[PHP] Re: php login

2005-02-16 Thread Jason Barnett
William Stokes wrote:
Hello,
I need to create solution for user authentication/recognition in my web
page. I think it would be a good idea to use mysql database for storing the
user info because the user info is later used to determine what parts of
site the recognized user is allowed to update.
Sounds like a fine idea to me.
The site is for a soccer club that has some 30+ teams. I want to give each
team the ability to update their own information but I don't want them to be
able to mess with others info. So each team has one named admin to whom I
need to give the access to their team info.
I'm willing to learn to write my own scripts if I can get some info how
these things are normally handled or I can use free ready scripts if someone
can reccoment me one
The basic process might go something like this:
- Create the user database
  - Build DB so that each user record needs a unique ID (auto-increment
number is usually best), a team name, user type (user / admin), and password
- Create a login function (user / password)
  - Query the user database; see if password matches stored password
- If login succeeds:
  - Start session: session_start()
  - Store username / team / user type in $_SESSION
  - Go to team home page (or whatever)
- If login fails:
  - Redirect user to the login page
- Create all of the individual web pages you want (show team / edit team
/ etc.)
- At the beginning of each web page you check for the user type in
$_SESSION.  Also, check for the user team in $_SESSION.
  - If the user isn't the required team / user type then send an error
message to the user
Rough outline, but this should be enough to get you started and to let
you know which parts of the manual you will need to read.  ;)
http://www.php.net/manual/en/index.php

BTW I am quite rookie with PHP.
Thanks a lot
-Will

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[PHP] Re: php login

2005-02-16 Thread Jamie Alessio
I need to create solution for user authentication/recognition in my web 
page. I think it would be a good idea to use mysql database for storing the 
user info because the user info is later used to determine what parts of 
site the recognized user is allowed to update.

William,
Take a look at the PEAR Auth class:
http://pear.php.net/package/Auth
http://pear.php.net/manual/en/package.authentication.auth.php
It allows you to use MySQL to store the user information and will 
probably save you some time on the actual login part of your script.

- Jamie
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[PHP] Re: php login

2005-02-16 Thread William Stokes
OK. Thanks a lot. So I need to studu the $_Session more closely.



Jamie Alessio [EMAIL PROTECTED] kirjoitti 
viestissä:[EMAIL PROTECTED]
 I need to create solution for user authentication/recognition in my web 
 page. I think it would be a good idea to use mysql database for storing 
 the user info because the user info is later used to determine what parts 
 of site the recognized user is allowed to update.

 William,
 Take a look at the PEAR Auth class:
 http://pear.php.net/package/Auth
 http://pear.php.net/manual/en/package.authentication.auth.php

 It allows you to use MySQL to store the user information and will probably 
 save you some time on the actual login part of your script.

 - Jamie 

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[PHP] Re: PHP Login Script

2004-08-25 Thread Torsten Roehr
Chuck [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 Could anyone let me know or point me to where I could find out how to
setup
 a login for my php site.  I've been looking around and found plenty of
stuff
 for PHP/Apache, but nothing for just PHP.

 Any help or info about this would be appreciated.

 Thanks,
 Chuck

Hi Chuck,

you could try those two PEAR packages:
http://pear.php.net/package/Auth
http://pear.php.net/package/LiveUser

If you have any questions about those packages that the docs and the source
code can't answer there is the PEAR general mailing list to help ;)

Best regards, Torsten Roehr

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[PHP] Re: php-login scripts

2004-06-28 Thread Aidan Lister
Hi,

You've sent this email to a mailing list with a couple of thousand users.
I'm probably not alone when I say what on earth are you talking about?.

I don't know what PHP-Login is, if you have a problem using whatever
software that may be - please contact them about it.

You can find the PEAR website here:
http://pear.php.net/


Sriranganath [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Dear Sir,

Can u send me the Check list for PHP-Login :

It is not clear in the website which files should we have to include under
which directories.

There are two or more files with the same name vizConfig.php
which one to include .?
i am trying this for the past 4 days. i am unable to get it done.


i have downloaded all the files:

1. details.php
2.edit.php
3.functions.php
4.global.php
5.index.php
6.list.php
7.login.php
8.logout.php
9. password.php
10.session_defaults.php
11.signup.php
12.user.phop
13. html_form.php
14.filter.php
15.config.php (?) i am doubt in this file

Also, You have told to download all the PEAR related packages. But you ahve
not given any link for this.


Finally, I request you to give me one complete catalogue having all the
related files and associated directories.

Your reply is highly appreciated.

Regards
Sriranganath

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[PHP] RE:[PHP] login problem fixed!!

2004-03-25 Thread Andy B
[snip]
please note this will only catch invalid queries. To catch the event
of the query being perfectly fine, but nothing coming back, just check
the values of num_rows or affected_rows (depending on the query).

[/snip]

um?? this way doesnt work for some strange reason... testing
affected_rows returns always with 0 so: if(mysql_affected_rows()==0){...}
will always get ran even if the query itself returned an invalid user
login...
num_of_rows will always return true and never false i guess because when
$result (the query itself) is invalid or returns the fact that the user
typed a wrong username and or password the db server returns NULL, false or
rightfully 0. thus the error:
num_of_rows() is not a valid resource type in:..login.php error

so as far as i know i have to test the literall existance of the $result
resource being true (a real login) or false (the login failed)...

at this point i cant test for $_SESSION['username'] because it hasnt been
registered yet...

anyhow..off my soap box

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Re: [PHP] RE:[PHP] login problem fixed!!

2004-03-25 Thread Richard Davey
Hello Andy,

Thursday, March 25, 2004, 9:53:05 AM, you wrote:

AB um?? this way doesnt work for some strange reason... testing
AB affected_rows returns always with 0 so:
AB if(mysql_affected_rows()==0){...}

It depends on your query. If you are doing a SELECT query then you
cannot use affected_rows, you must use num_rows instead. If you are
doing an UPDATE or INSERT query then swap that over.

AB num_of_rows will always return true and never false i guess because when

mysql_num_rows will never return true OR false because it doesn't return a
boolean, it returns a value, so you cannot check its contents like
this.

AB $result (the query itself) is invalid or returns the fact that the user
AB typed a wrong username and or password the db server returns NULL, false or
AB rightfully 0. thus the error:
AB num_of_rows() is not a valid resource type in:..login.php error

mysql_query ONLY returns a FALSE if the query fails for SELECT queries
(and show/explain/describe, but that's not relevant to this).

If your query is perfectly valid but simply returns no data, you can
only check for this with mysql_num_rows.

Your logic sequence should be as follows:

1. Send query to MySQL

2. Check if mysql_errno == 0
If it DOESN'T, your query had an error, so find out what it was by
echoing out mysql_error() and quitting gracefully.

3. If mysql_errno == 0 then your query ran perfectly, so...

4. Check value of mysql_num_rows. If == 0 then simply no data was
returned, so handle the error accordingly. If value == 1 then you know
you've got the data back that you wanted.

For INSERT/UPDATE queries substitute mysql_num_rows in the above for
affected_rows, principle is the same though - but be careful when
comparing your data types for affected rows.

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[PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Andy B
So, just for the sake of me getting this right, it would be better code if i
had the code like this:

?
$UserExists=mysql_query(select * from users where
username='$_POST[username]' and pwd=md5($_POST[password]));

//since query is done see if the user exists
if($UserExists) {
ExistingUserCanDoSomething(); }
else {
YouCantDoAnythingIfYouDontExist(); }
?

forgive the odd severely long redundant example names but... im sure that is
better than what i had before...

let me know if i got the right idea...

and $UserExists in this example is either true or false because empty set
in mysql isnt even a number it = NULL

echo $UserExists;//prints 0 if false and 1 if true
//at least in this instance of it (normally it would return total rows
matched)

at the point of logins i dont care about the # of rows it will alwas return
0 or 1 so  true/false is best for me right now. when i create the user
generater then i will need to check for multiple usernames/passwords (2
users cant have the same pwd or id)...

anyways...off my box again

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Re: [PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Richard Davey
Hello Andy,

Thursday, March 25, 2004, 10:43:54 AM, you wrote:

AB So, just for the sake of me getting this right, it would be better code if i
AB had the code like this:

AB ?
AB $UserExists=mysql_query(select * from users where
AB username='$_POST[username]' and pwd=md5($_POST[password]));

AB //since query is done see if the user exists
AB if($UserExists) {
AB ExistingUserCanDoSomething(); }
AB else {
AB YouCantDoAnythingIfYouDontExist(); }
?

Do you actually need to bring back the user data? What I mean is,
you're selecting * from the users table and doing nothing with it
other than worrying if the query was successful or not.

It would make far more sense if you just did this:

SELECT COUNT(username) AS hits FROM users WHERE ...

Providing your query syntax is good this will always return a value in
hits. A zero means no users, anything above and you've got a live
one.

Also - I doubt I need to mention this, but you're injecting POST
variables directly into a SQL query. I hope your example above was
just that and isn't the actual way you're doing it?

AB and $UserExists in this example is either true or false because empty set
AB in mysql isnt even a number it = NULL

$UserExists in your example will never be TRUE, it can only ever be
FALSE. mysql_query does not, under any circumstances, return a boolean
TRUE value. It either returns a FALSE (if it was a select query) or a
*resource identifier* regardless of empty sets.

Sometimes if this resource identifier equals the value of 1 then a
loose comparison to true might exist, but only because PHP is determining
this value as such, not because it really is a true boolean value.

In the example above, providing all the data is given (username and
password) the query will return what appears to be TRUE regardless
of what happens. Imagine you have a user bob in your database and
his password is hi, look at the two following queries:

SELECT * FROM users WHERE username='bob' AND password='hi'
SELECT * FROM users WHERE username='bob' AND password='incorrect'

Both of them will make mysql_query return a resource identifier
because they are both correct from a syntax point of view. But in
actual fact they're telling you two completely different things.

Without doing a COUNT or knowing how many rows the query returned, you
cannot determine if the user does already exist or not, all you can
tell is if your query worked and an invalid user does not = an invalid
query.

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[PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Andy B
Do you actually need to bring back the user data? What I mean is,
you're selecting * from the users table and doing nothing with it other than
worrying if the query was successful or not.

ops!! I forgot to mention that the username is used elsewhere in a different
file somewhere (to verify the session exists and stuff). thats the only
thing directly used elsewhere... as far as the password thing goes it needs
to know if they put in the right username and password (i.e. a row that has
the username/password they put in).

It would make far more sense if you just did this:

SELECT COUNT(username) AS hits FROM users WHERE ...

dont know because then how would i verify that the valid user was logged in
or if they typed the wrong stuff in??

Providing your query syntax is good this will always return a value in
hits. A zero means no users, anything above and you've got a live
one.

very true...might come in handy for the register a user part

Also - I doubt I need to mention this, but you're injecting POST
variables directly into a SQL query. I hope your example above was
just that and isn't the actual way you're doing it?

yikes!! good thing this is just a testing site...how to insert them if
$_POST isnt the right way then??

and $UserExists in this example is either true or false because empty set
in mysql isnt even a number it = NULL
$UserExists in your example will never be TRUE, it can only ever be
FALSE. mysql_query does not, under any circumstances, return a boolean
TRUE value. It either returns a FALSE (if it was a select query) or a
*resource identifier* regardless of empty sets.

Can we disagree here? if i take my original query (at the top of this email)
and assign the result of it to a variable $UserExists like we did above and
test it:
if($UserExists) {//assuming the server found anything to start with
echo $UserExists;
//fortunately the server found a match somewhere because
//the result of printing $UserExists is Resource id #4
} else {//what if the server couldnt find a valid row??
echo $UserExists;//results in a blank screen assuming the
//server couldnt create the resource id because of no valid
//matching rows
}
on the other hand if i didthis:
if(num_of_rows($UserExists){
echo num_of_rows($UserExists);//will get 1
} else {
echo num_of_rows($UserExists);//will get: warning: not a
//valid resource identifier for num_of_rows
}

now if i just did: select * from users for num_of_rows i would get 3 for an
answer because there are 3 rows in the table... and the else part would
never be used...

Sometimes if this resource identifier equals the value of 1 then a loose
comparison to true might exist, but only because PHP is determining this
value as such, not because it really is a true boolean value.

if that is so, then how do you explain the above??

In the example above, providing all the data is given (username and
password) the query will return what appears to be TRUE regardless
of what happens. Imagine you have a user bob in your database and
his password is hi, look at the two following queries:

again, explain the above...

SELECT * FROM users WHERE username='bob' AND password='hi'
SELECT * FROM users WHERE username='bob' AND password='incorrect'

different for sure...if your saying that i would still get a resource id
from both of those on my example then why does it somehow know the
difference?

Both of them will make mysql_query return a resource identifier

not if the comparison between the username/pwd from the form and the db are
different...then they wouldnt be the same thing (thats why i compare the
username against the password)

because they are both correct from a syntax point of view. But in
actual fact they're telling you two completely different things.

agree but im not testing the syntax

Without doing a COUNT or knowing how many rows the query returned, you
cannot determine if the user does already exist or not, all you can
tell is if your query worked and an invalid user does not = an invalid
query.

sorry for repeating but somehow it knows the difference...

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Re: [PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Richard Davey
Hello Andy,

Thursday, March 25, 2004, 11:57:09 AM, you wrote:

AB SELECT COUNT(username) AS hits FROM users WHERE ...

AB dont know because then how would i verify that the valid user was logged in
AB or if they typed the wrong stuff in??

Because it works like this:

SELECT COUNT(username) AS hits FROM users WHERE username='$u' AND
password='$p'

So.. if hits = 0, then no user with that username and password
combination exists.

If hits = 1 (or more!) then the user exists and their password
matches.

MySQL will run a COUNT query much faster than a SELECT, especially if
you have the main columns indexes.

AB yikes!! good thing this is just a testing site...how to insert them if
AB $_POST isnt the right way then??

Extract the values before-hand:

$username = $_POST['username'];

Now run tests on $username.

For example - should it be a minimum of 3 characters? If so, use
strlen to test this. Should it most certainly not contain HTML? Then
run it through strip_tags. Remove any extra spaces that might be
entered with trim(). Etc etc - you get the idea :) The final $username
can be fed into your query far more safely than before.

AB Can we disagree here? if i take my original query (at the top of this email)
AB and assign the result of it to a variable $UserExists like we did above and
AB test it:
AB if($UserExists) {//assuming the server found anything to start with
AB echo $UserExists;
AB //fortunately the server found a match somewhere because
AB //the result of printing $UserExists is Resource id #4

This doesn't mean the server found a match, it means your query didn't
have any SQL syntax errors in it. An empty set is still a valid
resource, but it doesn't mean the given user does (or does not) exist.

AB now if i just did: select * from users for num_of_rows i would get 3 for an
AB answer because there are 3 rows in the table... and the else part would
AB never be used...

You're not counting how many users are in the table, you're counting
to see if the username and password you gave exists, like so:

SELECT * FROM users WHERE username='$username' AND
password='$password'

Then you check mysql_num_rows.

It will equal 0 if no user was found matching your combination, or it
will return a number. If you have set your table so that Username must
be unique (which would be a sensible thing to do) then it could only
ever return a 0 or a 1.

AB Sometimes if this resource identifier equals the value of 1 then a loose
AB comparison to true might exist, but only because PHP is determining this
AB value as such, not because it really is a true boolean value.

AB if that is so, then how do you explain the above??

Like I said, PHP is turning your resource identifier into a boolean
and assuming anything  0 is TRUE.

AB not if the comparison between the username/pwd from the form and the db are
AB different...then they wouldnt be the same thing (thats why i compare the
AB username against the password)

The MySQL query function doesn't care about the query itself, it's
just a means to pass it to the database. The result doesn't contain
any row information at all, just a resource which PHP uses to retrieve
the data via further functions.

See the following code I just wrote to double-check this:

First I created a MySQL database + table as such:

CREATE DATABASE test
CREATE TABLE `users` (`username` VARCHAR (30), `password` CHAR (32)) 
INSERT INTO users (username, password) VALUES ('rich', 
'e1bfd762321e409cee4ac0b6e841963c')
INSERT INTO users (username, password) VALUES ('andy', 
'81c3b080dad537de7e10e0987a4bf52e')

There we have 2 users (rich and andy), the passwords are MD5 hashes of
php and mysql. I.e. the password for rich is php and andy is
mysql.

You can save the following HTML/PHP into a file somewhere in your web
directory, it should run without modification other than perhaps the
MySQL server/username/password.

-- Cut from here --
html
head
titleMySQL Test/title
/head

body

form action=?=$_SERVER['PHP_SELF']? method=post
Username: input type=text name=usernamebr
Password: input type=text name=passwordbr
input type=submit
/form

?php
mysql_connect('localhost','root','');
mysql_select_db('test');

$username = $_POST['username'];
$password = $_POST['password'];

$sql = SELECT * FROM users WHERE username='$username' AND 
password=MD5('$password');

if (isset($_POST['username']))
{
$result = mysql_query($sql);
echo $result . br;
}

echo pre;
print_r($_POST);
echo /pre;

echo Rows Returned:  . mysql_num_rows($result) . br;

echo Comparing \$result to TRUE: if (\$result) : br;
if ($result)
{
echo Valid user;
} else {
echo Error?;
}
?
/body
/html
-- End here --

Now if what you're saying is correct, the final if result() block
should only print valid user if the user exists in the 

[PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Andy B
if ($result)
{
echo Valid user;
} else {
echo Error?;
}
?
/body
/html
-- End here --

Now if what you're saying is correct, the final if result() block
should only print valid user if the user exists in the database,
right?

yup and believe it or not if($result) only returns true if a valid
username/password row can be found otherwise it returns a non existing
resource

For me it'll print valid user no matter what I do because the query is
always valid and that is all it's checking.

hmmm interesting... in your example of usernames here, when i type andy for
username and mysql for password it says valid user. now say i type andy
for a username and junk for a password it will now say error? because in
mysql's mind set there isnt any row anywhere that exists with andy for a
username and junk for a password. now take it the other way around: i type
useless for a username and mysql for a password and then it still says:
error?...
it seems that no matter what i do (unless you directly spoof the mysql
server) it cannt be fooled at all... at this point it is acting like it is
indistructable (i know what a wild dream) but have to have one for a min ...
in any case i cant find any loop holes in it anywhere... the only thing i
see i can do to reduce risk of hacks or possible outside interference is to
turn $result in your example into a session var $_SESSION['result']. since
$result can be changed from the query string from a link (wait testing...)
well doesnt exactly work but crashes it instead being a global like that...

If I enter a valid username and password combo the result is reflected
in mysql_num_rows, as shown in the code.

yup...it does on mine too... just like you say

Unless I have missed something significant from your original code/query
I'm at a complete loss as to how the above can give you any kind of
different result?

thats a good question i cant even answer...




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Re: [PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Richard Davey
Hello Andy,

Thursday, March 25, 2004, 1:17:54 PM, you wrote:

AB yup and believe it or not if($result) only returns true if a valid
AB username/password row can be found otherwise it returns a non existing
AB resource

Absolutely fascinating, I have never seen a MySQL server behave like
this. Could you post which version of MySQL you're using and perhaps
the MySQL part of phpinfo()? There must be something *somewhere* that
controls this behaviour.

All I can say for certainty is that if I uploaded your code onto my
web host, it'd fail. So long as you're building this in a controlled
environment and you know where it's going to go when it's live, then I
guess you can exploit this to its full potential.

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[PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Andy B
Absolutely fascinating, I have never seen a MySQL server behave like
this. Could you post which version of MySQL you're using and perhaps
the MySQL part of phpinfo()? There must be something *somewhere* that
controls this behaviour.

PHP Version 4.0.4pl1
Linux noir.propagation.net 2.0.36 #5 Wed Dec 16 18:09:02 CST 1998 i686
unknown
Apr 10 2001

Configure Command
'./configure' '--with-apache=../apache_1.3.19'
'--with-config-file-path=/etc' '--with-msql' '--without-gd'

PHP Core

Table with 3 columns and 59 rows

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On
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allow_url_fopen
1
1

arg_separator



asp_tags
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auto_append_file
no value
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auto_prepend_file
no value
no value

browscap
no value
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default_charset
no value
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default_mimetype
text/html
text/html

define_syslog_variables
Off
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disable_functions
no value
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display_errors
On
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display_startup_errors
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doc_root
no value
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enable_dl
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error_log
no value
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error_prepend_string
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error_reporting
no value
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expose_php
On
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extension_dir
/usr/local/lib/php/extensions/no-debug-non-zts-20001214
/usr/local/lib/php/extensions/no-debug-non-zts-20001214

file_uploads
1
1

gpc_order
GPC
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highlight.bg
#FF
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highlight.comment
#FF8000
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highlight.default
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highlight.html
#00
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highlight.keyword
#007700
#007700

highlight.string
#DD
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html_errors
On
On

ignore_user_abort
Off
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implicit_flush
Off
Off

include_path
.:/usr/local/lib/php
.:/usr/local/lib/php

log_errors
Off
Off

magic_quotes_gpc
On
On

magic_quotes_runtime
Off
Off

magic_quotes_sybase
Off
Off

max_execution_time
30
30

open_basedir
no value
no value

output_buffering
Off
Off

output_handler
no value
no value

post_max_size
8M
8M

precision
14
14

register_argc_argv
On
On

register_globals
On
On

safe_mode
Off
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1
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no value
no value

sendmail_path
/usr/sbin/sendmail -t -i
/usr/sbin/sendmail -t -i

short_open_tag
On
On

SMTP
localhost
localhost

sql.safe_mode
Off
Off

track_errors
Off
Off

upload_max_filesize
2M
2M

upload_tmp_dir
no value
no value

user_dir
no value
no value

variables_order
no value
no value

y2k_compliance
Off
Off
table end

mysql

Table with 2 columns and 7 rows

MySQL Support
enabled

Active Persistent Links
0

Active Links
0

Client API version
3.23.22-beta

MYSQL_INCLUDE


MYSQL_LFLAGS


MYSQL_LIBS

table end

Table with 3 columns and 9 rows

Directive
Local Value
Master Value

mysql.allow_persistent
On
On

mysql.default_host
no value
no value

mysql.default_password
no value
no value

mysql.default_port
no value
no value

mysql.default_socket
no value
no value

mysql.default_user
no value
no value

mysql.max_links
Unlimited
Unlimited

mysql.max_persistent
Unlimited
Unlimited
table end

interesting...seems to be pretty much the default install of all of it
but
All I can say for certainty is that if I uploaded your code onto my
web host, it'd fail. So long as you're building this in a controlled
environment and you know where it's going to go when it's live, then I
guess you can exploit this to its full potential.

i always fully test my code before i run it

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Re: [PHP] re:[PHP] login problem fixed!!

2004-03-25 Thread Richard Davey
Hello Andy,

Thursday, March 25, 2004, 5:45:52 PM, you wrote:

AB PHP Version 4.0.4pl1

Wow, that's an old version of PHP! It could be the cause of this,
there's nothing in you phpinfo to give anything else away (i.e. it's
identical to mine).

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Best regards,
 Richard Davey
 http://www.phpcommunity.org/wiki/296.html

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[PHP] RE:[PHP] login scripts not secure?? help!

2004-03-23 Thread Andy B
[snip]
There is no way to inject any kind of data to the super-global Arrays at all
[snip]

duhhh...how come i didnt think of that... well..guess its long nights
without coffee.. tnx...

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[PHP] Re: php login scripts

2002-01-27 Thread John Cuthbert

$user = $HTTP_GET_VARS[user];
$pass = $HTTP_GET_VARS[pass];

$real =  superduperunlieklytobeguesedpass;
if($user == $validuser  $pass == $real)
{
echo thank you for logging in here is the page;
?
HTML
etc
?php } else {
die(You supid idiot thats not a valid login);
?
and call the page as
http://superdomain.com/login.php?user=Imasuperduperuserpass=superduperunlie
klytobeguesedpass

You'd need to alter it obviously. Its good for secureing one page if you
want multi page you ... need to work on Sessions :S Im working on em now :S
scarry stuff :S

Laserjetter [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Depending on how secure the login information needs to be, you could just
 store it in a text file, maybe using password() to encrypt passwords. You
 could then access it using fopen() and save the contents of the file in an
 array.

 I'm not too hot on login and authentication though myself! I did get it
 working, there was a useful example in the PHP manual.

 LJ

 XX XX [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  hi. im new. i installed a login script on my site and after a few days,
it
  stopped working. i reinstalled it and it still refused to work after a
dew
  days. can anyone send me a good login script preferably with no MySql?
im
  very busy atm with all my school stuff.
 
  Thanks
  aron
 
  _
  Get your FREE download of MSN Explorer at
 http://explorer.msn.com/intl.asp.
 





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[PHP] Re: php login scripts

2002-01-21 Thread LaserJetter

Depending on how secure the login information needs to be, you could just
store it in a text file, maybe using password() to encrypt passwords. You
could then access it using fopen() and save the contents of the file in an
array.

I'm not too hot on login and authentication though myself! I did get it
working, there was a useful example in the PHP manual.

LJ

XX XX [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 hi. im new. i installed a login script on my site and after a few days, it
 stopped working. i reinstalled it and it still refused to work after a dew
 days. can anyone send me a good login script preferably with no MySql? im
 very busy atm with all my school stuff.

 Thanks
 aron

 _
 Get your FREE download of MSN Explorer at
http://explorer.msn.com/intl.asp.




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