[PHP-DB] upload binary into postgres

2004-02-09 Thread Hiro
Hi!

I would like to upload binary data into the PorstgreSQL.
Does anyone know how to upload the code? I do not want to use
OID. I want to insert binary direct into table.
I create table field bytea. Is it correct?

Pelase teach me how!



regards,
hiri
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[PHP-DB] Install Apache/PHP where to find libphp4.so?

2004-02-09 Thread Alain Barthlemy
Hi,

The problem is the following:

Computer 1:

Apache-2.0.48: ./configure --prefix=/www --enable-so --enable-modules=all
--enable-mods-shared=most
 
PHP-4.3.4: ./configure --with-apx2=/www/bin/apxs
--with-config-file-paths=/www/conf --enable-sigchild

libphp4.so is in /www/modules. I copied it from the PHP source dir
(/php-4.3.4/libs).

Everything works OK

+

Computer 2 (labtop for trial)

Apache-2.0.48 and PHP-4.3.4 thus no change and same configuration as above but
I don't find libphp4.so . I remember it was not easy to get it. If anybody can
tell me where to get it? Without that library difficult to read a PHP script of
course.

+

Linux-2.4.19 on both computers.

-- 
Alain Barthélemy
[EMAIL PROTECTED]
http://bartydeux.be
Linux User #315631

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[PHP-DB] field type, field length and field flags not working???

2004-02-09 Thread Daniel Audette
All questions on the bottom
Right now I am working along with STYS php in 24hrs(Sams)

I am using the following code 

?php 
   //connect to the mysql database
   $link = mysql_connect(localhost, $user, $pass);
   //make sure it worked
   if (!$link)
  die(Couldn't connect to MySQL);
   //get list of available databases
   $db_res = mysql_list_dbs($link);
   //loop through the available databases
   while($db_rows = mysql_fetch_row($db_res))
   {
  printb$db_rows[0]/b\n;
 //check to see if you are able to select that database
 if([EMAIL PROTECTED]($db_rows[0], $link))
 {
print dlddcouldn't connect -- .mysql_error()./dl;
continue;
 }
 //get list of tables for the above database
 $tab_res = mysql_list_tables($db_rows[0],$link);
 print \tdldd\n;
 //loop throught the table geting the rows
 while($tab_rows = mysql_fetch_row($tab_res))
 {
print \tb$tab_rows[0]/b\n;
$query_res = mysql_query(select * from $tab_rows[0]);
$num_fields = mysql_num_fields($query_res);
print \t\tdldd\n;
for($x = 0; $x  $num_fields; $x++)
{
   print \t\ti;
   print mysql_field_type($query_res, $x);
   print /i i;
   print mysql_field_len($query_res, $x);
   print /i b;
   print mysql_field_name($query_res, $x);
   print /b i;
   print mysql_field_flags($query_res, $x);
   print /i br\n;
}
print \t\t/dl\n;
 }
 print \t/dl\n;
   }
   mysql_close($link);

I am having problems with the FOR LOOP.  Here is a portion of the
results from the query from my mozilla browser

harrysdb

domains

unknown 1 id
unknown 10 domain
unknown 1 sex
unknown 19 mail


mysql

columns_priv

unknown 0 Host
unknown 0 Db
unknown 0 User
unknown 0 Table_name
unknown 0 Column_name
unknown 0 Timestamp
unknown 0 Column_priv

db

unknown 1 Host
unknown 7 Db
unknown 0 User
unknown 1 Select_priv
unknown 1 Insert_priv
unknown 1 Update_priv
unknown 1 Delete_priv
unknown 1 Create_priv
unknown 1 Drop_priv
unknown 1 Grant_priv
unknown 1 References_priv
unknown 1 Index_priv
unknown 1 Alter_priv
unknown 1 Create_tmp_table_priv
real 1 Lock_tables_priv

Why is it coming up with unknown for the field type and the field length
is wrong and field flags not showing either?

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[PHP-DB] Re: Grab and update values (Was Re: php-db Digest 8 Feb 2004)

2004-02-09 Thread Neil Smith [MVP, Digital media]
It's simple - no need for IF statements, as the SQL Select syntax does that 
for you !

Try

UPDATE tablename
SET value2=value1,
value1=0
WHERE value1  3
You might also want to look at the REPLACE INTO syntax in the manual too, 
for completeness.

Be aware though that this won't work if you need to do a join, as the join 
processor cannot know if you have changed a value which it's trying to join 
on. You may need to use temporary tables in that case.

Cheers - Neil.

At 00:44 09/02/2004 +, you wrote:
Message-ID: [EMAIL PROTECTED]
Date: Sun, 8 Feb 2004 15:03:52 +1100 (EST)
From: JeRRy [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
MIME-Version: 1.0
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: 8bit
Subject: Re: php-db Digest 8 Feb 2004 01:40:01 - Issue 2250
Hi,

I want to grab a value from one table field and place
another value in another table fied.
So If I had table value1 and it was set to 3 I want to
recognise the value 3 and put value 1 in table value2.
Example:

value1: 3
value2: (blank)
So now I need to check value1 and MAKE SURE 3 is the
value, if a lower value I want to do nothing.  If 3 
than I want to use the value
Example 2:

value1: 0 (grab 3 and reset to 0, if higher than 3 do
the same)
value2: 1 (If value1 is 3  than value 1 needs to go
in value2)
But how can I achieve this?

The queries are ran once a day, no more.  So when the
query is ran I could than execute the second query to
change the value#'s.
Would I be right in saying that I'd use a 'IF
statement' for this?  Or is there another way to do
this?
I am not sure exactly about executing a query with the
IF statement, I do know how to execute a message or
HTML information to output to the webpage.
I've done some reading online, but have not found what
I am requiring ... Could be looking in the wrong
place, as usual.  All help appreciated.
Jerry



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[PHP-DB] Question

2004-02-09 Thread Remember14a
Dear friends,
I was trying to make online quiz system using php and mysql.
When I added code to score the quiz,  it gives me parse error at line 131. My 
total code line isn't more than 120.

Any comments,or any other code to score the quiz, please
--
---
Parse error: parse error, unexpected $end in C:\webroot\display.php on line 
131

--
---

//Below is the code
?php
// open the connection
$conn = mysql_connect(localhost, , );

// pick the database to use
mysql_select_db(testdb,$conn);


// create the SQL statement
$sql = SELECT * FROM testTable;

// execute the SQL statement
$result = mysql_query($sql, $conn) or die(mysql_error());
//go through each row in the result set and display data

if (!$submit) {


 echo form method=post action=$PHP_SELF;
 echo table border=0;



while ($newArray = mysql_fetch_array($result)) {
 // give a name to the fields
$id  = $newArray['id'];
$testField = $newArray['testField'];
  $testFielda = $newArray['testFielda'];
  $testFieldb = $newArray['testFieldb'];
  $testFieldc = $newArray['testFieldc'];
  $testFieldd = $newArray['testFieldd'];

//echo the results onscreen


echo
trtd colspan=4brb$id/b/td/tr;
echo
TD$testFieldinput type=hidden name=$testField value=\$testField\ br
/td/tr
TDa)input type=radio name=$testFielda 
value=\$testFielda\$testFielda/td/tr
TDb)input type=radio name=$testFieldb 
value=\$testFieldb\$testFieldb/td/tr
TDc)input type=radio name=$testFieldc 
value=\$testFieldc\$testFieldc/td/tr
TDd)input type=radio name=$testFieldd 
value=\$testFieldd\$testFieldd/td/tr;
}
echo /table;


echo input type='submit' value='See how you did' name='submit';

echo /form;

}

elseif ($submit)
{
{

 $score = 0;
 $total = mysql_num_rows($result);
  while ($result = mysql_fetch_array($result))


  {

   $testFielde = $result[testFielde];
   $q = $result[q];

  if ($$q == $testFielde)
  {
  $score++;
  }

 }

 echo p align=centerbYou scored $score out of $total/b/p;
 echo p;

 if   ($score == $total) {
 echo Congratulations! You got every question right!;
 }
 elseif ($score/$total  0.34) {
 echo Oh dear. Not the best score, but don't worry, it's only a quiz.;
 }
 elseif ($score/$total  0.67) {
 echo Well done! You certainly know your stuff.;
 }
 else {
 echo Not bad - but there were a few that caught you out!;
 }

echo /p;

echo pHere are the answers:;

echo table border=0;
$result = mysql_query(SELECT * FROM $testtable ORDER BY id,$testdb);
while ($row = mysql_fetch_array($result)) {

$testField = $row[testFieldetestFielde];
$testFielde = $row[testFielde];
$q = $row[q];

echo trtdbr$testField/td/tr;

if ($$q == $testFielde)
  {
  echo trtdraquo;you answered ${$q}, which is correct/td/tr;
  }
elseif ($$q == ) {
echo trtdraquo;you didn't select an answer. The answer is 
$testFielde/td/tr;
}
else {
echo trtdraquo;you answered ${$q}. The answer is $testFielde/td/tr;
}

}
echo /table/p;

?


[PHP-DB] SMTP authentication

2004-02-09 Thread Marco A. Ortiz
Good afternoon dear friends: 

 

I want to ask you, how I must setup my PHP.INI file, to send e-mail from my
Web Site if my SMTP server requires authentication. Otherwise, I want to
know if exits some kind of “public” SMTP sever that I could use.

 

Thank you very much. 

 

mArK

 



Re: [PHP-DB] Question

2004-02-09 Thread Fedde van Feggelen
Heyaz,

You've got some unclosed statements. Try using tabs for each statement to 
make it easier on yourself
like:
if ($iusetabs == true){
echo  like this ;
}

And in your code.. things go wrong here:
==
echo /table;
echo input type='submit' value='See how you did' name='submit';
echo /form;
} elseif ($submit) {
{
$score = 0;
$total = mysql_num_rows($result);

good luck to you

laters,

Fedde

~= The sum of the intelligence on the planet is a constant; the population 
is growing. =~


Re: [PHP-DB] SMTP authentication

2004-02-09 Thread Fedde van Feggelen

I want to ask you, how I must setup my PHP.INI file, to send e-mail from my
Web Site if my SMTP server requires authentication. Otherwise, I want to
know if exits some kind of public SMTP sever that I could use.


I think you don't need to adjust your php.ini for that, just use the right 
params for sending the mails.
Isn't somthing like this is what you need? (got it from: 
http://nl3.php.net/mail) Or did i get your question wrong?

?
include(Mail.php);
$recipients = [EMAIL PROTECTED];

$headers[From]= [EMAIL PROTECTED];
$headers[To]  = [EMAIL PROTECTED];
$headers[Subject] = Test message;
$body = TEST MESSAGE!!!;

$params[host] = smtp.server;
$params[port] = 25;
$params[auth] = true;
$params[username] = user;
$params[password] = password;
// Create the mail object using the Mail::factory method
$mail_object = Mail::factory(smtp, $params);
$mail_object-send($recipients, $headers, $body);
?


laters,

Fedde

~= The sum of the intelligence on the planet is a constant; the population 
is growing. =~

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Re: [PHP-DB] Question

2004-02-09 Thread John W. Holmes
From: [EMAIL PROTECTED]

 Parse error: parse error, unexpected $end in C:\webroot\display.php on
line
 131

I'm not going to go through all of your code, but this error means you
missed a quote or bracket somewhere, i.e. you didn't supply a closing
bracket for an IF() condition.

?php
if($condition == 1)
{
  dothis();
?

---John Holmes...

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[PHP-DB] binary data into postgresql in bytea

2004-02-09 Thread Hiro
HI!


I wrote the code how to upload and insert binary data into postgresql.

 ?php

 $original_tmp = $_FILES['UploadedFile']['tmp_name'];
 $original_name = $_FILES['UploadedFile']['name'];
 $original_size = $_FILES['UploadedFile']['size'];
 $original_type = $_FILES['UploadedFile']['type'];
 print(hr\n);

 $fileHandle = fopen($original_tmp, r);
 $binaryContent = fread($fileHandle, $original_size);
 $binaryContent = pg_escape_bytea($binaryContent);
 fclose($fileHandle);

 $sql_insert = INSERT INTO objects(b_col, file_name, file_size,
file_type, file_date) VALUES
('$binaryContent'::bytea,'$original_name','$original_size','$original_type',now());
 pg_query($sql_insert) or DIE (Could not perform INSERT to table:
.pg_lst_error());
 ?




Does anyone know right code?
I do not think this is write code for postgresql.

The field which binary data is stored is bytea.


Regards,
hiro

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[PHP-DB] Re: SMTP authentication

2004-02-09 Thread Manuel Lemos
Hello,

On 02/09/2004 11:40 AM, Marco A. Ortiz wrote:
I want to ask you, how I must setup my PHP.INI file, to send e-mail from my
Web Site if my SMTP server requires authentication. Otherwise, I want to
know if exits some kind of public SMTP sever that I could use.
No, the mail() function does not SMTP authentication. You may want to 
use this class that comes with a wrapper function named smtp_mail() that 
works like mail() except that it does let you specify the authentication 
credentials:

http://www.phpclasses.org/mimemessage

http://www.phpclasses.org/smtpclass

--

Um abrao,
Manuel Lemos
Free ready to use OOP components written in PHP
http://www.phpclasses.org/
Metastorage - Data object relational mapping layer generator
http://www.meta-language.net/metastorage.html
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[PHP-DB] Re: php to mysql client problem.

2004-02-09 Thread michael
I've since used different combinations and discovered that I can access 
the database as long As I don't use Passwords...

I guess it is the Webserver and not the Sql server causing the problem...

Michael G. Tracey wrote:
This is my setup: Not really worried about security.

W2kPro w\sp4
Mysql 5.O
Mysqlcc0.9.4
Php 5.0.0.b3 [As CGI]
Apache2.0.48
I can now connect to my server from anywhere using Mysqlcc or another server... home, 
work, etc.
I can run Php scripts.
I can connect to the Apache Server.
Login to Mysql: Works.
==C:\mysql -u mike -p
==Enter password: 
==Welcome to the MySQL monitor. Commands end with ; or \g.
==Your MySQL connection id is 28 to server version: 5.0.0-alpha-max-nt
==Type 'help;' or '\h' for help. Type '\c' to clear the buffer.

PhpInfo Shows:

==MySQL Support enabled
==Active Persistent Links  0
==Active Links  0
==Client API version  3.23.57
==Directive  Local Value  Master Value
==mysql.allow_persistent  On  On
==mysql.connect_timeout  60  60
==mysql.default_host  localhost  localhost
==mysql.default_password  no value  no value
==mysql.default_port  3306  3306
==mysql.default_socket  no value  no value
==mysql.default_user  root  root
==mysql.max_links  Unlimited  Unlimited
==mysql.max_persistent  Unlimited  Unlimited
==mysql.trace_mode  Off  Off
I Try to connect from PHP and I get:
==Not connected : Client does not support authentication protocol ==requested by 
server; consider upgrading MySQL client
Could this be the Reason?: From the PHP info above.
==Client API version  3.23.57==
I'm thinking yes, but since copying the new files to the same directory overwrote all the others, is this the client version for all servers currently?? If not how do I force it to update.

I have all the servers working. I don't really at this point want to delete anything.



Michael G. Tracey

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[PHP-DB] Mysql and Kerberos

2004-02-09 Thread Ricardo Oliveira






Hi all,
 Does anyone knows a way to autheticate mysql database usersusing kerberos? I'd like to know if I can use Kerberos to validate the authentication data in the mysql_connect command.

Thanks for all help,
Ricardo Oliveira







 IncrediMail - O mundo do correio eletrônico finalmente desenvolveu-se - Clique aqui

[PHP-DB] PHP_SELF and parse error

2004-02-09 Thread Remember14a
Dear friends,

I tried to modify submit if elseif statement. That didn't work.I have pasted 
code of form and output with error.
Any comments on erros, please.

Asif



--
---
Notice: Undefined variable: submit in C:\webroot\display.php on line 16

Notice: Undefined variable: PHP_SELF in C:\webroot\display.php on line 19


1
Treatment of Hypertension

a)loop diuritics
b)clonazepam
c)benzodizap
d)lorazepam

2
Thrombolytic treatment of Myocardial infarction

a)streptokinase
b)diltiazm
c)aspirin
d)heparin


--
-
//code for above output and error


HTMLbody bgcolor=?php
// open the connection
$conn = mysql_connect(localhost, , );

// pick the database to use
mysql_select_db(testDB,$conn);


// create the SQL statement
$sql = SELECT * FROM testTable;

// execute the SQL statement
$result = mysql_query($sql, $conn) or die(mysql_error());
//go through each row in the result set and display data

if (!$submit) {


 echo form method=post action=$PHP_SELF;
 echo table border=0;



while ($newArray = mysql_fetch_array($result)) {
 // give a name to the fields
$id  = $newArray['id'];
$testField = $newArray['testField'];
  $testFielda = $newArray['testFielda'];
  $testFieldb = $newArray['testFieldb'];
  $testFieldc = $newArray['testFieldc'];
  $testFieldd = $newArray['testFieldd'];

//echo the results onscreen


echo
trtd colspan=4brb$id/b/td/tr;
echo
TD$testFieldinput type=hidden name=$testField value=\$testField\ br
/td/tr
TDa)input type=radio name=$testFielda 
value=\$testFielda\$testFielda/td/tr
TDb)input type=radio name=$testFieldb 
value=\$testFieldb\$testFieldb/td/tr
TDc)input type=radio name=$testFieldc 
value=\$testFieldc\$testFieldc/td/tr
TDd)input type=radio name=$testFieldd 
value=\$testFieldd\$testFieldd/td/tr;
}
echo /table;


echo input type='submit' value='See how you did' name='submit';

echo /form;

}

elseif ($submit)

?
/html


[PHP-DB] Re: php5/MySQL 4.1.1 connection error

2004-02-09 Thread michael
I have done the same thing... but still get

Could not connect: Client does not support authentication protocol 
requested by server; consider upgrading MySQL client

So beside copying the libmySQL.dll's to the System32 folder and the 
settings in the .ini... Should'nt there be more files to locate since 
the support files are not bundled... Where would I get these files.

Having a very hard time understanding how the one file is in php/dlls 
when it is not bundled.

Kengaun wrote:

Hi ALL,
MySql support is not bundled with PHP 5.0.0
I have managed to connect to MySQL after I have copied the new dll
libmySQL.dll(in php/dlls) folder to c:\windows\system32
And modified the php.ini as per below.
In php.ini
; Directory in which the loadable extensions (modules) reside.
extension_dir = c:\php\extensions
;;
; Dynamic Extensions ;
;;
extension=php_mysql.dll
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Re: [PHP-DB] PHP_SELF and parse error

2004-02-09 Thread ppi
Maybe you have register globals turned off?

Try this: $_SERVER[PHP_SELF] instead of $PHP_SELF.

On Mon, Feb 09, 2004 at 07:49:17PM -0500, [EMAIL PROTECTED] wrote:
 From: [EMAIL PROTECTED]
 Date: Mon, 9 Feb 2004 19:49:17 EST
 To: [EMAIL PROTECTED]
 X-Mailer: 9.0 for Windows sub 5003
 Subject: [PHP-DB] PHP_SELF and parse error
 
 Dear friends,
 
 I tried to modify submit if elseif statement. That didn't work.I have pasted 
 code of form and output with error.
 Any comments on erros, please.
 
 Asif
 
 
 
 --
 ---
 Notice: Undefined variable: submit in C:\webroot\display.php on line 16
 
 Notice: Undefined variable: PHP_SELF in C:\webroot\display.php on line 19
 
 
 1
 Treatment of Hypertension
 
 a)loop diuritics
 b)clonazepam
 c)benzodizap
 d)lorazepam
 
 2
 Thrombolytic treatment of Myocardial infarction
 
 a)streptokinase
 b)diltiazm
 c)aspirin
 d)heparin
 
 
 --
 -
 //code for above output and error
 
 
 HTMLbody bgcolor=?php
 // open the connection
 $conn = mysql_connect(localhost, , );
 
 // pick the database to use
 mysql_select_db(testDB,$conn);
 
 
 // create the SQL statement
 $sql = SELECT * FROM testTable;
 
 // execute the SQL statement
 $result = mysql_query($sql, $conn) or die(mysql_error());
 //go through each row in the result set and display data
 
 if (!$submit) {
 
 
  echo form method=post action=$PHP_SELF;

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Re: [PHP-DB] PHP_SELF and parse error

2004-02-09 Thread Chris Wright
Try using $_SERVER[PHP_SELF] instead of $PHP_SELF.

I believe $PHP_SELF is only set on servers with register variables turned
on.


ChrisPW

- Original Message - 
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 12:49 AM
Subject: [PHP-DB] PHP_SELF and parse error


 Dear friends,

 I tried to modify submit if elseif statement. That didn't work.I have
pasted
 code of form and output with error.
 Any comments on erros, please.

 Asif



 --

 ---
 Notice: Undefined variable: submit in C:\webroot\display.php on line 16

 Notice: Undefined variable: PHP_SELF in C:\webroot\display.php on line 19


 1
 Treatment of Hypertension

 a)loop diuritics
 b)clonazepam
 c)benzodizap
 d)lorazepam

 2
 Thrombolytic treatment of Myocardial infarction

 a)streptokinase
 b)diltiazm
 c)aspirin
 d)heparin


 --

 -
 //code for above output and error


 HTMLbody bgcolor=?php
 // open the connection
 $conn = mysql_connect(localhost, , );

 // pick the database to use
 mysql_select_db(testDB,$conn);


 // create the SQL statement
 $sql = SELECT * FROM testTable;

 // execute the SQL statement
 $result = mysql_query($sql, $conn) or die(mysql_error());
 //go through each row in the result set and display data

 if (!$submit) {


  echo form method=post action=$PHP_SELF;
  echo table border=0;



 while ($newArray = mysql_fetch_array($result)) {
  // give a name to the fields
 $id  = $newArray['id'];
 $testField = $newArray['testField'];
   $testFielda = $newArray['testFielda'];
   $testFieldb = $newArray['testFieldb'];
   $testFieldc = $newArray['testFieldc'];
   $testFieldd = $newArray['testFieldd'];

 //echo the results onscreen


 echo
 trtd colspan=4brb$id/b/td/tr;
 echo
 TD$testFieldinput type=hidden name=$testField value=\$testField\
br
 /td/tr
 TDa)input type=radio name=$testFielda
 value=\$testFielda\$testFielda/td/tr
 TDb)input type=radio name=$testFieldb
 value=\$testFieldb\$testFieldb/td/tr
 TDc)input type=radio name=$testFieldc
 value=\$testFieldc\$testFieldc/td/tr
 TDd)input type=radio name=$testFieldd
 value=\$testFieldd\$testFieldd/td/tr;
 }
 echo /table;


 echo input type='submit' value='See how you did' name='submit';

 echo /form;

 }

 elseif ($submit)

 ?
 /html


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[PHP-DB] Cookies ?

2004-02-09 Thread Omelin Morelos
Friends

Is there a way to read a cookie's with php , that were generated with
javascript ?

I am now usign :

$xidp=$_COOKIE;
print Xidp $xidp;

Thank you for your help in advanced.

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Re: [PHP-DB] Cookies ?

2004-02-09 Thread Chris Wright
Try using $_COOKIE['cookie_name']


- Original Message - 
From: Omelin Morelos [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 12:55 AM
Subject: [PHP-DB] Cookies ?


 Friends
 
 Is there a way to read a cookie's with php , that were generated with
 javascript ?
 
 I am now usign :
 
 $xidp=$_COOKIE;
 print Xidp $xidp;
 
 Thank you for your help in advanced.
 
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 PHP Database Mailing List (http://www.php.net/)
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[PHP-DB] Cookies ?

2004-02-09 Thread Omelin Morelos


-Mensaje original-
De: Omelin Morelos [mailto:[EMAIL PROTECTED]
Enviado el: Monday, February 09, 2004 4:56 PM
Para: [EMAIL PROTECTED]
Asunto: Cookies ?


Friends

Is there a way to read a cookie's with php , that were generated with
javascript ?

I am now usign :

$xidp=$_COOKIE;
print Xidp $xidp;

Thank you for your help in advanced.

-- 
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To unsubscribe, visit: http://www.php.net/unsub.php



RE: [PHP-DB] Cookies ?

2004-02-09 Thread Omelin Morelos
I have already tried it , It's not working.

Thanks

-Mensaje original-
De: Chris Wright [mailto:[EMAIL PROTECTED]
Enviado el: Monday, February 09, 2004 5:09 PM
Para: Omelin Morelos; [EMAIL PROTECTED]
Asunto: Re: [PHP-DB] Cookies ?


Try using $_COOKIE['cookie_name']


- Original Message - 
From: Omelin Morelos [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 12:55 AM
Subject: [PHP-DB] Cookies ?


 Friends
 
 Is there a way to read a cookie's with php , that were generated with
 javascript ?
 
 I am now usign :
 
 $xidp=$_COOKIE;
 print Xidp $xidp;
 
 Thank you for your help in advanced.
 
 -- 
 PHP Database Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php
 

-- 
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To unsubscribe, visit: http://www.php.net/unsub.php

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RE: [PHP-DB] Cookies ?

2004-02-09 Thread Miles Thompson
Did you refresh the page after setting the cookie?
mt
At 05:00 PM 2/9/2004 -0800, Omelin Morelos wrote:
I have already tried it , It's not working.

Thanks

-Mensaje original-
De: Chris Wright [mailto:[EMAIL PROTECTED]
Enviado el: Monday, February 09, 2004 5:09 PM
Para: Omelin Morelos; [EMAIL PROTECTED]
Asunto: Re: [PHP-DB] Cookies ?
Try using $_COOKIE['cookie_name']

- Original Message -
From: Omelin Morelos [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 12:55 AM
Subject: [PHP-DB] Cookies ?
 Friends

 Is there a way to read a cookie's with php , that were generated with
 javascript ?

 I am now usign :

 $xidp=$_COOKIE;
 print Xidp $xidp;

 Thank you for your help in advanced.

 --
 PHP Database Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php

--
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To unsubscribe, visit: http://www.php.net/unsub.php
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RE: [PHP-DB] Cookies ?

2004-02-09 Thread Omelin Morelos
yes , i tried accesing the cookie from an other page.

thank you

-Mensaje original-
De: Miles Thompson [mailto:[EMAIL PROTECTED]
Enviado el: Monday, February 09, 2004 5:37 PM
Para: [EMAIL PROTECTED]
Asunto: RE: [PHP-DB] Cookies ?


Did you refresh the page after setting the cookie?
mt
At 05:00 PM 2/9/2004 -0800, Omelin Morelos wrote:
I have already tried it , It's not working.

Thanks

-Mensaje original-
De: Chris Wright [mailto:[EMAIL PROTECTED]
Enviado el: Monday, February 09, 2004 5:09 PM
Para: Omelin Morelos; [EMAIL PROTECTED]
Asunto: Re: [PHP-DB] Cookies ?


Try using $_COOKIE['cookie_name']


- Original Message -
From: Omelin Morelos [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, February 10, 2004 12:55 AM
Subject: [PHP-DB] Cookies ?


  Friends
 
  Is there a way to read a cookie's with php , that were generated with
  javascript ?
 
  I am now usign :
 
  $xidp=$_COOKIE;
  print Xidp $xidp;
 
  Thank you for your help in advanced.
 
  --
  PHP Database Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php
 

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To unsubscribe, visit: http://www.php.net/unsub.php

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[PHP-DB] msql perfomance: fast through mysql, slow through php

2004-02-09 Thread jde
Greetings,

I have search the archives over the last two years and have not found 
any help for this question.

The basic setup: An apache/php server exists on the west coast of the 
US, and a linux/mysql server on the east coast.

My PHP snippet looks like this:

$result = mysql_query(select acolumn from atable where bcolumn=0, $db);
while ($row = mysql_fetch_assoc($result)) echo 'some stuff from the row';
The problem is, that the above snippet, to return seven rows, takes 
about 15 seconds.  Putting timing statements around the query and around 
the fetch calls shows that the query call takes only 0.03 seconds. 
However, each fetch call takes anywhere from  0.5 to 5 seconds each to 
complete.

However, if I am logged onto the apacher server and from the user prompt 
run the 'mysql' client, and perform the same exact query, the 'mysql' 
client can peform the query and return all the results, all 7 rows, in 
0.1 second.

This is apache 1.3/php 4.3.4 and mysql 4.0.17-standard.

I have tried all the mysql_connect flags without any change.

Should I expect such a performance difference? Is there something else I 
need to look for?

Thank you for your time,
jde
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