RE: [PHP] creating a mailing list
chris o'shea mailto:[EMAIL PROTECTED] on Thursday, April 29, 2004 2:44 AM said: Does anybody know the best way of doing a mass mail through php? i recall a solution being to write a properly formatted email and dump it into server's outgoing queue allowing the MTA (sendmail, exim, postfix*) to distribute the emails as it sees fit. hth, chris. * i think these are all MTA's. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: $_SERVER['SERVER_NAME'] in read-only.
AFAIK the content of the superglobal variables cannot be changed ( even
though i haven't found this in the docs i can remeber got beaten by PHP
for doing so :-) )
Back to the problem ( if existent ):
If you don't do stuff like '$_SERVER['SERVER_NAME'] = ;' inside your
script you won't run into trouble - I know some ppl like to use such
strange work-arounds ;-)
Otherwise using
define ( 'SERVER_NAME' , $_SERVER['SERVER_NAME'] );
right at startup will usually solve your problem ( as workarounds will
most likely kill other scripts if the SERVER_NAME is diffrent :-))
-- red
[...]
Hello,
I am using the variable $_SERVER['SERVER_NAME'] inside a function, for
example:
function check_servname() {
global $server ;
if($_SERVER['SERVER_NAME'] != $server) {
echo NOT OK, NOT GOOD SERVER NAME ;
exit ;
}
}
But we can modify the value of $_SERVER['SERVER_NAME'] before calling
the function check_servname(). And I am looking for a the right server
name not for a server name which may have been changed before calling
check_servername:
$_SERVER['SERVER_NAME'] = www.google.com ; //before calling
check_servname and $_SERVER['SERVER_NAME'] will be www.google.com
inside the function even the server name is not www.google.com.
Is there any way to get the server name with a variable which would be
read-only ?
Thanks,
Vincent.
Agreed - constants are the way to do this. I wanted to mention that the
$_SERVER variables are meant to hold values generated by your server. Of
course if you really ARE google then I'm going to feel stupid for even
mentioning this :)
http://www.php.net/reserved.variables
[...]
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Re: [PHP] variable-length arguments passed by reference... how?
Marek Kilimajer wrote: But workaround would be to call your function with array(): Thanks, I was afraid that might be the only way. I guess its possible if you write an extension (like mysqli) in C? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: global vars inside includes inside functions?
Hi,
Friday, April 30, 2004, 1:29:12 AM, you wrote:
RW [...]
?
function safeInclude($file) {
RW [...]
RW foreach ( $GLOBALS AS $k = $v ) {
RW $$k = $v ;
RW }
RW [...]
if(file_exists($file)) {
include($file);
} else {
debug(file $file not found);
}
}
?
RW [...]
RW (better, as no eval-syntax is required)
RW-- red
That makes local copies only, still no access to the global variable
The other thing to consider is that everything dies at the conclusion of
the function. It may be better to do this via a class construct
--
regards,
Tom
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Re: [PHP] Re: global vars inside includes inside functions?
Again ain't no problem anyway
foreach ( $GLOBALS AS $k = $v ) {
$$k = $GLOBALS[$k] ;
}
zap you are done ... again when using a function to include
a file with relying on depts within the file you would most
probably use a registry-pattern or similar to access the required
variables.
-- red
That makes local copies only, still no access to the global variable
The other thing to consider is that everything dies at the conclusion of
the function. It may be better to do this via a class construct
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Re: [PHP] Using HTTP_REFERRER to ensure forms posted from server
--- Terence [EMAIL PROTECTED] wrote: To avoid malicious users creating their own forms and posting to my site, is it advisable to use the $_SERVER['HTTP_REFERRER'] to ensure that posted forms only come from the intended source? Anyone out there using this? Hopefully not. :-) Referer is just as easy to spoof as the form data you're expecting. What you're wanting to do is prevent spoofed form submissions, and New York PHP has a nice resource that I encourage you to read: http://phundamentals.nyphp.org/PH_spoofed_submission.php Hope that helps. Chris = Chris Shiflett - http://shiflett.org/ PHP Security - O'Reilly Coming Fall 2004 HTTP Developer's Handbook - Sams http://httphandbook.org/ PHP Community Site http://phpcommunity.org/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable-length arguments passed by reference... how?
Hi,
Friday, April 30, 2004, 1:40:26 AM, you wrote:
AC I want to create a function similar to the MySqli extensions'
AC mysqli_stmt_bind_param() function. I assume that this function takes
AC its arguments passed by reference. Now, I know how to do variable
AC length argument lists in a function with func_get_arg(s) but how do I
AC tell it that they are to be passed by reference?
Just make them all references, if it was expecting a copy it will just
get a reference to a copy, if it was expecting a reference it will get
one. I do a similar trick in a class loader I use that copes with
variable length argument lists and passing by reference.
A bit like this
$num_args = func_num_args();
$arg_list = func_get_args();
$vars = 'function_to_call(';
for ($i = 0; $i $num_args; $i++) {
$vars .= ($i 0)? ',':'';
$varname = 'variable'.$i;
$$varname = $arg_list[$i];
$vars .= \$$varname;
}
$vars .= ');';
//that leaves you with a string you can use eval on
eval($vars);
--
regards,
Tom
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Re: [PHP] Re: $_SERVER['SERVER_NAME'] in read-only.
From: Red Wingate [EMAIL PROTECTED] AFAIK the content of the superglobal variables cannot be changed ( even though i haven't found this in the docs i can remeber got beaten by PHP for doing so :-) ) They can be changed and you can even add to them. $_SERVER['foo'] = 'bar'; is valid and now it's a superglobal, too. I wouldn't recommend relying on this, though. If you talking about the users changing the values of of superglobals then that's different. Users can't directly set $_SERVER values, for example, but they can pass values that may influence them. $_SERVER['HTTP_REFERRER'] comes from what the user supplies, for instance, so they are able to manipulate it. A user would not be able to set $_SERVER['SERVER_NAME'] or $_SERVER['PHP_SELF'], though. Which ones are safe or not just takes some research or asking. :) ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Listing all id's in array
Alex Hogan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I have asked a lot of questions in the last few weeks, but I do try to
preface those questions by checking out the php.net online manual first.
Anyway, here is one way to do it. There are probably more elegant
solutions, but I don't know off hand what they are.
$model = array();
$query = SELECT product_id
FROM products;
$result = mysql_query($query) or die(error in query);
$i = 0;
while($row = mysql_fetch_array($result)){
$model[$i] = $row['product_id'];
$i++;
}
I think $i is not needed here. If you add it to the array with $model[] =
... PHP will automatically use and increment an integer for the key.
Regards, Torsten
print_r($model);
alex hogan
-Original Message-
From: Phpu [mailto:[EMAIL PROTECTED]
Sent: Wednesday, April 28, 2004 3:01 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Listing all id's in array
I want to list all the product id's af the database in an array, but i
do
not how.
I have this script but it is not working:
$model = array();
$query = SELECT product_id FROM products;
$result = mysql_query($query) or die(error in query - $query -
.mysql_error());
while (list($product_id) = mysql_fetch_array($result)) {
$model = $product_id;
}
echo $model;
Plese someone tell me how to do it...
Thanks
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Re: [PHP] variable-length arguments passed by reference... how?
A bit like this
$num_args = func_num_args();
$arg_list = func_get_args();
$vars = 'function_to_call(';
for ($i = 0; $i $num_args; $i++) {
$vars .= ($i 0)? ',':'';
$varname = 'variable'.$i;
$$varname = $arg_list[$i];
$vars .= \$$varname;
}
$vars .= ');';
//that leaves you with a string you can use eval on
eval($vars);
I know I'm probably paranoid, but eval() always bugs me. I think for
what you want to do you can use call_user_func_array()
$args = func_get_args();
call_user_func_array('function_to_call', $args);
http://www.php.net/manual/en/function.call-user-func-array.php
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[PHP] Re: Single quotes inside double quoted string (Was: Re: [PHP] Re: Problem with a class... any help will be appreciated.)
Elliot J. Balanza [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Actually you are right the problem is not in the proccess of writing to
the
database, the problem is that after writing to the database it wont jump
to the next function it wont go to login() or any other function for this
matter.
If $this-login() is not called then this line does not evaluate to true:
if(md5($pass)==$row_revisa['Password']) {
Have you printed out both values to see if they are equal?
Regards, Torsten
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[PHP] how to verify PHP has been installed with ldap?
Greetings,
I've installed PHP with ldap. But I got this error Fatal error: Call to
undefined function: ldap_connect() in /home/me/public_html/test1.php on
line 5. Why ldap_connect() is undefined?
This is what I did:
==
# ./configure --with-apxs=/usr/local/apache/bin/apxs
--with-config-file-path=/usr/local/apache/php.ini --with-mysql --with-zlib
--with-ldap
# make
# make install
==
It went through without obvious errors.
And this is the PHP script test1.php that generates the above error:
?php
$dn=cn=john smith, ou=Users, ou=eng,dc=iastate, dc=edu;
$password = ok4now;
if (!($ldap = ldap_connect(w2kdc1.eng.some.edu, 389))) {
die (Could not connect to LDAP server);
}
if (!($res = @ldap_bind($ldap, $dn, $password))) {
die (Could not bind to $dn);
}
echo bind fine!;
?
So my question is how to verify PHP has been installed with ldap support?
Thanks in advance for any help,
Bing
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php-general Digest 29 Apr 2004 20:35:55 -0000 Issue 2734
php-general Digest 29 Apr 2004 20:35:55 - Issue 2734
Topics (messages 184930 through 184970):
Re: global vars inside includes inside functions?
184930 by: De Greef Sébastien
184953 by: Red Wingate
184962 by: Tom Rogers
184963 by: Red Wingate
web page existance check
184931 by: Decapode Azur
184932 by: Vinod Panicker
creating a mailing list
184933 by: chris o'shea
184935 by: Vinod Panicker
184936 by: Chris Hayes
184959 by: Chris W. Parker
Re: Problem with a class... any help will be appreciated.
184934 by: Marius Dascalu
Single quotes inside double quoted string (Was: Re: [PHP] Re: Problem with a class...
any help will be appreciated.)
184937 by: John W. Holmes
184942 by: Elliot J. Balanza
184969 by: Torsten Roehr
Changing passwords
184938 by: Jason Barnett
184948 by: Jason Sheets
$_SERVER['SERVER_NAME'] in read-only.
184939 by: Vincent M.
184940 by: Jay Blanchard
184941 by: Jason Barnett
184960 by: Red Wingate
184966 by: John W. Holmes
Re: Nonsense mail
184943 by: Elliot J. Balanza
184952 by: trlists.clayst.com
__toString or not __toString
184944 by: Thomas Björk
184945 by: Thomas Björk
184946 by: Thomas Björk
Re: GD support
184947 by: Marek Kilimajer
184950 by: Anton Krall
Re: php code in a .js file?
184949 by: Craig Donnelly
Re: Fetching XML for parsing
184951 by: Pablo
variable-length arguments passed by reference... how?
184954 by: Aric Caley
184955 by: Aric Caley
184956 by: Marek Kilimajer
184957 by: Jay Blanchard
184958 by: Marek Kilimajer
184961 by: Aric Caley
184965 by: Tom Rogers
184968 by: Jason Barnett
Re: Using HTTP_REFERRER to ensure forms posted from server
184964 by: Chris Shiflett
Re: Listing all id's in array
184967 by: Torsten Roehr
how to verify PHP has been installed with ldap?
184970 by: Bing Du
Administrivia:
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--
---BeginMessage---
normally you just put
global $something;
at the begining of your function..
Like this
function safeInclude($file) {
global $something;
if(file_exists($file)) { include($file);
} else {
debug(file $file not found);
}
}
Justin French [EMAIL PROTECTED] a écrit dans le message news:
[EMAIL PROTECTED]
Can someone see a way to achieve what I want?
I have the following function:
?
function safeInclude($file) {
if(file_exists($file)) {
include($file);
} else {
debug(file $file not found);
}
}
?
When used in this context...
?
$something = 'foo';
safeInclude('somethingElse.inc');
?
... somethingElse.inc cannot see the global variable $something.
So, if an include is wrapped in a function, it would appear that the
global variables no longer apply to the namespace of the included file.
Is there anyway I can get around this?
My only guess is I could add the line global $GLOBALS; to
safeInclude(), but I have no idea how this affects memory usage or
anything else.
---
Justin French
http://indent.com.au
---End Message---
---BeginMessage---
[...]
?
function safeInclude($file) {
[...]
foreach ( $GLOBALS AS $k = $v ) {
$$k = $v ;
}
[...]
if(file_exists($file)) {
include($file);
} else {
debug(file $file not found);
}
}
?
[...]
(better, as no eval-syntax is required)
-- red
---End Message---
---BeginMessage---
Hi,
Friday, April 30, 2004, 1:29:12 AM, you wrote:
RW [...]
?
function safeInclude($file) {
RW [...]
RW foreach ( $GLOBALS AS $k = $v ) {
RW $$k = $v ;
RW }
RW [...]
if(file_exists($file)) {
include($file);
} else {
debug(file $file not found);
}
}
?
RW [...]
RW (better, as no eval-syntax is required)
RW-- red
That makes local copies only, still no access to the global variable
The other thing to consider is that everything dies at the conclusion of
the function. It may be better to do this via a class construct
--
regards,
Tom
---End Message---
---BeginMessage---
Again ain't no problem anyway
foreach ( $GLOBALS AS $k = $v ) {
$$k = $GLOBALS[$k] ;
}
zap you are done ... again when using a function to include
a file with relying on depts within the file you would most
probably use a registry-pattern or similar to access the required
variables.
-- red
That makes local copies only, still no access to the global variable
The other thing to consider is that everything dies at the conclusion of
the function. It may be better to do this via a class construct
---End Message---
---BeginMessage---
Hello,
[PHP] Re: how to verify PHP has been installed with ldap?
So my question is how to verify PHP has been installed with ldap support?
Thanks in advance for any help,
Bing
?php phpinfo() ?
or, more specifically:
?php
$loaded = extension_loaded('ldap');
echo 'The ldap extension is ' . $loaded ? 'loaded' : 'not loaded';
?
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[PHP] Midgard anyone?
Has anyone dabbled long enough to figure out Midgard? I've been meaning to evaluate the Framework and CMS for a long time and I think I have the time now to do it. Nevertheless, I would like to get a heads up on it before jumping in. Any comparisons to other CMSs/Frameworks? Thanks in advance, -- Adrian Madrid http://www.hyperxmedia.com HyperX Media 45 West 9000 South, Unit 2 Sandy, UT 84020 Office: 801.566.0670 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] how to verify PHP has been installed with ldap?
From: Bing Du [EMAIL PROTECTED] So my question is how to verify PHP has been installed with ldap support? ?php phpinfo(); ? And see if there is an ldap section. ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php code in a .js file?
Craig Donnelly wrote: Why not just use a .php instead of a .js? script language=Javascript src=jsscript.php/script Regards, Craig That was what I meant ;) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] how to verify PHP has been installed with ldap?
I don't see a ldap section in the output of phpinfo(). I need to add a bit more background information here... This is not a fresh php install. I've already installed PHP Version 4.3.4. But now I want to add ldap support to it. So I added --with-ldap option in the configure command. Then I did make and make install. However, phpinfo() still shows the old information. For instance, Build Date was Mar 3 2004 11:15:34, Configure Command was the one without --with-ldap, etc.. I removed config.cache before doing configure/make/make install and also restarted the apache server, but nothing helped. Do I need to do anything on the apache server? What did I do wrong? Bing From: Bing Du [EMAIL PROTECTED] So my question is how to verify PHP has been installed with ldap support? ?php phpinfo(); ? And see if there is an ldap section. ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Help please.
JUST FOR ALL OF YOU OUTTHERE TO KNOW... the problem was that site had Frontpage 2002 extensions installed. Incredibly enough, that was sufficient not to accept the files. Thanks again to all that answered. Vamp Jason Sheets [EMAIL PROTECTED] escribió en el mensaje news:[EMAIL PROTECTED] Check the filesystem permissions of the destination folder to make sure the web server user has write access to it. What does line 20 of d:\inetpub\sites\www.kamasutra.com.mx\web\mbt\includes\photographs.php attempt to do. With NTFS filesystems you must always remember to set the filesystem permissions (just like you have to in Unix). Jason -Original Message- From: Elliot J. Balanza [mailto:[EMAIL PROTECTED] Sent: Wednesday, April 28, 2004 8:03 PM To: [EMAIL PROTECTED] Subject: [PHP] Help please. Hi, I'm running the same class in two different sites on the same sever (apparently under the exact same conditions) yet one server sends me an error Warning: copy(d:/inetpub/sites/www.kamasutra.com.mx/web/fotos/bobl-39409.jpg): failed to open stream: Permission denied in d:\inetpub\sites\www.kamasutra.com.mx\web\mbt\includes\photographs.php on line 20 whenever I try to upload an image while the second one does loads it. This is driving me crazy, any ideas? Help will be appreciated. Vamp -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Single quotes inside double quoted string (Was: Re: [PHP] Re: Problem with a class... any help will be appreciated.)
Yes actually the same proccess in the first script works.
If i remove the $this-login(); instruction and write the instruction within
the if works also... the only thing not working is the $this-login().
Torsten Roehr [EMAIL PROTECTED] escribió en el mensaje
news:[EMAIL PROTECTED]
Elliot J. Balanza [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Actually you are right the problem is not in the proccess of writing to
the
database, the problem is that after writing to the database it wont
jump
to the next function it wont go to login() or any other function for
this
matter.
If $this-login() is not called then this line does not evaluate to true:
if(md5($pass)==$row_revisa['Password']) {
Have you printed out both values to see if they are equal?
Regards, Torsten
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[PHP] Re: call_user_func possible bug in PHP5Rc1 PHP5RC2, am I crazy?
Curt, Ben, Thank you for your thoughts. Actually, [EMAIL PROTECTED] addressed this via bugs at http://bugs.php.net/bug.php?id=28189 . [27 Apr 11:47pm CEST] [EMAIL PROTECTED] The behavior that's new in PHP 5 isn't the inability to call a method by call name instead of instance. It's that if you do so, PHP treats it as a static method call. When a static method is invoked in PHP 5, you cannot reference $this because it no longer exists and was never meaningful in the first place. In light of this statement and further testing in PHP4, I'm not sure if an object was being instantiated or not. It certainly didn't pipe up with an error. However, my intention was to call call_user_func with the assumption that it would instantiate the class with the default constructor and any default arguments defined in the method signature of the constructor (in my example, none) and call an the specified instance method because ... wait for it ... it was defined as an instance method not a static method. What was tripping me up was that neither the PHP4 manual description of this function nor Zeev's 3rd Edition of Core PHP5 indicate that any method of a class would be called statically even if it was not defined in the class as static. Basically, the change in behavior between PHP4 and PHP5 was very surprising to me. IMHO, I believe that such behavior is fundamentally disconnected from the perpetrated behavior of accepted practices. ie, if I wanted a method to be called statically, I would have defined it statically. ie, if the method signature of an object defines it as an instance method, I kind of expect it to ONLY ever be called or callabe as an instance method. Ben Ramsey wrote: snip I would suggest that you read up on object-oriented programming and learn a little more about how things work. You really need to do: $test = new test_call_user_func(); to create the object. Then you can use $test to access the methods of that object. Actually, the intention was to allow some tightly coupled delegation via SOAP. I know, tight coupling is asking for it on long term maintainence but I really didn't have a say in some of the architecture. I haven't found an equivalent of Java's Class.forName(String Name_of_class_to_be_instantiated), so I thought call_user_func would suffice, instantiate a default version of my object, etc etc ... Anyone else, back me up on this if I'm wrong. I think that you and Curt are indeed correct about being able to use a $this only in an instance. My issue is that I have not yet found anywhere were this change of behavior in PHP5 that [EMAIL PROTECTED] describes is documented. If someone could point me to where we all could help with the documentation, that'd be great. V -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re[2]: [PHP] variable-length arguments passed by reference... how?
Hi,
Friday, April 30, 2004, 3:51:19 AM, you wrote:
JB I know I'm probably paranoid, but eval() always bugs me. I think for
JB what you want to do you can use call_user_func_array()
JB $args = func_get_args();
JB call_user_func_array('function_to_call', $args);
JB http://www.php.net/manual/en/function.call-user-func-array.php
The only time eval can be a problem is if you use it on client
supplied data otherwise it is no worse than any other function.
How does call_user_func_array() cope with pass by reference ? which is
the op problem.
--
regards,
Tom
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Re: [PHP] Change Permissions in Windows
Stephen Craton wrote: I don't have a security tab, I don't know why, but it isn't there... http://www.melchior.us/tabs.gif Hi Stephen and List, I don't have an XP Pro at hand now. So, I will tell you how to activate the security tab with no exact instructions. Not having the security tab is the default for XP Pro (Perhaps MS thinks Security is not important). To see (and use) it, follow this way: 1. Open any folder, select tools, tools of folder. 2. Go to the Folder View options (Or something like that). 3. There is a box with Advanced Options, there must be one about Advanced Rigths (Or something similar) ... 4. This option MUST be checked and you will see the security options on any file. Hope this helps, if not, tell me and I will check on an XP Pro when having one near. Regards, Jordi. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] variable-length arguments passed by reference... how?
* Thus wrote Tom Rogers ([EMAIL PROTECTED]):
Hi,
Friday, April 30, 2004, 3:51:19 AM, you wrote:
JB I know I'm probably paranoid, but eval() always bugs me. I think for
JB what you want to do you can use call_user_func_array()
JB $args = func_get_args();
JB call_user_func_array('function_to_call', $args);
JB http://www.php.net/manual/en/function.call-user-func-array.php
The only time eval can be a problem is if you use it on client
supplied data otherwise it is no worse than any other function.
It is *very* expensive to use eval, expecially when this has been
said:
If eval() is the answer, you're almost certainly asking the
wrong question. -- Rasmus Lerdorf, BDFL of PHP
Here are a couple alternatives:
function argbyref($args) {
$args['arg'] = 'changed';
}
$args['arg'] = 'not changed';
argbyref($args);
function argwitharray($args) {
$args['arg'] = 'changed';
}
$arg = 'not changed';
argwitharray(array('arg' = $arg));
Curt
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[PHP] Re: call_user_func possible bug in PHP5Rc1 PHP5RC2, am I crazy?
In light of this statement and further testing in PHP4, I'm not sure if
an object was being instantiated or not. It certainly didn't pipe up
with an error.
Unfortunately, no (http://www.php.net/call_user_func):
Object methods may also be invoked statically using this function by
passing array($objectname, $methodname) to the function parameter.
However, my intention was to call call_user_func with the assumption
that it would instantiate the class with the default constructor and any
default arguments defined in the method signature of the constructor (in
You can do something like this with the Reflection API.
my example, none) and call an the specified instance method because ...
wait for it ... it was defined as an instance method not a static method.
What was tripping me up was that neither the PHP4 manual description of
this function nor Zeev's 3rd Edition of Core PHP5 indicate that any
method of a class would be called statically even if it was not defined
in the class as static. Basically, the change in behavior between PHP4
and PHP5 was very surprising to me.
IMHO, I believe that such behavior is fundamentally disconnected from
the perpetrated behavior of accepted practices.
ie, if I wanted a method to be called statically, I would have defined
it statically.
ie, if the method signature of an object defines it as an instance
method, I kind of expect it to ONLY ever be called or callabe as an
instance method.
Ben Ramsey wrote:
snip
I would suggest that you read up on object-oriented programming and
learn a little more about how things work.
You really need to do:
$test = new test_call_user_func();
to create the object. Then you can use $test to access the methods of
that object.
Actually, the intention was to allow some tightly coupled delegation via
SOAP. I know, tight coupling is asking for it on long term maintainence
but I really didn't have a say in some of the architecture.
I haven't found an equivalent of Java's Class.forName(String
I'm not familiar with this Java class, but it appears to be doing
Reflections. PHP5 has an actual Reflection_* classes to give you this
functionality. I can even send you a small script about the new
Reflection API if you like. However, this site should explain
Reflection_Class:
http://sitten-polizei.de/php/reflection_api/docs/language.reflection.class.reflection_class.html
$class = Reflection_Class('SomeClass');
$method = $class-getMethod('Method');
$args = array($param1, $param2);
$method-invoke($class, $args);
Name_of_class_to_be_instantiated), so I thought call_user_func would
suffice, instantiate a default version of my object, etc etc ...
Anyone else, back me up on this if I'm wrong.
I think that you and Curt are indeed correct about being able to use a
$this only in an instance.
My issue is that I have not yet found anywhere were this change of
behavior in PHP5 that [EMAIL PROTECTED] describes is documented.
If someone could point me to where we all could help with the
documentation, that'd be great.
V
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Re: [PHP] how to verify PHP has been installed with ldap?
* Thus wrote Bing Du ([EMAIL PROTECTED]): I don't see a ldap section in the output of phpinfo(). I need to add a bit more background information here... This is not a fresh php install. I've already installed PHP Version 4.3.4. But now I want to add ldap support to it. So I added --with-ldap option in the configure command. Then I did make and make install. However, phpinfo() still shows the old information. For instance, Build Date was Mar 3 2004 11:15:34, Configure Command was the one without --with-ldap, etc.. This usually means that either you have multiple installation's of apache and php's make install isn't putting the the module in the right place. Or, that your current apache config loads modules from a different place than apxs told php it should go. If you issue: ls -laF `apxs -q LIBEXECDIR` You should see your libphp5.so there with the latest timestamp. if not, see if there are some errors issued with the 'make install' (like are you issuing that as root?) Also, look in the 'apache' section from phpinfo() and look at the value for 'Server root', php will usually be loaded relative to that directory. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: variable-length arguments passed by reference... how?
Aric Caley wrote:
I want to create a function similar to the MySqli extensions'
mysqli_stmt_bind_param() function. I assume that this function takes
its arguments passed by reference. Now, I know how to do variable
length argument lists in a function with func_get_arg(s) but how do I
tell it that they are to be passed by reference?
I'm using PHP5 and I want to stick by the latest recomendations..
There's a much simpler way to do this: just put in the in the declaration.
?php
error_reporting(E_ALL);
// Receives an array $args like you would get with func_get_args()
function test($args) {
$args[0] = 'blah';
$args[1] = 'I am different';
$args[2] = 'Do you see me in the original?';
}
$total = 10; // Set to any positive number of arguments
for ($i=0; $i $total; $i++) {
$args[$i] = $i;
}
test($args); // My bad, call_user_func_array passes a copy by default!?
echo 'pre';
print_r($args);
echo '/pre';
?
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[PHP] Introduction to Reflections: describe.php
I'm getting off the computer, so I figured I'd go ahead and just send this to you. As my subject suggests, this class shows all of the Reflections_* classes at work. One warning though: describe.php cannot describe the Reflections API itself, this causes the server to crash. Enjoy. Jason http://sitten-polizei.de/php/reflection_api/docs/language.reflection.class.reflection_method.html describe.php Description: application/unknown-content-type-phpfile -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Create Password for EXISTING PDF FILE
I want to create password to an existing pdf file How can I do that with PHP
[PHP] having problems setting up ez publish
hello folks, I'm having problems setting up ez publish. do we have an ez publish guru here? I'm in need of help with how to implement this system. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] problems with ez publish
hello folks, I'm having problems setting up ez publish. do we have an ez publish guru here? I'm in need of help with how to implement this system. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] having problems setting up ez publish
hello folks, I'm having problems setting up ez publish. do we have an ez publish guru here? I'm in need of help with how to implement this system. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] re-keying an array
been RTFMing for about 10 minutes, and can't find the function to re-key an array. In other words, I want an array of items to remain in their current order, but have the keys renumbered counting from zero. yes, I know it can be done with a foreach, but I was hoping for something native :) can anyone point me to the right page in the manual? --- Justin French http://indent.com.au -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] having problems setting up ez publish
We heard you the first two times. Please don't re-post. If there's a ez guru here, they'll respond in their own time. Of course you could try doing some work yourself first, perhaps visiting http://ez.no/community/forum -- a forum dedicated purely to EZ, in which I'm sure you'll find a higher ratio of people who can help. Please do your homework before posting a question -- even Googling for EZ CMS forum would have got your where you needed to go. --- Justin French http://indent.com.au -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
http://www.php.net/manual/en/function.array-values.php ? Richard Friday, April 30, 2004, 3:48:06 AM, thus was written: been RTFMing for about 10 minutes, and can't find the function to re-key an array. In other words, I want an array of items to remain in their current order, but have the keys renumbered counting from zero. yes, I know it can be done with a foreach, but I was hoping for something native :) can anyone point me to the right page in the manual? --- Justin French http://indent.com.au -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
Justin French wrote: been RTFMing for about 10 minutes, and can't find the function to re-key an array. In other words, I want an array of items to remain in their current order, but have the keys renumbered counting from zero. yes, I know it can be done with a foreach, but I was hoping for something native :) can anyone point me to the right page in the manual? array_values() $newarray = array_values($old_array); Although this begs the question of why you'd need to rekey an array... -- ---John Holmes... Amazon Wishlist: www.amazon.com/o/registry/3BEXC84AB3A5E/ php|architect: The Magazine for PHP Professionals www.phparch.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
On 30/04/2004, at 12:06 PM, John W. Holmes wrote:
Although this begs the question of why you'd need to rekey an
array...
It seemed the easiest way to get the first two elements off the
beginning of the array after shuffle()ing it, or so I thought -- but
I'm more than happy to hear of a better way, as always :)
My only requirement is really to end up with an array named $files that
can be used later on in the template in a foreach loop.
?
shuffle($filenames);// random sort
$filenames = array_values($filenames); // re-key
for($i=0;$i2;$i++) {
$files[] = path/to/.$filenames[$i];
}
?
... then in the template:
? foreach($files as $file): ?
div ...
...
? include($file); ?
...
/div
? endforeach; ?
Like I said, always happy to see something in a few less lines :)
---
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http://indent.com.au
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Re: [PHP] having problems setting up ez publish
thanks mate I have done my homework first of course. I was posting to find some one who is an expert. php-general is a newsgroup that covers all issues related to php. that's my understanding. if i am wrong, then i'm sorry. thanks anyway. Justin French [EMAIL PROTECTED] news:[EMAIL PROTECTED] We heard you the first two times. Please don't re-post. If there's a ez guru here, they'll respond in their own time. Of course you could try doing some work yourself first, perhaps visiting http://ez.no/community/forum -- a forum dedicated purely to EZ, in which I'm sure you'll find a higher ratio of people who can help. Please do your homework before posting a question -- even Googling for EZ CMS forum would have got your where you needed to go. --- Justin French http://indent.com.au -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
Justin French wrote:
On 30/04/2004, at 12:06 PM, John W. Holmes wrote:
Although this begs the question of why you'd need to rekey an array...
It seemed the easiest way to get the first two elements off the
beginning of the array after shuffle()ing it, or so I thought -- but I'm
more than happy to hear of a better way, as always :)
My only requirement is really to end up with an array named $files that
can be used later on in the template in a foreach loop.
?
shuffle($filenames);// random sort
$filenames = array_values($filenames);// re-key
for($i=0;$i2;$i++) {
$files[] = path/to/.$filenames[$i];
}
?
... then in the template:
? foreach($files as $file): ?
div ...
...
? include($file); ?
...
/div
? endforeach; ?
Like I said, always happy to see something in a few less lines :)
If I'm following what you want to do correctly:
for($i=0;$i2;$i++)
{
$key = array_rand($filenames);
$files[] = path/to/.$filenames[$key];
unset($filenames[$key]);
}
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[PHP] hello list
Do you guys know of any php based text indexers? similar to lucene? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
* Thus wrote Justin French ([EMAIL PROTECTED]):
On 30/04/2004, at 12:06 PM, John W. Holmes wrote:
Although this begs the question of why you'd need to rekey an
array...
It seemed the easiest way to get the first two elements off the
beginning of the array after shuffle()ing it, or so I thought -- but
I'm more than happy to hear of a better way, as always :)
My only requirement is really to end up with an array named $files that
can be used later on in the template in a foreach loop.
?
shuffle($filenames); // random sort
$filenames = array_values($filenames);// re-key
for($i=0;$i2;$i++) {
$files[] = path/to/.$filenames[$i];
}
?
Yeah, the array_values is unnecessary:
// this will resort the way the items are ordered
shuffle($filenames);// random sort
Normally a simple foreach loop would work but since you're grabbing
the first two, a slice of the array will work:
foreach(array_slice($filenames, 0, 2) as $filename) {
$files[] = path/to/ . $filelname;
}
Curt
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Re: [PHP] re-keying an array
* Thus wrote John W. Holmes ([EMAIL PROTECTED]):
Justin French wrote:
On 30/04/2004, at 12:06 PM, John W. Holmes wrote:
Like I said, always happy to see something in a few less lines :)
If I'm following what you want to do correctly:
for($i=0;$i2;$i++)
{
$key = array_rand($filenames);
heh.. there are almost to many array_* functions :)
Curt
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Re: [PHP] how to verify PHP has been installed with ldap?
Or... did you restart apache after running your make install? If not, that might be a good idea... `/path/to/apachectl restart` On Thursday 29 April 2004 04:00 pm, Curt Zirzow wrote: * Thus wrote Bing Du ([EMAIL PROTECTED]): I don't see a ldap section in the output of phpinfo(). I need to add a bit more background information here... This is not a fresh php install. I've already installed PHP Version 4.3.4. But now I want to add ldap support to it. So I added --with-ldap option in the configure command. Then I did make and make install. However, phpinfo() still shows the old information. For instance, Build Date was Mar 3 2004 11:15:34, Configure Command was the one without --with-ldap, etc.. This usually means that either you have multiple installation's of apache and php's make install isn't putting the the module in the right place. Or, that your current apache config loads modules from a different place than apxs told php it should go. If you issue: ls -laF `apxs -q LIBEXECDIR` You should see your libphp5.so there with the latest timestamp. if not, see if there are some errors issued with the 'make install' (like are you issuing that as root?) Also, look in the 'apache' section from phpinfo() and look at the value for 'Server root', php will usually be loaded relative to that directory. Curt -- I used to think I was indecisive, but now I'm not so sure. -- Evan Nemerson [EMAIL PROTECTED] http://coeusgroup.com/en -- To think is to differ. -Clarence Darrow -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] re-keying an array
On 30/04/2004, at 1:47 PM, Curt Zirzow wrote:
foreach(array_slice($filenames, 0, 2) as $filename) {
$files[] = path/to/ . $filelname;
}
Ahh array_slice() is EXACTLY what I was looking for :)
---
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[PHP] making changes on arrays
I'm practicing from a beginning PHP book regarding
arrays and the PHP manual, so please no one flame me
that I didn't try to research before posting. I'm
thinking that what I want to do requires me to use the
function array_walk or a foreach loop, but I'm not so
sure so maybe someone help here can help.
I want to have an array, perform an action on the
values in the array, and have those actions
permanently affect the values in the array. Here's
something I've written to test it out how I thought it
could be done:
?php
$array = ('zero\0', 'one\1', 'two\2', 'three\3');
// look at array before changes
print_r($array);
// maybe use foreach or array_walk next?
foreach ($array as $value)
{
stripslashes($value);
}
// look at array after changes
print_r($array);
?
I'm guessing by now someone can see my error, but I
don't know enough programming to spot it. What I
thought would happen is my values would have the
backslash removed in the second print_r(). What I
would want is for any changes made in the array
(meaning my values) to be permanent in the array
afterwards. If I can accomplish the code above, I
figure I can create my own functions to affect changes
on values or at least better understand what I'm
looking at in other people's examples/comments at the
online PHP manual.
Thank you in advance.
Katie
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[PHP] Maintaining State Remotely
I'm writing some code to login into my favorite sport site to get stats. I get logged in ok with the post request showing my username and password, the response screens welcomes me by name. However when I send a second request immediately after the successful login, I'm being told I need to login. I thought perhaps it might be cookies, so I tried setting the cookies to the values previously set on the first attempt, but no luck. Any ideas? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] making changes on arrays
Hi Katie,
The foreach construct operates on copies of the array values. I usually just
stick to C-like syntax:
for( $i = 0; $i count( $array ); $i++ )
{
$array[$i] = doSomething( $array[$i] );
}
cheers,
Travis
Katie Marquez wrote:
I'm practicing from a beginning PHP book regarding
arrays and the PHP manual, so please no one flame me
that I didn't try to research before posting. I'm
thinking that what I want to do requires me to use the
function array_walk or a foreach loop, but I'm not so
sure so maybe someone help here can help.
I want to have an array, perform an action on the
values in the array, and have those actions
permanently affect the values in the array. Here's
something I've written to test it out how I thought it
could be done:
?php
$array = ('zero\0', 'one\1', 'two\2', 'three\3');
// look at array before changes
print_r($array);
// maybe use foreach or array_walk next?
foreach ($array as $value)
{
stripslashes($value);
}
// look at array after changes
print_r($array);
?
I'm guessing by now someone can see my error, but I
don't know enough programming to spot it. What I
thought would happen is my values would have the
backslash removed in the second print_r(). What I
would want is for any changes made in the array
(meaning my values) to be permanent in the array
afterwards. If I can accomplish the code above, I
figure I can create my own functions to affect changes
on values or at least better understand what I'm
looking at in other people's examples/comments at the
online PHP manual.
Thank you in advance.
Katie
__
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mailto:[EMAIL PROTECTED]
http://www.dawnstar.com
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[PHP] about ssl socket programming
Hi,
I am running qmail+vpopmail+courier-imap on gentoo box with ssl.
And now making the password change script in php.
I used to use this code in my previous server.
?php
$socket=fsockopen(ssl://localhost, 993, $errno, $errstr, 30);
if(!$socket) {
echo $errstr ($errno)br /\n;
} else {
echo okbr;
fwrite($socket, $_POST[email_address]\r\n);
echo fread($socket, 1024);
echo brbr---brbr;
fwrite($socket, PASS $_POST[password]\r\n);
echo fread($socket, 1024);
$checkpassword=substr($line,0,1);
if ($checkpassword=='+')
{
echo bPassword changed/b ;
system(sudo /pathtovpop/vpopmail/bin/./vpasswd
'$_POST[email_address]' '$_POST[new_password]');
echo bra href=/horde/impmain page/a;
} else {
echo INVALID LOGIN;
}
fclose($socket);
}
?
When I run this script, I've got this error:
* OK [CAPABILITY IMAP4rev1 UIDPLUS CHILDREN NAMESPACE
THREAD=ORDEREDSUBJECT THREAD=REFERENCES SORT QUOTA IDLE AUTH=PLAIN ACL
ACL2=UNION] Courier-IMAP ready. Copyright 1998-2004 Double Precision,
Inc. See COPYING for distribution information. USER NO Error in IMAP
command received by server.
PASS NO Error in IMAP command received by server.
INVALID LOGIN
-
How can I implement this?
help~
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Re: [PHP] making changes on arrays
Hi,
that's something I tripped over myself when I started out :)
foreach takes one element after another from the array and copies it
into that new variable - in your case $value ...
you can modify it all you want - the value 'still' being in the array
will not be affected.
you could operate directly one the value in the array with:
// calculate the number of items in the array before starting the
// loop - will be faster the larger the array
$arCount = count($array);
for ($i = 0; $i $arCount; ++$i) {
stripslashes($array[$i]);
}
although, on second thought I don't think that stripslashes will do
what you want it to, because it's designed to get rid of slashes
before special characters like the songle quote (I think, but try it
for yourself).
So, if you want your array to change from
$array = ('zero\0', 'one\1', 'two\2', 'three\3');
to
$array = ('zero0', 'one1', 'two2', 'three3');
(as I understood) then I'd recommend using str_replace.
That one also has the advantage of taking arrays as arguments so you
can save the whole for / foreach
$array = str_replace('\'', '', $array);
Richard
Friday, April 30, 2004, 6:01:30 AM, thus was written:
I'm practicing from a beginning PHP book regarding
arrays and the PHP manual, so please no one flame me
that I didn't try to research before posting. I'm
thinking that what I want to do requires me to use the
function array_walk or a foreach loop, but I'm not so
sure so maybe someone help here can help.
I want to have an array, perform an action on the
values in the array, and have those actions
permanently affect the values in the array. Here's
something I've written to test it out how I thought it
could be done:
?php
$array = ('zero\0', 'one\1', 'two\2', 'three\3');
// look at array before changes
print_r($array);
// maybe use foreach or array_walk next?
foreach ($array as $value)
{
stripslashes($value);
}
// look at array after changes
print_r($array);
?
I'm guessing by now someone can see my error, but I
don't know enough programming to spot it. What I
thought would happen is my values would have the
backslash removed in the second print_r(). What I
would want is for any changes made in the array
(meaning my values) to be permanent in the array
afterwards. If I can accomplish the code above, I
figure I can create my own functions to affect changes
on values or at least better understand what I'm
looking at in other people's examples/comments at the
online PHP manual.
Thank you in advance.
Katie
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Re: [PHP] making changes on arrays (SOLVED)
Very cool, Travis! Thank you for answering so
quickly! You guys work fast around here :)
Katie
--- Travis Low [EMAIL PROTECTED] wrote:
Hi Katie,
The foreach construct operates on copies of the
array values. I usually just
stick to C-like syntax:
for( $i = 0; $i count( $array ); $i++ )
{
$array[$i] = doSomething( $array[$i] );
}
cheers,
Travis
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Re: [PHP] making changes on arrays
* Thus wrote Katie Marquez ([EMAIL PROTECTED]):
I want to have an array, perform an action on the
values in the array, and have those actions
permanently affect the values in the array. Here's
something I've written to test it out how I thought it
could be done:
?php
$array = ('zero\0', 'one\1', 'two\2', 'three\3');
// look at array before changes
print_r($array);
// maybe use foreach or array_walk next?
foreach ($array as $value)
{
stripslashes($value);
First: Most php functions always return a modified version of the
variable instead of modifying them directly. So in order to
actually keep the changes:
$value = stripslashes($value);
Second:
If you are using php 5 you can do something like, note the way
$value is referenced with :
foreach($array as $value) {
$value = stripslashes($value);
}
php 4's foreach always works on a copy so you have to access the
array directly:
foreach($array as $index = $value) {
$array[$index] = $value;
}
Curt
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Re: [PHP] Re: global vars inside includes inside functions?
Pattern are always done using OOP, but phppatterns that is one of the best sources on this topic i could think of :-) -- red [] Red, can you provide any more info or resources on a registry-pattern? I've found this: http://www.phppatterns.com/index.php/article/articleview/75/1/1/ , but I'm not really looking to get into OOP just yet :) [...] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] word to pdf via web server ??
hello, does any know how to conver microsoft word document to pdf via on the server using php language?? i try to implementing the feature that allow user to upload microsoft word document to the web server, after the upload, it automatic covert to pdf file ??? any one done that ? thanks john -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] text indexers
hello! anybody here who knows text based indexers? e.g. lucene(java based) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Maintaining State Remotely
* Thus wrote php chucker ([EMAIL PROTECTED]): I'm writing some code to login into my favorite sport site to get stats. I get logged in ok with the post request showing my username and password, the response screens welcomes me by name. However when I send a second request immediately after the successful login, I'm being told I need to login. I thought perhaps it might be cookies, so I tried setting the cookies to the values previously set on the first attempt, but no luck. It could be that your missing a cookie. The website might be sending a cookie when you request the login page. Or you might not be sending the value back to them properly. It's really hard to say without observing the whole login process and observing how they handle your session accross they website visit. Liveheaders and firebird could help out in finding out what they're sending and when. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] making changes on arrays (SOLVED)
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Katie Marquez
katie_marquez2004@ To: Travis Low [EMAIL PROTECTED],
php
yahoo.com [EMAIL PROTECTED]
cc:
04/30/2004 11:46 AM Subject: Re: [PHP] making changes on
arrays
(SOLVED)
Very cool, Travis! Thank you for answering so
quickly! You guys work fast around here :)
Katie
--- Travis Low [EMAIL PROTECTED] wrote:
Hi Katie,
The foreach construct operates on copies of the
array values. I usually just
stick to C-like syntax:
for( $i = 0; $i count( $array ); $i++ )
{
$array[$i] = doSomething( $array[$i] );
}
cheers,
Travis
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