php-general Digest 26 Mar 2012 06:39:23 -0000 Issue 7745
php-general Digest 26 Mar 2012 06:39:23 - Issue 7745
Topics (messages 317260 through 317262):
Re: foreach weirdness
317260 by: Matijn Woudt
317261 by: Simon Schick
317262 by: Arno Kuhl
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---BeginMessage---
On Sun, Mar 25, 2012 at 4:11 PM, Arno Kuhl a...@dotcontent.net wrote:
From: Simon Schick [mailto:simonsimc...@googlemail.com]
Sent: 24 March 2012 12:30 AM
To: Robert Cummings
Cc: a...@dotcontent.net; php-gene...@lists.php.net
Subject: Re: [PHP] foreach weirdness
2012/3/23 Robert Cummings rob...@interjinn.com
On 12-03-23 11:16 AM, Arno Kuhl wrote:
it still does not produce the correct result:
0 1 3 6 10 15 21
0 1 3 6 10 15 15
This looks like a bug... the last row should be the same. What version
of PHP are you using? Have you checked the online bug reports?
Hi, Robert
Does not seem like a bug to me ...
http://schlueters.de/blog/archives/141-References-and-foreach.html
What you should do to get the expected result:
Unset the variable after you don't need this reference any longer.
Bye
Simon
--
Hi Simon, unsetting the $value does fix the problem, but I found that any
time you assign $value by reference in a foreach loop you have to do an unset
to avoid corrupting the array unless you continue to assign $value by
reference (as illustrated in the article you linked).
So doing something as simple as:
$array = array(0, 1, 2, 3, 4, 5, 6);
foreach ($array as $key=$value) {
echo Key: $key; Value: $valuebr /\n;
}
and then follow with (from the php manual):
foreach ($array as $key=$value) {
echo Key: $key; Value: $valuebr /\n;
}
will not only give the wrong result, it will corrupt the array for *any*
further use of that array. I still think it’s a bug according to the
definition of foreach in the php manual. Maybe php needs to do an implicit
unset at the closing brace of the foreach where was an assign $value by
reference, to remove the reference to the last element (or whatever element
it was pointing to if there was a break) so that it doesn't corrupt the
array, because any assign to $value after the foreach loop is completed will
corrupt the array (confirmed by testing). The average user (like me) wouldn't
think twice about reusing $value after ending the foreach loop, not realising
that without an unset the array will be corrupted.
BTW thanks for that reference, it was quite an eye-opener on the pitfalls of
using assign by reference, not only in the foreach loop.
Cheers
Arno
Note that somewhat similar error was discussed on this list a few
months ago[1]. You could probably have solved it yourself if you
searched the mailing list archives.
- Matijn
[1] http://www.mail-archive.com/php-general@lists.php.net/msg269552.html
---End Message---
---BeginMessage---
2012/3/25 Arno Kuhl a...@dotcontent.net:
will not only give the wrong result, it will corrupt the array for *any*
further use of that array. I still think it’s a bug according to the
definition of foreach in the php manual. Maybe php needs to do an implicit
unset at the closing brace of the foreach where was an assign $value by
reference, to remove the reference to the last element (or whatever element
it was pointing to if there was a break) so that it doesn't corrupt the
array, because any assign to $value after the foreach loop is completed will
corrupt the array (confirmed by testing). The average user (like me) wouldn't
think twice about reusing $value after ending the foreach loop, not realising
that without an unset the array will be corrupted.
Hi, Arno
Requesting that will at least require a major-release (f.e. PHP 6.0)
... but I would rather request to add a notice or warning to the
documentation of references to remind stuff like that.
http://www.php.net/manual/en/language.references.php
I think this is stuff more people will stumble over ...
Bye
Simon
---End Message---
---BeginMessage---
Requesting that will at least require a major-release (f.e. PHP 6.0) ... but I
would rather request to add a notice or warning to the documentation of
references to remind stuff like that.
http://www.php.net/manual/en/language.references.php
I think this is stuff more people will stumble over ...
Bye
Simon
--
I agree it would be wrong to change php's handling of call by reference in
foreach loops because there may be a need to access that reference after
completing the loop. I was going to suggest there should be a warning in the
manual to unset the reference after the foreach loop is completed, but I see
the current online manual has that warning prominently displayed on the foreach
php-general Digest 26 Mar 2012 19:16:14 -0000 Issue 7746
php-general Digest 26 Mar 2012 19:16:14 - Issue 7746
Topics (messages 317263 through 317277):
Re: foreach weirdness
317263 by: Arno Kuhl
including PHP code from another server..
317264 by: rene7705
317265 by: Stuart Dallas
317266 by: Simon Schick
317267 by: Stuart Dallas
317268 by: Stuart Dallas
317269 by: Curtis Maurand
317270 by: rene7705
317272 by: Lester Caine
317273 by: Alex Pojarsky
317277 by: Stuart Dallas
CURL -d
317271 by: QI.VOLMAR QI
Re: Thinking out loud - a continuation...
317274 by: Jay Blanchard
317275 by: Stuart Dallas
317276 by: Jay Blanchard
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---BeginMessage---
Note that somewhat similar error was discussed on this list a few months
ago[1]. You could probably have solved it yourself if you searched the mailing
list archives.
- Matijn
[1] http://www.mail-archive.com/php-general@lists.php.net/msg269552.html
---
Thanks Matijn, I missed that discussion, not following the list that actively.
I'll try search next time before raising an issue.
Cheers
Arno
---End Message---
---BeginMessage---
Hi.
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested includes by massaging what it
retrieves. Or so is my thinking.
The problem I'm facing, and for which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and include(_once)? I
haven't figured out yet how to transform a relative path include/require.
What about for instance a require_once($fileIwantNow)?
I do both in my /code tree atm.
For my own purposes, I could massage my own PHP in /code/libraries_rv and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might find some
free tips here again.
Greetings,
from spring sun soaked amsterdam.nl,
Rene
---End Message---
---BeginMessage---
REMOVE THAT SCRIPT FROM YOUR SERVER RIGHT NOW!
See follow-up email direct to you for the reason!
On 26 Mar 2012, at 14:53, rene7705 wrote:
Hi.
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
RE: [PHP] foreach weirdness
Requesting that will at least require a major-release (f.e. PHP 6.0) ... but I would rather request to add a notice or warning to the documentation of references to remind stuff like that. http://www.php.net/manual/en/language.references.php I think this is stuff more people will stumble over ... Bye Simon -- I agree it would be wrong to change php's handling of call by reference in foreach loops because there may be a need to access that reference after completing the loop. I was going to suggest there should be a warning in the manual to unset the reference after the foreach loop is completed, but I see the current online manual has that warning prominently displayed on the foreach page. I had a version of the manual from July last year that didn't have the warning, so I'll update my local manual and make sure I keep it up to date. Lesson learned (both manual and foreach references). Cheers Arno -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] foreach weirdness
Note that somewhat similar error was discussed on this list a few months ago[1]. You could probably have solved it yourself if you searched the mailing list archives. - Matijn [1] http://www.mail-archive.com/php-general@lists.php.net/msg269552.html --- Thanks Matijn, I missed that discussion, not following the list that actively. I'll try search next time before raising an issue. Cheers Arno -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] including PHP code from another server..
Hi.
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested includes by massaging what it
retrieves. Or so is my thinking.
The problem I'm facing, and for which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and include(_once)? I
haven't figured out yet how to transform a relative path include/require.
What about for instance a require_once($fileIwantNow)?
I do both in my /code tree atm.
For my own purposes, I could massage my own PHP in /code/libraries_rv and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might find some
free tips here again.
Greetings,
from spring sun soaked amsterdam.nl,
Rene
Re: [PHP] including PHP code from another server..
REMOVE THAT SCRIPT FROM YOUR SERVER RIGHT NOW!
See follow-up email direct to you for the reason!
On 26 Mar 2012, at 14:53, rene7705 wrote:
Hi.
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested includes by massaging what it
retrieves. Or so is my thinking.
The problem I'm facing, and for which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and include(_once)? I
haven't figured out yet how to transform a relative path include/require.
What about for instance a require_once($fileIwantNow)?
I do both in my /code tree atm.
For my own purposes, I could massage my own PHP in /code/libraries_rv and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might find some
free tips here again.
Greetings,
from spring sun soaked amsterdam.nl,
Rene
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
Hi, Rene
I just want to say the same ... whatever you're trying to do here - it
will end up in a major security-isse that (I think) you won't fix that
soon as someone has hacked your server.
That sounds like you don't wanna pay 10$ per month for a good
multiple-domain-hosting solution.
If you're searching for something cheap for multi-domains, take a look
at providers like DreamHost or something similar.
Bye
Simon
2012/3/26 Stuart Dallas stu...@3ft9.com:
REMOVE THAT SCRIPT FROM YOUR SERVER RIGHT NOW!
See follow-up email direct to you for the reason!
On 26 Mar 2012, at 14:53, rene7705 wrote:
Hi.
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested includes by massaging what it
retrieves. Or so is my thinking.
The problem I'm facing, and for which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and include(_once)? I
haven't figured out yet how to transform a relative path include/require.
What about for instance a require_once($fileIwantNow)?
I do both in my /code tree atm.
For my own purposes, I could massage my own PHP in /code/libraries_rv and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might find some
free tips here again.
Greetings,
from spring sun soaked amsterdam.nl,
Rene
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
On 26 Mar 2012, at 15:17, Simon Schick wrote: Hi, Rene I just want to say the same ... whatever you're trying to do here - it will end up in a major security-isse that (I think) you won't fix that soon as someone has hacked your server. I couldn't care less about Rene's stuff. It's compromising the security of every customer on that server, and that's not acceptable. Security is arguably more important when using shared servers because your lack of focus on security issues has consequences for everyone else on that server, and potentially on that network. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/
Re: [PHP] including PHP code from another server..
On 26 Mar 2012, at 14:53, rene7705 wrote:
My last thread got derailed into a javascript and even photoshop
discussion, and while I can't blame myself for that really, this time I
would like to bring a pure PHP issue to your scrutiny.
I run several sites now, on the same shared hoster, but with such a setup
that I cannot let PHP require() or include() code from a central place
located on another domain name on the same shared hosting account, not the
normal way at least.
$_SERVER['DOCUMENT_ROOT'] is a completely different path for each of the
domains on the same hosting account, and obviously you can't access one
domain's directory from another domain.
Hoster support's reply is A) I dont know code, B) You can't include code
from one domain on another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster, many
files.
Plus, as I add more domains that use the same code base, my overhead and
waiting time increases lineary at a steep incline.
So.. Since all of this code is my own, and tested and trusted, I can just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested includes by massaging what it
retrieves. Or so is my thinking.
The problem I'm facing, and for which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and include(_once)? I
haven't figured out yet how to transform a relative path include/require.
What about for instance a require_once($fileIwantNow)?
I do both in my /code tree atm.
For my own purposes, I could massage my own PHP in /code/libraries_rv and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might find some
free tips here again.
Don't do this. Use a central source to host your code by all means, but create
constantly updated copies on every server that uses it. Since I use git for
source control I make use of the submodule feature to make this simplicity
itself. It's worth investing time in building the processes that ensure
consistency between your various environments. The best ops strategy is the
lazy op's strategy!
Set up cron scripts on each server to update that code periodically so
everything is always up to date. I wouldn't recommend that unless you have good
testing procedures in place before your code hits production, but from what
I've seen I find the highly doubtful. However, sharing code at runtime over
http is a very very very bad idea.
Even farms with hundreds or thousands of servers, all running the same
application on a fast local network, don't share code in this way. Each server
has its own copy of the code, and it's the deployment processes that ensure
they're kept up to date.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
Re: [PHP] including PHP code from another server..
rsync is your friend.
--C
Stuart Dallas
wrote:
On 26 Mar 2012, at 14:53, rene7705 wrote:
My last thread got derailed into a javascript and even
photoshop
discussion, and while I can't blame myself for
that really, this time I
would like to bring a pure PHP
issue to your scrutiny.
I run several sites
now, on the same shared hoster, but with such a
setup
that I cannot let PHP require() or include() code from a
central place
located on another domain name on the same
shared hosting account, not
the
normal way at
least.
$_SERVER['DOCUMENT_ROOT'] is a completely different
path for each of the
domains on the same hosting account,
and obviously you can't access one
domain's directory from
another domain.
Hoster support's reply is A) I
dont know code, B) You can't include code
from one domain on
another and C) use multiple copies, 1 for each domain
But that directory (my opensourced /code in the zip on
http://mediabeez.wsbtw), takes a while to update to my hoster,
many
files.
Plus, as I add more domains that
use the same code base, my overhead and
waiting time
increases lineary at a steep incline.
So..
Since all of this code is my own, and tested and trusted, I can
just
eval(file_get_contents('
http://sitewithwantedcode.com/code/get_php.php?file=/code/sitewide_rv/autorun.php'))
hehe
And get_php.php takes care of the nested
includes by massaging what it
retrieves. Or so is my
thinking.
The problem I'm facing, and for
which I'm asking your most scrutinous
feedback, is:
How would you transform _nested_ require(_once) and
include(_once)? I
haven't figured out yet how to transform a
relative path
include/require.
What about for
instance a require_once($fileIwantNow)?
I do both in my
/code tree atm.
For my own purposes, I could
massage my own PHP in /code/libraries_rv
and
/code/sitewide_rv manually, but I'd also like to be able to include a
single copy of the 3rd party free libs that I use in
/code/libraries(/adodb-5.10 for instance). And god knows how
they might
include and require.
Plus, I'd like to turn this into another free how-to blog entry on
http://mediabeez.ws, plus accompanying code, so I think I might
find
some
free tips here again.
Don't do this. Use a central source to host your code by all means,
but
create constantly updated copies on every server that uses
it. Since I use
git for source control I make use of the
submodule feature to make this
simplicity itself. It's worth
investing time in building the processes
that ensure consistency
between your various environments. The best ops
strategy is the
lazy op's strategy!
Set up cron scripts on each
server to update that code periodically so
everything is always
up to date. I wouldn't recommend that unless you have
good
testing procedures in place before your code hits production, but
from what I've seen I find the highly doubtful. However, sharing
code at
runtime over http is a very very very bad idea.
Even farms with hundreds or thousands of servers, all
running the same
application on a fast local network, don't
share code in this way. Each
server has its own copy of the
code, and it's the deployment processes
that ensure they're kept
up to date.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
[PHP] CURL -d
I have this lines:
curl -H Content-Type: application/json -d hello world \
http://api.pusherapp.com/apps/17331/channels/test_channel/events?\
The option -d is for data. But How I can set it on the PHP CURL extension?
I have found that if I set something like array('Hello Word', 'name'
= 'my_name'), for the POST data may occurs. Can you give me a little
help?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
Curtis Maurand wrote: rsync is your friend. and is even available for windows machines ... -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk// Firebird - http://www.firebirdsql.org/index.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
Now, as the issue adressed and script removed, can you please explain what exactly are the issues of using such approach? I mean security ones, not performance. 2012/3/26 Lester Caine les...@lsces.co.uk: Curtis Maurand wrote: rsync is your friend. and is even available for windows machines ... -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk// Firebird - http://www.firebirdsql.org/index.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
[snip] This is one of those projects. It is apparently going to be trying every step of the way. [/snip] I was proven right this morning after all of Robert's good work and what I had added to make this work. It turns out that the one service who was anxious to consume the JSON output expects that the JSON be a certain format. When I run their format through jslint it does not validate unless I add quotes around the name portion of the name:value pairs. In addition they use (perfectly valid) square brackets around the children groups that the output from json_encode() does not contain. I am ready to take a loss on this one but I really didn't lose - Robert gave me a great way to retrieve the data with one query and create valid JSON from it. Thanks again Robert! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
On 26 Mar 2012, at 19:12, Jay Blanchard wrote: [snip] This is one of those projects. It is apparently going to be trying every step of the way. [/snip] I was proven right this morning after all of Robert's good work and what I had added to make this work. It turns out that the one service who was anxious to consume the JSON output expects that the JSON be a certain format. When I run their format through jslint it does not validate unless I add quotes around the name portion of the name:value pairs. In addition they use (perfectly valid) square brackets around the children groups that the output from json_encode() does not contain. I am ready to take a loss on this one but I really didn't lose - Robert gave me a great way to retrieve the data with one query and create valid JSON from it. Thanks again Robert! Square brackets in JSON represent arrays. Take their JSON, run it through json_decode, and assuming it decodes correctly compare the structure to what you already have. You should then be able to modify what you have so it generates JSON in the format they are expecting. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
[snip] Square brackets in JSON represent arrays. Take their JSON, run it through json_decode, and assuming it decodes correctly compare the structure to what you already have. You should then be able to modify what you have so it generates JSON in the format they are expecting. [/snip] Done. I knew about the square brackets. In the code being used the array, if blank, gets square brackets. For some reason an array containing actual data does not. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
On 26 Mar 2012, at 17:41, Alex Pojarsky wrote: Now, as the issue adressed and script removed, can you please explain what exactly are the issues of using such approach? I mean security ones, not performance. It's the wrong solution to a process and organisation problem. Ultimately it's not really a problem IF you control every part of the infrastructure. Rene clearly doesn't so it has implications for everyone sharing that infrastructure, and anyone using the applications hosted there. * It requires the host to enable allow_url_fopen which means every single script on the server is then able to include/require URLs. It just needs one of them to have a related vulnerability and suddenly people can execute arbitrary PHP code on the server. * Rene mentioned that the code is open source. This implies that the security risk is lessened because the code that is being made publicly accessible is already publicly accessible, so the opportunity for someone to find vulnerabilities already exists. It gets an order of magnitude worse if other people start ignorantly using his code because they're essentially giving him the ability to execute arbitrary PHP code on their server. Not good no matter how much he protests that he won't be evil. * You specifically wished to exclude performance from the discussion, but scalability is potentially a big issue here and should not be completely ignored. I think the real issue for Rene is that of perceived complexity. The idea of having to manually keep many copies of the same code in sync is what leads to finding solutions like this one. This solution leads to unnecessary network traffic and introduces potential security risks that go way beyond your own code, and even if it's not a big issue now it has the potential to become catastrophic! I'd put a fair amount of cash on my guess that Rene is not using any form of source control. To me that is the best solution to this problem. Curtis mentioned rsync which will also do the job, but in my view you're nuts if you're not using some form of source control already, and building a largely automated process around that is trivial and automatically audited. Rene: please read a book / website / something on PHP security. Some things are important whether you believe they are or not. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] including PHP code from another server..
I understand what performance issues this brings, but as for security was just a bit curious. You have just showed me what I was thinking about, but you wrote it much better, clear and structured. Thank you. 2012/3/26 Stuart Dallas stu...@3ft9.com: On 26 Mar 2012, at 17:41, Alex Pojarsky wrote: Now, as the issue adressed and script removed, can you please explain what exactly are the issues of using such approach? I mean security ones, not performance. It's the wrong solution to a process and organisation problem. Ultimately it's not really a problem IF you control every part of the infrastructure. Rene clearly doesn't so it has implications for everyone sharing that infrastructure, and anyone using the applications hosted there. * It requires the host to enable allow_url_fopen which means every single script on the server is then able to include/require URLs. It just needs one of them to have a related vulnerability and suddenly people can execute arbitrary PHP code on the server. * Rene mentioned that the code is open source. This implies that the security risk is lessened because the code that is being made publicly accessible is already publicly accessible, so the opportunity for someone to find vulnerabilities already exists. It gets an order of magnitude worse if other people start ignorantly using his code because they're essentially giving him the ability to execute arbitrary PHP code on their server. Not good no matter how much he protests that he won't be evil. * You specifically wished to exclude performance from the discussion, but scalability is potentially a big issue here and should not be completely ignored. I think the real issue for Rene is that of perceived complexity. The idea of having to manually keep many copies of the same code in sync is what leads to finding solutions like this one. This solution leads to unnecessary network traffic and introduces potential security risks that go way beyond your own code, and even if it's not a big issue now it has the potential to become catastrophic! I'd put a fair amount of cash on my guess that Rene is not using any form of source control. To me that is the best solution to this problem. Curtis mentioned rsync which will also do the job, but in my view you're nuts if you're not using some form of source control already, and building a largely automated process around that is trivial and automatically audited. Rene: please read a book / website / something on PHP security. Some things are important whether you believe they are or not. -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] CURL -d
On Mon, 2012-03-26 at 09:45 -0600, QI.VOLMAR QI wrote:
I have this lines:
curl -H Content-Type: application/json -d hello world \
http://api.pusherapp.com/apps/17331/channels/test_channel/events?\
The option -d is for data. But How I can set it on the PHP CURL extension?
I have found that if I set something like array('Hello Word', 'name'
= 'my_name'), for the POST data may occurs. Can you give me a little
help?
Have a look at curl_setopt() which can set those flags as you need
inside PHP:
http://uk3.php.net/manual/en/function.curl-setopt.php
--
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] CURL -d
I know guess that it is a POST field, but the detail is on simulate the -d
without a label. I've already looked at setopt man page, but nothing seems
like what I need.
2012/3/26 Ashley Sheridan a...@ashleysheridan.co.uk
**
On Mon, 2012-03-26 at 09:45 -0600, QI.VOLMAR QI wrote:
I have this lines:
curl -H Content-Type: application/json -d hello world \
http://api.pusherapp.com/apps/17331/channels/test_channel/events?\
http://api.pusherapp.com/apps/17331/channels/test_channel/events?%5C%3E
The option -d is for data. But How I can set it on the PHP CURL extension?
I have found that if I set something like array('Hello Word', 'name'
= 'my_name'), for the POST data may occurs. Can you give me a little
help?
Have a look at curl_setopt() which can set those flags as you need inside
PHP:
http://uk3.php.net/manual/en/function.curl-setopt.php
--
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] Thinking out loud - a continuation...
On 12-03-26 02:12 PM, Jay Blanchard wrote: [snip] This is one of those projects. It is apparently going to be trying every step of the way. [/snip] I was proven right this morning after all of Robert's good work and what I had added to make this work. It turns out that the one service who was anxious to consume the JSON output expects that the JSON be a certain format. When I run their format through jslint it does not validate unless I add quotes around the name portion of the name:value pairs. In addition they use (perfectly valid) square brackets around the children groups that the output from json_encode() does not contain. I am ready to take a loss on this one but I really didn't lose - Robert gave me a great way to retrieve the data with one query and create valid JSON from it. Thanks again Robert! *lol* No worries... it's all about solving problems :) Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
[snip] *lol* No worries... it's all about solving problems :) [/snip] the other folks who needed to consume the JSON have all done so successfully today - just this one. The guy who runs it was plenty arrogant when I discussed with him. He is the one who wanted me to remove the extra array name. I cooked up some regex to do that but then all of the opening/closing curlies were out of whack. If I had kept going it would have been maddening. I told him he needed to fix his JSON parsing. He said I needed to add the square brackets. Programmer stand-off. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
On 12-03-26 05:14 PM, Jay Blanchard wrote: [snip] *lol* No worries... it's all about solving problems :) [/snip] the other folks who needed to consume the JSON have all done so successfully today - just this one. The guy who runs it was plenty arrogant when I discussed with him. He is the one who wanted me to remove the extra array name. I cooked up some regex to do that but then all of the opening/closing curlies were out of whack. If I had kept going it would have been maddening. I told him he needed to fix his JSON parsing. He said I needed to add the square brackets. Programmer stand-off. Did you end up with a satisfactory output? It's not overly difficult to generate an array instead of an object. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
[snip] Did you end up with a satisfactory output? It's not overly difficult to generate an array instead of an object. [/snip] I did for all but this one instance. Are you saying that it would be easy to make of the children arrays? I thought they were already - am I missing something? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
On 12-03-26 06:52 PM, Jay Blanchard wrote: [snip] Did you end up with a satisfactory output? It's not overly difficult to generate an array instead of an object. [/snip] I did for all but this one instance. Are you saying that it would be easy to make of the children arrays? I thought they were already - am I missing something? They are arrays... but JSON_encode is creating objects. You can create arrays by traversing the array structure recursively and outputing your own JavaScript code to build a JavaScript array. I don't know if that would serve the purpose, but you would end up with an array. Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
[snip] On Mar 26, 2012, at 5:58 PM, Robert Cummings wrote: On 12-03-26 06:52 PM, Jay Blanchard wrote: [snip] Did you end up with a satisfactory output? It's not overly difficult to generate an array instead of an object. [/snip] I did for all but this one instance. Are you saying that it would be easy to make of the children arrays? I thought they were already - am I missing something? They are arrays... but JSON_encode is creating objects. You can create arrays by traversing the array structure recursively and outputing your own JavaScript code to build a JavaScript array. I don't know if that would serve the purpose, but you would end up with an array. [/snip] I'm listening - so could this be added to the code that you just wrote? Or do I need to recurse the output from json_encode()? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RES: [PHP] CURL -d
Hi try this :
$ch = curl_init();
curl_setopt ( $ch, CURLOPT_URL, URL HERE );
curl_setopt ( $ch, CURLOPT_FOLLOWLOCATION, 1 );
curl_setopt ( $ch, CURLOPT_HEADER, 1 );
curl_setopt ( $ch, CURLOPT_TIMEOUT, 10);
curl_setopt ( $ch, CURLOPT_SSL_VERIFYPEER, false );
curl_setopt ( $ch, CURLOPT_SSL_VERIFYHOST, false );
This to use SSL Certicade
curl_setopt ( $ch, CURLOPT_SSLCERT, Public Key );
curl_setopt ( $ch, CURLOPT_SSLCERTPASSWD, '');
curl_setopt ( $ch, CURLOPT_SSLCERTTYPE, 'PEM' ); -- Type o certificade
curl_setopt ( $ch, CURLOPT_SSLKEY, Private Key );
curl_setopt ( $ch, CURLOPT_SSLKEYPASSWD, Password of private key);
curl_setopt ( $ch, CURLOPT_RETURNTRANSFER, 1 );
curl_setopt ( $ch, CURLOPT_POST, true );
curl_setopt ( $ch, CURLOPT_PORT , 443 ); -- port
curl_setopt($ch, CURLOPT_POSTFIELDS, DATA HERE );
curl_setopt($ch, CURLOPT_HTTPHEADER,
array(
'User-Agent: Some name',
'Accept-Encoding: gzip, deflate',
'POST some post data HTTP/1.1',
'Host: some host',
'Content-type: application/soap+xml; charset=utf-8', The content type
'Content-Length: ', length of data
// This for soap action
'SOAPAction: action here ')
);
$xResult = curl_exec($ch);
Alejandro M.S.
-Mensagem original-
De: QI.VOLMAR QI [mailto:qi.vol...@gmail.com]
Enviada em: segunda-feira, 26 de março de 2012 12:46
Para: PHP General
Assunto: [PHP] CURL -d
I have this lines:
curl -H Content-Type: application/json -d hello world \
http://api.pusherapp.com/apps/17331/channels/test_channel/events?\
The option -d is for data. But How I can set it on the PHP CURL extension?
I have found that if I set something like array('Hello Word', 'name'
= 'my_name'), for the POST data may occurs. Can you give me a little help?
--
PHP General Mailing List (http://www.php.net/) To unsubscribe, visit:
http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Thinking out loud - a continuation...
On 12-03-26 07:05 PM, Jay Blanchard wrote: [snip] On Mar 26, 2012, at 5:58 PM, Robert Cummings wrote: On 12-03-26 06:52 PM, Jay Blanchard wrote: [snip] Did you end up with a satisfactory output? It's not overly difficult to generate an array instead of an object. [/snip] I did for all but this one instance. Are you saying that it would be easy to make of the children arrays? I thought they were already - am I missing something? They are arrays... but JSON_encode is creating objects. You can create arrays by traversing the array structure recursively and outputing your own JavaScript code to build a JavaScript array. I don't know if that would serve the purpose, but you would end up with an array. [/snip] I'm listening - so could this be added to the code that you just wrote? Or do I need to recurse the output from json_encode()? I think you need two things... the recursive post processor that removes the string indexes for the children. And then a function that creates a JavaScript array expression from an object or array. The question I have for you... is given the following array structure that might be generated from my previous code: ?php array ( 'exec-001' = array ( 'name' = 'exec-001', 'children' = array ( 'sub-exec-011' = array ( 'name' = 'sub-exec-011', 'children' = array ( 'sub-sub-exec-111' = array ( 'name' = 'sub-sub-exec-111', 'children' = array() ), 'sub-sub-exec-112' = array ( 'name' = 'sub-sub-exec-112', 'children' = array() ) ) ), 'sub-exec-012' = array ( 'name' = 'sub-exec-012', 'children' = array ( 'sub-sub-exec-121' = array ( 'name' = 'sub-sub-exec-121', 'children' = array() ), 'sub-sub-exec-122' = array ( 'name' = 'sub-sub-exec-122', 'children' = array() ) ) ) ) ), 'exec-002' = array ( 'name' = 'exec-002', 'children' = array ( 'sub-exec-021' = array ( 'name' = 'sub-exec-021', 'children' = array ( 'sub-sub-exec-211' = array ( 'name' = 'sub-sub-exec-211', 'children' = array() ), 'sub-sub-exec-212' = array ( 'name' = 'sub-sub-exec-212', 'children' = array() ) ) ), 'sub-exec-022' = array ( 'name' = 'sub-exec-022', 'children' = array ( 'sub-sub-exec-221' = array ( 'name' = 'sub-sub-exec-221', 'children' = array() ), 'sub-sub-exec-222' = array ( 'name' = 'sub-sub-exec-222', 'children' = array() ) ) ) ) ) ); ? On first blush, I think you want the following structure (from your recent posts): ?php array ( 0 = array ( 'name' = 'exec-001', 'children' = array ( 0 = array ( 'name' = 'sub-exec-011', 'children' = array ( 0 = array ( 'name' = 'sub-sub-exec-111', 'children' = array() ), 1 = array ( 'name' = 'sub-sub-exec-112', 'children' = array() ) ) ), 1 = array ( 'name' = 'sub-exec-012', 'children' = array ( 0 = array ( 'name' = 'sub-sub-exec-121', 'children' = array() ), 1 = array ( 'name' = 'sub-sub-exec-122', 'children' = array() ) ) ) ) ), 1 = array ( 'name' = 'exec-002', 'children' = array ( 0 = array (
