Hi,
Yes, what Ashley said is correct. Also, if you want to avoid writing
$perm several times in the if, or if you have a lot of permissions you
can do:
if (in_array($perm, array(11, 22)))
And you can put in that array all the permissions you need to.
Regards,
Jonathan
On Fri, Dec 18, 2009 at
Thank you Ashley, it makes perfect sense. I don't know why I didn't just set
up some tests like Shiplu suggested!
I've rewritten all my code BACK to the correct way. (I thought it looked
cooler, oh well).
On Fri, Dec 18, 2009 at 10:47 AM, Ashley Sheridan
wrote:
> On Fri, 2009-12-18 at 10:21 -0
On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote:
> In a nutshell:
>
> Will this work?
>
> if ($perm == (11 || 12))
>
>
> Explanation:
>
> I am laying the groundwork for a photo viewing system with a private and
> public mode, and additionally if an admin is logged in, there is an
> addi
Hi everybody,
thank you for all the help and thoughts. I have solved it, but I guess
it is not an elegant solution. What I do now, is simply check again for
the second case. There are 2 cases. Either first page OR all pages,
second case: following pages OR all pages.
My booking checking look
At 11:52 AM +0100 12/7/09, Merlin Morgenstern wrote:
Hello everybody,
I am having trouble finding a logic for following problem:
Should be true if:
page = 1 OR page = 3, but it should also be true if page = 2 OR page = 3
The result should never contain 1 AND 2 in the same time.
This obviously
Hey Merlin
Merlin Morgenstern wrote on 2009-12-07 11:52:
Hello everybody,
I am having trouble finding a logic for following problem:
Should be true if:
page = 1 OR page = 3, but it should also be true if page = 2 OR page = 3
The result should never contain 1 AND 2 in the same time.
This obvi
Merlin Morgenstern wrote:
You have described the problem very well. This is exactly where I can
not find a solution.
the page number translates to the following: 1= first page 2= following
pages 3= all pages
This are the options a user has while booking a product on my site. Now
if ther is
On Mon, 2009-12-07 at 12:49 +0100, Merlin Morgenstern wrote:
>
> Ashley Sheridan wrote:
> > On Mon, 2009-12-07 at 11:52 +0100, Merlin Morgenstern wrote:
> >> Hello everybody,
> >>
> >> I am having trouble finding a logic for following problem:
> >>
> >> Should be true if:
> >> page = 1 OR page =
Ashley Sheridan wrote:
On Mon, 2009-12-07 at 11:52 +0100, Merlin Morgenstern wrote:
Hello everybody,
I am having trouble finding a logic for following problem:
Should be true if:
page = 1 OR page = 3, but it should also be true if page = 2 OR page = 3
The result should never contain 1 AND 2
On Mon, 2009-12-07 at 11:52 +0100, Merlin Morgenstern wrote:
> Hello everybody,
>
> I am having trouble finding a logic for following problem:
>
> Should be true if:
> page = 1 OR page = 3, but it should also be true if page = 2 OR page = 3
>
> The result should never contain 1 AND 2 in the sam
Devendra Jadhav wrote:
what do you think about this?
if( ! (page == 1 && page == 2)){
//here
}
Well a simple && (and) does not help.
I want to have all results that contain either page = 1 OR page = 3, AND
in the same time I want to have the results that contain page=2 OR page= 3
, B
what do you think about this?
if( ! (page == 1 && page == 2)){
//here
}
On Mon, Dec 7, 2009 at 4:22 PM, Merlin Morgenstern wrote:
> Hello everybody,
>
> I am having trouble finding a logic for following problem:
>
> Should be true if:
> page = 1 OR page = 3, but it should also be true if pa
If this seems simple to you remember I have no formal training in logic
structure or DB design
Neither do I - and probably a lot of others here too ;)
the value of a status field is given in the sdk text as such...
...This number is determined by adding the following values togeth
On Sun, 2008-10-19 at 11:26 -0400, Robert Cummings wrote:
> On Sun, 2008-10-19 at 10:03 +0100, Ashley Sheridan wrote:
> > On Sun, 2008-10-19 at 01:10 -0400, Robert Cummings wrote:
> > > On Sat, 2008-10-18 at 22:56 -0600, Govinda wrote:
> > > > Hi all
> > > >
> > > > This is not exactly PHP, but a
On Sun, 2008-10-19 at 10:03 +0100, Ashley Sheridan wrote:
> On Sun, 2008-10-19 at 01:10 -0400, Robert Cummings wrote:
> > On Sat, 2008-10-18 at 22:56 -0600, Govinda wrote:
> > > Hi all
> > >
> > > This is not exactly PHP, but an issue that we have to work out in code
> > > (whatever we use) -
>
On Oct 18, 2008, at 11:10 PM, Robert Cummings wrote:
On Sat, 2008-10-18 at 22:56 -0600, Govinda wrote:
To cut down on fraudulent orders, our cc processor (whatever we call
them), to enable "Address Verification System (AVS)", ...
The
docs make this clear that they want: "The numeric port
On Sun, 2008-10-19 at 01:10 -0400, Robert Cummings wrote:
> On Sat, 2008-10-18 at 22:56 -0600, Govinda wrote:
> > Hi all
> >
> > This is not exactly PHP, but an issue that we have to work out in code
> > (whatever we use) -
> > I am working on a shopping cart site which will have orders from any
On Sat, 2008-10-18 at 22:56 -0600, Govinda wrote:
> Hi all
>
> This is not exactly PHP, but an issue that we have to work out in code
> (whatever we use) -
> I am working on a shopping cart site which will have orders from any
> country.
>
> To cut down on fraudulent orders, our cc processor
AVS generally only exists for us and canada and parts of the uk, if I
remember correctly. Usually they're just looking for the beginning
part of the street address, not the concatenation or anything else
like that. No need for apartment numbers, for example if you're just
looking at avs.
If you're
tedd wrote:
> If two, or more, users hit the site at the same time then a RACE
> condition may have one user getting something they didn't ask for or
> not getting anything at all.
>
> The complicated way I figure I could solve this would be to:
>
> 1. Generate a random string name for the file
tedd wrote:
Hi gang:
Here's the logic problem.
First the site:
http://php1.net/b/zip-files/
Now, the site works well enough. The user selects what they want, clicks
Submit, the order is assembled in zip file and presented to the user for
downloading.
However, as it stands now, before the
On Wed, Jul 9, 2008 at 6:11 PM, Jochem Maas <[EMAIL PROTECTED]> wrote:
> generate a unique hash as the name based on the contents of the zip, then
> if 2 people
> happen to want exactly the same selection you won't have to build/zip it
> twice ...
> just check if the zip happens to exist before tr
generate a unique hash as the name based on the contents of the zip, then if 2
people
happen to want exactly the same selection you won't have to build/zip it twice
...
just check if the zip happens to exist before trying to build it.
have the script do garbage collection on old zip files ... i
On Wed, Jul 9, 2008 at 7:45 PM, tedd <[EMAIL PROTECTED]> wrote:
> Hi gang:
>
> Here's the logic problem.
>
> First the site:
>
> http://php1.net/b/zip-files/
>
> Now, the site works well enough. The user selects what they want, clicks
> Submit, the order is assembled in zip file and presented to th
Write a script that cron runs that checks dates of files and removes 1 month
old ones?
On Wed, Jul 9, 2008 at 4:45 PM, tedd <[EMAIL PROTECTED]> wrote:
> Hi gang:
>
> Here's the logic problem.
>
> First the site:
>
> http://php1.net/b/zip-files/
>
> Now, the site works well enough. The user select
Hi, I am doing an online calendar for holiday application.
Now I got a table with these fields among many others.
`req_id` int(11) NOT NULL auto_increment,
`req_date` date NOT NULL,
`username` varchar(100) NOT NULL,
`start_date` date NOT NULL,
`end_date` date NOT NULL,
`days_off` int
Wee Keat wrote:
Hey Jeff,
How are you mate? Was lazying around and saw your email to the list. :)
What exactly do you need help with? Is it the following line?
// Stuck here
$html_menu .= "$sub_page";
}
$html_menu .= '';
Do you need to get the value of the link and
On Thu, 16 Dec 2004 13:11:02 +1100, Jeffery Fernandez
<[EMAIL PROTECTED]> wrote:
> I am trying to build a html menu dynamically from data sitting in an
> array. I have been successful so far until it came to the point of
> populating the sub-menu of the system. Can someone help me out with the
> lo
> What's in your array?
$array1[0] = 'firstname';
$array1[1] = 'lastname';
$array1[2] = 'tkt_title';
I got that fixed.
Thanks.
alex hogan
**
The contents of this e-mail and any files transmitted with it are
confidential and i
Alex Hogan wrote:
I gotcha..,
I do have one question though. I ran your code and it only returns the
first letter for that element in the array. For instance fieldone
returns as f and tableone returns as t.
The output looks like this;
SELECT f,f,f FROM t,t.
alex
What's in your array?
--
***
On 20 April 2004 16:44, Alex Hogan wrote:
> foreach ( $array1 as $flds ) {
> if ( $start ) {
> $query .= $flds;
> $start = false;
> } else {
> $query .= ", " . $flds;
>
> }
> }
$query .= implode(", ", $array1);
Cheers!
Mike
--
Apr 20 at 9:55am, Alex Hogan wrote:
> function myselect($array1, $array2){
> $query = "SELECT".foreach($array1 as $flds){ $flds[$i]; }.
> "FROM".foreach($array2 as $tbls){ $tbls[$n]; } ...
Alex, if you merely wish to place the values of an array into your
query, you might also try doing it th
[snip]
I do have one question though. I ran your code and it only returns the
first letter for that element in the array. For instance fieldone returns
as f and tableone returns as t. The output looks like this; SELECT f,f,f
FROM t,t.
[/snip]
Never mind I found it. It should be;
$query = "SELEC
[snip]
> $query = "SELECT ";
> $start = true;
> foreach ( $array1 as $flds ) {
> if ( $start ) {
> $query .= $flds[$i];
> $start = false;
> } else {
> $query .= ", " . $flds[$i];
> }
> }
> $query .= " FROM ";
> $start = true;
> foreach ( $
Alex Hogan wrote:
Hi All,
I am having a logic problem. (insert jokes here) I am trying to create a
function that will allow me to pass any number of fields and tables into a
blanket query.
I am getting an error; Unexpected foreach. I have tried placing the loop in
several different places and am
Crockford wrote:
>
>
>
>
> > -Original Message-
> > From: Marco Tabini [mailto:marcot@;tabini.ca]
> > Sent: 11 November 2002 14:46
> > To: Tony Crockford
> > Cc: Php-General@Lists. Php. Net
> > Subject: Re: [PHP] Logic headache, please help.
&g
> -Original Message-
> From: Marco Tabini [mailto:marcot@;tabini.ca]
> Sent: 11 November 2002 14:46
> To: Tony Crockford
> Cc: Php-General@Lists. Php. Net
> Subject: Re: [PHP] Logic headache, please help.
>
>
> How about building an array of all the levels
How about building an array of all the levels:
$a = array();
for ($i = 1; $i <= $maxlevels; $i++)
$a[] = $i;
then for each level you can create a new array that is the difference
between the original array and an array that contains the current level:
for ($i = 1; $i <= $maxlevels; $i++
On Tue, Jun 04, 2002 at 04:40:26AM +0400, Ricardo Fitzgerald wrote:
>
> I'm trying to echo a neat table
I've GOT to bust your chops. That table and your code are anything BUT
neat. For neat, you need to put tags to close each cell. Also
nest your code properly...
if ($value2 ==0) {
p; $valueChk <= 3)
>
> //for 3rd row
> if($valueChk == 3)
>
>
>
> -Original Message-
> From:
[EMAIL PROTECTED]
>
[mailto:[EMAIL PROTECTED]
> t]On Behalf Of Naintara Jain
> Sent: Tuesday, June 04, 2002 2:37 PM
> To: Ricardo Fitzgerald; [EMAIL PROTECT
The problem here is that you have defined three different variables
$value1,$value2,$value3.
Keep only one variable (say,$valueChk) that can take values 1,2 or 3.
Then check for the condition.
And there's another mistake in the script, you are checking
---if ($value2 ==0)---
twice, you probably m
"Dan McCullough" <[EMAIL PROTECTED]> wrote:
> Question. I am trying to check to see if a certain piece of code should
be run. Here is an
> example.
> if ($type != "add") || ($type != "edit") || ($type != "delete") {//if this
or this or this then
> then run this code
As pointed out, your paranth
now change || to && and see if that does the job
-Original Message-
From: Dan McCullough [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, December 05, 2001 12:57 PM
To: PHP General List
Cc: Richard S. Crawford
Subject: Re: [PHP] Logic
that didnt work,i started off with
if ($type
that didnt work,i started off with
if ($type != "add") {
that works
} else {
this works
}
I have done this before I'm just having a brain cramp.
if (($type != "add") || ($type != "edit") || ($type != "delete")) {
print $subcat_output;
} else {
print "Back to List of Subcategories";
}
---
You need parentheses around the entire antecedent:
if (($type !="add") || ($type !="edit") || ($type !="delete")) { //etc
^--- Note these parentheses---^
Hope that helps.
At 05:28 PM 12/4/2001, Dan McCullough wrote:
>Question. I am trying to check to see if a
try:
http://php.resourceindex.com/Complete_Scripts/Link_Management/
you should be able to find some examples here.
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