Re: [PHP-DB] Variables & Forms

2007-10-17 Thread Niel Archer
Hi Ron

"" is perfectly legitimate in an e-mail header field like "Subject:".
All headers may contain any combination of ASCII characters except CR
and LF which are used to terminate the field (See RFC8222 section 2.2).

There is also defined a means to "fold" lines which involves using the
CR+LF+white-space combination to indicate multiple line entries.  Is it
possible your e-mail header fields are doing this and your access to the
headers does not take this possibility into account?  Without your POP
handling code it's impossible to say whether this is your problem or not.

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RE: [PHP-DB] Variables & Forms

2007-10-17 Thread Bastien Koert

Ron,
 
The email subject line should not have a  tag in it at all. It is not 
allowed under the specifications if I remember correctly. I would suggest that 
when you suck the message in, first thing to do is to remove the  tag 
with str_replace...
 
Would this get you on your way?
 
Bastien> From: [EMAIL PROTECTED]> To: php-db@lists.php.net> Date: Tue, 16 Oct 
2007 09:47:13 -0500> Subject: [PHP-DB] Variables & Forms> > I am programming a 
form this morning.  I don't understand arrays really well.  I think this is 
what I am needing to use, but I am really not sure.> > I have a PHP script that 
checks a POP e-mail address and is suppose to take the incoming message and 
save it to a mySQL table based on the subject line.  Every now and then the 
subject line is broken with something like a  and so I have a handful of 
messages that need to be indexed manually.  IE my script can't see a "Subject: 
Correspondence for message 123" --- it is being received as "Subject: 
Correspondence for message 123"  I am trying to update the mySQL table 
with a form instead of continuing to use phpmyadmin to do these updates. > > 
What I am wanting to do in my form is call up all the incoming messages that 
have a message value of 0 and I can read through the incoming message to see 
what their reference number is and type it in the field that I have called 
"new_correspondence_received".  An example of my HTML code is below.> > Where I 
am getting stuck is if I have more than 1 message that wasn't indexed 
automatically I am not sure how to retrieve the values of: 
correspondence_reference and new_correspondence_reference.  (The only reason I 
am displaying correspondence_received is to look for the reference number)  Can 
what I am trying to do be accomplished through an array to find out the values 
submitted?  What changes need to be made to my form so I can find out the 
values being submitted?> > Each message received that isn't automatically index 
is dispayed through this form, one  per message, thanks for your help.  
Ron> > > > >  
172> > > > > 
> > > Message here> > > 
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RE: [PHP-DB] Variables in database content

2004-05-23 Thread Sunmaia
Hi

you need eval()

http://uk2.php.net/manual/en/function.eval.php

HTH

Peter

> -Original Message-
> From: Brian Stoffer [mailto:[EMAIL PROTECTED]
> Sent: 23 May 2004 23:34
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] Variables in database content
> 
> 
> Hi there.  I have what I suspect is an easy one, but was unable to find 
> something similar in the archives (it's a tough one to search for...).
> 
> Basically I have a table with a text block column.  The actual content 
> that lives in column contains php variables that I want to be able to 
> use when I pull the text out of the database.  Let me give you an 
> example:
> 
> Content:
> "Hi there.  My name is $name.  This is a bunch of text that $othername 
> is telling me to populate with some data.  Hopefully you will be able 
> to help $othername and I get this to work.  Thanks!"
> 
> Now, in my script I want to be able to pull names out of another table, 
> initialize the $name and $othername variables, then pull out the 
> content above, parse the "names" variables and display it in the 
> browser.
> 
> My problem is the variables don't get parsed.  I've tried a few obvious 
> things, like storing the text in a variable, using print or echo, and 
> so-on, even processing it with the various text-to-html functions 
> hoping that it would process the variables, but it seems like it's 
> treating the text as a literal and not actually parsing the variables.
> 
> I suspect it has something to do with either the order, the method of 
> output, or some pre-processing that I'm missing, but after a few hours 
> I simply can't get it.
> 
> Thanks for any advice!
> 
> -b
> 
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Re: [PHP-DB] Variables not working within Functions

2003-10-19 Thread Colin Kettenacker
Or pass the variable $username as an argument into your function:

function LoginSystem($username) {
// your function code
}

LoginSystem($username);

ck

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Chris Wanstrath [EMAIL PROTECTED] on 10/15/03 7:57 PM wrote:

> You are using a variable outside of the function's scope.
> In the function, do this:
> global $username;
> 
> Visit www.php.net/man to get a better understanding of globals and
> scope.
> 
> On Wed, 2003-10-15 at 22:10, Adam Symonds wrote:
>> Hi,
>> I am starting to us functions with my work but I am having troubles
>> With the variables in the functions..
>> 
>> If I have the following function called from my page it will work but the
>> variable wont
>> ($username)
>> but if I put this code straight on the page then it works fine..
>> 
>> Any reason for the variable not to work in the function but in straight
>> coding?
>> Thanx
>> 
>> 
>> 
>> Sample Function Below:
>> 
>> ==
>> function LoginSystem()
>> {
>> echo "";
>> if ( !isset( $_SESSION['login'] ) ) {
>> 
>> echo "";
>> echo "Username: > size=10> Password: > size=10> ";
>> echo "Not A Member
>> Yet? ";
>> echo "";
>> 
>> } else {
>> echo "Welcome $username    > href=../Users/Logout.php>> size=1>Logout   ";
>> }
>> echo "";
>> }

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Re: [PHP-DB] Variables not working within Functions

2003-10-15 Thread Chris Wanstrath
You are using a variable outside of the function's scope.
In the function, do this:
global $username;

Visit www.php.net/man to get a better understanding of globals and
scope.

On Wed, 2003-10-15 at 22:10, Adam Symonds wrote:
> Hi,
> I am starting to us functions with my work but I am having troubles
> With the variables in the functions..
> 
> If I have the following function called from my page it will work but the
> variable wont
> ($username)
> but if I put this code straight on the page then it works fine..
> 
> Any reason for the variable not to work in the function but in straight
> coding?
> Thanx
> 
> 
> 
> Sample Function Below:
> 
> ==
> function LoginSystem()
>  {
> echo "";
> if ( !isset( $_SESSION['login'] ) ) {
> 
> echo "";
> echo "Username:  size=10> Password:  size=10> ";
> echo "Not A Member
> Yet? ";
> echo "";
> 
>  } else {
> echo "Welcome $username     href=../Users/Logout.php> size=1>Logout   ";
> }
> echo "";
>  }

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RE: [PHP-DB] Variables de SESSION dentro de funciones PHP

2002-12-13 Thread Francisco José Saiz : : netPerceptions
Thanks, I'll try it now.

-Original Message-
From: Leif K-Brooks [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 13, 2002 1:49 PM
To: Francisco José Saiz :: netPerceptions
Subject: Re: [PHP-DB] Variables de SESSION dentro de funciones PHP


You're mixing register_globals off session code with register_globals on

session code.  $HTTP_SESSION_VARS['myvar'] doesn't get defined until the

second page view after setting it.  Try:

session_start();

function OneFunction()
{
$GLOBALS['HTTP_SESSION_VARS']['myvar'] = 'ABC';
}
onefunction();
echo($HTTP_SESSION_VARS["myvar"]);



Francisco José Saiz :: netPerceptions wrote:

>Hi,
>
>I have made a PHP function that reads a tablename from a file. I want 
>to keep the tablename value into a session var. I register the session 
>vars and assign the value. But when I try to access outside the 
>function the variable is empty.
>
>I do this:
>
>session_start();
>
>function OneFunction
>{
>   $myvar="ABC";
>   session_register("myvar");
>}
>
>echo($HTTP_SESSION_VARS["myvar"]);
>
>
>And do not prints nothing.
>
>Why? Is a scope fault?
>
>Thanks.
>
>-----Original Message-
>From: Snijders, Mark [mailto:[EMAIL PROTECTED]]
>Sent: Friday, December 13, 2002 1:08 PM
>To: '_netPerceptions?='; [EMAIL PROTECTED]
>Subject: RE: [PHP-DB] Variables de SESSION dentro de funciones PHP
>
>
>english please!!!
>
>
>
>___
>
>Mark Snijders, Developer
>Atos Origin 
>Groenewoudeseweg 1, Room VN-515 
>5621 BA  Eindhoven, The Netherlands 
>*   : [EMAIL PROTECTED] 
>*:+31 (0)40 - 2785992 (tel) 
>* : +31 (0)40 - 2788729 (fax) 
>
>The information in this mail is intended only for use of the individual

>or entity to which it is addressed and may contain information that is 
>privileged, confidential and exempt from disclosure under applicable 
>law. Access to this mail by anyone else than the addressee is 
>unauthorized. If you are not the intended recipient, any disclosure, 
>copying, distribution or any action taken omitted to be taken in 
>reliance of it, is prohibited and may be unlawful.
>
>
>
>-Original Message-
>From: _netPerceptions?= [mailto:[EMAIL PROTECTED]]
>Sent: vrijdag 13 december 2002 12:33
>To: [EMAIL PROTECTED]
>Subject: [PHP-DB] Variables de SESSION dentro de funciones PHP
>
>
>Hola,
> 
>tengo una función en PHP que me lee de un fichero una configuración de 
>unas tablas de BBDD, quiero que el nombre de las tablas así como los 
>datos de conexión, me queden residentes en unas variables de sesión. 
>Cuando registro las variables dentro de la función, al acceder desde 
>cualquier otro punto con $HTTP_SESSION_VARS["nombrevariable"] me pone 
>como que está vacía.
> 
>¿alguien podría aclararme el tratamiento de estas variables en PHP?
> 
>Saludos y muchas gracias.
>
>
>
>  
>

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RE: [PHP-DB] Variables de SESSION dentro de funciones PHP

2002-12-13 Thread Francisco José Saiz : : netPerceptions
Hi, 

I have made a PHP function that reads a tablename from a file. I want to
keep the tablename value into a session var. I register the session vars
and assign the value. But when I try to access outside the function the
variable is empty.

I do this:

session_start();

function OneFunction
{
$myvar="ABC";
session_register("myvar");
}

echo($HTTP_SESSION_VARS["myvar"]);


And do not prints nothing.

Why? Is a scope fault?

Thanks.

-Original Message-
From: Snijders, Mark [mailto:[EMAIL PROTECTED]] 
Sent: Friday, December 13, 2002 1:08 PM
To: '_netPerceptions?='; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Variables de SESSION dentro de funciones PHP


english please!!!



___ 

Mark Snijders, Developer 
Atos Origin 
Groenewoudeseweg 1, Room VN-515 
5621 BA  Eindhoven, The Netherlands 
*   : [EMAIL PROTECTED] 
*:+31 (0)40 - 2785992 (tel) 
* : +31 (0)40 - 2788729 (fax) 

The information in this mail is intended only for use of the individual
or entity to which it is addressed and may contain information that is
privileged, confidential and exempt from disclosure under applicable
law. Access to this mail by anyone else than the addressee is
unauthorized. If you are not the intended recipient, any disclosure,
copying, distribution or any action taken omitted to be taken in
reliance of it, is prohibited and may be unlawful.



-Original Message-
From: _netPerceptions?= [mailto:[EMAIL PROTECTED]]
Sent: vrijdag 13 december 2002 12:33
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables de SESSION dentro de funciones PHP


Hola,
 
tengo una función en PHP que me lee de un fichero una configuración de
unas tablas de BBDD, quiero que el nombre de las tablas así como los
datos de conexión, me queden residentes en unas variables de sesión.
Cuando registro las variables dentro de la función, al acceder desde
cualquier otro punto con $HTTP_SESSION_VARS["nombrevariable"] me pone
como que está vacía.
 
¿alguien podría aclararme el tratamiento de estas variables en PHP?
 
Saludos y muchas gracias.



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RE: [PHP-DB] Variables de SESSION dentro de funciones PHP

2002-12-13 Thread Michael Hazelden
through the magic of babelfish!

I have a function in PHP that reads of a file a configuration to me of BBDD
tables, I want that the name of the tables as well as the data of
connection, I have left residents in session variables. When registry the
variables within the function, when acceding from any other point with
$$HTTP_SESSION_VARS["nombrevariable "] puts to me because she is empty.
somebody could clarify the treatment to me of these variables in PHP?
Greetings and thank you very much. 

(just in case he can't speak English!)
-Original Message-
From: Ruprecht Helms [mailto:[EMAIL PROTECTED]]
Sent: 13 December 2002 12:32
To: Francisco José Saiz :@mayn.de: netPerceptions
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Variables de SESSION dentro de funciones PHP


Hi  Francisco José Saiz netPerceptions,

would you be so kind and repeat your mail in english.

Regards,
Ruprecht

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RE: [PHP-DB] Variables de SESSION dentro de funciones PHP

2002-12-13 Thread Ruprecht Helms
Hi  Francisco José Saiz netPerceptions,

would you be so kind and repeat your mail in english.

Regards,
Ruprecht

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RE: [PHP-DB] Variables de SESSION dentro de funciones PHP

2002-12-13 Thread Snijders, Mark
english please!!!



___ 

Mark Snijders, Developer 
Atos Origin 
Groenewoudeseweg 1, Room VN-515 
5621 BA  Eindhoven, The Netherlands 
*   : [EMAIL PROTECTED] 
*:+31 (0)40 - 2785992 (tel) 
* : +31 (0)40 - 2788729 (fax) 

The information in this mail is intended only for use of the individual or
entity to which it is addressed and may contain information that is
privileged, confidential and exempt from disclosure under applicable law.
Access to this mail by anyone else than the addressee is unauthorized. If
you are not the intended recipient, any disclosure, copying, distribution or
any action taken omitted to be taken in reliance of it, is prohibited and
may be unlawful.



-Original Message-
From: _netPerceptions?= [mailto:[EMAIL PROTECTED]]
Sent: vrijdag 13 december 2002 12:33
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables de SESSION dentro de funciones PHP


Hola,
 
tengo una función en PHP que me lee de un fichero una configuración de
unas tablas de BBDD, quiero que el nombre de las tablas así como los
datos de conexión, me queden residentes en unas variables de sesión.
Cuando registro las variables dentro de la función, al acceder desde
cualquier otro punto con $HTTP_SESSION_VARS["nombrevariable"] me pone
como que está vacía.
 
¿alguien podría aclararme el tratamiento de estas variables en PHP?
 
Saludos y muchas gracias.


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RE: [PHP-DB] Variables

2002-11-08 Thread Hutchins, Richard
It would seem that your IF statement, as it is written below, evaluates to
true every time because I'm guessing that the hexadecimal value of the
string timeb is larger than the hexadecimal value of timea. Like I said,
just a guess.

I'm also guessing that you actually want to compare two values from your
database when you do your if ($tim1 < $tim2). Assuming that timea and timeb
are columns in your database and are included in the $result of your query,
can you just do: 

if($myrow["timea"] < $myrow["timeb"]){
do stuff;
} 

HTH

> -Original Message-
> From: Steve Dodkins [mailto:Steve.Dodkins@;ebm-ziehl.co.uk]
> Sent: Friday, November 08, 2002 9:26 AM
> To: Php-Db (E-mail)
> Subject: [PHP-DB] Variables
> 
> 
> Hi
> 
> The following will print the variables ($tim1 and $tim2) 
> correctly but the
> IF statement using the same vars will not work, it will only 
> work as below
> which seems to work by comparing the text values of the 2 
> variables $tim1
> $tim2.
> 
> while($myrow = mysql_fetch_array($result))
> 
> {
> $tim1="timea";
> $tim2="timeb";
> if ($tim1 < $tim2)
> {
> echo
> "".$myrow[$tim1]."".$myrow[$tim2]."".$
> myrow["labor_o
> rd_no"]."".$myrow["labor_wkyr"]."".$myrow["wor
> ks_orders_cust
> omer_id"]."".$myrow["works_orders_part_no"].""
> .$myrow["works
> _orders_qty"]."".$myrow["labor_qty"]."".$myrow
> ["labor_time"]
> ."".$myrow["timea"];
> 
> Regards
> 
> Steve Dodkins
> 
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RE: [PHP-DB] Variables coming from forms

2002-09-22 Thread Peter Lovatt

could be a register globals issue?

Peter

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-Original Message-
From: Achilles Maroulis [mailto:[EMAIL PROTECTED]]
Sent: 22 September 2002 07:04
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables coming from forms


Hi. I have posted this thread before but didn't come to a solution so I try
again.

I've installed Apache 2.0 and PHP 4.2.3 (both with the msi installers) on
Windows 2000 Pro.
The problem I have is that I get the message

Notice: Undefined variable: var_name in 

every time I pass a new variable into another page whether this happens
using the URL or a form or even sessions.

The strange thing is that if I run phpinfo() in the same page (where the
variable is considered to be undefined) I see that my variables do exist in
the variables section of phpinfo.


For example. If I use a form to pass a variable in a php file like this:

  
  


and have the var.php like this:


I'll get the message:
Notice: Undefined variable: var in C:\Progr.\htdocs\var.php on line 2

while I'll also get a line like this in the variables section of phpinfo():
Variable  Value
_GET["var"] the value I typed before

I think this is really strange. Has anyone something to suggest?

Thanx in advance!!
Achilles


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RE: [PHP-DB] variables gone?

2002-05-29 Thread Mark Roedel


Beginning in PHP 4.2.0, the normal behavior with respect to preloaded
variables was changed (specifically, the default value of the
register_globals configuration entry was changed from "on" to "off").

For details, see
http://www.php.net/manual/en/language.variables.predefined.php


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LeTourneau University |  to be entertained."
Longview, Texas, USA  |  -- John Powell


> -Original Message-
> From: Rob Fraser [mailto:[EMAIL PROTECTED]] 
> Sent: Wednesday, May 29, 2002 8:49 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] variables gone?
> 
> 
> I am probably doing something silly but I don't know what (story of
> my life). I have just upgraded to 4.2.1 and now all the variables I
> post in forms or in query strings are now coming up undefined errors 
> and are in absent. I'm running PHP under IIS 4.
>
> What am I doing wrong?

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Re: [PHP-DB] variables gone?

2002-05-29 Thread Ed Gorski

In php.ini you need to turn register_globals on..you also might want to 
start using the $_GET, $_POST, $_SESSION global arrays

ed

At 02:49 PM 5/29/2002 +0100, Rob Fraser wrote:
>Dear All,
>I am probably doing something silly but I don't know what (story of my
>life). I have just upgraded to 4.2.1 and now all the variables I post in
>forms or in query strings are now coming up undefined errors and are in
>absent. I'm running PHP under IIS 4.
>What am I doing wrong?
>
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RE: [PHP-DB] Variables

2002-04-25 Thread Ryan Jameson (USA)

In an attempt to be less vague I think you want to change your line:

 $c . $count+1 = $artist[$count];

to be:

$varName = $c.($count+1);
$$varName = $artist[$count];

Got it now?

---

I think what you don't know is this:

$varName = "c1";
$$varName = 3;
that just set $c1 to equal 3.

Does that help? 

-Original Message-
From: Julio Cuz, Jr. [mailto:[EMAIL PROTECTED]]
Sent: Thursday, April 25, 2002 9:56 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables


HI--
* I have the following variables: $c1 thru $c10.
* I also have a FOR loop like this:
 for($count = 0; $count < sizeof($artist); $count++)
 { echo "$artist[$count]"; }
 // $artist is a list of ten (10) artist's names.
* What I'm trying to do is something like this:  Combine the variables 
with the info inside the FOR loop:
 for($count = 0; $count < sizeof($artist); $count++)
 {  //Trying to assign the value of $c1, $c2, $c3, etc. 
using the value of the variable $count.
//But so far, it only processes the value of $count 
alone, and it ignores $c
 //The line below should read like this:  $c1 = $artist[0], 
next line:  $c2 = $artist[1], etc.
 $c . $count+1 = $artist[$count];
 }

Help!!!

Julio Cuz, Jr.
Riverside Community College
[EMAIL PROTECTED]

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RE: [PHP-DB] Variables

2002-04-25 Thread Ryan Jameson (USA)

I think what you don't know is this:

$varName = "c1";
$$varName = 3;
that just set $c1 to equal 3.

Does that help? 

-Original Message-
From: Julio Cuz, Jr. [mailto:[EMAIL PROTECTED]]
Sent: Thursday, April 25, 2002 9:56 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables


HI--
* I have the following variables: $c1 thru $c10.
* I also have a FOR loop like this:
 for($count = 0; $count < sizeof($artist); $count++)
 { echo "$artist[$count]"; }
 // $artist is a list of ten (10) artist's names.
* What I'm trying to do is something like this:  Combine the variables 
with the info inside the FOR loop:
 for($count = 0; $count < sizeof($artist); $count++)
 {  //Trying to assign the value of $c1, $c2, $c3, etc. 
using the value of the variable $count.
//But so far, it only processes the value of $count 
alone, and it ignores $c
 //The line below should read like this:  $c1 = $artist[0], 
next line:  $c2 = $artist[1], etc.
 $c . $count+1 = $artist[$count];
 }

Help!!!

Julio Cuz, Jr.
Riverside Community College
[EMAIL PROTECTED]

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Re: [PHP-DB] Variables in a loop

2001-10-30 Thread Jason G.


If you have a string that is the name of an input field, you can do one of 
3 things:

Ex:
$sName = "input".$i;  //result = "input1"
$sName = "input".$i;  //result = "input2"
etc...

1: Variable Variables
$value = $$sName;

2: If you posted the form
$value = $HTTP_POST_VARS[$sName];

3: If you used GET with the form
$value = $HTTP_GET_VARS[$sName];

Regards,
-Jason Garber
IonZoft.com






At 09:10 AM 10/30/2001 +0100, * R&zE: wrote:
>
>From: LeTortorec, Jean-Louis <[EMAIL PROTECTED]>
>Date: Mon, Oct 29, 2001 at 04:03:45PM -0500
>Message-ID: <615315231286D21182E40008C7B1EED23C6E76@COMPAQ3000>
>Subject: [PHP-DB] Variables in a loop
>
> > I'm trying to write a loop to read variables I receive from a form:
> >
> > 
> > 
> > 
> > 
> > 
> >
> >
> > I'd like to get something like:
> >
> > for ($i=1; $i<=10; $i++) { $tab[$i]="a".$i ;}
> >
> >
> > The expression "a".$i is actually a string, not a variable.  Any idea 
> how to
> > "read" the value of that string?
> >
> > Thanks for your help.
> >
> > Jean-Louis
>
>
>
>
>
>Why don't you just use an array?
>
>
>
>
>
>
>
>
>
>--
>
>* R&zE:
>
>
>-- 
>-- Renze Munnik
>-- DataLink BV
>--
>-- E: [EMAIL PROTECTED]
>-- W: +31 23 5326162
>-- F: +31 23 5322144
>-- M: +31 6 21811143
>--
>-- Stationsplein 82
>-- 2011 LM  HAARLEM
>-- Netherlands
>--
>-- http://www.datalink.nl
>-- 
>
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Re: [PHP-DB] Variables in a loop

2001-10-30 Thread Bruno Gimenes Pereti

try




 
 

and

for ($i=1; $i<=10; $i++) { $tab[$i]=$a[$i] ;}

This way $a will be a array.

Hope it helps
Bruno Gimenes Pereti.

- Original Message -
From: "LeTortorec, Jean-Louis" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, October 29, 2001 7:03 PM
Subject: [PHP-DB] Variables in a loop


> I'm trying to write a loop to read variables I receive from a form:
>
> 
> 
> 
> 
> 
>
>
> I'd like to get something like:
>
> for ($i=1; $i<=10; $i++) { $tab[$i]="a".$i ;}
>
>
> The expression "a".$i is actually a string, not a variable.  Any idea how
to
> "read" the value of that string?
>
> Thanks for your help.
>
> Jean-Louis
>
>
>
>
>


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Re: [PHP-DB] Variables in a loop

2001-10-29 Thread


From: LeTortorec, Jean-Louis <[EMAIL PROTECTED]>
Date: Mon, Oct 29, 2001 at 04:03:45PM -0500
Message-ID: <615315231286D21182E40008C7B1EED23C6E76@COMPAQ3000>
Subject: [PHP-DB] Variables in a loop

> I'm trying to write a loop to read variables I receive from a form:
>  
> 
> 
>  
>  
> 
>  
>  
> I'd like to get something like:
>  
> for ($i=1; $i<=10; $i++) { $tab[$i]="a".$i ;}
>  
>  
> The expression "a".$i is actually a string, not a variable.  Any idea how to
> "read" the value of that string?
>  
> Thanks for your help.
>  
> Jean-Louis





Why don't you just use an array?









-- 

* R&zE:


-- 
-- Renze Munnik
-- DataLink BV
--
-- E: [EMAIL PROTECTED]
-- W: +31 23 5326162
-- F: +31 23 5322144
-- M: +31 6 21811143
--
-- Stationsplein 82
-- 2011 LM  HAARLEM
-- Netherlands
--
-- http://www.datalink.nl
-- 

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RE: [PHP-DB] Variables in a loop

2001-10-29 Thread Rick Emery

Lookup "Variable Variables" in the PHP manual.  You'll use something like:
${$i}

-Original Message-
From: LeTortorec, Jean-Louis [mailto:[EMAIL PROTECTED]]
Sent: Monday, October 29, 2001 3:04 PM
To: '[EMAIL PROTECTED]'
Subject: [PHP-DB] Variables in a loop


I'm trying to write a loop to read variables I receive from a form:
 


 
 

 
 
I'd like to get something like:
 
for ($i=1; $i<=10; $i++) { $tab[$i]="a".$i ;}
 
 
The expression "a".$i is actually a string, not a variable.  Any idea how to
"read" the value of that string?
 
Thanks for your help.
 
Jean-Louis
 
 
 
 


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RE: [PHP-DB] Variables in a loop

2001-10-29 Thread Mark Newnham

http://www.php.net/manual/en/language.variables.variable.php

> -Original Message-
> From: LeTortorec, Jean-Louis [mailto:[EMAIL PROTECTED]]
> Sent: Monday, October 29, 2001 2:04 PM
> To: '[EMAIL PROTECTED]'
> Subject: [PHP-DB] Variables in a loop
> 
> 
> I'm trying to write a loop to read variables I receive from a form:
>  
> 
> 
>  
>  
> 
>  
>  
> I'd like to get something like:
>  
> for ($i=1; $i<=10; $i++) { $tab[$i]="a".$i ;}
>  
>  
> The expression "a".$i is actually a string, not a variable.  
> Any idea how to
> "read" the value of that string?
>  
> Thanks for your help.
>  
> Jean-Louis
>  
>  
>  
>  
> 

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RE: [PHP-DB] Variables in MySQL Insert Queries

2001-08-25 Thread Howard Picken

You've created the query but haven't actually run the query.

i.e.

  $result = mysql_query($sql);

I'm new to this but I think that's what you're problem is.

Howard

-Original Message-
From: plague [mailto:[EMAIL PROTECTED]]
Sent: Friday, 24 August 2001 3:57 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables in MySQL Insert Queries


I am using this code to connect to my database and insert form data from a
user:

$connect = mysql_connect("myhost","user","pass") or die (" not connected");
@mysql_select_db("dbname");
$sql="INSERT INTO tablename
(id,first,last,age,email,sfuser,sfship,icq,ac,loca,ref)
Values(,`$first`,`$last`,'$age',`$email`,`$sfuser`,`$sfship`,`$icq`,`$ac`,`$
loca`,`$ref`)";
echo (mysql_affected_rows()?"success":"failure");
mysql_close($connect);

The script returns "success" except for it doesn't insert the data ( from a
form ).

The age column is BLOB, not INT.

I would really appreciate the help of someone, as this has really stumped
me.

Thanks,

plague



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RE: [PHP-DB] Variables in MySQL Insert Queries

2001-08-24 Thread KSchneider

plague --

unfortunately i don't have the beginnings of this thread, but if your code 
below is verbatim, it looks as though you are missing the mysql_query() 
statement.  that should drop your information.  


kate

> -Original Message-
> From: plague [mailto:[EMAIL PROTECTED]]
> Sent: Friday, August 24, 2001 12:57 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] Variables in MySQL Insert Queries
> 
> 
> I am using this code to connect to my database and insert form data from
> a
> user:
> 
> $connect = mysql_connect("myhost","user","pass") or die (" not
> connected");
> @mysql_select_db("dbname");
> $sql="INSERT INTO tablename
> (id,first,last,age,email,sfuser,sfship,icq,ac,loca,ref)
> Values(,`$first`,`$last`,'$age',`$email`,`$sfuser`,`$sfship`,`$icq`,`$ac`,`$
> loca`,`$ref`)";
> echo (mysql_affected_rows()?"success":"failure");
> mysql_close($connect);
> 
> The script returns "success" except for it doesn't insert the data (
> from a
> form ).
> 
> The age column is BLOB, not INT.
> 
> I would really appreciate the help of someone, as this has really
> stumped
> me.
> 
> Thanks,
> 
> plague
> 
> 
> 

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RE: [PHP-DB] Variables in MySQL Insert Queries

2001-08-24 Thread Rick Emery

If this is an exact copy of your script, then you've surrounded each
variable name in the VALUES(...) with back-ticks.  Why?

-Original Message-
From: plague [mailto:[EMAIL PROTECTED]]
Sent: Friday, August 24, 2001 12:57 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Variables in MySQL Insert Queries


I am using this code to connect to my database and insert form data from a
user:

$connect = mysql_connect("myhost","user","pass") or die (" not connected");
@mysql_select_db("dbname");
$sql="INSERT INTO tablename
(id,first,last,age,email,sfuser,sfship,icq,ac,loca,ref)
Values(,`$first`,`$last`,'$age',`$email`,`$sfuser`,`$sfship`,`$icq`,`$ac`,`$
loca`,`$ref`)";
echo (mysql_affected_rows()?"success":"failure");
mysql_close($connect);

The script returns "success" except for it doesn't insert the data ( from a
form ).

The age column is BLOB, not INT.

I would really appreciate the help of someone, as this has really stumped
me.

Thanks,

plague




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RE: [PHP-DB] variables

2001-08-22 Thread Beau Lebens

if there is a value in $HTTP_POST_VARS["variable_name"] then it came via a
form with method="POST", if there's a value in
$HTTP_GET_VARS["variable_name"] then it came from querystring or a form with
method="GET"

beau

// -Original Message-
// From: J-E-N [mailto:[EMAIL PROTECTED]]
// Sent: Thursday, 23 August 2001 1:24 PM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] variables
// 
// 
// Hello there.
// 
// Is there a way to know whether a variable was passed by a 
// form or just typed from the address bar?
// 

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Re: [PHP-DB] Variables and DB

2001-04-19 Thread Johannes Janson

how about posting the code? or describe
the problem a bit closer.

Johannes

"Rui Machado" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Hello
>
> I'm writting a registration form with connection to
> mysql DB, but I have a problem in the last step, I
> can't access the variables to put them in the DB.
> I'm using the same file to process the form, but the
> last step is confirmation of the data and insertion in
> the DB, here it fails because I can't submit the
> variables.
>
> Any clue?
>
> I was thinking of doing hidden types but I think this
> is not the best way.
>
> Use GLOBALS?
>
> Thanks
>
> Rui Machado
>
> __
> Do You Yahoo!?
> Yahoo! Auctions - buy the things you want at great prices
> http://auctions.yahoo.com/
>
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Re: [PHP-DB] variables

2001-03-29 Thread Phil Jackson

Dunno without looking at code, but try storing the value of $customer into a
local variable when the script is invoked - something is wiping it clean.
my thunks,
Phil J.


Scott Kalbach wrote:

> I am having a problem with losing a variables value. What I am doing is
> taking the value from a database, 'customer_id',  and putting it into a
> hidden form value called 'customer'. When I hit submit on the form it sends
> me to a page where it does several queries to several databases and pulls
> information all based on the value $customer.
>
> I have the individual queries in include files. It does the first 2 queries
> fine,but when it gets to the third, the value of $customer seems to be gone,
> so I get no result for the rest of the query's. I looked in my scripts but
> can't figure out any reason it would lose this value.
>
> Any ideas?
>
> Thanks,
>
> Scott Kalbach
>
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Re: [PHP-DB] variables

2001-03-29 Thread Terry Romine


On Thursday, March 29, 2001, at 04:58 PM, Scott Kalbach wrote:

> I have the individual queries in include files. It does the first 2 
> queries
> fine,but when it gets to the third, the value of $customer seems to be 
> gone,
> so I get no result for the rest of the query's. I looked in my scripts 
> but
> can't figure out any reason it would lose this value.
>
> Any ideas?

I'd check over between the last query that has a valid value of 
$customer and make sure that my code for  is there. I have had a 
number of these to have to track down *grin*

HTH
Terry

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