[PHP-DB] Re: [PHP] Regex for telephone numbers
On 12/29/2010 4:35 PM, Daniel P. Brown wrote:
On Wed, Dec 29, 2010 at 19:12, Ethan Rosenberg eth...@earthlink.net wrote:
Dear List -
Thank you for all your help in the past.
Here is another one
I would like to have a regex which would validate that a telephone number
is in the format xxx-xxx-.
Congrats. People in Hell would like ice water. Now we all know
that everyone wants something. ;-P
Really, this isn't a PHP question, but rather one of regular
expressions. That said, something like this (untested) should work:
?php
$numbers = array(
'123-456-7890',
'2-654-06547',
'sf34-asdf-',
'abc-def-ghij',
'555_555_',
'000-000-',
'8007396325',
'241-555-2091',
'800-555-0129',
'900-976-739',
'5352-342=452',
'200-200-2000',
);
foreach ($numbers as $n) {
echo $n.(validate_phone($n) ? ' is ' : ' is not ').'a valid
US/Canadian telephone number.'.PHP_EOL;
}
function validate_phone($number) {
if
(preg_match('/^[2-9]{1,}[0-9]{2,}\-[2-9]{1,}[0-9]{2,}\-[0-9]{4,}$/',trim($number)))
{
return true;
}
return false;
}
?
Actually...
Specified here [1] it says that the {1,} is the same as '+'. I think you should
drop the comma. If you don't this would be valid 844-2345-123456
^[2-9]{1,}[0-9]{2,}\-[2-9]{1,}[0-9]{2,}\-[0-9]{4,}$
should be
^[2-9]{1}[0-9]{2}\-[2-9]{1}[0-9]{2}\-[0-9]{4}$
1 http://us.php.net/manual/en/regexp.reference.repetition.php
Jim Lucas
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[PHP-DB] Re: [PHP] goto - My comments
On 12/18/2010 9:17 PM, Ethan Rosenberg wrote:
Dear List -
Thanks to all for your EXCELLENT comments. I definitly agree that goto
is a command to be avoided at all costs. In this case, I could not
figure out how to acheive the desired result without the goto. So
being a newbie, I humbly request that you show [and at the same time
teach] me how to rewrite the code to eleiminate the goto.
Additionally, would you please do the same for the code I list below.
This code runs perfectly.
==
This is the form:
form action=srchrhsptl2.php method=post
centerSite: input type=text name=Site value=AA /
Record Number: input type=text name=MedRec /
First Name: input type=text name=Fname /
Last Name: input type=text name=Lname /br /br /
Phone: input type=text name=Phone /
Height: input type=decimal name=Height //inputbr /br /
Maleinput type=radio name=Sex value = 0/input
Femaleinput type=radio name=Sex value = 1/inputbr /br /br /
input type=submit /br /br /
input type=reset value = Clear Form //center
/form
Not sure if you can change the values for the Sex field to 'Male'
'Female' respectively, but it would simplify the following example.
Here is my rendition of how I would do it.
?php
...
$query = select * from Intake3 where 1 ;
$allowed_fields = array('Site', 'MedRe', 'Fname', 'Lname',
'Phone', 'Sex', 'Height');
# deal with the special case first
# Normally you do not want to modify the _POST/_GET/_REQUEST array, but
# in this case, it is used as an quick example of how to get the data
# passed along. if you can change the field values to Male/Female you
# could remove the following section and have just the foreach() loop.
if ( ! empty($_POST['Sex']) )
{
if ( $_POST['Sex'] === '1' )
$_POST['Sex'] = 'Female';
else
$_POST['Sex'] = 'Male';
}
# Now deal with the rest...
foreach ( $allowed_fields AS $field )
{
if ( ! empty( $_POST[$field] ) )
{
$value = mysql_real_escape_string( $_POST[$field] );
$query .= AND `{$field}` = '{$value}' ;
}
}
in the end, you will end up with a nicely formatted SQL query to execute.
I would suggest cleaning up the output code some and use *_assoc()
instead of the *_array() function call. It gives you back the array
version of the output. This way instead of calling $row[0], $row[...]
you would call $row['Fname'] or $row['Lname'] instead.
Get rid of all those commented out sections and you will have a good
script to play with.
Let us know what comes of it...
==
THANK YOU EVER SO MUCH FOR YOUR HELP.
Ethan
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[PHP-DB] Re: [PHP] Sample script files with 3 different select boxes with mysql conditions in select boxes
Robert Cummings wrote: On Thu, 2008-01-03 at 09:18 -0600, Balaji A wrote: Hi, I have a table with the below fields. (id, title, language, author link to the book). Initially I want to display a page with 3 select boxes (language, author title). Initially first select box displays the available language by querying the database. On selecting one language, author select box should show the matching records from the database. After selecting the author, matching records should display in title. Could any body send the sample script files with 3 select boxes? Anything else you'd like to add to the requirements document? Cheers, Rob. I would think it be best if it was javascript based so it dynamically loads the data via AJAX or a predefined JS hash, but then when JS was disabled, it would be best if it fell back to old school and submitted the form when I select the lang-auth-book. Thanks -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Re: the opposite of a join?
Colin Guthrie wrote: Martin Marques wrote: SELECT * FROM company WHERE id NOT IN (SELECT companyID FROM contacts); Not ideal as has been mentioned else where in this thread. Col I think one would have to take into account the DB type being used here. I can have MySQL and PostgreSQL setup and running with the same table structure (well, as close as you can get) configured with two different databases in them. SQL #1 SELECT * FROMcompany WHERE id NOT IN ( SELECT companyID FROMcontacts ); SQL #2 SELECT company.* FROMcompany LEFT JOIN contacts ON ( company.companyID = contacts.companyID ) WHERE contacts.companyID IS NULL Now, both SQL statements will perform relatively the same on either DB's with a small data set. but, if you have a large data set, MySQL will benefit from having the Sub-Query style statement Where-as PostgreSQL will shine with the JOIN command. This is only from my own personal testing. Mind you that I have only been using PostgreSQL for a year or so. But one problem that I have always ran into with MySQL is that when JOIN'ing tables that have large data sets is a PITA. So, if I was running MySQL, I would use SQL #1, but if I were using PostgreSQL, I would use SQL #2 If anybody else has suggestions or comments about performance between MySQL vs. PostgreSQL with regards to similarly formed SQL calls, I would like to hear their experiences. -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Re: the opposite of a join?
Robert Cummings wrote: On Wed, 2007-10-03 at 14:49 -0700, Jim Lucas wrote: This is only from my own personal testing. Mind you that I have only been using PostgreSQL for a year or so. But one problem that I have always ran into with MySQL is that when JOIN'ing tables that have large data sets is a PITA. Were you doing left joins when you experienced those problems? Left joins are usually very fast. So, if I was running MySQL, I would use SQL #1, but if I were using PostgreSQL, I would use SQL #2 I'd use the left join whenever available. Cheers, Rob. Honestly, I cannot remember. It was right when I first started with PHP/mysql back in 1999. I think we were using a JOIN (without the LEFT) Which I think the default is an INNER JOIN if I do recall. I really have never played with performance over the past few years. This past year I have been working on a new DB with Call Detail Records for a phone company. On average we have to deal with processing 2 - 4 million records each billing cycle. So, having to work with that amount of CDR's and a couple thousand client records that are associated with them, makes for a good performance test on SQL statements. -- Jim Lucas Perseverance is not a long race; it is many short races one after the other Walter Elliot Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] any php/Linux gurus out there?
I being a person that is working with both RH 7.0 7.1 would not recommend forcing an upgrade. I did that when I attempted to upgrade to 7.2 and wanted to try a few new things that didn't come with the install. I ended up having to reinstall the entire OS. So, make the effort and upgrade all the deps also. it will be worth it in the long run. Jim Lucas - Original Message - From: Jason Wong [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, March 04, 2002 8:18 PM Subject: Re: [PHP-DB] any php/Linux gurus out there? On Tuesday 05 March 2002 07:52, Peter Lovatt wrote: Hi I am running the security upgrade and am getting the following error when I run the RPM The install is RH 7.0 and was pre-installed. I had assumed that the RPMs from Redhat would match the pre installed version, as it was standard. I am a humble programmer (and part time sys admin!), rather than a Linux/RH guru, so would appreciate some advice. What is the best way to deal with this ? error: failed dependencies: libcrypto.so.1 is needed by php-4.0.6-9.7.0 libmm.so.11 is needed by php-4.0.6-9.7.0 libssl.so.1 is needed by php-4.0.6-9.7.0 libcrypto.so.1 is needed by php-imap-4.0.6-9.7.0 Have you followed the instructions given on the RH website? Most upgrades are performed using: rpm -Uvh xxx.rpm or rpm -Fvh xxx.rpm -- Jason Wong - Gremlins Associates - www.gremlins.com.hk /* I'd love to go out with you, but I'm doing door-to-door collecting for static cling. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] easy date format question
$today = date(Ymd);
$sql = INSERT into table (date) values ('$today');
when the $today variable is inserted into a mysql date column it will fit
just right.
but, if you want to insert it into a timestamp column, you will have to padd
it with 6 zero's
Jim Lucas
www.bend.com
- Original Message -
From: Matthew Crouch [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, March 01, 2002 2:50 PM
Subject: [PHP-DB] easy date format question
should be simple as pie, of course, but i can't find a straightforward
syntax example in the documentation. i'm trying to change the PHP date
format to mysql's.
my code:
$today = date(MMDD);
$sql = INSERT into table (date) values ('$today');
and so on...
is filling the date field with zeros, instead of 2002-02-28
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Re: [PHP-DB] Passing form values with quotes, to itself
it is called magic quotes and it can be enabled through the php.ini file. Jim Lucas - Original Message - From: William Fong [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, February 13, 2002 10:36 AM Subject: Re: [PHP-DB] Passing form values with quotes, to itself Doesn't PHP have something that will automatically do this? I can't remember, but I think you had to enable it in php.ini or when you compile. (just like to know for future reference). thx. -w -- William Fong - [EMAIL PROTECTED] Phone: 626.968.6424 x210 | Fax: 626.968.6877 Wireless #: 805.490.7732| Wireless E-mail: [EMAIL PROTECTED] - Original Message - From: David Fudge [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, February 13, 2002 10:12 AM Subject: Re: [PHP-DB] Passing form values with quotes, to itself : before you submit to the db, you have to escape the quotes like this: : : $Body = addslashes($Body); : all will show up as \ \ : and ' ' will be \' \' : : when you pull the info from the db, you'll have to use stripslashes() to : remove those you put in. : $Body = stripslashes($Body_from_db); : : - Original Message - : From: Faye Keesic [EMAIL PROTECTED] : To: [EMAIL PROTECTED] : Sent: Wednesday, February 13, 2002 1:02 PM : Subject: [PHP-DB] Passing form values with quotes, to itself : : : Hi there. : : I have a form that contains several fields w/ text info (which may or may : not contain single and double quotes). : : When the user clicks Preview, the form's action is set to call itself : ($PHP_SELF), and the info is displayed nicely so they can read it over, : and : verify it before saving to the db. : : What I'm having problems with is that when the data has quotes, the text : data cuts off. : : If I use: input type=text name=Body value= ?php echo $Body; ? : then double quotes are cut off. : : If I use: input type=text name=Body value=' ?php echo $Body; ?' : then single quotes are cut off. : : I want nothing cut off! I've tried addslashes()..still cuts off. : : I hope that all made sense... : -- : Faye : : : -- : PHP Database Mailing List (http://www.php.net/) : To unsubscribe, visit: http://www.php.net/unsub.php : : : : -- : PHP Database Mailing List (http://www.php.net/) : To unsubscribe, visit: http://www.php.net/unsub.php : -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] A while loop prob ?
Try this
if ($submit)
{
if($search == )
{
$error1 = font color=redNo Records found. Please use at least 1
character in search box/font;
} else {
$srchsql = select * from $tbn where name like \%$search%\ ;
$srchresult = mysql_query($srchsql, $con);
$name =$srchrow['name'];
$details =$srchrow['details'];
$price =$srchrow['price'];
$imgloc =$srchrow['imgloc'];
while (list($name, $details, $price, $imgloc) =
mysql_fetch_array($srchresult))
{
$display_srch_rows .=
trtd$imgloc/tdtd$name/tdtd$details/tdtd$price/td/tr;
}
echo $display_srch_rows;
}
}
the problem is, you were overwriting your results each time you went into
the loop therefor always ending up with the last returned result set.
if you use .= instead of = you will concat the results, therefor
making one long string.
then echo/print the $display_srch_rows variable.
Jim Lucas
- Original Message -
From: Dave Carrera [EMAIL PROTECTED]
To: php List [EMAIL PROTECTED]
Sent: Wednesday, February 13, 2002 11:40 AM
Subject: [PHP-DB] A while loop prob ?
Hi All
What have I done wrong here.
3 yes 3 hours I have been plaing with this loop.
All it shows is the last record in my db.
It should show and record containing any string in the search.
Error works
Please help I beg you...
As always thank you for any help
Dave C
- My Code Starts Here
if ($submit){
if($search == ){
$error1 = font color=redNo Records found. Please use at least
1 character in search box/font;
}
else
{
$srchsql = select * from $tbn where name like \%$search%\ ;
$srchresult = mysql_query($srchsql, $con);
$name =$srchrow['name'];
$details =$srchrow['details'];
$price =$srchrow['price'];
$imgloc =$srchrow['imgloc'];
while (list($name, $details, $price, $imgloc)
=mysql_fetch_array($srchresult)){
$display_srch_rows =
trtd$imgloc/tdtd$name/tdtd$details/tdtd$price/td/tr
;
}
}
}
Dave Carrera
Website Designer
http://www.davecarrera.com
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Re: [PHP-DB] Passing form values with quotes, to itself
Try this. input type=text name=Body value=?=htmlspecialchars($Body)? That should to the job. Jim Lucas - Original Message - From: Faye Keesic [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, February 13, 2002 10:02 AM Subject: [PHP-DB] Passing form values with quotes, to itself Hi there. I have a form that contains several fields w/ text info (which may or may not contain single and double quotes). When the user clicks Preview, the form's action is set to call itself ($PHP_SELF), and the info is displayed nicely so they can read it over, and verify it before saving to the db. What I'm having problems with is that when the data has quotes, the text data cuts off. If I use: input type=text name=Body value= ?php echo $Body; ? then double quotes are cut off. If I use: input type=text name=Body value=' ?php echo $Body; ?' then single quotes are cut off. I want nothing cut off! I've tried addslashes()..still cuts off. I hope that all made sense... -- Faye -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Passing form values with quotes, to itself
it will still cut off with the double quots. if you have a double quote inside of a double quoted value property ? $myvalue = And he asked, \what have you done, son\? ; ? input type=text name=something value=?=addslashes($myvalue)? This will still break. it does care if they are escaped. Jim Lucas - Original Message - From: David Fudge [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, February 13, 2002 10:12 AM Subject: Re: [PHP-DB] Passing form values with quotes, to itself before you submit to the db, you have to escape the quotes like this: $Body = addslashes($Body); all will show up as \ \ and ' ' will be \' \' when you pull the info from the db, you'll have to use stripslashes() to remove those you put in. $Body = stripslashes($Body_from_db); - Original Message - From: Faye Keesic [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, February 13, 2002 1:02 PM Subject: [PHP-DB] Passing form values with quotes, to itself Hi there. I have a form that contains several fields w/ text info (which may or may not contain single and double quotes). When the user clicks Preview, the form's action is set to call itself ($PHP_SELF), and the info is displayed nicely so they can read it over, and verify it before saving to the db. What I'm having problems with is that when the data has quotes, the text data cuts off. If I use: input type=text name=Body value= ?php echo $Body; ? then double quotes are cut off. If I use: input type=text name=Body value=' ?php echo $Body; ?' then single quotes are cut off. I want nothing cut off! I've tried addslashes()..still cuts off. I hope that all made sense... -- Faye -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Select rows where ?
select * from table where columnsomething select * from table where column NOT LIKE %something% Jim Lucas - Original Message - From: Dave Carrera [EMAIL PROTECTED] To: php List [EMAIL PROTECTED] Sent: Tuesday, February 12, 2002 10:39 AM Subject: [PHP-DB] Select rows where ? Hi All How do I select the rows that DO NOT contain a certain character. I.e. : select * from tablename where field dose not contain A Any pointers as always appreciated. davec Dave Carrera Website Designer http://www.davecarrera.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] # of Records in Table
does the table have an autoincrement column? Jim Lucas - Original Message - From: Zach Curtis [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Wednesday, January 23, 2002 10:27 AM Subject: [PHP-DB] # of Records in Table What syntax can I use to determine how many records are in a MySQL table and then retrieve the value of the field password for the last record? I tried using some combinations of COUNT(*) and LIMIT with no success. Thanks. Zach Curtis POPULUS -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Passing parameter in Paging
better yet, have a starting page multiplied by the page length define a constant that gives the page limit then have the receiving page do some math and do a mysql_data_seek() or array_seek() (which ever you are using) and then limit the returns by the page limit size? wouldn't that be the easiest way? if not, please let me know, cuz I am using that for pagination throughout my site via a couple function calls. Jim - Original Message - From: olinux [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, December 28, 2001 2:58 PM Subject: Re: [PHP-DB] Passing parameter in Paging Aren't all these form solutions making things more complex than they need to be? Why not just pass the parameters in the URL Use php to echo out start_at and end_at variables ie. A HREF=http://website.com/search.php?keyword=somethingstart_at=15end_at=30; 2/A A HREF=http://website.com/search.php?keyword=somethingstart_at=31end_at=45; 3/A etc. olinux --- Mihail Bota [EMAIL PROTECTED] wrote: Bogdan, in this respect, I have a question: can I pass the values of javascript variables to php variables? if yes, how? Mihai On Fri, 28 Dec 2001, Bogdan Stancescu wrote: I don't understand why you won't use forms with buttons and hidden controls since you know about this solution. I have two suggestions along this line: 1. You probably don't want buttons on the page -- you may use image icons instead (similar to a tape recorder's play and fast forward for next page and last page) 2. If you don't want to use images either, you may use regular links with href='javascript:document.nextPage.submit()' where nextPage would be the form name with the page forward data -- and so on. HTH __ Do You Yahoo!? Send your FREE holiday greetings online! http://greetings.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Mysql result resource error
which one was giving you the problem? the first or second mysql try. if it
was the second, try wrapping the $cattyname with single quotes like this
Minor_Category = '$cattyname'. if the $cattyname var has anything but
numbers, the statement won't work.
Jim
- Original Message -
From: Shannon Doyle [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, December 19, 2001 4:19 PM
Subject: [PHP-DB] Mysql result resource error
Hi People,
I am getting a Not a valid Mysql result resource error with the
following code, can someone take a look at this for me and see if there
is anything that stands out
Thanks,
Shannon
?
$cattyname = ;
$sql = select Minor_Category main where Page = 'wines' order by
Minor_Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results2 = mysql_db_query($db,$sql,$dbh);
for($j = 0; $j mysql_num_rows($results2); $j++) {
$array[$j] = mysql_fetch_array($results2);
}
mysql_close($dbh);
for ($h = 0; $h count($array); $h++) {
if ($array[$h][Minor_Category] != $cattyname) {
$cattyname = $array[$h][Minor_Category];
echo trtd colspan='4'a
name='.$cattyname.'/ab.$cattyname./b/td/td/tr;
$catname = ;
$sql = select Category,Code,Description,Pack,Unit,Price from main where
Page = 'wines' Minor_Category = $cattyname order by Category;
$dbh = @mysql_connect($dbhost,$dbuser,$dbpass);
$results = mysql_db_query($db,$sql,$dbh);
for($i = 0; $i mysql_num_rows($results); $i++) {
$array[$i] = mysql_fetch_array($results);
}
mysql_close($dbh);
for ($i = 0; $i count($array); $i++) {
if ($array[$i][Category] != $catname) {
$catname = $array[$i][Category];
echo trtd colspan='4'a
name='.$catname.'/ab.$catname./b/tdtd
align='center'pbCarton Size/b/p/tdtd
align='center'pbUnit/b/p/tdtd
align='right'pbPrice/b/p/tdtda href='#top'img
src='images/arrow.gif' border='0'/a/td/tr;
}
echo trtd/tdtdpa
href=javascript:order_now(quot;.$array[$i][Code].quot;)img
src='images/order.gif' border='0'/a/tdtd/tdtd
align='left'p.$array[$i][Description]./p/tdtd
align='center'p.$array[$i][Pack]./p/tdtd
align='center'p.$array[$i][Unit]./p/tdtd
align='right'p$.$array[$i][Price]./p/td/tr\n;
}
}
}
?
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Re: [PHP-DB] Checkboxes, PHP, and MySQL
Try this input type=checkbox name=firstvalue ?=($result[32]?checked:)? Jim - Original Message - From: SpyProductions Support Team [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, December 20, 2001 8:40 AM Subject: [PHP-DB] Checkboxes, PHP, and MySQL I've looked around in a few of the PHP lists for an answer to this, but can't come up with one. Here's what I am doing: I have a form with a few checkboxes. When the information as to whether the checkboxes are checked or not is 'saved' into the MySQL table, they are represented by a value of '1' - fine. When I want to edit this information, in the form of a similar form with checkboxes, the boxes are not checked off if they were before. What I am stuck on is how a checkbox can get checked off when pulling information from the MySQL as an array. Here's a line of code showing my array coming out. input type=checkbox name=firstvalue value='$result[32]' $result is the array. I guess what I am asking is that if a checkbox is assigned a value of one, why doesn't it appear as already checked off? Thanks, -Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] Learning PHP Sessions
one problem I see, you are trying to populate the variable after you
register it.
session_start();
$myvar = something;
session_register('myvar');
echo $myvar;
Jim Lucas
- Original Message -
From: Russ Michell [EMAIL PROTECTED]
To: Steve Cayford [EMAIL PROTECTED]
Cc: Matthew Tedder [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, October 31, 2001 8:44 AM
Subject: Re: [PHP-DB] Learning PHP Sessions
* session_register('myvar'); creates a session var called $myvar
* session_start(); needs to be called from the top of each script that
will need the session var
$myvar
* session_destroy('myvar'); rids you of $myvar completely.
* session_destroy('HTTP_SESSION_VARS'); rids you off *all* currently
registered session vars
Note that a variable used in this way is refered to as 'myvar' and
referenced a snormal within the
script as: $myvar
HTH you out.
Russ
On Wed, 31 Oct 2001 09:55:33 -0600 Steve Cayford
[EMAIL PROTECTED] wrote:
This is really off-topic for this list, but...
From my understanding of sessions, you really don't want
session_start()
in an if{} block. Every time you hit this script, it will have no memory
of any session variables until you call session_start().
-Steve
On Tuesday, October 30, 2001, at 02:30 PM, Matthew Tedder wrote:
?php
/*
Hi,
I'm new to PHP and am having trouble understanding how to use PHP
sessions. My book tells in near the beginning how to start them and
register
session variables, but I can't figure out how to destroy a session or
later
read those session variables. I'm also trying to do this across
frames, but
can't even get it to work within a single page.
Here's what I've learned so far and what my problems are:
*/
/* To start a session */
session_start();
/* To register a session variable */
session_register(myvar);
$myvar = some value;
/*
PROBLEM #1: From the above commands, I get a $PHPSESSID that seems to
be
globally available for use, but I cannot seem to read my values back
out of
the registered session variable from anywhere... I tried:
*/
print $myvar\n; /* and absolutely nothing is printed */
/* To destroy a session */
session_destroy();
/*
PROBLEM #2: This says there is no session to destroy. It's rather
strange
because I can still print the $PHPSESSID value..
I've attached my code...
*/
?
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#---#
Believe nothing - consider everything
Russ Michell
Anglia Polytechnic University Webteam
Room 1C 'The Eastings' East Road, Cambridge
e: [EMAIL PROTECTED]
w: www.apu.ac.uk/webteam
www.theruss.com
#---#
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Re: [PHP-DB] New users on mysql using php
go grab yourself a copy of phpmyadmin http://phpmyadmin.sourceforge.net/download.html jim - Original Message - From: Harpreet [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Thursday, October 25, 2001 2:02 PM Subject: [PHP-DB] New users on mysql using php I connect to mysql database using the following: $StrConnectionUser=mysql_connect(ipaddress,$USER); mysql_select_db(database name, $StrConnectionUser); My question is how can I add new users to mysql using the web interface. Like can i run the Grant and revoke (mysql commands) in my php page?? This way i can add or delete users that can have access to the mysql database through the web. I hope the above makes sense. Thanks, Regards, Harpreet Kaur Software Developer Crispin Corporations Inc. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP-DB] array-problems
- Original Message -
From: Jim Lucas [EMAIL PROTECTED]
To: Bart Verbeek [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, October 24, 2001 12:42 PM
Subject: Re: [PHP-DB] array-problems
Try this:
BEGIN:PHP-CODE
$result = mysql_query (SELECT DISTINCT date FROM linktracker WHERE name
LIKE '$PHP_AUTH_USER' GROUP BY date ORDER BY date);
if (mysql_num_rows($result))
{
for($i=0;$icount($row);$i++)
{
$date = array(
begin = array($i = $row[date]),
end = array($i = $row[date])
);
}
} else {
print (Sorry, no record were found.);
}
function drawSelect($which)
{
global $date;
foreach($date[$which] AS $date_begin)
{
?
option value=?=$date_begin??=$date_begin?/option
?
}
}
?
table
tr
tdBegindate/td
tdEnddate/td
/tr
tr
tdform method=post action=index.php name=date_select
input type=hidden name=action value=date_select
select name=date_begin
?
drawSelect(begin);
?
/select
/td
tdselect name=date_end
?
rsort($date[end]);
drawSelect(end);
?
/select
/td
/tr
tr
td colspan=2input type=submit name=Submit
value=Submit/form/td
/tr/table
END:PHP-CODE
btw - you need to watch your closing '' you are missing a few. Plus to
get distince to work right you need to use the GROUP BY clause.
Jim
- Original Message -
From: Bart Verbeek [EMAIL PROTECTED]
To: Php-General-list [EMAIL PROTECTED]; PHP-DB mailinglist
[EMAIL PROTECTED]
Sent: Wednesday, October 24, 2001 12:23 PM
Subject: [PHP-DB] array-problems
Hello,
Can anyone help me with this script I'm using?
I've saved dates in a database and want to make two select-lists of
these
dates in a html-form.
I want to select each unique date one time (no doubles).
List 1 is used to set the begin-date of the query for the report, List 2
will
set the end-date and must be reversed.
When the form is processed the data selected between the begin-date and
the
end-date has to be show.
I can't seem to get my code to work: the select-lists stay empty after
processing the code below.
Can anyone help? Tips...
regards,
Bart
BEGIN:PHP-CODE
$i=0;
$result = mysql_query (SELECT DISTINCT date FROM linktracker WHERE
name
LIKE '$PHP_AUTH_USER' ORDER BY date);
if ($row = mysql_fetch_array($result)) {
do {
$date = array(
begin = array($i = $row[date]),
end = array($i = $row[date])
);
$i++;
} while ($row = mysql_fetch_array($result));
} else {print (Sorry, no record were found.);
} //end else $result
print(tabletrtdBegindate/tdtdEnddate/td/tr\n.
trtdform method=\post\ action=\index.php\
name=\date_select\.
input type=\hidden\ name=\action\
value=\date_select\.
select name=\date_begin\);
while (list($key, $date_begin) = each($date[begin])) {
echo option value=\.$date_begin .\ . $date_begin .
/option\n;
}
print(/select/tdtdselect name=\date_end\);
rsort($date[end]);
while (list($key, $date_end) = each($date[end])) {
echo option value=\.$date_end .\ . $date_end .
/option\n;
}
print(/select/td/tr\ntrtd colspan=\2\.
input type=\submit\ name=\Submit\
value=\Submit\.
/form/td/tr/table);
mysql_free_result ($result);
mysql_close();
END:PHP-CODE
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