I've got a database table with a whole list of windows file paths.
eg
Advent Tower PC\C\Program Files\Microsoft Office\Microsoft Binder.lnk
Advent Tower PC\C\Program Files\Microsoft Office\Microsoft Excel.lnk
Advent Tower PC\C\Program Files\Microsoft Office\Microsoft Office Setup.lnk
Advent Tower
I've been racking my brain and the web for finding a solution and no
luck so far.
Here's the form:
$display_block .= HRInput item: form method=post
action=\additem.php\nbsp;nbsp;nbsp;nbsp;Item ID:input
type=\text\ name=\sel_item_id\BRQuantity: select
name=\sel_item_qty\;
$display_block .= option
From: Robert Sossomon [EMAIL PROTECTED]
And here is the additem.php file where it check for the info in the
field and it is erroring out.
It would be rather useful to know the error...
$get_iteminfo = select * from GCN_items where 'item_num' LIKE
'%$_POST[sel_item_id]%';
Take away the
; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Query Error
From: Robert Sossomon [EMAIL PROTECTED]
And here is the additem.php file where it check for the info in the
field and it is erroring out.
It would be rather useful to know the error...
$get_iteminfo = select * from GCN_items where
From: Robert Sossomon [EMAIL PROTECTED]
The errors as it prints are:
The query I just ran was: select * from GCN_items where `item_num` =
'%fm-a294%'
The query I just ran was: Resource id #2
0
Those aren't errors; it's just what you asked the script to display. Your
query simply isn't
!
-Original Message-
From: CPT John W. Holmes [mailto:[EMAIL PROTECTED]
Sent: Tuesday, November 04, 2003 1:31 PM
To: Robert Sossomon; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Query Error
From: Robert Sossomon [EMAIL PROTECTED]
The errors as it prints are:
The query I
Hello guys
Does anybody have a clue on what wrong with the following sentence?
select author_code from author where author_code not in
(select author_code from authorxcat);
Thanks
***
:
Subject: [PHP-DB] Query error
10/02/2002 10:54 AM
something like
select author_code from author where author_code not in ($previousResults)
HTH
Beau
// -Original Message-
// From: Wilmar Perez [mailto:[EMAIL PROTECTED]]
// Sent: Wednesday, 2 October 2002 10:54 PM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] Query error
//
//
// Hello
when i perform query an mysql db, to insert a new record, the PHP says:
Warning: Supplied argument is not a valid MySQL result resource in
g:\wwwroot\phpusermanager-1.0\add_order.php on line 24
the snippet is as follows
?
// connect to the database
$conn = mysql_connect ($db_host, $db_user,
On Sunday 05 May 2002 14:44, erich wrote:
when i perform query an mysql db, to insert a new record, the PHP says:
Warning: Supplied argument is not a valid MySQL result resource in
g:\wwwroot\phpusermanager-1.0\add_order.php on line 24
the snippet is as follows
?
// connect to the
Echo your INSERT statement, so that you know what it looks like, if you
have the values you expect, field names are spelled correctly. that you're
not inserting char into int, etc.
Use mysql_errno() and mysql_err() (Check those against manual to determine
what error you are getting. Use
Ok what is wrong with this sql statement?
$sql = UPDATE $table_name SET
c_name=\$c_name\,s_addy=\$s_addy\,city=\$city\,state=\state\zip=\zi
p\,phone=\$phone\;
The error I recieve is as follows
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in
/path/to/wwwdemo_change.php3 on line
Try putting single quotes around your variables in your update statement
instead of the escaped double quotes, they are easier to read.
Also, were you wanting to update all entries in that table to the same,
c_name, s_addy, city, state, zip and phone? If not, you will need to
add 'where
Ok jas
Ok what is wrong with this sql statement?
$sql = UPDATE $table_name SET
c_name=\$c_name\,s_addy=\$s_addy\,city=\$city\,state=\state\zip=\zi
p\,phone=\$phone\;
insufficient checking:
comma missing between state and zip
incorrectly escaped before phone
...
I have looked on MySQL.com
Did you type this out or cut/paste? There was a comma missing between
state\zip . Should work when you add the comma.
Add a WHERE condition for the update, otherwise every row will be set to
these values.
Common practice is to use single quotes around the char variables, saves a
lot of
When I run any kind of query this is the value of result Resource id #2
Example
$result= mysql_query (" Select * from ACCT_TBL ") or die
("Error".mysql_error());
print result;
any ideas?
randy
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Looks fine, now retrieve the rows from the query.
-Original Message-
From: Randy Johnson [mailto:[EMAIL PROTECTED]]
Sent: Thursday, January 25, 2001 12:46 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] query error
When I run any kind of query this is the value of result
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