[Proto-Scripty] Re: Reverse sinusodal transition
On Wednesday 18 February 2009 16:18:37 Jim Higson wrote:
> On Wednesday 18 February 2009 15:53:08 Brendan O Connor wrote:
> > run the the same function again using -xCo
> >
> > I use the following
> >
> > moveRight : function(mvePan,xCo){
> >
> >
> > menuFrag.scrollCnt = menuFrag.scrollCnt + 1;
> > new Effect.Move(mvePan, {duration: .5,
> > x: xCo, y: 0, mode: 'relative',
> > transition: Effect.Transitions.sinoidal
> > },{queue:'front'});
> > },
> >
> > moveLeft : function(mvePan,xCo){
> > xCo = xCo*-1;
> > menuFrag.scrollCnt = menuFrag.scrollCnt - 1;
> > new Effect.Move(mvePan, {duration: .5,
> > x: xCo, y: 0, mode: 'relative',
> > transition: Effect.Transitions.sinoidal
> > },{afterFinish:myCallBack});
> > }
> > },
>
> That's pretty much what I'm doing now, but for big parallel effects with
> lots of different morphs it would be neater to be able to do something like
> this:
>
> {
> transition: forwards? Effect.Transitions.sunoidal :
> Effect.Transitions.reverse(sunoidal)
> }
Actually, that wouldn't work at all :-)
Something more like this:
{
transition: forwards? Effect.Transitions.sunoidal :
Effect.Transitions.sunoidal.backwards()
}
--
Jim
my wiki ajaxification thing: http://wikizzle.org
my blog: http://jimhigson.blogspot.com/
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[Proto-Scripty] Re: Reverse sinusodal transition
valid point..my solution is for slide show so its very simple
2009/2/18 Jim Higson
>
> On Wednesday 18 February 2009 15:53:08 Brendan O Connor wrote:
>
> > run the the same function again using -xCo
> >
> > I use the following
> >
> > moveRight : function(mvePan,xCo){
> >
> >
> > menuFrag.scrollCnt = menuFrag.scrollCnt + 1;
> > new Effect.Move(mvePan, {duration: .5,
> > x: xCo, y: 0, mode: 'relative',
> > transition: Effect.Transitions.sinoidal
> > },{queue:'front'});
> > },
> >
> > moveLeft : function(mvePan,xCo){
> > xCo = xCo*-1;
> > menuFrag.scrollCnt = menuFrag.scrollCnt - 1;
> > new Effect.Move(mvePan, {duration: .5,
> > x: xCo, y: 0, mode: 'relative',
> > transition: Effect.Transitions.sinoidal
> > },{afterFinish:myCallBack});
> > }
> > },
> That's pretty much what I'm doing now, but for big parallel effects with
> lots
> of different morphs it would be neater to be able to do something like
> this:
>
> {
> transition: forwards? Effect.Transitions.sunoidal :
> Effect.Transitions.reverse(sunoidal)
> }
>
> than have to worry about negating all the different morph parameters.
>
> Maybe I should just have a go at hacking a reverse function into
> Effect.Transitions.
>
> --
> Jim
> my wiki ajaxification thing: http://wikizzle.org
> my blog: http://jimhigson.blogspot.com/
>
> >
>
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[Proto-Scripty] Re: Reverse sinusodal transition
On Wednesday 18 February 2009 15:53:08 Brendan O Connor wrote:
> run the the same function again using -xCo
>
> I use the following
>
> moveRight : function(mvePan,xCo){
>
>
> menuFrag.scrollCnt = menuFrag.scrollCnt + 1;
> new Effect.Move(mvePan, {duration: .5,
> x: xCo, y: 0, mode: 'relative',
> transition: Effect.Transitions.sinoidal
> },{queue:'front'});
> },
>
> moveLeft : function(mvePan,xCo){
> xCo = xCo*-1;
> menuFrag.scrollCnt = menuFrag.scrollCnt - 1;
> new Effect.Move(mvePan, {duration: .5,
> x: xCo, y: 0, mode: 'relative',
> transition: Effect.Transitions.sinoidal
> },{afterFinish:myCallBack});
> }
> },
That's pretty much what I'm doing now, but for big parallel effects with lots
of different morphs it would be neater to be able to do something like this:
{
transition: forwards? Effect.Transitions.sunoidal :
Effect.Transitions.reverse(sunoidal)
}
than have to worry about negating all the different morph parameters.
Maybe I should just have a go at hacking a reverse function into
Effect.Transitions.
--
Jim
my wiki ajaxification thing: http://wikizzle.org
my blog: http://jimhigson.blogspot.com/
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[Proto-Scripty] Re: Reverse sinusodal transition
the value that you use for xCo
run the the same function again using -xCo
I use the following
moveRight : function(mvePan,xCo){
menuFrag.scrollCnt = menuFrag.scrollCnt + 1;
new Effect.Move(mvePan, {duration: .5,
x: xCo, y: 0, mode: 'relative',
transition: Effect.Transitions.sinoidal
},{queue:'front'});
},
moveLeft : function(mvePan,xCo){
xCo = xCo*-1;
menuFrag.scrollCnt = menuFrag.scrollCnt - 1;
new Effect.Move(mvePan, {duration: .5,
x: xCo, y: 0, mode: 'relative',
transition: Effect.Transitions.sinoidal
},{afterFinish:myCallBack});
}
},
2009/2/18 Jim Higson
>
> Hi,
>
> There are Sinusoidal transitions and Reverse (linear) transitions - is
> there a
> way to get a reverse Sinusoidal?
>
> Thanks,
> Jim
>
> --
> Jim
> my wiki ajaxification thing: http://wikizzle.org
> my blog: http://jimhigson.blogspot.com/
>
> >
>
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