On Aug 9, 2011, at 3:41 PM, Peter Lind wrote:
On 9 August 2011 22:38, Chris Stinemetz chrisstinem...@gmail.com
wrote:
Yes, debug your code and figure out why it's looping twice instead.
For instance, try the other query in the mysql console.
Thank you! It was the first query. I put a
On 9 August 2011 20:31, Chris Stinemetz chrisstinem...@gmail.com wrote:
Okay. I am pretty new to mysql so this may seem like a ridiculous
question to some people.
I am trying to use a LEFT JOIN query, but the results I am finding
unusual. For every record occurrence there is for the query,
Is users.user_id unique?
yes it is.
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On 9 August 2011 20:49, Chris Stinemetz chrisstinem...@gmail.com wrote:
Is users.user_id unique?
yes it is.
What does your result look like? Hard to say what the problem is
without seeing the result.
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What does your result look like? Hard to say what the problem is
without seeing the result.
I am echoing the query and printing the get array just for debugging
purposes, but below you can see how it is repeating its' self.
Thank you
Array
(
[id] = Bella Roe 4980 Roe Blvd
)
Bella
On 9 August 2011 21:23, Chris Stinemetz chrisstinem...@gmail.com wrote:
What does your result look like? Hard to say what the problem is
without seeing the result.
I am echoing the query and printing the get array just for debugging
purposes, but below you can see how it is
Okay. I just validated it is not in the left join query, but in my php. I
was able to build the correct relations.
Does anyone see any think in the php code below that may cause duplicate
table rows?
Thank you all.
?php
//store.php
include_once 'includes/connect.php';
include_once
You already have a foreign key, that is stores.store_by references
users.user_id. You might not have declared it (which is OK) but if that is the
key you want that is fine.
I suspect you are seeing an inadvertent Cartesian product. The way you have
written this query you will get one row
On Tue, Aug 9, 2011 at 2:55 PM, Frank Flynn fr...@declan.com wrote:
You already have a foreign key, that is stores.store_by references
users.user_id. You might not have declared it (which is OK) but if that is
the key you want that is fine.
I suspect you are seeing an inadvertent Cartesian
When I dump the query and run it in console I get the results I want. Not
sure what I am doing wrong.
Your php code had more than one query running (one inside the other).
It's the outer query that runs twice, not the inner one returning
double the results
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Your php code had more than one query running (one inside the other).
It's the outer query that runs twice, not the inner one returning
double the results
Thanks Peter,
Do you have any suggestions on how to fix this?
Thank you,
Chris
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On 9 August 2011 22:25, Chris Stinemetz chrisstinem...@gmail.com wrote:
Your php code had more than one query running (one inside the other).
It's the outer query that runs twice, not the inner one returning
double the results
Thanks Peter,
Do you have any suggestions on how to fix this?
Yes, debug your code and figure out why it's looping twice instead.
For instance, try the other query in the mysql console.
Thank you! It was the first query. I put a LIMIT 1 on it and now it is
working correctly. I appreciate your help!
Thank you,
Chris
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On 9 August 2011 22:38, Chris Stinemetz chrisstinem...@gmail.com wrote:
Yes, debug your code and figure out why it's looping twice instead.
For instance, try the other query in the mysql console.
Thank you! It was the first query. I put a LIMIT 1 on it and now it is
working correctly. I
On Wed, Feb 11, 2009 at 7:36 PM, mrfroasty mrfroa...@gmail.com wrote:
Hello,
I have been browsing on mysql manual
http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html
with not much of success.I am trying to put 2 foreign keys(from
different external table) on my table,
This worked for me:
CREATE TABLE hotel (
items_no int(16) NOT NULL auto_increment,
INDEX (items_no),
PRIMARY KEY (items_no)
)ENGINE=INNODB;
CREATE TABLE pack (
items_no int(16) NOT NULL auto_increment,
INDEX
I am not up to scratch with innodb, but in oracle
you would have a Primary key on both the id fields in the Car and person
table and a Foreign key on PersonId linking it to Id in the Person table.
IN your select an index on PersonId would be beneficial if the tables get
large.
Jack
2008/10/2 J
On Thu, Oct 2, 2008 at 6:50 AM, Jack van Zanen [EMAIL PROTECTED] wrote:
I am not up to scratch with innodb, but in oracle
you would have a Primary key on both the id fields in the Car and person
table and a Foreign key on PersonId linking it to Id in the Person table.
IN your select an
Doug,
One way to handle this is the following:
On the page that lists the people, under the edit link, you put something
like a href=editscript.php?id=$idEdit/a. When the user clicks that
link, the $id will be passed in the URL.
In your editscript.php page, inside the form where you're editing
Douglas,
The form that shows the editable fields has a hidden field named 'DID'
having the value of $zid. In your updaterecord procedure, you will have to
use the variable $_GET[DID] instead of $zid. You can of course just add one
line of code:
$zid = $_GET[DID];
to help you out. One other
On Wednesday 26 February 2003 00:37, Jorge Miguel Fonseca Martins wrote:
As this has nothing to do with databases you should post to the php-general
list.
$test[]=a;
$test[]=b;
foreach ($test as $key=$value)
{
if($key == something) echo $key
}
even though theres no key in the
On Friday 18 January 2002 00:25, James Kupernik wrote:
I found the problem in the form and fixed that, but now anytime I want to
submit the form by hitting enter, it acts like it's reloading the page.
What would be the cause of that? When I click on the submit button the
verification and
Sorry about that
?php
if ($submit) {
if ($person == -) {
$error = Please select your name!;
} elseif ($magicword != password) {
$error = Please enter correct password!;
} else {
echo bHi $person, here are the catalog requests/b\n;
mysql_insert_id()
Grant Boggs wrote:
What's the best way to get the primary key of a row just inserted into a
mySQL database?
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Head geek: Technology Services Coordinator
webmaster:
This has been covered countless times on the list... :)
http://www.php.net/manual/en/function.mysql-insert-id.php
-Original Message-
From: Grant Boggs [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, August 22, 2001 7:24 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Getting key of row just
Matthew Loff [EMAIL PROTECTED] wrote in message
002b01c12b64$92e1cc80$0100a8c0@bang">news:002b01c12b64$92e1cc80$0100a8c0@bang...
This has been covered countless times on the list... :)
http://www.php.net/manual/en/function.mysql-insert-id.php
I figured as much. Thanks guys!
--
mysql_insert_id()
i *think* also
pg_lastiod()
or something similar...
At 08:57 PM 2/27/01 -0800, Richard S. Crawford wrote:
Suppose I put data into a table using an Insert query, and that the table
generates a primary key for the data. Is there a way to get at that
primary key without running
Perfect! Thanks.
At 01:05 PM 2/28/01 +0800, Beau Lebens wrote:
mysql_insert_id()
i *think* also
pg_lastiod()
or something similar...
At 08:57 PM 2/27/01 -0800, Richard S. Crawford wrote:
Suppose I put data into a table using an Insert query, and that the table
generates a primary key for the
ry 2001 01:53
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] foreign key problem
hello all!
i have a little problem ,hope someone can help me out
the problem is :
let i have two tables T1 and T2 ,now T1 has following
fields
cntryid
cntryname
cntrycode etc.
now cntryid is the primary key
ation (table), R1, then
every R2.F entry must either be a value equal to an R1.P primary key value
or be null"
Regards,
Chris
-Original Message-
From: Bob Hall [mailto:[EMAIL PROTECTED]]
Sent: 31 January 2001 01:53
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] foreign k
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