[PHP] Re: syntax help

If you want to actually want the variables $flyertotal, $emailtotal, and $phonetotal, use the line: ${$array[0]."total"} = $row[0]; But as you defined $array, that will actually create the variables $Flyertotal, $Emailtotal, and $Phonetotal (note the caps). On 2/13/2004 6:10 AM, Bob pilly wrot

Re: [PHP] Re: syntax help~~~

At 06.08.2001 10:31, you wrote: >Hi.. >I just wanna laugh really want to laugh WUWUAHAHAHAHAHA >I have figure out the solution amazingly! here will be the code I am > running >LoL it works without separating the code if you add the ; at the end of the $temp = $username."watch" l

[PHP] Re: syntax help~~~

Hi.. I just wanna laugh really want to laugh WUWUAHAHAHAHAHA I have figure out the solution amazingly! here will be the code I am running LoL I separated the query code with the database connection coding LoL after that.. its work! Thanks for everyone who help me :) Regards Ko

[PHP] Re: syntax help~~~

Hello ! We could keep things simpler ... Why not give a try to this ?: $watchlist_query = mysql_query( "Create Table $temp ( WId int Not Nullauto_increment, QId int not null, Primary Key (WId) )" ) or die ("Error ! Cannot create table !" . mysql_error() ); Hope it would work :o) (At least th