> while ($r = mysql_fetch_array($result2))
> { // Begin While
> extract($r);
> echo "";
> }} //End While
>
> echo "$EventName - $EventDate 
> Directory contains a total of ".count($images)." image files ";
>
> echo " bordercolor=#CC33CC border=1 class=txt> bgcolor=White>";
>
> for($i = $from; $i < $pics && $i < $total; $i++){
>
> if($j == $num_prow){
> echo "
>  href=\"MainPhoto.php?Image=$thumb[$i]&PhotoPath=$PathVar\">
> 
> ";
> if(in_array($images[$i],$result))echo " class=blue>Comments";
> echo "";
> //
> $j = 1;
>
> }else{
> echo "
href=\"MainPhoto.php?Image=$images[$i]&PhotoPath=$PathVar\">";
> //
> if(in_array($images[$i],$result))echo " class=blue>Comments";//
>
> $j++;
>
> }
> }
> echo "";
>
> if ($page == 1) // this is the first page - there is no previous page
> echo "Previous";
> else// not the first page, link to the previous page
> echo " "\" class=cssbtn>Previous";
>
> for ($i = 1; $i <= $numPages; $i++) {
> echo " | ";
> if ($i == $page)
> echo "$i";
> else
> echo "$i";
> }
>
> if ($page == $numPages) // this is the last page - there is no next
page
> echo " | Next";
> else// not the last page, link to the next page
> echo " |  . "\" class=cssbtn>Next";
> /*
> if($i < $total){echo " href=\"".$PHP_SELF."?PathVar=$PathVar&page=$pp\">Next";}
> if($page != $total){echo "  href=\"".$PHP_SELF."?PathVar=$PathVar&page=$total\">Last";}
> */
> echo "";
>
> closedir($handle);
> ?>
>
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[PHP-DB] Photo Gallery Comments.. NOT WORKING

2003-09-25 Thread Adam Symonds
Hi I have the following code which is a photo gallery, I have set it up so
users
can add comments to the photos, what I want to happen is in the gallery if a
user
has posted a comment on the photo, I want it to say comments under the photo
in the gallery, I have tried doing this using  IN_ARRAY but I am getting an
error msg,

Warning: in_array(): Wrong datatype for second argument
on line 203

line 203 is this: if(in_array($images[$i],$result))echo "Comments";
will have a play around with a few things and left yuo know if I suceed b4
you get back.

Can someone see what I am doing wrong with the in_array..

Thanx In advance
Adam

==

";
} //End While
} else {
echo "no comments";
}

//end of comments selection

//page vars
$total = count($images);
$limit = 15;
$page = $_GET['page'];
$num_prow=3;

//$offset = ($page - 1) * $limit;

//$jpgs=0;
$handle=opendir($PathVar);
$index=0;
$images;
$last_updated;

while($file=readdir($handle)){

if($file!='.' && $file!='..'){
$myfile=explode(".",$file);

if($myfile[1]=='jpg' || $myfile[1]=='JPG'){
$images[$index]=$file;
//$size[$index]=filesize($file);
//$date[$index]=filemtime($file);
$thumb[$index]=$file;
$index++;
$jpgs++;
}
}
}

if(!$images){
print "::Warning::This folder contains no allowed image files.";
exit;
}

$total=count($images);

$numPages = ceil($total / $limit);


$j=0;

// Set first set of pictures
if(!isset($pics)){$pics=$page * $limit;}

//$pics = $page * $limit;


$from = $pics-$limit;
$pp = $pics+$limit;
// =OUTPUT=

$query2 = "SELECT * FROM eventlistings WHERE PhotoPath = $PathVar";
   $result2 = mysql_query($query2, $mysql_access) or DIE(mysql_error());
if ($result2) {
while ($r = mysql_fetch_array($result2))
{ // Begin While
extract($r);
echo "";
}} //End While

echo "$EventName - $EventDate 
Directory contains a total of ".count($images)." image files ";

echo "";

for($i = $from; $i < $pics && $i < $total; $i++){

if($j == $num_prow){
echo "


";
if(in_array($images[$i],$result))echo "Comments";
echo "";
//
$j = 1;

}else{
echo "";
//
if(in_array($images[$i],$result))echo "Comments";//

$j++;

}
}
echo "";

if ($page == 1) // this is the first page - there is no previous page
echo "Previous";
else// not the first page, link to the previous page
echo "Previous";

for ($i = 1; $i <= $numPages; $i++) {
echo " | ";
if ($i == $page)
echo "$i";
else
echo "$i";
}

if ($page == $numPages) // this is the last page - there is no next page
echo " | Next";
else// not the last page, link to the next page
echo " | Next";
/*
if($i < $total){echo "Next";}
if($page != $total){echo " Last";}
*/
echo "";

closedir($handle);
?>

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