Re: [PHP] Still having ereg migranes
I think you should really ask at a unix list Mako Shark wrote: Heheh. Maybe I wasn't clear, or maybe I'm missing something. Well, one way without regex would be to explode() numbers on a comma and use in_array() to see if you're value exists. That should look for your number, preceded by either the beginning of the string or a comma and followed by either a comma or the end of the string. I can't use PHP commands to do this. I can only have an ereg statement, but that has to be placed in a grep statement. Maybe I should ask a Unix list, but I figure with the ereg(i) expertise here, this is my best bet. By the time my shell_exec() call returns its results, it should return only those files with the actual number. At that point, I can't explode() it and start searching for the number all over again using in_array() or any other commands. By the time Unix returns its results, the only thing I can do is carry on assuming I have only those tags that contain the number without having to search through the array. I appreciate the help, but while these commands would work in some situations, it won't work in mine. The whole finding-if-it's-in-the-list thing has to happen in the ereg that I pass to grep. __ Do you Yahoo!? Yahoo! Web Hosting - Let the expert host your site http://webhosting.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Still having ereg migranes
Sorry to repost this, but I haven't found a solution and it's still nagging me. Maybe some of you can come up with something I can't. Here was my original post: I've made myself an INPUT TYPE=HIDDEN tag that contains in the value attribute a list of comma-delimited numbers. I need to find if a certain number is in these tags (and each file contains one tag). I need an ereg statement that will let me search these lines to see if a number exists, obviously in the beginning or the end or the middle or if it's the only number in the list. So, say I need #1, I need to grep each file to find if 1 is in its INPUT TYPE=HIDDEN list. Here's what I mean (searching for number 1): INPUT TYPE = HIDDEN NAME = numbers VALUE = 1,2,3,4,5 //beginning INPUT TYPE = HIDDEN NAME = numbers VALUE = 0,1,2,3,4,5 //middle INPUT TYPE = HIDDEN NAME = numbers VALUE = 5,4,3,2,1 //end INPUT TYPE = HIDDEN NAME = numbers VALUE = 1 //only I can't grab all the tags and search for it in PHP (there would be too many tags to parse through and I'd rather let the OS handle that). I need to do this at the operating system level. Does anybody yet have a solution? I *know* it's possible, but I can't get it and I've been working on it for days now. This is one of those really annoying bugs that really grates on a programmer. __ Do you Yahoo!? Yahoo! Web Hosting - Let the expert host your site http://webhosting.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Still having ereg migranes
first way:
if(ereg('([^0-9]|^)'.$your_number.'([^0-9]|$)',$_REQUEST['numbers']) )
second way:
$numbers=explode(',',$_REQUEST['numbers']);
if(in_array($your_number,$numbers))
Mako Shark wrote:
Sorry to repost this, but I haven't found a solution
and it's still nagging me. Maybe some of you can come
up with something I can't. Here was my original post:
I've made myself an INPUT TYPE=HIDDEN tag that
contains in the value attribute a list of
comma-delimited numbers. I need to find if a certain
number is in these tags (and each file contains one
tag). I need an ereg statement that will let me search
these lines to see if a number exists, obviously in
the beginning or the end or the middle or if it's the
only number in the list. So, say I need #1, I need to
grep each file to find if 1 is in its INPUT
TYPE=HIDDEN list. Here's what I mean (searching for
number 1):
INPUT TYPE = HIDDEN NAME = numbers VALUE =
1,2,3,4,5 //beginning
INPUT TYPE = HIDDEN NAME = numbers VALUE =
0,1,2,3,4,5 //middle
INPUT TYPE = HIDDEN NAME = numbers VALUE =
5,4,3,2,1 //end
INPUT TYPE = HIDDEN NAME = numbers VALUE = 1
//only
I can't grab all the tags and search for it in PHP
(there would be too many tags to parse through and I'd
rather let the OS handle that). I need to do this at
the operating system level. Does anybody yet have a
solution? I *know* it's possible, but I can't get it
and I've been working on it for days now. This is one
of those really annoying bugs that really grates on a programmer.
__
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RE: [PHP] Still having ereg migranes
Sorry to repost this, but I haven't found a solution
and it's still nagging me. Maybe some of you can come
up with something I can't. Here was my original post:
I've made myself an INPUT TYPE=HIDDEN tag that
contains in the value attribute a list of
comma-delimited numbers. I need to find if a certain
number is in these tags (and each file contains one
tag). I need an ereg statement that will let me search
these lines to see if a number exists, obviously in
the beginning or the end or the middle or if it's the
only number in the list. So, say I need #1, I need to
grep each file to find if 1 is in its INPUT
TYPE=HIDDEN list. Here's what I mean (searching for
number 1):
INPUT TYPE = HIDDEN NAME = numbers VALUE =
1,2,3,4,5 //beginning
INPUT TYPE = HIDDEN NAME = numbers VALUE =
0,1,2,3,4,5 //middle
INPUT TYPE = HIDDEN NAME = numbers VALUE =
5,4,3,2,1 //end
INPUT TYPE = HIDDEN NAME = numbers VALUE = 1
//only
I can't grab all the tags and search for it in PHP
(there would be too many tags to parse through and I'd
rather let the OS handle that). I need to do this at
the operating system level. Does anybody yet have a
solution? I *know* it's possible, but I can't get it
and I've been working on it for days now. This is one
of those really annoying bugs that really grates on a programmer.
Well, one way without regex would be to explode() numbers on a comma and
use in_array() to see if you're value exists.
$ar = explode(',',$_GET['numbers']);
if(in_array($search_number,$ar))
{ //number is present; }
else
{ //number is not present; }
With regex, maybe something like this?
if(preg_match('/^|,'.$search_number.',|$/',$_GET['numbers']))
{ //number is present; }
else
{ //number is not present; }
That should look for your number, preceded by either the beginning of
the string or a comma and followed by either a comma or the end of the
string.
Let me know if that works.
---John Holmes...
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RE: [PHP] Still having ereg migranes
first way:
if(ereg('([^0-9]|^)'.$your_number.'([^0-9]|$)',$_REQUEST['numbers'])
) second way:
$numbers=explode(',',$_REQUEST['numbers']);
if(in_array($your_number,$numbers))
Not sure I get this but, again, I can't use $_REQUEST
or explode or in_array at this point. The entire
process needs to happen in the shell_exec() command,
because I'd much rather have that handle the whole
shebang than PHP.
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