Matthew Ferry wrote:
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query event_time brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out
Try this as your SQL. It should give you all the results, then you can use PHP
to sort it all out.
SELECT * FROM egw_cal WHERE cal_category='501' and cal_id in (SELECT cal_id
FROM egw_cal_dates where cal_start $tstamp)
-TG
= = = Original message = = =
Hello Everyone
Got a simple /
This is a join - Read up on them, they're very useful and don't require
the overhead of a sub-query.
SELECT egw_cal.* FROM egw_cal_dates
LEFT JOIN egw_cal using (cal_id)
where egw_cal_dates.cal_start $tstamp
AND egw_cal.cal_category = '501'
-Micah
On 02/12/2007
Thanks Everyone...
After I sent that...I got thinking about doing both queries in one statement.
So thats what I did.
Its working fine...
Here is the updated code:
?php
$todays_year = date(Y);
$todays_month = date(m);
$todays_day = date(d);
$tstamp = mktime(0, 0, 0, $todays_month,
Chris Carter wrote:
What wrong with this syntax, its not giving any error on runtime but I am
facing a blank page while paging.
$query= SELECT * FROM gurgaonmalls WHERE mallname = '$mallname' limit $eu,
$limit ;
Have you tried...
echo p $query /p;
...to unsure the variables have the values
Make sure that your second query is returning only one row, if it dont
help, try this:
$query=select email from usuarios where userName in (select username
from fussv where folio = 'FUSS-130-2006')
MySQL think that you second query returns more than 1 row, that's why
mysql dont accept your
Check your version. Subselects were only added in MySQL Version 4.1.
Regards,
Dwight
-Original Message-
From: Edwin Cruz [mailto:[EMAIL PROTECTED]
Sent: Thursday, September 28, 2006 10:53 AM
To: 'Miguel Guirao'; php-db@lists.php.net
Subject: RE: [PHP-DB] SQL query
Make sure
OK, this makes my day clear!!
I have versión 3.23.49-3 of MySQL
Thanks Dwight!
-Original Message-
From: Dwight Altman [mailto:[EMAIL PROTECTED]
Sent: Jueves, 28 de Septiembre de 2006 11:32 a.m.
To: php-db@lists.php.net
Subject: RE: [PHP-DB] SQL query
Check your version. Subselects
Create a form for editing the record
Then on the display funtion just put a link on each record to that form
and pass the id of that record like a
href=editrecord.php?id=?=$row['id']?edit/a
On the edit form just grab the data of the $id passed on the url and put
those values on the input fields
SELECT DISTINCT(file_name), Count(file_name) FROM $table_name WHERE date
BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by ???
desc
In the above sql statement, I'm trying to achieve:
1. select all file names, between two dates.
2. list them, and order by the highest number of
Ah...
you can name the count()..
live and learn, cheers dude...
brett king [EMAIL PROTECTED]
15/01/2004 11:17
Please respond to
[EMAIL PROTECTED]
To
[EMAIL PROTECTED], [EMAIL PROTECTED]
cc
Subject
RE: [PHP-DB] SQL query...
SELECT DISTINCT(file_name), Count(file_name) FROM $table_name
use alias for 'Count(file_name)' to use in order by clause
F.x.
SELECT DISTINCT(file_name), Count(file_name) as file_count FROM $table_name
WHERE date BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by
file_count desc
Hope that solves it
Nitin
- Original Message -
From:
Try this
SELECT DISTINCT(file_name), Count(file_name) AS cnt FROM $table_name WHERE
date
BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by cnt;
desc
Regards,
Muhammed Mamedov
tmchat.com
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent:
From: Muhammed Mamedov [EMAIL PROTECTED]
Try this
SELECT DISTINCT(file_name), Count(file_name) AS cnt FROM $table_name
WHERE
date
BETWEEN '2003-10-01' AND '2003-12-31' group by file_name order by cnt;
desc
If you're GROUPing by file_name then you don't need DISTINCT(file_name)...
it's
id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
Adam
On Sat, 7 Sep 2002, Bryan McLemore wrote:
Hi Guys I have written this SQL Query :
CREATE TABLE tasks (id INT AUTO_INCREMENT, name VARCHAR(50), desc TEXT, address
VARCHAR(50), startDate DATE, lastWork DATE, progress
It would unless you told it not to. Set a flag
$lastContactType='';
Then on the first page you display something where then display it and then
if ($lastContactType != $row['contactType']){
echo $row['contactType'];
$lastContactType=$row['contactType'];
} // if ($lastContactType
Hello Chip,
Could you please send your program to dig more.And also
send your database schema.
Do you want to
select title,name from your_table_name where title='title1' and
name='blue2';
Is the title and name field are unique.If it so,then the above query will
helps you.
try replacing
WHERE display=$custcatergory);
with
WHERE display='$custcatergory');
and also tru echoing the value of that SQL statement (assign it to a var
first) to make sure you are getting the right thing.
HTH
/b
// -Original Message-
// From: CrossWalkCentral [mailto:[EMAIL
Thanks I will try that.
Beau Lebens [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
try replacing
WHERE display=$custcatergory);
with
WHERE display='$custcatergory');
and also tru echoing the value of that SQL statement (assign it to a var
first) to make
/ANSI_diff_Sub-selects.html
-Original Message-
From: Pierre
Sent: Mon 11/12/2001 12:20 AM
To: Gonzalez, Lorenzo; [EMAIL PROTECTED]
Cc:
Subject: Re: [PHP-DB] SQL query
Thanks but I think subselect
in other RDBMs this is easily done with a subselect - don't know if it's
doable in MySQL or not, someone else can confirm, or you can try it
yourself...
select * from table1 where table1.id not in (select table2.id);
-Lorenzo
-Original Message-
From: Pierre
Thanks but I think subselect is not possible with MYSQL.
Pierre
- Original Message -
From: Gonzalez, Lorenzo [EMAIL PROTECTED]
To: Pierre [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Monday, November 12, 2001 1:08 PM
Subject: RE: [PHP-DB] SQL query
in other RDBMs this is easily done
22 matches
Mail list logo
