Hello,
I have this application which is accessed via a web portal. The first
thing my application must do is make sure the visitor is logged in via
the portal. The only way to do this is by making a request to a
specific URL. This URL (which includes the log in cookie id) will
return XML
simple use fopen() or file()
as $fp = fopen(http://somedomain/some.url?blablah,r;);
and read via fread()
/tom
On Fri, 12 Mar 2004 10:54:53 -0500
Roger Spears [EMAIL PROTECTED] wrote:
Hello,
I have this application which is accessed via a web portal. The first
thing my application must
How do I make my application load a URL and trap the returned data so
that it never creates any browser output?
Aside from the fopen() and fread() that was suggested by another person
you can also use the ob_* functions.
Chris
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PHP General Mailing List (http://www.php.net/)
To
Tom Meinlschmidt wrote:
simple use fopen() or file()
as $fp = fopen(http://somedomain/some.url?blablah,r;);
and read via fread()
Perhaps I was mistaken, I thought:
$fp = fopen(http://somedomain/some.url?blablah,r;);
fread();
Would just return the actual HTML code of the page and NOT the
Best way would be filegetcontents() and implode the content
with \n.
eg:
?php
$temp = filegetcontents('http://www.somedomain.com');
$temp = implode ( \n , $temp );
echo $temp ;
?
Chris Boget wrote:
How do I make my application load a URL and trap the returned data so
that it never
Tom Meinlschmidt wrote:
simple use fopen() or file()
as $fp = fopen(http://somedomain/some.url?blablah,r;);
and read via fread()
Then I replied with:
Perhaps I was mistaken, I thought:
$fp = fopen(http://somedomain/some.url?blablah,r;);
fread();
Would just return the actual HTML code of
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