Indeed kickstarter (or similar) cannot be about general research of
infrastructure.
It has to be about something visible, a goal that's shared in a crowd.
IMO a campaign to achieve cpython-3.latest parity in pypy will get backers.
Not only from pypy users, but also from cpython world, because:
* i
Hey,
thanks for your answers. I know you are working on numpy and similar
libraries, as well about the fundraisers on your site.
I am glad there is something happening around this.
Thank you for your work and information,
Daniel
čt 19. 5. 2016 v 23:53 odesílatel Armin Rigo napsal:
> Hi,
>
> O
Hi,
On 19 May 2016 at 21:29, Kotrfa wrote:
> Of course, I cannot ensure that you might get reasonably funded on
> kickstarter-like sites. But, what can you lose by making a campaign? It
> would be definitely much more visible than on your website
I should add that we did that already: we have th
Hi Daniel.
As for kickstarter - it requires you to be american to start with :-P
As for numpy etc. - I can assure you we're working on the support for
those libraries as fast as possible, at the same time looking for
funding through commercial sources.
As for the website modernization - yes, thi
Thanks for answer Maciej!
I'm glad that this is in progress. It isn't possible to make some image
about the situation from what I have found on the web. You response
clarifies that a bit. I understand how difficult it can be.
But I disagree with you regarding kickstarter. Pypy is connected to use
Hi Daniel.
We've done all of the proposed scenarios. We had some success talking
to companies, but there is a lot of resistance for various reasons
(and the successful proposals I can't talk about), including the
inability to pay open source from the engineering budget and instead
doing it via the
On 19 May 2016 at 14:58, wrote:
> -- Forwarded message --
> From: Daniel Hnyk
> To: pypy-dev@python.org
> Cc:
> Date: Thu, 19 May 2016 12:58:36 +
> Subject: Question about funding, again
> Hello,
>
> my question is simple. It strikes me why you don't have more financial
> su
