RE: [PHP-DB] Parse error

2002-02-21 Thread Cami

try:
?

$origVar = 100;
echo POriginal value is.$origVar./p;

$origVar += 25;
echo PAdded a value, now it's .$origVar./p;

$origVar -= 12;
echo PSubtracted a value, now it's .$origVar./p;

$origVar .=  chickens;
echo PFinal answer: .$origVar./p;

?

Cami

-Original Message-
From: Jennifer Downey [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 21, 2002 2:33 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Parse error


Can someone tell me why I am getting a parse error in this little snip?

?

$origVar = 100;
echo POriginal value is $origVar/p;

$origVar += 25;
echo PAdded a value, now it's $origVar/p;

$origVar -= 12;
echo PSubtracted a value, now it's $origVar/p;

$origVar .=  chickens;
echo PFinal answer: $origVar/p;

?

Thanks in advance
Jen Downey



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RE: [PHP-DB] I cant get the logic for this...

2002-02-18 Thread Cami

Hi Dave,
I wrote the following script which does exaclty that.

Cami

?
mysql_connect ($hname, $usrname, $password) OR DIE (unable to connect);

$selectstmnt = your sql statement;

$result = mysql_db_query ($dbname, $selectstmnt);
$numrows = mysql_num_rows($result);
 $i=3;
echo table cellpadding=0 border=0 callspacing=0;

if ($result) {
while ($list = mysql_fetch_array ($result))
 {

if($i==3)   { $i=0;
echo tr; }

echo td width=\126\ height=\23\ valign=\middle\
align=\center\.$list[yourvariablename]./td;


 $i++;
if($i==3)   {
echo /tr; }
  } // end while fetch_array
if ($numrows%3==2){echo tdnbsp;/td/tr;}
if ($numrows%3==1){echo tdnbsp;/tdtdnbsp;/td/tr;}

   } //end if numrows0
echo /table;
?

-Original Message-
From: Greg Donald [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 18, 2002 2:14 PM
To: Dave Carrera; php List
Subject: Re: [PHP-DB] I cant get the logic for this...



 I want to display return results from my query (which works fine)
 In I tidy way on screen.

 So my result returns say seven results, I have a table, and I want to
 show
 3 results per row of the table... I.e.:

 Table
 TR
 TD = result1 /TD  TD result2 /TD TD = result3 /TD
 /TD
 /TR
 TR
 TD = result4 /TD  TD result5 /TD TD = result6 /TD
 /TD
 /TR
 TR
 TD = result7 /TD  TD resultempty /TD TD = resultempty /TD
 /TD
 /TR
 /table

 The last two td in row 3 are empty because result found 7 results.

 This cant be fixed so echo statements wont work as the result could
 Be 3 or 10 or 56 or whatever.

 As Always your help and or guidance in this matter is appreciated.

You need a incrementer variable so you can tell when you have 3 td cells
built, so you know when to end the current tr and start a new one.

Then, you need to test that variable again when you run out of
mysql_num_rows(), and fill the 1 or 2 needed td cells with nbsp;

Also, you might wanna look around for some table building classes if your
data is always gonna be really abstract.


Greg Donald - http://destiney.com/
http://phprated.com/ | http://phplinks.org/ | http://phptopsites.com/



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[PHP-DB] sending bulk emails

2001-11-02 Thread Cami

Hi guys,
Does anybody know how to send bulk emails using php?
Thanks,
Cami

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RE: RE: [PHP-DB] sending bulk emails

2001-11-02 Thread Cami

Oh dear,
Please do not worry. I would never send spam emails. One of my clients for
which I am developing a database want to be able to send his members emails
.  The problem would have been simple if he had a few members but he has
tens of tousands. So with some help from some of you and adopting a send
mail library I think that now is in the process of being sorted. So just to
calm you guys down. I would never do a spam email.
Thank you everybody for your help,
Cami


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RE: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Cami

Hi Ian,
Try this:
mysql select *,(case when title like '%The%' then substring (title, 5, 255)
when title like '%A%' then substring (title, 3, 255) when title like '%An%'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
Hope it helps,
Cami

-Original Message-
From: Ian Evans [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 01, 2001 9:20 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL: Alphabetizing title results in library
format


Petr Tuma wrote:

 What error message it produce?

Ok, table titles is composed of:

+--+-++
| titlesid | releaseyear | title  |
+--+-++

mysql select *,(case when title like 'The %' then substring (title, 5, 255)
when title like 'A %' then substring (title, 3, 255) when title like 'An %'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
ERROR 1064: You have an error in your SQL syntax near 'when title like 'The
%' then substring (title, 5, 255) when title like 'A %' the' at line 1


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Ian Evans
Digital Hit Entertainment - News and Information
http://www.digitalhit.com


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RE: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Cami

Have you tried it like this:
mysql select case when title like '%The %' then substring (title, 5, 255)
when title like '%A %' then substring (title, 3, 255) when title like '%An
%' then substring (title, 4, 255) else title end as sort_col from titles
order by sort_col;
I can't tested, but that's what the manual say.
Cami

-Original Message-
From: Ian Evans [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 01, 2001 9:20 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL: Alphabetizing title results in library
format


Petr Tuma wrote:

 What error message it produce?

Ok, table titles is composed of:

+--+-++
| titlesid | releaseyear | title  |
+--+-++

mysql select *,(case when title like 'The %' then substring (title, 5, 255)
when title like 'A %' then substring (title, 3, 255) when title like 'An %'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
ERROR 1064: You have an error in your SQL syntax near 'when title like 'The
%' then substring (title, 5, 255) when title like 'A %' the' at line 1


--
Ian Evans
Digital Hit Entertainment - News and Information
http://www.digitalhit.com


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[PHP-DB] Transforming doc files into html

2001-08-04 Thread Cami

Hi there,
Does anybody know if is any way in which when you upload a word document
file you can parse it and transform
it into an html file?
Is this possible ? Has anybody tried it? I know I can transform it into a
txt file but wouldn't it be even better if we can do an html file?

Thanks,
Cami


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[PHP-DB] Error 127

2001-07-19 Thread Cami


Hi everybody,
All of the sudden I got an error one of mysql tables.
Got error 127 from table handler.
Can't browse it not even from phpmyadmin get the same error. Anybody had
this before? What do I do to recuperate my table?
I really appreciate any help,
Thanks,
Cami


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RE: [PHP-DB] Error 127

2001-07-19 Thread Cami


Thanks everybody for pointing me to the right place.
I manage to recover it.
Thank God.
Cami
-Original Message-
From: Cami [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 19, 2001 3:57 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Error 127



Hi everybody,
All of the sudden I got an error one of mysql tables.
Got error 127 from table handler.
Can't browse it not even from phpmyadmin get the same error. Anybody had
this before? What do I do to recuperate my table?
I really appreciate any help,
Thanks,
Cami


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RE: [PHP-DB] Only Insert on Error?

2001-07-18 Thread Cami

Try using ' instead of \ like:


if ($M_First_Name) {
$sql = INSERT INTO $table_name
(First_Name, Last_Name, Family_Position, Address, Address1, City, State,
Zip, Email,
Home_Phone, Work_Phone, Coop_Month, Timestamp) VALUES
('$M_First_Name', '$M_Last_Name', '$MatherFamilyPosition','$M_Address1',
'$M_Address2', '$M_City', '$M_State', '$M_Zip', '$M_Email', '$M_H_Phone',
'$M_W_Phone', '$coopmonth', 'NOW()');
if(! $result = mysql_query($sql,$connection)) {
print(ERROR .mysql_errno().: .mysql_error().br\n$sqlbr\n);
}
}



if ($M_First_Name) {
$sql = INSERT INTO $table_name
(First_Name, Last_Name, Family_Position, Address, Address1, City, State,
Zip, Email,
Home_Phone, Work_Phone, Coop_Month, Timestamp) VALUES
('$M_First_Name', '$M_Last_Name', '$MatherFamilyPosition','$M_Address1',
'$M_Address2', '$M_City', '$M_State', '$M_Zip', '$M_Email', '$M_H_Phone',
'$M_W_Phone', '$coopmonth', 'NOW()');
//  if(! $result = mysql_query($sql,$connection)) {
//  print(ERROR .mysql_errno().: .mysql_error().br\n$sqlbr\n);
//  }
}

Hope it works,
Cami


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