Re: [PHP] fgetcsv doesn't return an array?
On Thu, 15 Mar 2012 12:09:53 -0500, Jay Blanchard jay.blanch...@sigmaphinothing.org sent: I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay | Just want to clarify something not directly related to the OP's question: This: 153 |$csvCurrentLine = array(); Does not set a *type* for $csvCurrentLine, so if you're next line is this: 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); Any previous assignments are lost; the notion that presetting $csvCurrentLine to an array has no bearing when you then immediately set the same variable to something else. The type $csvCurrentLine has after line 154 is entirely dependent on what fgetcsv() is returning, and nothing that happened prior to line 154. -- Tamara Temple aka tamouse__ May you never see a stranger's face in the mirror -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv doesn't return an array?
Tamara Temple wrote: On Thu, 15 Mar 2012 12:09:53 -0500, Jay Blanchard jay.blanch...@sigmaphinothing.org sent: I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154$csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155$currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Just want to clarify something not directly related to the OP's question: This: 153 |$csvCurrentLine = array(); Does not set a *type* for $csvCurrentLine, so if you're next line is this: 154$csvCurrentLine = fgetcsv($csvFile, 4096, ','); Any previous assignments are lost; the notion that presetting $csvCurrentLine to an array has no bearing when you then immediately set the same variable to something else. The type $csvCurrentLine has after line 154 is entirely dependent on what fgetcsv() is returning, and nothing that happened prior to line 154. In this case, Jay's attempt to fix the problem was simply wrong. fgetcsv may well not return an array, and the error in this code was simply that situation. If an array is not returned by fgetcsv then there was an error, hence line 155 fails every time you hit the 'EOF' condition. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk// Firebird - http://www.firebirdsql.org/index.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv doesn't return an array?
[snip] Not sure why, but ok. Thanks everyone! An empty line would lead to $csvCurrentLine == array() which as a boolean would be false but would not necessarily mean EOF. By using === to check the value the expression will only evaluate to false at EOF or an error. -Stuart [/snip] Makes perfect sense! I just wasn't reading it right. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv doesn't return an array?
I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay |
Re: [PHP] fgetcsv doesn't return an array?
On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard jay.blanch...@sigmaphinothing.org wrote: I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay | Are you using this in a loop or something? fgetcsv returns FALSE on errors, including End Of File. - Matijn -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv doesn't return an array?
On 3/15/2012 12:23 PM, Matijn Woudt wrote: On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard jay.blanch...@sigmaphinothing.org wrote: I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay | Are you using this in a loop or something? fgetcsv returns FALSE on errors, including End Of File. [/snip] I am using it in a loop. End Of File is an error? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv doesn't return an array?
On 03/15/2012 10:09 AM, Jay Blanchard wrote: I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(,, $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay | From the manual fgetcsv() returns NULL if an invalid handle is supplied or FALSE on other errors, including end of file. do this 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); var_dump($csvCurrentLine); 155 $currentLine = implode(,, $csvCurrentLine); What does it say about the variable from the failing line? -- Jim Lucas http://www.cmsws.com/ http://www.cmsws.com/examples/ http://www.bendsource.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv doesn't return an array?
On Thu, Mar 15, 2012 at 1:29 PM, Jay Blanchard
jay.blanch...@sigmaphinothing.org wrote:
On 3/15/2012 12:23 PM, Matijn Woudt wrote:
On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard
jay.blanch...@sigmaphinothing.org wrote:
I thought that fgetcsv returned an array. I can work with it like an
array
but I get the following warning when using it
|Warning: implode(): Invalid arguments passed on line 155
154 $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
155 $currentLine = implode(,, $csvCurrentLine);
|
Everything that I have read online indicates that it is because
$csvCurrentLine is not declared as an array. Adding a line to the code
153 |$csvCurrentLine = array();
Does not get rid of the warning. The warning isn't interfering with the
script working, but it us annoying. Does anyone know the solution?
Thanks!
Jay
|
Are you using this in a loop or something? fgetcsv returns FALSE on
errors, including End Of File.
[/snip]
I am using it in a loop. End Of File is an error?
Yes. fgetcsv() returns NULL if an invalid handle is supplied or
FALSE on other errors, including end of file.
I usually use it in a while loop like this:
?php
while ($row = fgetcsv($csvFilePointer)) {
// ... process the row
}
?
Andrew
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Re: [PHP] fgetcsv doesn't return an array?
Jay Blanchard wrote:
154 $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
155 $currentLine = implode(,, $csvCurrentLine);
I am using it in a loop. End Of File is an error?
You certainly need to break out on $csvCurrentLine = false which indicates end
of file at least.
My own 'loop' is
$row=0;
while (($data = fgetcsv($handle, 800, ,)) !== FALSE) {
if ( $row ) $contact-RecordLoad( $data, $row );
$row++;
}
The row bit strips the header line from the csv file ...
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Re: [PHP] fgetcsv doesn't return an array?
On Thu, Mar 15, 2012 at 6:40 PM, Andrew Ballard aball...@gmail.com wrote:
On Thu, Mar 15, 2012 at 1:29 PM, Jay Blanchard
jay.blanch...@sigmaphinothing.org wrote:
On 3/15/2012 12:23 PM, Matijn Woudt wrote:
On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard
jay.blanch...@sigmaphinothing.org wrote:
I thought that fgetcsv returned an array. I can work with it like an
array
but I get the following warning when using it
|Warning: implode(): Invalid arguments passed on line 155
154 $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
155 $currentLine = implode(,, $csvCurrentLine);
|
Everything that I have read online indicates that it is because
$csvCurrentLine is not declared as an array. Adding a line to the code
153 |$csvCurrentLine = array();
Does not get rid of the warning. The warning isn't interfering with the
script working, but it us annoying. Does anyone know the solution?
Thanks!
Jay
|
Are you using this in a loop or something? fgetcsv returns FALSE on
errors, including End Of File.
[/snip]
I am using it in a loop. End Of File is an error?
Yes. fgetcsv() returns NULL if an invalid handle is supplied or
FALSE on other errors, including end of file.
I usually use it in a while loop like this:
?php
while ($row = fgetcsv($csvFilePointer)) {
// ... process the row
}
?
Please, don't do that. Use this instead:
while (($csvCurrentLine = fgetcsv($csvFile, 4096, ',')) !== FALSE) {
}
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Re: [PHP] fgetcsv doesn't return an array?
[snip]
Please, don't do that. Use this instead:
while (($csvCurrentLine = fgetcsv($csvFile, 4096, ',')) !== FALSE) {
}
[/snip]
Not sure why, but ok. Thanks everyone!
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Re: [PHP] fgetcsv doesn't return an array?
On 15 Mar 2012, at 20:26, Jay Blanchard wrote:
[snip]
Please, don't do that. Use this instead:
while (($csvCurrentLine = fgetcsv($csvFile, 4096, ',')) !== FALSE) {
}
[/snip]
Not sure why, but ok. Thanks everyone!
An empty line would lead to $csvCurrentLine == array() which as a boolean would
be false but would not necessarily mean EOF. By using === to check the value
the expression will only evaluate to false at EOF or an error.
-Stuart
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[PHP] fgetcsv
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
//Common for all trials
$demoID = fopen(newDemoID.csv, r);;
$ID = 43;
$data = fgetcsv($demoID);
First try with while:
/*
while ($data) {
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] .
.\n;
}
}
*/
Takes for every.
I can't use just the below because it only compares the first row.
/*
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] . .\n;
}
*/
I know this is simple, but I've hit codes block due to lack of sleep.
Thanks,
Dan
Sample Data:
5,1,Smith,Myrtle
6,2,Smith,Carita
7,3,Smith,Paul
8,4,Smith,Donald
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Re: [PHP] fgetcsv
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
//Common for all trials
$demoID = fopen(newDemoID.csv, r);;
$ID = 43;
$data = fgetcsv($demoID);
First try with while:
/*
while ($data) {
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] .
.\n;
}
}
*/
Takes for every.
I can't use just the below because it only compares the first row.
/*
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] . .\n;
}
*/
I know this is simple, but I've hit codes block due to lack of sleep.
Thanks,
Dan
Sample Data:
5,1,Smith,Myrtle
6,2,Smith,Carita
7,3,Smith,Paul
8,4,Smith,Donald
Maybe try something like this.
?php
//Common for all trials
$fh = fopen(newDemoID.csv, r);;
# What we are looking for
$ID = 43;
# check for valid handle
if ( is_resource($fh) ) {
# Loop through file handler
# if we get data, we check it
# if/when we get false, we break out of the while loop
while ( ($data = fgetcsv($fh) ) !== false ) {
# Check for the value you are looking for.
if ( $data[0] == $ID ) {
# Obvious...
echo {$data[1]},{$data[2]},{$data[3]}\n;
}
}
fclose($fh);
}
?
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Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
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Re: [PHP] fgetcsv
On Jan 9, 2008 5:35 PM, Danny Brow [EMAIL PROTECTED] wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
//Common for all trials
$demoID = fopen(newDemoID.csv, r);;
$ID = 43;
$data = fgetcsv($demoID);
First try with while:
/*
while ($data) {
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] .
.\n;
}
}
*/
As an alternative, you could try this:
?
$wolfID = 43;
$data = file_get_contents($filename);
$line = explode(\n,$data);
for($i=0;$icount($line);$i++) {
$field = explode(,,$line[$i]); // Replace the comma with your separator.
$match = str_replace(','',str_replace('','',$field[0])); //
Strip quotes, if they exist.
if($match == $wolfID) {
echo $line[$i].\n;
}
}
?
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Daniel P. Brown
Senior Unix Geek and #1 Rated Year's Coolest Guy By Self Since 1979.
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Re: [PHP] fgetcsv
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
So are you trying to compare the first column or the first row? You've
said you want to compare both.
To compare the first row:
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_row = array('1','2','John Smith');
$data = fgetcsv($handle, 1000, ,);
if ($data === false) {
echo Unable to get anything from the file.;
}
if (is_array($data)) {
if ($data == $my_row) {
echo The first row matched\n;
} else {
echo The first row didnt match\n;
}
}
fclose($handle);
If you really do want to compare the first column, then the time to do
it will be based on how big the csv file is. If you have a big file,
it's going to take a long time to go through each row and then look at
the first field.
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_value = '1';
$row_count = 0;
while (($data = fgetcsv($handle, 1000, ,)) !== FALSE) {
$row_count++;
if ($data[0] == $my_value) {
echo Found my_value on row , $row_count, \n;
} else {
echo Did not find my_value on row , $row_count, \n;
}
}
fclose($handle);
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Re: [PHP] fgetcsv
I need to compare the first field of each row. But this idea is shot to
hell, i've been running one of the examples on the file and it's been
about an hour+ already... 6500 records have to be checked... I think
MySQL is calling my name right now.
Thanks,
Dan
On Thu, 2008-01-10 at 09:59 +1100, Chris wrote:
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
So are you trying to compare the first column or the first row? You've
said you want to compare both.
To compare the first row:
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_row = array('1','2','John Smith');
$data = fgetcsv($handle, 1000, ,);
if ($data === false) {
echo Unable to get anything from the file.;
}
if (is_array($data)) {
if ($data == $my_row) {
echo The first row matched\n;
} else {
echo The first row didnt match\n;
}
}
fclose($handle);
If you really do want to compare the first column, then the time to do
it will be based on how big the csv file is. If you have a big file,
it's going to take a long time to go through each row and then look at
the first field.
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_value = '1';
$row_count = 0;
while (($data = fgetcsv($handle, 1000, ,)) !== FALSE) {
$row_count++;
if ($data[0] == $my_value) {
echo Found my_value on row , $row_count, \n;
} else {
echo Did not find my_value on row , $row_count, \n;
}
}
fclose($handle);
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Re: [PHP] fgetcsv
Danny Brow wrote:
I need to compare the first field of each row. But this idea is shot to
hell, i've been running one of the examples on the file and it's been
about an hour+ already... 6500 records have to be checked... I think
MySQL is calling my name right now.
Thanks,
Dan
On Thu, 2008-01-10 at 09:59 +1100, Chris wrote:
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE (example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of the
following.
So are you trying to compare the first column or the first row? You've
said you want to compare both.
To compare the first row:
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_row = array('1','2','John Smith');
$data = fgetcsv($handle, 1000, ,);
if ($data === false) {
echo Unable to get anything from the file.;
}
if (is_array($data)) {
if ($data == $my_row) {
echo The first row matched\n;
} else {
echo The first row didnt match\n;
}
}
fclose($handle);
If you really do want to compare the first column, then the time to do
it will be based on how big the csv file is. If you have a big file,
it's going to take a long time to go through each row and then look at
the first field.
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_value = '1';
$row_count = 0;
while (($data = fgetcsv($handle, 1000, ,)) !== FALSE) {
$row_count++;
if ($data[0] == $my_value) {
echo Found my_value on row , $row_count, \n;
} else {
echo Did not find my_value on row , $row_count, \n;
}
}
fclose($handle);
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even on a slow machine 6500 records should be very fast.
Are you doing this through a web interface or command line?
If browser, are you sure that your script is still running? Could the PHP
timeout be exceeded?
Try the other example that I gave you.
pre?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$st = microtime(true);
$file = '/tmp/testing.csv';
$fh = fopen($file, w+) or die('Could not open new file for writing');
for ( $i=0; $i1; $i++ ) {
fputcsv($fh, array($i,1,Smith{$i},Myrtle{$i}));
}
fclose($fh);
//Common for all trials
$fh = fopen($file, r) or die('Could not open file ({$file}) for reading');
# What we are looking for
$ID = ;
# Loop through file handler
# if we get data, we check it
# if/when we get false, we break out of the while loop
while ( ($data = fgetcsv($fh) ) !== false ) {
# Check for the value you are looking for.
if ( $data[0] == $ID ) {
# Obvious...
echo {$data[0]},{$data[1]},{$data[2]},{$data[3]}\n;
}
}
fclose($fh);
echo Run time was .round(microtime(true) - $st, 6). seconds.;
?
I looked for the last result, time for me was
,1,Smith,Myrtle
Run time was 0.04 seconds.
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and some have greatness thrust upon them.
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by William Shakespeare
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RE: [PHP] fgetcsv
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Re: [PHP] fgetcsv
On Wed, January 9, 2008 4:35 pm, Danny Brow wrote:
I'm trying to compare a value to the first field in a csv fILE
(example
of the data below). Using while takes too long and I can't figure out
how to compare just one row at a time. I've tried some variations of
the
following.
//Common for all trials
$demoID = fopen(newDemoID.csv, r);;
$ID = 43;
$data = fgetcsv($demoID);
First try with while:
/*
while ($data) {
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] .
.\n;
}
}
*/
Takes for every.
*IF* the line you are looking for is almost always in the early rows,
and *IF* you only need the first match,
you can use the above and put a break; inside the if { }
This will let the script end as soon as it finds the answer.
You do have another $data = fgetcsv($demoID); inside the while loop,
right?
Otherwise you are looking at the same first line over and over and
over and over and over until PHP gives up on you.
I can't use just the below because it only compares the first row.
/*
if ($data[0] == $wolfID) {
print $data[1] . , . $data[2] . , . $data[3] . .\n;
}
*/
I know this is simple, but I've hit codes block due to lack of sleep.
It's actually not simple at all, since you are trying to scan through
a large file (it must be large to take a long time) and find only one
chunk at the beginning of a row.
There are several other techniques to consider:
#1.
Put the data into an SQL database before you try to search for
specific field/value information.
SQL was designed to make this stuff fast.
CSV was designed to dump files out to pass between
spreadsheets/databases.
#2.
*IF* the file isn't TOO large compared to your available RAM, you
could load the whole thing with file_get_contents and then do some
preg magic to find the line you want:
$file = file_get_contents(/full/path/to/file);
preg_match(/^$wolfID,.*\$/ms, $file, $match);
var_dump($match);
//use preg_match_all to find ALL the lines that match
#3.
*IF* the file is too large, and *IF* the CSV parsing is the slow part
(which I doubt) it's possible that a simple fgets() and simple check
sch as:
if (substr($line, 0, strlen($wolfID)) == $wolfID)
would be faster...
Actually, pull the strlen($wolfID) out of the loop into a variable,
and maybe use strpos instead of substr instead and...
The biggest time sink is probably reading the file line by line,
though, not the actual processing which is pretty minimal... In which
case this solution will probably not significantly beat your current
time.
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Re: [PHP] fgetcsv
6500 rows is chump-change.
You probably don't have the fgetcsv inside the while loop to get past
the first row... :-)
On Wed, January 9, 2008 6:09 pm, Danny Brow wrote:
I need to compare the first field of each row. But this idea is shot
to
hell, i've been running one of the examples on the file and it's been
about an hour+ already... 6500 records have to be checked... I think
MySQL is calling my name right now.
Thanks,
Dan
On Thu, 2008-01-10 at 09:59 +1100, Chris wrote:
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE
(example
of the data below). Using while takes too long and I can't figure
out
how to compare just one row at a time. I've tried some variations
of the
following.
So are you trying to compare the first column or the first row?
You've
said you want to compare both.
To compare the first row:
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_row = array('1','2','John Smith');
$data = fgetcsv($handle, 1000, ,);
if ($data === false) {
echo Unable to get anything from the file.;
}
if (is_array($data)) {
if ($data == $my_row) {
echo The first row matched\n;
} else {
echo The first row didnt match\n;
}
}
fclose($handle);
If you really do want to compare the first column, then the time to
do
it will be based on how big the csv file is. If you have a big file,
it's going to take a long time to go through each row and then look
at
the first field.
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_value = '1';
$row_count = 0;
while (($data = fgetcsv($handle, 1000, ,)) !== FALSE) {
$row_count++;
if ($data[0] == $my_value) {
echo Found my_value on row , $row_count, \n;
} else {
echo Did not find my_value on row , $row_count, \n;
}
}
fclose($handle);
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RE: [PHP] fgetcsv
Um, I've read the manual. On Wed, 2008-01-09 at 20:11 -0500, Bastien Koert wrote: http://ca.php.net/manual/en/function.fgetcsv.php _ Discover new ways to stay in touch with Windows Live! Visit the City @ Live today! http://getyourliveid.ca/?icid=LIVEIDENCA006 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv
You are so right, takes all of 0.122 s to process the whole file with
the fgetcsv inside the while loop Guess I need to look up why this
was the problem.
Thanks everyone!
On Wed, 2008-01-09 at 20:59 -0600, Richard Lynch wrote:
6500 rows is chump-change.
You probably don't have the fgetcsv inside the while loop to get past
the first row... :-)
On Wed, January 9, 2008 6:09 pm, Danny Brow wrote:
I need to compare the first field of each row. But this idea is shot
to
hell, i've been running one of the examples on the file and it's been
about an hour+ already... 6500 records have to be checked... I think
MySQL is calling my name right now.
Thanks,
Dan
On Thu, 2008-01-10 at 09:59 +1100, Chris wrote:
Danny Brow wrote:
Hi Everyone,
I'm trying to compare a value to the first field in a csv fILE
(example
of the data below). Using while takes too long and I can't figure
out
how to compare just one row at a time. I've tried some variations
of the
following.
So are you trying to compare the first column or the first row?
You've
said you want to compare both.
To compare the first row:
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_row = array('1','2','John Smith');
$data = fgetcsv($handle, 1000, ,);
if ($data === false) {
echo Unable to get anything from the file.;
}
if (is_array($data)) {
if ($data == $my_row) {
echo The first row matched\n;
} else {
echo The first row didnt match\n;
}
}
fclose($handle);
If you really do want to compare the first column, then the time to
do
it will be based on how big the csv file is. If you have a big file,
it's going to take a long time to go through each row and then look
at
the first field.
?php
$handle = fopen('file.csv', 'r') or die(unable to open file);
$my_value = '1';
$row_count = 0;
while (($data = fgetcsv($handle, 1000, ,)) !== FALSE) {
$row_count++;
if ($data[0] == $my_value) {
echo Found my_value on row , $row_count, \n;
} else {
echo Did not find my_value on row , $row_count, \n;
}
}
fclose($handle);
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[PHP] fgetcsv() excel data missing
Hi all, I used fgetcsv() function to get the data from a excel file. While reading the data it shows some special characters . I found the same problems in http://bugs.php.net/bug.php?id=12127edit=2 Is it a bug? Plz help me. Binoy __ __ __ __ Sent via the WebMail system at softwareassociates.co.uk --- Scanned by MessageExchange.net (13:31:20 SPITFIRE) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] fgetcsv() excel data missing
[snip] I used fgetcsv() function to get the data from a excel file. While reading the data it shows some special characters . I found the same problems in http://bugs.php.net/bug.php?id=12127edit=2 Is it a bug? [/snip] What special characters does it show? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] fgetcsv() excel data missing
Hi,
Thanks for the reply.
It shows ÐÏࡱá\\þÿ etc.
source code I used is
$handle = fopen (file.xls,r);
while ($data = fgetcsv ($handle, 1000, ,))
{
$num = count($data);
for ($c=0; $c $num ; $c++)
{
$str_email = $data[$c];
echo $str_email;
}
}
Binoy
__ __ __ __
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RE: [PHP] fgetcsv() excel data missing
[snip]
Thanks for the reply.
It shows ÐÏࡱá\\þÿ etc.
source code I used is
$handle = fopen (file.xls,r);
while ($data = fgetcsv ($handle, 1000, ,))
{
$num = count($data);
for ($c=0; $c $num ; $c++)
{
$str_email = $data[$c];
echo $str_email;
}
}
[/snip]
You have to save the .xls file as a .csv file, then you can open and getcsv
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RE: [PHP] fgetcsv() excel data missing
Thanks Jay. Could anybody please tell me how to read the data from an excel file ? It should work independent of the operating system. I don't want the csv format. Binoy __ __ __ __ Sent via the WebMail system at softwareassociates.co.uk --- Scanned by MessageExchange.net (14:20:44 SPITFIRE) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] fgetcsv() excel data missing
[snip] Could anybody please tell me how to read the data from an excel file ? It should work independent of the operating system. I don't want the csv format. [/snip] Start here http://us4.php.net/com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv() excel data missing
Binoy AV wrote: Thanks Jay. Could anybody please tell me how to read the data from an excel file ? It should work independent of the operating system. I don't want the csv format. excel files aren't independent of the OS, csv files are. Excel files need to be parsed, because they contain heaps of formatting data. If you're using php on a windows OS, then you can use COM or .NET to read it in. On other systems however, you'll likely run into problems pretty quickly, and will most probably need to write your own parser routine Binoy __ __ __ __ Sent via the WebMail system at softwareassociates.co.uk --- Scanned by MessageExchange.net (14:20:44 SPITFIRE) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv() excel data missing
On Fri, 2005-02-18 at 09:12, M. Sokolewicz wrote: Binoy AV wrote: Thanks Jay. Could anybody please tell me how to read the data from an excel file ? It should work independent of the operating system. I don't want the csv format. excel files aren't independent of the OS, csv files are. Excel files need to be parsed, because they contain heaps of formatting data. If you're using php on a windows OS, then you can use COM or .NET to read it in. On other systems however, you'll likely run into problems pretty quickly, and will most probably need to write your own parser routine Not to mention the different versions of excel that alter the format. Bret -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] fgetcsv() excel data missing
Binoy AV wrote: Could anybody please tell me how to read the data from an excel file ? It should work independent of the operating system. I don't want the csv format. For your first step, you'll have to convince Microsoft to OpenSource their code... Oh, yeah. You can't do that. :-) -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv
Hello. I wonder if PHP has fgetcsv() function why doesn't PHP has fputcsv ? -- zhuravlev alexander u l s t u n o c ([EMAIL PROTECTED]) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv
zhuravlev alexander wrote: Hello. I wonder if PHP has fgetcsv() function why doesn't PHP has fputcsv ? -- zhuravlev alexander u l s t u n o c ([EMAIL PROTECTED]) because it would be bloat, basically. We now have file_put_contents in php5, which I like...but still view as bloat. You can easily enough use fopen and fwrite to add content to the csv file. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv quit working......
I have a customer who's webhost upgraded their server recently and a script that was working fine quit working. The error they are getting is this fgetcsv(): supplied argument is not a valid stream resource. I don't know what they did with Apache, but as far as I know, nothing else changed. Can anyone offer any advice on troubleshooting this one? Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv quit working......
Check to make sure the file exists, you should probably through some debug code around the area that is failing. Jason On Sun, 2003-03-09 at 18:50, CDitty wrote: I have a customer who's webhost upgraded their server recently and a script that was working fine quit working. The error they are getting is this fgetcsv(): supplied argument is not a valid stream resource. I don't know what they did with Apache, but as far as I know, nothing else changed. Can anyone offer any advice on troubleshooting this one? Chris -- Jason Sheets [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv quit working......
I thought about this possibility, but it turns out 4 different scripts on the same server accessing different files from different locations and using different methods are all failing. Chris At 07:53 PM 3/9/2003, Jason Sheets wrote: Check to make sure the file exists, you should probably through some debug code around the area that is failing. Jason On Sun, 2003-03-09 at 18:50, CDitty wrote: I have a customer who's webhost upgraded their server recently and a script that was working fine quit working. The error they are getting is this fgetcsv(): supplied argument is not a valid stream resource. I don't know what they did with Apache, but as far as I know, nothing else changed. Can anyone offer any advice on troubleshooting this one? Chris -- Jason Sheets [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv Help
Hello, Justin French [EMAIL PROTECTED] wrote: [snip] Sample line from your CSV should look like this: --- 1,foo,harry said \what is it?\,foo 1,bah,\don't know\ said sally,something --- When echoing these values to the browser, you would strip the slashes. [/snip] The double quotes aren't really necessary unless 1. You have a comma in the field 2. You have double quotes in the field So, 1,foo,Harry said what is it,foo would have no problem with fgetcsv(). And, btw, the are also escaped with another . - E -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv Help
I am parsing a csv file with fgetcsv and the fields are surrounding by double quotes, now I am running into a problem periodically that when there are quotes within the value it is treating it like another value instead of the same value. Any ideas on how to get around that? I am thinking I might have to convert all quotes to quot; and then turn all quot;,quot; back into quotes and then the first quot; in the file and then last one since obviously they will not have a comma in between them. This seems like a while lot of work.. Ideas? Rick A wise women once said: No one can help everybody, but everybody can help somebody. - Unknown -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv Help
Richard, I am parsing a csv file with fgetcsv and the fields are surrounding by double quotes, now I am running into a problem periodically that when there are quotes within the value it is treating it like another value instead of the same value. Any ideas on how to get around that? I am thinking I might have to convert all quotes to quot; and then turn all quot;,quot; back into quotes and then the first quot; in the file and then last one since obviously they will not have a comma in between them. This seems like a while lot of work.. Ideas? The first idea is that the system that outputs a .CSV with quotes within a quoted field is broken big-time and that's the part that needs fixing! I'm on the same wavelength as you describe: you can't use any automated csv function on such a file. Quotes should only appear in pairs. The closing quote must therefore appear immediately prior to a field separator (eg comma) - whitespace not withstanding, unless it is the last field on a line, in which case it will appear immediately prior to a record separator. One possibility is to write a 'filter' script to do this - and thus leave your existing code intact. The filter could take in the file, explode on quotes, and then cycle through the resultant array looking at the first non-whitespace data in every second element, clean/recode where necessary, and then implode and output. Alternatively could join/unset consecutive array elements which have been split inappropriately (by 'internal' quotes), and then implode using the other style of quotes/another separator, if this can be made to work later in the process... What a palaver! =dn -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv Help
How is the CSV being generated? Seems to me like your problem isn't ggetcsv(), but rather the file itself. Commonly, a CSV file is a series of values, separated by a comma (duh!!). The separated values are generally enclosed in double quotes (), as it would appear yours are. Any double quotes within each value (eg: she said hello) are escaped with a slash (eg: she said \hello\). If you are generating the CSV, then you can addslashes() to each value to escape the quotes, and then later on, stripslashes() to get rid of them. Sample line from your CSV should look like this: --- 1,foo,harry said \what is it?\,foo 1,bah,\don't know\ said sally,something --- When echoing these values to the browser, you would strip the slashes. Cheers, Justin on 11/12/02 7:13 PM, Richard Baskett ([EMAIL PROTECTED]) wrote: I am parsing a csv file with fgetcsv and the fields are surrounding by double quotes, now I am running into a problem periodically that when there are quotes within the value it is treating it like another value instead of the same value. Any ideas on how to get around that? I am thinking I might have to convert all quotes to quot; and then turn all quot;,quot; back into quotes and then the first quot; in the file and then last one since obviously they will not have a comma in between them. This seems like a while lot of work.. Ideas? Rick A wise women once said: No one can help everybody, but everybody can help somebody. - Unknown Justin French http://Indent.com.au Web Development Graphic Design -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv Help
I did email the company that the csv feed is coming from so we'll see what comes of that. I really hope they fix it. Well here is what I did to solve the problem: I pulled the csv file in using file(), then found the string length, used substr() to get rid of the first double quote in the line and the newline and double quote at the end of the line. Then I replaced all double quotes with it's html entity equivalent. Then replaced quot;,quot; back into , since that means those quotes are supposed to be there.. hopefully :) then I just stuck quotes on the beginning and end of the line. Created a new file and flushed the data into a new file. If anybody needs the code, I can send it to them. Hopefully though the company will get this fixed! Cheers! Rick I am parsing a csv file with fgetcsv and the fields are surrounding by double quotes, now I am running into a problem periodically that when there are quotes within the value it is treating it like another value instead of the same value. Any ideas on how to get around that? I am thinking I might have to convert all quotes to quot; and then turn all quot;,quot; back into quotes and then the first quot; in the file and then last one since obviously they will not have a comma in between them. This seems like a while lot of work.. Ideas? The happiest people are those who think the most interesting thoughts. Those who decide to use leisure as a means of mental development, who love good music, good books, good pictures, good company, good conversation, are the happiest people in the world. And they are not only happy in themselves, they are the cause of happiness in others. - Phelps -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv and end of line in values
greetings, i have problems using fgetcsv to explode a .csv file. some values consist of line-breaks. although these values are enclosed by quotes, php recognizes the line-break and starts a new dataset. the script workes fine in my old environment (win2k, apache 1.3.23, php 4.1.1), the problem occures in my new environment (win2k, apache 2.0.43, php 4.3.0). maybe config-params? i mentioned a new enclusure-attribute in fgetcsv since php 4.3.0. but experimenting with this didn't succeed. i also tried some different syntaxes in the delimiter-attrib of fgetcsv, no success. does anybody have any suggestion? thx. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] fgetcsv or other
Hello, Just remember that fgetcsv() returns an array. So the first column is $thearray[0]; You can just pass it to the function that generates the image BEFORE you go to the next line of your csv file. Or, am I missing something? - E On Saturday, October 12, 2002 2:05 AM Bryan Koschmann wrote: Hi, I need to read from a csv file (with quotes). I use the example from the manual, and it does spit it out how I want it, but I need to access one of the fields and pass that data to something else. So it's like this, I need my csv file to be displayed in a table, but the last column will contain an image generate using data from the first column. Does anyone have any examples? I've been searching the net, but haven't really found much. Thanks! Bryan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv or other
Hi, I need to read from a csv file (with quotes). I use the example from the manual, and it does spit it out how I want it, but I need to access one of the fields and pass that data to something else. So it's like this, I need my csv file to be displayed in a table, but the last column will contain an image generate using data from the first column. Does anyone have any examples? I've been searching the net, but haven't really found much. Thanks! Bryan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv With a String?
Is there any way that I can use fgetcsv, but have it get its input from a string, instead of using a file pointer? From the online docs, there doesn't seem to be a way, but I thought I'd check with the list. -- JR -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] fgetcsv
Hi all - just wondering if anyone knows of a function like fputcsv - that is, writes a line to a csv file - opposite of fgetcsv. Any help would be appreciated :-) swadie ~~~ Steve Wade Youth Outreach Coordinator Fusion Australia Ltd (Sydney North) ABN 26 001 273 105 +61 2 9477 1110
RE: [PHP] fgetcsv
Hi all - just wondering if anyone knows of a function like fputcsv - that is, writes a line to a csv file - opposite of fgetcsv. A CSV file is just a text file with a different file extension, so you can use fgets to write it out... Jason -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
