Hi Frank,
I use Hmisc and Design in my research a lot, the LaTeX facilities are
very handy. But I don't think they can work with OpenOffice document
format (ODF), or did I miss something?
Thanks.
Shige
On Jan 13, 2008 2:03 AM, Frank E Harrell Jr [EMAIL PROTECTED] wrote:
??? wrote:
Dear
Hi R-people,
I try using mca (multiple correspondence analysis) in evocation data
(data base feminino2.csv attach in this mail).
Well in this database have 4 evocations for each 120 persons.
If I use this script:
base-read.csv(feminino2.csv)
require(MASS)
plot(mca(base,abbrev=T),rows = F)
On Thu, 2008-01-10 at 09:47 -0800, eugen pircalabelu wrote:
Hi R-users!
I have the following example:
a-data.frame(cat=c(5,10,15), dog=c(5,10, 15), mouse=c(10,10,20))
b-data.frame(cat=c(15,10,5), dog=c(15, 10, 5), mouse=c(20,10,10))
rownames(b)-c(scared, happy, sad)
rownames(a)-c(scared,
Dear R-helpers,
On Jan 12, 2008, at 5:17 PM, Deepayan Sarkar wrote:
On 1/12/08, Michael Kubovy [EMAIL PROTECTED] wrote:
Dear r-helpers,
Does anyone have a straightforward example of putting together three
unrelated (expect for a common y-axis) xyplot() figures in what would
be in base
Quelqu'un, certainement vous, a demandé votre désinscription de cette lettre
d'info, merci de suivre les informations qui suivent.
Pour vous désinscrire, cliquez sur le lien suivant :
Thanks Richard. I am just trying to understand exactly what is R's arima
doing, and I am having a hard time. It seems that xreg is necessary to force
arima to include the constant term, but it appears that exactly how this is
done is not documented. If a series is not differenced, e.g. AR(1), then
Hi All,
I'm new with R; this is a basic question. I was given a matrix I of (nrow,
ncol), I would like to create another matrix A with some data in the matrix
I, say [1,4] (row 1, column 4) to [271,19000] (row 271, column 19000). How
do I do this? Please help. Thank you very much.
--mc
You need to make sure all your xlab's are the same size. Try:
states - data.frame(state.x77,
state.name = dimnames(state.x77)[[1]],
state.region = state.region)
plot1 - xyplot(Murder ~ Population, data = states,
xlab =
Thanks, Frank. The clarification as well as the referred resources are
extremely helpful.
Shige
On Jan 13, 2008 10:14 PM, Frank E Harrell Jr [EMAIL PROTECTED] wrote:
宋时歌 wrote:
Hi Frank,
I use Hmisc and Design in my research a lot, the LaTeX facilities are
very handy. But I don't think
Try this:
A - I[1:271, 4:19000]
On 13/01/2008, My Coyne [EMAIL PROTECTED] wrote:
Hi All,
I'm new with R; this is a basic question. I was given a matrix I of (nrow,
ncol), I would like to create another matrix A with some data in the matrix
I, say [1,4] (row 1, column 4) to [271,19000] (row
宋时歌 wrote:
Hi Frank,
I use Hmisc and Design in my research a lot, the LaTeX facilities are
very handy. But I don't think they can work with OpenOffice document
format (ODF), or did I miss something?
Thanks.
Shige
You're correct. Conversion from LaTeX to OpenOffice or Word is
jim holtman wrote:
?cor.test
and the help page says:
formula: a formula of the form ~ u + v, where each of u and v are
numeric variables giving the data values for one sample. The samples
must be of the same length.
Yes, but does that answer the question? Seems to me that Joe knows
Try this:
code - readLines(site)
On 13/01/2008, John Lande [EMAIL PROTECTED] wrote:
dear R user,
I need a function that download the code of web page as html, to further
parse it.
something like
site=http://www.R-project.com;
code=function(site)
code
!DOCTYPE HTML PUBLIC -//W3C//DTD
dear R user,
I need a function that download the code of web page as html, to further
parse it.
something like
site=http://www.R-project.com;
code=function(site)
code
!DOCTYPE HTML PUBLIC -//W3C//DTD HTML 4.01 Transitional//EN
html
head
titleThe R Project for Statistical Computing/title
link
Jarek Jasiewicz wrote:
Charles Annis, P.E. wrote:
Jarek:
Although it is not universally agreed on, I believe the first step in any
data analysis is to PLOT YOUR DATA.
dd - data.frame(a=c(1, 2, 3, 4, 5, 6), b=c(3, 5, 6, 7, 9, 10))
plot(b ~ a, data=dd)
simple.model - lm(b~a,data=dd)
mymatrix - oldmatrix[1:271,4:19000]
--- My Coyne [EMAIL PROTECTED] wrote:
Hi All,
I'm new with R; this is a basic question. I was
given a matrix I of (nrow,
ncol), I would like to create another matrix A with
some data in the matrix
I, say [1,4] (row 1, column 4) to [271,19000] (row
See
?download.file
?url
Omegahat package RCurl
You do realize that the 'code of web page' is just what you download?
E.g. (working example)
readLines(url(http://www.r-project.org;))
On Sun, 13 Jan 2008, John Lande wrote:
dear R user,
I need a function that download the code of web page
Henric Nilsson (Public) wrote:
Jarek Jasiewicz wrote:
Charles Annis, P.E. wrote:
Jarek:
Although it is not universally agreed on, I believe the first step
in any
data analysis is to PLOT YOUR DATA.
dd - data.frame(a=c(1, 2, 3, 4, 5, 6), b=c(3, 5, 6, 7, 9, 10))
plot(b ~ a, data=dd)
Hi the list.
Is there a bug in mmlcr package ?
The following code does not compile:
mmlcrTest - function(dataW){
dataL -
reshape(dataW,idvar=id,timevar=T,varying=list(paste(T,0:10,sep=)),direction=long,v.names=score)
resultR - mmlcr(outer= ~ 1 | id,
components =
I seem to have a problem getting latex (Hmisc) to
work.
Any suggestions as to what I am doing wrong?
Thanks
library(Hmisc)
aa - data.frame(aa=1:10, bb=rnorm(10, 5, 2),
cc=rnorm(10, 20, 4))
rr - lm(cc~aa+bb, data=aa); rr
latex(rr)
latex(rr)
'latex' is not recognized as an internal or external
Try specifying the file= argument:
latex(rr, file = )
On Jan 13, 2008 1:05 PM, John Kane [EMAIL PROTECTED] wrote:
I seem to have a problem getting latex (Hmisc) to
work.
Any suggestions as to what I am doing wrong?
Thanks
library(Hmisc)
aa - data.frame(aa=1:10, bb=rnorm(10, 5, 2),
Hello,
Newbie question and hope you can help .
I have two vector V1 and V2, where length(V2) = length of (V1) * 2;
length(V1) ~ 16,000.
For each member in V1, I need to compare 2 element of V2 for equality
i.e.
for (I in 1:length (V1)) {
if ( v2[i] == v1[i] v2[i+1]==v1[i] ){
My Coyne wrote:
Hello,
Newbie question and hope you can help .
I have two vector V1 and V2, where length(V2) = length of (V1) * 2;
length(V1) ~ 16,000.
For each member in V1, I need to compare 2 element of V2 for equality
If just the comparison is concerned, you can do it in
Works just fine, thanks. I'll blame the help as
being very slightly ambiguous.
Of course another 2-3 minutes experimenting and I
should have gotten it.
--- Gabor Grothendieck [EMAIL PROTECTED]
wrote:
Try specifying the file= argument:
latex(rr, file = )
On Jan 13, 2008 1:05 PM, John
[EMAIL PROTECTED] wrote:
WRT: Say length(V1) is n, do you want to compare
v1[1] with v2[1] and v2[2] and v1[2] with v2[3] and v2[4]
or
v1[1] with v2[1] and v2[n+1] and v1[2] with v2[2] and v2[n+2]
v1[1] with (v2[1] and v2[2])
v1[2] with (v2[3] and v2[4])
v1[3] with (v2[5] and v2[6])
John Kane wrote:
Works just fine, thanks. I'll blame the help as
being very slightly ambiguous.
From the help file:
\section{Side Effects}{
creates various system files and runs various Linux/UNIX system
commands which are assumed to be in the system path.
}
\details{
If running under
Thank Frank,
I simply seem to have misread part of the first
example
--
x - matrix(1:6, nrow=2,
dimnames=list(c('a','b'),c('c','d','enLine 2')))
## Not run:
latex(x) # creates x.tex in working directory
w - latex(x, file='/tmp/my.tex')
What is the formula used in Shapiro-Wilk Statistic?
Thanks
Eduardo (São Paulo/ Brazil)
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
first hit on google:
http://en.wikipedia.org/wiki/Shapiro-Wilk_test
=)
b
On Jan 13, 2008, at 4:01 PM, [EMAIL PROTECTED] wrote:
What is the formula used in Shapiro-Wilk Statistic?
Thanks
Eduardo (São Paulo/ Brazil)
__
R-help@r-project.org mailing
John Kane wrote:
Thank Frank,
I simply seem to have misread part of the first
example
--
x - matrix(1:6, nrow=2,
dimnames=list(c('a','b'),c('c','d','enLine 2')))
## Not run:
latex(x) # creates x.tex in working directory
w - latex(x,
Hi Uwe,
Thank you so much for your help. It works great with your
suggestion/help. WOW, what a difference!
--MyC
[EMAIL PROTECTED] wrote:
WRT: Say length(V1) is n, do you want to compare
v1[1] with v2[1] and v2[2] and v1[2] with v2[3] and v2[4]
or
v1[1] with v2[1] and v2[n+1] and v1[2]
hi;
When I first started looking at R code, I thought that the - notation for
assignment made the code less readable (and I still do). Then I found that
now one can use = in place of - for assignment (I understand this
started since version 1.4). Anyway, I think using = makes the code much
No.
f - function(a = 3, b = 4) a-b
f(b = 10)
[1] -7
f(b - 10)
[1] 6
but if you only replace it in the context:
x - ...
then it should be ok.
On Jan 13, 2008 5:41 PM, Nasser Abbasi [EMAIL PROTECTED] wrote:
hi;
When I first started looking at R code, I thought that the - notation for
Note that the zoo package has a multiway merge for zoo class time
series:
library(zoo)
as.matrix(do.call(merge, lapply(test, function(x) zoo(unname(x), names(x)
A B C D X
A a a NA NA a
B b b NA b b
C c c NA c c
D d d NA d d
E e e e e e
F f NA f f f
G g NA g NA g
H h NA h
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of John Kane
Sent: Sunday, January 13, 2008 03:56 PM
## Not run:
latex(x) # creates x.tex in working directory
w - latex(x, file='/tmp/my.tex')
-
I think there
Most R users believe that there is a clear distinction between - and
=.
Gabor's example is a wonderful illustration of that distinction.
Most users recommend - for assignment for greater clarity and
readability.
The important characteristic for readability is the space on both sides of
the
I think it is worth pointing out that, if you use ESS with (X)emacs,
- (with spaces) is produced when you type _. It requires only two
keystrokes (shift and -), and the spaces are done for you. The = sign
requires three because you need to type the spaces on each side.
Jon
Running Version 2.6.0 GUI 1.21.
Generally, I enjoy working with the OSX GUI,
which has some very pleasant features.
Kudos to the developers!
There is a nice history panel which slides out of the
Console window. The buttons on the panel work as expected.
I am puzzled by the behavior of
Richard M. Heiberger wrote:
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of John Kane
Sent: Sunday, January 13, 2008 03:56 PM
## Not run:
latex(x) # creates x.tex in working directory
w - latex(x, file='/tmp/my.tex')
Discovered by accident:
If your R session has become unresponsive to escape presses etcetera,
you can try this.
Open a terminal window, run the command
ps -ax | grep R.app
Note the process ID number in the first column. Say it's 1234.
Then run
kill -4 1234
The key is that the signal you
.. and don't forget that 6 - x works but 6 = x won't ...
Gabor Grothendieck [EMAIL PROTECTED] 01/13/08 10:50 PM
No.
f - function(a = 3, b = 4) a-b
f(b = 10)
[1] -7
f(b - 10)
[1] 6
but if you only replace it in the context:
x - ...
then it should be ok.
On Jan 13, 2008 5:41 PM, Nasser
And of course let's not forget that a particularly twisted individual
could overwrite =:
`=` - function(x,y) print(x+y)
3 = 4
[1] 7
3 - 4
Error in 3 - 4 : invalid (do_set) left-hand side to assignment
I also was for a while mystified by the - assignment, and preferred
= instead, but
Duncan Murdoch wrote:
Gad Abraham wrote:
Hi,
In 2.6.0 arima() used to return an object with attribute `x' which is
the observed time series, but this has been dropped from 2.6.1.
This breaks the forecast function in package forecast.
There's no mention of it in the changelog for 2.6.1.
On Jan 13, 2008 8:02 PM, Day, Roger S. [EMAIL PROTECTED] wrote:
Discovered by accident:
If your R session has become unresponsive to escape presses etcetera,
you can try this.
Open a terminal window, run the command
ps -ax | grep R.app
Note the process ID number in the first column. Say
I've spent several hours trying to track the answer down myself and failed
miserably so a simple question for everyone that will no doubt have a
painfully obvious answer.
What's the command to calculate the critical value of r using a two tailed
test with a given alpha and degrees of freedom?
Dear useRs,
The following plots only print 2 of the 4 labels under the bars, is there
a way please to force all 4 labels to print?
par(mfrow=c(1,2),mar=c(2,7,3,1))
dat-data.frame(AgeGroup=c(2-15,16-20,21-25,26-39),
Aorta=c(20,8,30,60),
Coronary=c(7,30,55,65))
Quoth Mark Wardle on Prickle-Prickle, Chaos 14, 3174:
I can see that f(b - 10) is equivalent to f(assign(b), 10))
f(assign(b, 10))?
My undestanding is that assign applies to the parental environment;
but the return value of assign, namely 10, is passed to f as the local
variable a.
The default
On 14/01/2008, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Its not related to scoping. f(b = 10) passes 10 as argument b
but f(b - 10) assigns to variable b (which has nothing to do with
argument b) and then passes the result of the b-10 expression (which is
10) to f. Since no argument was
On Mon, 14 Jan 2008, Mark Wardle wrote:
On 13/01/2008, Gabor Grothendieck [EMAIL PROTECTED] wrote:
No.
f - function(a = 3, b = 4) a-b
f(b = 10)
[1] -7
f(b - 10)
[1] 6
I had to go and read (and re-read) the R manual on lexical scope to
lexical scope does not come into this; S behaves
Its not related to scoping. f(b = 10) passes 10 as argument b
but f(b - 10) assigns to variable b (which has nothing to do with
argument b) and then passes the result of the b-10 expression (which is
10) to f. Since no argument was specified it uses positional
matching and the first position is
Dear list,
I am using R 2.6 on a Windows XP machine.
I divided my device window and tried to set the backgroundcolor for each plot
region/figure region separately. This seems not possible?? A simple example:
# create random numbers
a - rnorm(100)
# divide device window
par(mfrow=c(1,2))
# set
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