If you want to actually want the variables $flyertotal, $emailtotal, and
$phonetotal, use the line:
${$array[0].total} = $row[0];
But as you defined $array, that will actually create the variables
$Flyertotal, $Emailtotal, and $Phonetotal (note the caps).
On 2/13/2004 6:10 AM, Bob pilly
Hi..
I just wanna laugh really want to laugh WUWUAHAHAHAHAHA
I have figure out the solution amazingly! here will be the code I am running
LoL
?
mysql_connect('localhost','coconut','tkming') or die (Unable to connect to SQL
Server);
mysql_select_db('helpwatch') or die (Unable to
At 06.08.2001 10:31, you wrote:
Hi..
I just wanna laugh really want to laugh WUWUAHAHAHAHAHA
I have figure out the solution amazingly! here will be the code I am
running
LoL
it works without separating the code if you add the ; at the end of the
$temp = $username.watch line...
Hello !
We could keep things simpler ...
Why not give a try to this ?:
$watchlist_query = mysql_query( Create Table $temp ( WId int Not
Nullauto_increment, QId int not null, Primary Key (WId) ) ) or die (Error
! Cannot create table ! . mysql_error() );
Hope it would work :o)
(At least the
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