Dear List -
Here is a code snippet:
$bla = array(g1 = $results[7][6],
h1 = $results[7][7]);
print_r($bla);
$value = h1;
$locate1 = array_search($value, $bla);
echo This is locate ; print_r($locate1);
if(in_array($value, $bla)) print_r($bla);
direction.
Alice
From: rene7...@gmail.com
Date: Thu, 11 Mar 2010 07:12:15 +0100
Subject: Re: [PHP] Array Search Problem
To: aj...@alumni.iu.edu
CC: php-general@lists.php.net
(almost) all the tricks are in the comments of the help page for a
function, on php.net
but all functions accept
Hi,
I have the code as shown in the following that I am trying to create the
image of based on the file loaded into the file and additional edits. The
problem here appears to be that no matter what value I have in the
$distance_to_destination variable, it does not affect any changes on the
Hi,
I have two arrays here that I have combined into a new array, as shown here:
$from = explode(-, $from);
$change = explode(-,$change);
$new_array = array_combine($from,$change);
I then tried reading it from a file and do string matches, trying to find out
the key using the array_search
did you read the help for those functions on php.net?
On Wed, Mar 10, 2010 at 4:12 PM, Alice Wei aj...@alumni.iu.edu wrote:
Hi,
I have the code as shown in the following that I am trying to create the
image of based on the file loaded into the file and additional edits. The
problem here
did you read the help for those functions on php.net?
Yes, I found a recursive way to find out the index like I wanted, by doing
something like
$from = explode(-, $from);
$state_colors= explode(-, $state_colors);
$change = explode(-,$change);
$count = count($new_array);
$i=0;
foreach
(almost) all the tricks are in the comments of the help page for a
function, on php.net
but all functions accept only a given (and usually documented) set of
parameter(type)s, so you'll probably have to prepare the var, or even
call the function in a loop, outputting to yet another descriptively
Hello All,
I've been trying for days now to make this work.
I'm trying to search my array for a value and return the key.
I get the visitor's IP and try this -- this is the latest,
I've tried a few functions to echo the name associated with the viz_ip.
$viz_ip= $_SERVER['REMOTE_ADDR'];
Malcolm wrote:
Hello All,
I've been trying for days now to make this work.
I'm trying to search my array for a value and return the key.
I get the visitor's IP and try this -- this is the latest,
I've tried a few functions to echo the name associated with the viz_ip.
$viz_ip=
I've been trying for days now to make this work.
This worked for me (with my IP address for 'John'):
?php
$viz_ip= $_SERVER['REMOTE_ADDR'];
echo (Your IP is $viz_ip);
$byte_ip= array(
204.126.202.56=Mark,
63.230.76.166=Bob,
84.196.101.86=John,
);
function _array_search
Thank you Sirs,
I was echoing the viz-ip so I know it was getting set but
I couldn't get it.
both work .. I got the clue from John, the last echo line did the
trick.
On Sun, 23 Jan 2005 17:26:58 +0100, Jochem Maas [EMAIL PROTECTED]
wrote:
Malcolm wrote:
Hello All,
I've been trying
probably missing something but php have a function called array_search.
Ben
On Sun, 23 Jan 2005 11:33:16 -0500 (EST), [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
I've been trying for days now to make this work.
This worked for me (with my IP address for 'John'):
?php
$viz_ip=
I've a 2 D array and would like to search for vals. in the first dimension
only i.e.
myArray[0][0]
myArray[1][0]
myArray[2][0]
myArray[3][0]
.
.
.
and not in the elements myArray[0][1]
CODE:
for($l = 0; $l count($layer); $l++) {
$key = array_search($layer[$l], $layerDes); // $layerDes
Oops! Sorry I got a reply for this but didn't read my mail carefully
enough. Thanks to Tim Ward for pointing out the problem.
I've a 2 D array and would like to search for vals. in the first dimension
only i.e.
myArray[0][0]
myArray[1][0]
myArray[2][0]
myArray[3][0]
.
.
.
and not in the
I have an array of names, like below...
$people = array(Jim,John,JP);
Is there a way in an IF statement to see if someone's name is in the array?
Like...
if ($people =~ $person) { }
I don't want to have to create a foreach loop to go through the array to see
if that person is there.
Joseph
PROTECTED]
Sent: Friday, August 31, 2001 6:40 PM
Subject: [PHP] array search
I have an array of names, like below...
$people = array(Jim,John,JP);
Is there a way in an IF statement to see if someone's name is in the array?
Like...
if ($people =~ $person) { }
I don't want to have
HristovIcyGEN Corporationhttp://www.icygen.comBALANCED SOLUTIONS
- Original Message -
From: Joseph Bannon [EMAIL PROTECTED]
To: PHP (E-mail) [EMAIL PROTECTED]
Sent: Friday, August 31, 2001 6:40 PM
Subject: [PHP] array search
I have an array of names, like below...
$people = array(Jim
a btree or
some other type of search methodology.
Johan
-Original Message-
From: Papp Gyozo [mailto:[EMAIL PROTECTED]]
Sent: Friday, August 31, 2001 10:02 AM
To: Joseph Bannon; PHP (E-mail)
Subject: Re: [PHP] array search
yes, in_array($person, $people)!
however, you may take a look
What about going the other way? Say I have a sentence...
Hi, my name is Bob.
...and I want to search the sentence for one of the values (people) in the
array...
$people = array(Jim,John,JP,Bob);
Can this be done?
Thanks,
Joseph
-Original Message-
yes, in_array($person,
try this :
$people = array ('philip','sasheen','jim');
$string = 'Hi, my name is philip, I miss Sasheen';
foreach ($people as $person) {
if (stristr($string,$person)) {
$matches[] = $person;
}
}
// results live in $matches now.
print_r($matches);
stristr is
btw, you may want to search for a name surrounded by spaces as philip vs
philips, jim vs jimmy, etc. probably other considerations as well, or
maybe not :)
philip
On Fri, 31 Aug 2001, Philip Olson wrote:
try this :
$people = array ('philip','sasheen','jim');
$string = 'Hi, my name
On Vie 31 Ago 2001 17:49, you wrote:
What about going the other way? Say I have a sentence...
Hi, my name is Bob.
...and I want to search the sentence for one of the values (people) in the
array...
$people = array(Jim,John,JP,Bob);
Can this be done?
Yes, split the sentence into parts
yes, in_array($person, $people)!
however, you may take a look into the manual.
- Original Message -
From: Joseph Bannon [EMAIL PROTECTED]
To: PHP (E-mail) [EMAIL PROTECTED]
Sent: Friday, August 31, 2001 5:40 PM
Subject: [PHP] array search
I have an array of names, like below
23 matches
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