Hello to All,
CORRECTION to my previous post:
I produced a horrible bug in the display of time/space measurements at the end
of the script.
With the bugfix, the time/space display, the use of ^: does not appear very
fast any more.
Please accept my apologies,
JoHo
Hello to All,
NB. ... using Function Power for the iteration ... J807 JoHo
niter=: 4
(]([,<@])6&?@:>@:{.)^:niter[,<55 NB. deal 6 out of 55 in boxes
+--+-+-+-+-+
|55|19 46 33 41 43 15|53 18 16 15 20 54|41 15 24 23 36
All,
I'm sorry my description of my problem wasn't very clear. I actually wasn't
worried about the exact number of generations of 6 random numbers. I just
wanted to understand how I could generate multiple sets of 6 random
integers without having to type them all out one at a time, as I had done
That’s what ;/6 (? $~) 55 (amoung others) does.
We wondered mainly how many repetitions you actually wanted to get.
There were 5 in your example and you wanted something extended 50 times.
None knew what it was you wanted extended and if it was to be counted.
Did you intend to get
• 50
• 51
•
The original requirement was to have the integers in each set of 6 be
unique in that set. Zeros are OK.
Skip
>
>
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I see your point. actually x?y (deal as in the vocabulary) doesn't
allow repetitions. An analogy is dealing a hand of cards where you will
never (legally) have 2 aces of spades . hence, with 2 cards 1 and 0, you
can't get 1 1 . If you have 2 cards each having a 1 and 0 you can get
your
5 6 ?@$ 55
52 3 9 16 4 3
26 30 24 34 30 50
46 51 16 19 26 26
20 46 12 50 39 27
3 39 45 46 46 33
:)
This actually isn't the same result as your code, though.
(4#2) ? 2
0 1
0 1
0 1
1 0
1 1 i.~ (1e6#2) ? 2
100
0 0 i.~ (1e6#2) ? 2
100
There are never any 1 1 or 0 0
(5#6)?55
42 16 14 29 38 25
14 37 22 4 54 6
47 51 35 32 26 45
13 53 10 29 3 15
21 8 20 45 30 52
Don Kelly
On 2020-03-23 5:47 p.m., 'Jim Russell' via Programming wrote:
Who do I thank tor this? It is a particularly clear and helpful exclamation.
Thank you!
On Mar 13, 2020, at 3:56 AM,
This was me. Very nice to hear that someone found it helpful. Thanks for going
out of your way to say thanks!
Jim Russell wrote:
> Who do I thank tor this? It is a particularly clear and helpful exclamation.
> Thank you!
>
> > On Mar 13, 2020, at 3:56 AM, ethiejiesa via Programming
> >
Who do I thank tor this? It is a particularly clear and helpful exclamation.
Thank you!
> On Mar 13, 2020, at 3:56 AM, ethiejiesa via Programming
> wrote:
>
> I'll contribute a little prose. Hopefully, it's helpful.
>
> In this particular case, notice that > transforms your list of boxes
If that’s what was intended, I’d rather write
;/6 (? $~) 55
(adhering to the DRY principle).
Am 13.03.20 um 16:22 schrieb Raul Miller:
Here's another approach:
;/6?255#55
Here, I decided that "extended fifty times" really meant that you
wanted another 50 copies of that expression
Here's another approach:
;/6?255#55
Here, I decided that "extended fifty times" really meant that you
wanted another 50 copies of that expression (extended linearly). But
of course you can tweak the numbers.
FYI,
--
Raul
On Fri, Mar 13, 2020 at 12:49 AM Skip Cave wrote:
>
> How can I
0. It may be helpful to think of &.> as "each". In fact, "each" is defined
as such by some J standard library somewhere. Enter "each" in your J
session and see what you get.
1. See https://code.jsoftware.com/wiki/Essays/Under for examples of &. ,
including from daily life (e.g. "under
Yes, those are not precise terms. I personally think of &. as embodying
conjugation (from group theory). For monads, the analogy is often precise:
u&.v y <-> v^:_1 u v y
But you are right, the idea of conjugation is abstract enough that it is
embodied by a dizzingly wide variety of applications:
In my opinion, “do” and “undo” is not the idea/concept of &.
and doesn’t get across what it actually does.
&. is very helpful in a plethora of use cases
it is like transform, work in transformed space, transform back
(like working with conjugate matrices or in fourier space, e.g.)
From my
I'll contribute a little prose. Hopefully, it's helpful.
In this particular case, notice that > transforms your list of boxes into a 5x6
table:
> (6?55);(6?55);(6?55);(6?55);(6?55)
13 4 19 43 3 52
10 1 4 46 52 11
38 12 48 50 54 45
36 54 39 35 53 50
44 1 7 54 11 41
Wow! Two completely different ways to generate multiple sets of random
integers. Roger used &. which I haven't really ever used or understood. I
will definitely need to understand &. for the future. Devon used @, which I
also haven't used very much. I need to find some practice and training
6 5?@$55
Will give you a 6x5 table that is 6 independent rows of 5?55.
On Fri, Mar 13, 2020 at 12:52 AM Roger Hui
wrote:
>6 ?&.> 5 $ 55
>
> ┌┬─┬───┬─┬───┐
> │47 28 45 25 8 36│22 40 23 20 11 49│15 16 42 38 4 5│50 45
6 ?&.> 5 $ 55
┌┬─┬───┬─┬───┐
│47 28 45 25 8 36│22 40 23 20 11 49│15 16 42 38 4 5│50 45 38 37 13 28│42 4
36 7 23 49│
└┴─┴───┴─┴───┘
6 ?&.> 50 $ 55
How can I generate the following result extended 50 times, without explicit
looping?
(6?55);(6?55);(6?55);(6?55);(6?55)
┌───┬───┬─┬─┬───┐
│13 4 19 43 3 52│10 1 4 46 52 11│38 12 48 50 54 45│36 54 39 35 53 50│44 1 7
54 11 41│
Hi everyone,
I'm am amateur trying to learn J. Someday I hope to apply the language in
an actuarial context, but first I'm trying to get some chops. As a
challenge, I've been trying to program The Game of Life using J. I'm
attempting to directly translate the APL version described here:
On Mon, Mar 25, 2013 at 5:22 PM, Jeremy Smith
actuaryjeremysm...@gmail.com wrote:
life =: +./@((1 ,: [) (*.2) 3 4 e.0/ +/@(+/@(1 0 _1 |.0 2/ 1 0 _1 |.0 1/
[)))
And then (i.4) gen board indeed gives me what I want. But I cannot figure
out how to define gen so that the syntax 4 gen board
Jeremy,
Sometimes mixing tacit and explicit definitions gives very simple programs
especially if you want to use a conjunction like power
gen1 =: 4 : 'life^:(i.:x)y'
gen2 =: 4 : 'life ^:x y' if you only want the final result
Fraser
take a look at the life demo
On Mar 25, 2013 4:22 PM, Jeremy Smith actuaryjeremysm...@gmail.com
wrote:
Hi everyone,
I'm am amateur trying to learn J. Someday I hope to apply the language in
an actuarial context, but first I'm trying to get some chops. As a
challenge, I've been trying to
If you are willing to use explicit verbs, maybe this will do.
gen1 =: 13 :'life^:(i.x)y'
gen1
4 : 'life^:(i.x)y'
(4 gen1 sbd) -:(i. 4) gen sbd
1
--
(B=) -my sig
Brian Schott
--
For information about J forums see
Other people have already answered. But, curiously, I have not seen
any tacit implementations yet.
Perhaps:
gen=: life@]^:(i.@[)
--
Raul
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For information about J forums see http://www.jsoftware.com/forums.htm
Maybe Raul did not see yours, like I did not see Fraser's. Could there
be some latency in the email?
On Mon, Mar 25, 2013 at 3:49 PM, Zsbán Ambrus amb...@math.bme.hu wrote:
On 3/25/13, Raul Miller rauldmil...@gmail.com wrote:
Other people have already answered. But, curiously, I have not seen
On 3/25/13, Raul Miller rauldmil...@gmail.com wrote:
Other people have already answered. But, curiously, I have not seen
any tacit implementations yet.
Have I turned invisible or something?
Ambrus
--
For information about J
On Mon, Mar 25, 2013 at 3:49 PM, Zsbán Ambrus amb...@math.bme.hu wrote:
On 3/25/13, Raul Miller rauldmil...@gmail.com wrote:
Other people have already answered. But, curiously, I have not seen
any tacit implementations yet.
Have I turned invisible or something?
I saw a post from you, but it
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