RE: [PHP-DB] Parse error

[Cami]

try:
<?

$origVar = 100;
echo "<P>Original value is".$origVar."</p>";

$origVar += 25;
echo "<P>Added a value, now it's ".$origVar."</p>";

$origVar -= 12;
echo "<P>Subtracted a value, now it's ".$origVar."</p>";

$origVar .= " chickens";
echo "<P>Final answer: ".$origVar."</p>";

?>

Cami

-----Original Message-----
From: Jennifer Downey [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 21, 2002 2:33 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Parse error


Can someone tell me why I am getting a parse error in this little snip?

<?

$origVar = 100;
echo "<P>Original value is $origVar</p>";

$origVar += 25;
echo "<P>Added a value, now it's $origVar</p>";

$origVar -= 12;
echo "<P>Subtracted a value, now it's $origVar</p>";

$origVar .= " chickens";
echo "<P>Final answer: $origVar</p>";

?>

Thanks in advance
Jen Downey



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