[PHP-DB] Re: php/mysql error

I think you can get this error when you sql query fails. Try copy and pasting the $sql query to the mysql command line and see what response you get (it looks as though this would work though unless you haven't got a table called test). I guess it might be that you are not successfully logging on

[PHP-DB] Problem with include()

Can anyone spot why I get the error Warning: Failed opening 'd:/www/htdocs/ski-info-online/poll.php?id=KnChooseBoots' for inclusion (include_path='') in d:\WWW\htdocs/ski-info-online/skiKnSkiBoots.php on line 113 Here is the calling line: ?php include($DOCUMENT_ROOT .

[PHP-DB] Re: Pass var from JavaScript to PHP

err...what javascript the form is HTML? Try... form name=NAME method=get OR post action=?php echo $PHP_SELF? Then in your page have a php tag that checks for the presence of $Find (in your case), e.g. if ($Find) { sql = (SELECT * FROM table WHERE $criteria = value); then the rest... }

Re: [PHP-DB] Problem with include()

lesystem? Peter -Original Message- From: TorrentUK [mailto:[EMAIL PROTECTED]] Sent: 13 November 2001 12:47 To: [EMAIL PROTECTED] Subject: [PHP-DB] Problem with include() Can anyone spot why I get the error Warning: Failed opening 'd:/www/htdocs/ski-info-online/pol

Re: [PHP-DB] Problem with include()

Original Message - From: TorrentUK [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, November 13, 2001 11:24 AM Subject: Re: [PHP-DB] Problem with include() Hi Peter, I'll be surprised if that's it as I am running this through an Apache server which insists on the \ being /

Re: [PHP-DB] Problem with include()

-- From: TorrentUK [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, November 13, 2001 1:16 PM Subject: Re: [PHP-DB] Problem with include() According to the php manual it can pass args and values. The value I pass in through the $id then determines what poll is presented to the

[PHP-DB] What's wrong with my function? :(

Please could some take a look at this code and tell me why when I take my IF statements out of the function and put in them in the same place where I call the function from they work, but as soon as I replace them with the function name they don't? Appreciate any help. torrent Here's the

Re: [PHP-DB] What's wrong with my function? :(

Yep, that'll be it. Thanks for the help. :) torrent Charles F. McKnight [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Tue, 30 Oct 2001, TorrentUK wrote: SNIP you either need to pass the variables to the function or use global v

Re: [PHP-DB] Help in passing multiple HTML form options to SQL query -- Newbie

= select * from tbl where ctry='$country[0]'; for ($n=1; count($country) $n; $n++) { $sql.= or ctry='$country[$n]'; } richard TorrentUK wrote: I am designing a ski web site and am presently trying to put together a resort database. I started the search script tonight and am quite

[PHP-DB] Help in passing multiple HTML form options to SQL query -- Newbie

I am designing a ski web site and am presently trying to put together a resort database. I started the search script tonight and am quite pleased that it works. Where I am struggling is that I would like my visitors to be able to select multiple countries from the drop down list and for my query