Set the expire date to be 0. then the browser will delete them after the
browser window is closed.
-Jason Garber
IonZoft.com
At 02:39 PM 10/29/2001 +0100, Andy wrote:
Hello,
I have developed a member login system with cookies. Now I have the prob,
that the session stayes existend when the
There is a command line version of winzip.
I don't know much about it, but a friend of mine was just saying the other
day that he had used it to zip some files at the server in an ASP
environment.
In php you could call the winzip exectutable using exec. In asp you'd use
some shell object or
I have developed a site using PHP and MySQL.
My question:
How do I share the data stored in the database with another site?
Regards,
Matthew
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On Wed, 31 Oct 2001 14:34, Matthew Delmarter wrote:
I have developed a site using PHP and MySQL.
My question:
How do I share the data stored in the database with another site?
Regards,
Matthew
If you mean to let another site access your mysql data directly, you'll
need to set up
If the other site is on the same server, you can use the same method to log
in (same username and password). If it's on a separate computer you need to
either create a new user or change the existing user to have remote access.
To create a user with remote access:
GRANT [privileges] ON
I may be a little backward here but wasn't mysql_db_*() deprecated?
Keep in mind it was a long day at work and I'm tired. I could be on fire
right now and probably just want to open a window to cool off. :)
Mike
Sc [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL
Hi all
Sorry about what is probably a total dickhead about to enter your midst,
but I've never installed php or seen it much at all before but am trying to
do it now.
Using RH 7.1 and Apache 1.3.19
Want to install php4 and mysql combo and totally ignorant.
Installed php rpm.
Restarted
Hi all
Sorry about what is probably a total dickhead about to enter your midst,
but I've never installed php or seen it much at all before but am trying to
do it now.
Using RH 7.1 and Apache 1.3.19
Want to install php4 and mysql combo and totally ignorant.
Installed php rpm.
Restarted
On Wed, 31 Oct 2001 15:40, Mike Frazer wrote:
I may be a little backward here but wasn't mysql_db_*() deprecated?
Keep in mind it was a long day at work and I'm tired. I could be on
fire right now and probably just want to open a window to cool off. :)
Mike
Since 4.06, according to the
PHP is a server-parsed language. You need to add the right directives to
your httpd.conf file in the global config section. They should be something
*like* the following:
AddType application/x-httpd-php .php4 .php3 .phtml .php
AddType application/x-httpd-php-source .phps
You may also need
Hello Warwick,
You're correct in assuming that Apache isn't set up right. It needs to be
set to parse the .php files. Here's how to do this: Locate httpd.conf
(/usr/local/apache/conf/httpd.conf for my compile). And uncomment/add
these lines: AddType application/x-httpd-php .php .php3 AddType
On Wed, 31 Oct 2001 14:52, J W W L (Warwick) Berg wrote:
Hi all
Sorry about what is probably a total dickhead about to enter your
midst, but I've never installed php or seen it much at all before but
am trying to do it now.
Using RH 7.1 and Apache 1.3.19
Want to install php4 and mysql
Hey thanks guys for the help, but it's still not happening. Apache had
already the AddType lines mentioned by y'all.
Any other ideas?
Thanks
Warwick
J W W L Berg wrote:
Hi all
Sorry about what is probably a total dickhead about to enter your midst,
but I've never installed php or
Hey thanks guys for the help, but it's still not happening.
Apache had already the AddType lines mentioned by y'all.
It's possible the AddType lines are inside a container that
will ensure they're not executed. Backtrack to the Block
element that the AddType lines are in, and see what it
Hi Warwick,
Did you look at the install notes that come with PHP? It explains there how
you have to configure Apache to recognize php files and give them to the php
interpreter...checkout the README or INSTALL files that come with PHP...
jack
-Original Message-
From: J W W L (Warwick)
There is no BLOCK element in the httpd.conf. Is that where I should be
looking?
Warwick
Jason Murray wrote:
Hey thanks guys for the help, but it's still not happening.
Apache had already the AddType lines mentioned by y'all.
It's possible the AddType lines are inside a container that
On Wed, 31 Oct 2001 15:15, Jason Murray wrote:
Hey thanks guys for the help, but it's still not happening.
Apache had already the AddType lines mentioned by y'all.
It's possible the AddType lines are inside a container that
will ensure they're not executed. Backtrack to the Block
element
John, Jason didn't literally mean for you to search for the exact string
'Block' - he was telling you to look through the various types of
ThisIsAnApacheDirective tags found in your httpd.conf file, such as
Directory, File etc etc
There is no BLOCK element in the httpd.conf. Is that where I
OK, there goes any pretense of intelligence that I may have been able to
muster ;-)
The AddType tag was found inside another as follows:
IfModule mod_php4.c
Is there some way I can check if this module is present, otherwise what
you're saying is that the AddType isn't being executed if the
On Wed, 31 Oct 2001 15:44, J W W L (Warwick) Berg wrote:
OK, there goes any pretense of intelligence that I may have been able
to muster ;-)
The AddType tag was found inside another as follows:
IfModule mod_php4.c
Is there some way I can check if this module is present, otherwise what
Hey all;
If i have a variable say, $seat and i want to go through variables with a
number, ie. $seat1 , $seat2 etc. how would i go about it? i have one setup
where $p increments (so then you have $seat$p) but i cant get it to work
properly (tried all sorts of combinations with ' and and .
SC
What you want should look something like this: ${seat.$p}
where $p can be incremented in a loop.
However, I was advised to use an array which would look something like this:
$seat[$p]
where $p can also be incremented in a loop.
Hope this helps.
hugh
- Original Message -
From: sc
I don't know if this will work for Oracle but try putting a backslash before
the single quote mark (e.g. it\'s) the ' should then taken as another
character by php.
Hope this works for you.
Hugh
- Original Message -
From: Kevin Dewsnup [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent:
the first one that you gave me works fine... thanks for that..
-sc
Hugh Danaher [EMAIL PROTECTED] wrote in message
000d01c161cf$eb160d20$9106f4d8@win95">news:000d01c161cf$eb160d20$9106f4d8@win95...
SC
What you want should look something like this: ${seat.$p}
where $p can be incremented in
Um! could they be commented out still?
# AddType application/x-httpd-php .php4 .php3 .phtml .php
# AddType application/x-httpd-php-source .phps
Make sure you remove the hash signs whatever they called :)
AddType application/x-httpd-php .php4 .php3 .phtml .php
AddType
On Tue, Oct 30, 2001 at 09:54:19PM -0800, Hugh Danaher wrote:
I don't know if this will work for Oracle but try putting a backslash before
the single quote mark (e.g. it\'s) the ' should then taken as another
character by php.
Hope this works for you.
single quotes are escaped using
I am not sure if this helps , but I followed the instructions on the
following URL for setting up PHP and SQL. It used an older version of
Apache (Apache 1.3.12) and I think the author used something like RedHat
6.
Well, anyways, I followed it and it was okay.
Try taking a look at the
Give ImagePNG a try...
-Jason Garber
At 10:22 PM 10/29/2001 -0800, costa wrote:
The text printed on this image looks sloppy and grainy. (This image is being
generated on a linux server RH 7.1, Apache 1.3.19, with GD 1.8) I remember
seeing something about adjusting the quality of the image, but
Hi,
I have installed PHPMyAdmin-2.2.0 on my webserver in a directory of one my
virtual hosts. My machine is running Apache 1.3.12 and BIND DNS server.
I have MySQL installed already and I have already tested successfully
using the text commands.
My Apache configuration has virtual host
Hi!
I have to create array of classes.
When I do it this way:
f add($sth)
$this-array[] = $sth;
it doesn't work :( when i'm trying to get class from there it says that this is not an
object.
How to do it rigth way?
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