Hi,
Let me get this straight:
You're trying to transfer a file from a local PC (A) to a server (B). And your
code is running on (B)?
If so, then, (assuming you have things setup correctly, ie have an ftpserver
running on (A)), you should be using ftp_get() or similar.
If not, could
Hi,
I have a table called Bookings and a table called User. Bookings are created
and hold the User_ID of the User who created it (Booking.Booked_User) and
the User who will be going on the booking (Booking.Booking_Creator). How can
I create a report that lists both users on each row. If I do
Hi,
how can I get the pathinformation you can see in the file-field if you
chose one file within a formular for transfer.
Regards,
Ruprecht
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how can I get the pathinformation you can see in the file-field if you
chose one file within a formular for transfer.
http://nl.php.net/manual/en/function.pathinfo.php ?
laters,
Fedde
~= Everybody lies, but it doesn't matter because nobody listens =~
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PHP Database Mailing List
Hi,
Try something like this:
SELECT U1.User_Name
, U2.User_Name
, B.Booking_Date
FROMUSER U1
, USER U2
, BOOKING B
WHERE B.Booking_Creator = U1.User_ID
AND B.Booked_User = U2.User_ID'
Jack
-Original
On Monday 06 October 2003 18:31, Ruprecht Helms wrote:
how can I get the pathinformation you can see in the file-field if you
chose one file within a formular for transfer.
If you mean when you do an HTTP upload, then no, you cannot get the path info.
All you get is the file name. This is for
Thank you!
Jacob A. Van Zanen [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
Try something like this:
SELECT U1.User_Name
, U2.User_Name
, B.Booking_Date
FROM USER U1
, USER U2
, BOOKING B
WHERE B.Booking_Creator = U1.User_ID
AND B.Booked_User = U2.User_ID'
Jack
On Monday 06 October 2003 16:48, Ruprecht Helms wrote:
I want that (B) can locate the file on (A) and upload it to the
subdirectory on (B). This should also be possible in the case the user
have no ftp-server on his local pc.
If (A) does not have an ftp server installed then you're asking for
On Mon, 2003-10-06 at 13:07, Jason Wong wrote:
On Monday 06 October 2003 18:31, Ruprecht Helms wrote:
how can I get the pathinformation you can see in the file-field if you
chose one file within a formular for transfer.
If you mean when you do an HTTP upload, then no, you cannot get the
On Mon, 2003-10-06 at 13:05, Jason Wong wrote:
Now I tried the method with move_uploaded (http-upload).
This is the testscript
?php
// upload.php: PHP File Upload im Safe Mode21.5.02/vo
// (http-Protokoll und POST-Mechanismus)
// Skript funktioniert auch im Safe
Ok this time I checked the SQL select syntax! So I hope it's not something
that easy again (Well actually easy would be nice)
The other day I Posted a email question about getting a 37000 sql error but
my sql syntax was wrong. Yes I felt stupid but this time I corrected the
syntax and I am
Hi
Does the query return data when executed not through a browser but
directly on the database?
If yes, how much time does it take to return the data. I believe default
time out for apache is 30 seconds.
So maybe it's a webserver setting that needs to be increased.
Jack
-Original
and put it inside a transaction cos in case something goes wrong part of
the way through
pete
Jeff Shapiro wrote:
This should do it:
UPDATE Bookings
SET
Booking_Start_Date = CONCAT(DATE_FORMAT(Booking_Start_Date,
'%Y-%m-%d'), '09:00:00'),
Booking_End_Date =
Hi,
I could use some help here. I've been running a Red Hat 9 server for
the last couple of months that uses FreeTDS/unixODBC to connect to a
Microsoft SQL Server 2k Server. Lately I've added the Windows server to
the Active Directory Domain, and now php cannot keep a persistant
connection
Ruprecht,
I've experienced this problem, its that you need to turn ftp_pasv on.
ftp_pasv($connection_id,true);
That should take care of it, don't' worry about anything else.
Michael Scappa
Lead Developer
Verve Internet Solutions for higher education
-Original Message-
From:
Robin Kopetzky wrote:
Good afternoon.
I found this code in a program I'm renovating and think this is very
redundant. Also, it does slow queries down while doing all of the
conversions.
prod_id in the mysql database is declared an integer.
SQL above
where prod_id = ' . (int)$prod_id . '
Robin Kopetzky wrote:
Good afternoon.
I found this code in a program I'm renovating and think this is very
redundant. Also, it does slow queries down while doing all of the
conversions.
prod_id in the mysql database is declared an integer.
SQL above
where prod_id = ' . (int)$prod_id . '
Hello,
For some reason php will not connect to a remote mysql server.. Using the
following code:
?php
$link = mysql_connect('hostname:3306', username, password)
or die(Could not connect: . mysql_error() . \n);
print (Connected successfully);
mysql_close($link);
?
Returns
That's not it.
The user can connect to the database using the mysql client on the same
machine as the webserver to the database machine.
Blake
On 07/10/2003 12:03 AM, Andy Green [EMAIL PROTECTED] wrote:
check the permissions granted to the user to make sure that it's not
restricted to
Hi, All:
I have some information stored in the database.
When I try to show them, sometimes it give me the
following warning:
Warning: printf(): Too few arguments ...
Here is the problematic code:
printf(textarea COLS=56 ROWS=7 name=\description\$des/textarea br);
I figured out that if there
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