You unsizzled my sizzle! But yeah, that will work just fine. Thanks.
On Friday, December 14, 2012 2:28:49 PM UTC-7, Jason wrote:
>
>
>
> Try it this way
>
> $('logins').select('li.seaside').invoke('show');
>
> or
>
> $('logins').select('li.fav').invoke('show');
>
> or with the variable
>
> $('l
Try it this way
$('logins').select('li.seaside').invoke('show');
or
$('logins').select('li.fav').invoke('show');
or with the variable
$('logins').select('li.'+group).invoke('show');
if you use the attribute selector instead of a class selector it
will interpret it very literally instead of "
