Hello everyone..tryin to run this qry against a mysql db, but after it runs,
it doesn't assign anything to the variables as it should. If i return all
rows, and spit out each record in the result in an array, i have the same
problem, but have 24 'blank' records instead of 1. Any ideas? Thanks
After logging in successfully, i start an infinite loop between index.php
and login.php, what's up? Please help.
?
// index.php - secure page
session_start();
if (!isset($PHP_AUTH_USER))
{
// If empty, send header causing dialog box to appear
;);
// exit();
// }
// else
// {
// $status = 0;
// header(Location:
http://dev.e-dbapps.com/customscripts/error.php?e=$status;);
// exit();
// }
// }
//?
-Patrick
Is it possible to user the target=_top reference when using a
header(Location = ...)?
If so, anyone have an example.
Thanks
-patrick
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PHP
IT Manager
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PaginiWeb.com - Professional Web Design
www.PaginiWeb.com
Patrick Hartnett [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Is it possible to user the target=_top reference when using a
header(Location = ...)?
If so
Not sure about the multiple connections side, but to kill a connection:
mysql_close($link);
where $link is your connection variable/string
hope this helps.
-Patrick
From: James Taylor [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Subject: [PHP] Connecting to
here is a function used to authenticate users against mysql database.
Problem is, I am not connecting for some reason. I have the db variables:
$db_host
$db_user
$db_pass
$db_name
They are populated from an include (x.php) in the beginning of the php
section. It is getting past the connect
Thanks for all the help so far, great to have others out there helping.
Only way it will let me connect is to explicitly use the connection
information in the connect statement and the select_db statements, can't
pass in the variables.
This seems a little on the insecure side, and a pain. Is
Are case statements not implemented in PHP4?
If so, can someone help me debug this one, I seem to have some syntax
incorrect, and am not sure what exactly is wrong with the statement. I get
a parse error on the first line, but can't find any documentation on case
statements in PHP4, so I am
try this, it sees if there is a result, and you can then proceed to do what
you need to do.
if (mysql_num_rows($result) == 1) //match found
{
//do something here;
}
// no match found
else
{
//do something here;
use it after your query to see if there is a result set. Like follows:
$result = mysql_query($query) or die (Error in query: . mysql_error());
// if row exists - user/pass combination is correct
if (mysql_num_rows($result) == 1)
{
return 1;
}
Trying to build a database which uses the webpage name as one of the
selection criteria. (building page specific menus). How do I get the
current file name? Can't seem to find any help on this.
-Patrick
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MSN Photos is the
It seems I spoke to quick...here is how to get the current file name.
$this_file = $_SERVER['REQUEST_URI'];
echo( $this_file );
the result is formatted as follows:
/applications.php
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