Re: [PHP] Problem with is_dir function
I cannot explain your error message,
are you sure that the following error message provide from these lines ?
If not, I think your machine is blasted, so find out an exorcist or a witch.
Good luck !
- Original Message -
From: "Roger Lewis" <[EMAIL PROTECTED]>
To: "Roger Lewis" <[EMAIL PROTECTED]>; "Php-General"
<[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 3:41 AM
Subject: RE: [PHP] Problem with is_dir function
>
> On Saturday, November 02, 2002 11:07 AM, I wrote
>
> * > I'm having a problem with the is_dir function, or maybe I don't
> understand
> > how it supposed to work. I'm using the following code to check whether
or
> > not a directory called $user_dir exists. If it exists, I am returned
the
> > proper message. But if it doesn't exist, I get the following error
> message
> > that says that it doesn't exist. (I already knew that!)
>
>
> >
>
> > Can someone please explain what I am doing wrong here, and how to return
a
> > usable value if the directory doesn't exist.
>
>
> > $test = is_dir($user_dir);
> > if($test){echo "You have a user directory. It is $user_dir";}
> > else{echo "Your user directory doesn't exist";
> > return;}
>
>
> > Thanks a lot.
>
> > Roger Lewis
>
>
> This is a follow-up to my original posting.
> * I did not get an answer as to why is_dir does not return a "false"
value;
> however, file_exists does the job nicely. Thanks for all the suggestions.
> * Roger
>
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RE: [PHP] Problem with is_dir function
On Saturday, November 02, 2002 11:07 AM, I wrote
* > I'm having a problem with the is_dir function, or maybe I don't
understand
> how it supposed to work. I'm using the following code to check whether or
> not a directory called $user_dir exists. If it exists, I am returned the
> proper message. But if it doesn't exist, I get the following error
message
> that says that it doesn't exist. (I already knew that!)
> Can someone please explain what I am doing wrong here, and how to return a
> usable value if the directory doesn't exist.
> $test = is_dir($user_dir);
> if($test){echo "You have a user directory. It is $user_dir";}
> else{echo "Your user directory doesn't exist";
> return;}
> Thanks a lot.
> Roger Lewis
This is a follow-up to my original posting.
* I did not get an answer as to why is_dir does not return a "false" value;
however, file_exists does the job nicely. Thanks for all the suggestions.
* Roger
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RE: [PHP] Problem with is_dir function
I believe the path is of the correct format.
So for example, if
$user_dir = /home/sites/home/users/demodocs/web/userforum/user
and $user_dir exists, then
is_dir($user_dir) should = 1
however, if $user_dir doesn't exist, then
is_dir($user_dir) should = 0
Isn't this the correct logic?
Roger
-Original Message-
From: Andrew Brampton [mailto:andrew@;bramp.freeserve.co.uk]
Sent: Saturday, November 02, 2002 11:24 AM
To: Roger Lewis; [EMAIL PROTECTED]
Subject: Re: [PHP] Problem with is_dir function
what values of $user_dir are you passing to is_dir?
echo them out before the test, you might be sending paths which are most
certainly not directories... for example:
c:\windows
/home/blah
would be valid, but
c:\windows\win.com
/home/blah/myfile
http://somesite/somepath
ftp://someftpserver/incoming
are invalid
Hope this helps
Andrew
- Original Message -
From: "Roger Lewis" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Saturday, November 02, 2002 7:06 PM
Subject: [PHP] Problem with is_dir function
> I'm having a problem with the is_dir function, or maybe I don't understand
> how it supposed to work. I'm using the following code to check whether or
> not a directory called $user_dir exists. If it exists, I am returned the
> proper message. But if it doesn't exist, I get the following error
message
> that says that it doesn't exist. (I already knew that!)
>
>
>
>
> Can someone please explain what I am doing wrong here, and how to return a
> usable value if the directory doesn't exist.
>
>
> $test = is_dir($user_dir);
> if($test){echo "You have a user directory. It is $user_dir";}
> else{echo "Your user directory doesn't exist";
> return;}
>
>
> Thanks a lot.
>
> Roger Lewis
>
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with is_dir function
what values of $user_dir are you passing to is_dir?
echo them out before the test, you might be sending paths which are most
certainly not directories... for example:
c:\windows
/home/blah
would be valid, but
c:\windows\win.com
/home/blah/myfile
http://somesite/somepath
ftp://someftpserver/incoming
are invalid
Hope this helps
Andrew
- Original Message -
From: "Roger Lewis" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Saturday, November 02, 2002 7:06 PM
Subject: [PHP] Problem with is_dir function
> I'm having a problem with the is_dir function, or maybe I don't understand
> how it supposed to work. I'm using the following code to check whether or
> not a directory called $user_dir exists. If it exists, I am returned the
> proper message. But if it doesn't exist, I get the following error
message
> that says that it doesn't exist. (I already knew that!)
>
>
>
>
> Can someone please explain what I am doing wrong here, and how to return a
> usable value if the directory doesn't exist.
>
>
> $test = is_dir($user_dir);
> if($test){echo "You have a user directory. It is $user_dir";}
> else{echo "Your user directory doesn't exist";
> return;}
>
>
> Thanks a lot.
>
> Roger Lewis
>
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--
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[PHP] Problem with is_dir function
I'm having a problem with the is_dir function, or maybe I don't understand how it supposed to work. I'm using the following code to check whether or not a directory called $user_dir exists. If it exists, I am returned the proper message. But if it doesn't exist, I get the following error message that says that it doesn't exist. (I already knew that!) http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
