I am not sure if this is the right place to ask this naive question.
I got a simple form addform.html and add.php look like the following.
But everytime I got empty value from firstname and lastname. It seems like
the input value in the html page was not passed on to the php variable $firstname
On Saturday, June 1, 2002 at 4:51:20 PM, you wrote:
I got a simple form addform.html and add.php look like the following.
But everytime I got empty value from firstname and lastname. It seems like
the input value in the html page was not passed on to the php variable
$firstname in add.php.
Do you mind telling me where this php.ini is?
And I tried the second attempt like this:
$query = INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'), $_POST['firstname'], $_POST['surname']);
which returns error:
Parse error: parse error, unexpected
Some thoughts:
a) Why is $firstname empty?
It's empty because the PHP directive register_globals = off.
So, PHP will not create $firstname automatically. This is
most likely the cause.
b) How do I access $firstname with register_globals = off then?
Many ways. Regardless of
$query = INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'),
$_POST['firstname'], $_POST['surname']);
which returns error:
Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING
or
T_VARIABLE or T_NUM_STRING in
On Saturday, June 1, 2002 at 5:00:18 PM, you wrote:
Do you mind telling me where this php.ini is?
Create a php script containing just ?php phpinfo(); ?. That page will tell
you where your php.ini is (or should be).
And I tried the second attempt like this:
$query = INSERT INTO friends (id,
Create a php script containing just ?php phpinfo(); ?. That page will tell
you where your php.ini is (or should be).
it told me it's in php/lib, but it's not there.
Try this...
$query = INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'),
Sorry. When I input Andras as firstname in the form, ...
On Sat, 1 Jun 2002 17:22:02 +0100
[EMAIL PROTECTED] (Wei Wang) wrote:
Create a php script containing just ?php phpinfo(); ?. That page will tell
you where your php.ini is (or should be).
it told me it's in php/lib, but it's
On Saturday, June 1, 2002 at 5:22:02 PM, you wrote:
Create a php script containing just ?php phpinfo(); ?. That page will tell
you where your php.ini is (or should be).
it told me it's in php/lib, but it's not there.
The default php.ini is called php.ini-recommended and will be in the
Is there anything I should do to make the php.ini come into effect? I did
put the register_global = On but still got empty values.
And my $_POST version is like this:
?php
$db = pg_connect(dbname=friends);
$query = INSERT INTO friends (id, firstname, surname) values
Sorry.
I restared apache and php.ini came into effect.
On Sat, 1 Jun 2002 17:29:13 +0100
[EMAIL PROTECTED] (Stuart Dallas) wrote:
On Saturday, June 1, 2002 at 5:22:02 PM, you wrote:
Create a php script containing just ?php phpinfo(); ?. That page will tell
you where your php.ini is (or
On Saturday, June 1, 2002 at 5:35:03 PM, you wrote:
Is there anything I should do to make the php.ini come into effect? I did
put the register_global = On but still got empty values.
you may not need to do anything or you may need to restart your http server.
Have a look at your phpinfo()
On Saturday, June 1, 2002 at 5:37:37 PM, you wrote:
Sorry.
I restared apache and php.ini came into effect.
If you're going to run with register_globals on you should make sure you
understand the implications:
http://www.php.net/manual/en/security.registerglobals.php.
--
Stuart
--
PHP
Changed the query and get this error when input dave as firstname:
ERRORERROR: Attribute 'dave' not found
add2.php is:
html
body
?php
$db = pg_connect(dbname=friends);
$query = INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'), .$_POST['firstname'].,
On Saturday, June 1, 2002 at 6:00:22 PM, you wrote:
$query = INSERT INTO friends (id, firstname, surname) values
(nextval('friends_id_seq'), .$_POST['firstname']., .$_POST['surname'].);
It's so obvious you're gonna kick yourself (I did!). You need to enclose the
two values in quotes, like
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