Sorry about that Jeff.
I have attached the data file to this email.
Kind regards,
Casey Wright
Casey Wright BSc (Hons I)I PhD Candidate I The University of Queensland
School of Medicine l Room 2, Level 1, Clinical Sciences Building, The
Prince Charles Hospital, Rode Road,
On 09/20/2010 04:00 AM, Samantha McKenzie wrote:
The data look fine and correlation/regression can be done on them with
correct output. Just not scatterplots.
I tried a work around using the following script, but still with the
same result:
attach(Mass)
Mass
str(Mass)
names(Mass)
I did not reproduce the error either, because I failed to find the
function scattperplot in your script. :D I suggest that you check
whether they read the data into R correctly.
On 2010-9-20 10:00, Samantha McKenzie wrote:
Hello,
I teach statistics and use R Commander for teaching. I have 2
Hi!
I would like to select probes (affy expression set) of genes that are
cancer-related. Conventionally the decision whether a gene is
cancer-related or not is made by looking up the literature. Since this
is not possible for all genes on the array I wonder if there is a way of
doing this
LinkedIn
Tal Galili requested to add you as a connection on LinkedIn:
--
Arnaud,
I'd like to add you to my professional network on LinkedIn.
- Tal Galili
Accept invitation from Tal Galili
Hi All,
I have trying to do what I thought was a reasonably simple graph but I think
I'm now going in circles with the colour. Attached is a picture of where I'm
up to.
The line creating this is:
qplot(ageincgraph$age, ageincgraph$rate, position=dodge, stat=identity,
geom=bar ) + aes(
Tal:
Invite everyone on R-Help, why not?
Please check your contact e-mail address!
Edwin
--
On Mon, 20 Sep 2010 02:14:17 -0700 (PDT)
Tal Galili via LinkedIn mem...@linkedin.com wrote:
LinkedIn
Tal Galili requested to add you as a connection on
LinkedIn:
If you want to change the fill colours, then you need to specify fill
instead of colour
ggplot(ageincgraph, aes(x = age, y = rate, fill = era)) +
geom_bar(position = dodge, stat = identity) +
scale_fill_manual(values=c(red,orange,yellow))
Dear List,
I ran a regression model using lm and produced a regression line using
abline.
The line ranges from -20 to 20 in x axis,
and the section I only want is from -20 to 0.
Please kindly advise any function in abline () to set the range of x axes.
Thank you
Elaine
Hi!
I would like to select probes (affy expression set) of genes that are
cancer-related. Conventionally the decision whether a gene is
cancer-related or not is made by looking up the literature. Since this
is not possible for all genes on the array I wonder if there is a way of
doing this
Hello
How can I substitute all NA values by zero in a R zoo series?
I've been reading about na.locf and na.omit but I think none of them do
what I need.
thanks.
--
View this message in context:
http://r.789695.n4.nabble.com/Substitute-NAs-by-zero-tp2546715p2546715.html
Sent from the R help
Check the following thread from a couple of years ago:
http://www.mail-archive.com/r-help@r-project.org/msg14521.html
cheers,
-Girish
--
View this message in context:
http://r.789695.n4.nabble.com/Substitute-NAs-by-zero-tp2546715p2546725.html
Sent from the R help mailing list archive at
v-c(1,2,3,4,5,6,7,8,97,6,5,4,NA,NA)
b-zoo(v)
b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 NA NA
b[is.na(b)]-0
b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 0 0
is.zoo(b)
[1] TRUE
On Mon, Sep 20, 2010 at 2:37 AM, skan
Edwin and everyone else - I am very sorry for this accidental spamming!
Please ignore.
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) |
Hi Jan
r-help-boun...@r-project.org napsal dne 17.09.2010 12:43:40:
Hello Petr,
but I think this is how your code really works. Did you try it?
it does, but the R documentation says somewhere:
Warning: for() loops are used in R code much less often than in
compiled languages. Code that
Hi Jan
Jan private jrheinlaen...@gmx.de napsal dne 18.09.2010 12:12:29:
Hello Petr,
thank you for your ideas. The split() looks most realistic.
What about this idea:
1. Define three functions Refun1, Refun2, Refun3 for the three different
sections of the calculations (same as you
Hi,
In this case, str() would help you a lot too to understand the structure
of your ft object, and especially which element contains what.
Ivan
Le 9/20/2010 04:59, Michael Bedward a écrit :
A good function to know about is names(). For example...
ft- fisher.test( my.data )
names(ft)
darckeen wrote:
I'm trying to get the following section of code to work, I think the problem
is being caused by the assignment of data to the lm function not evaluating
to train in the parent environment but I can't seem to figure out how to
do this.
I'd suggest simplifying this. Packing
On Mon, 2010-09-20 at 17:31 +0800, elaine kuo wrote:
Dear List,
I ran a regression model using lm and produced a regression line using
abline.
The line ranges from -20 to 20 in x axis,
and the section I only want is from -20 to 0.
Please kindly advise any function in abline
Thanks Thierry, will have a go when back in the office tomorrow. I had tried
ggplot as opposed to qplot but didn't get any further.
I'm actually after a greyscale graph for black and white printing (red etc
was just so I could see the change before tweaking further). A reasonably
thorough
On 09/20/2010 07:25 PM, Edwin Groot wrote:
Tal:
Invite everyone on R-Help, why not?
Please check your contact e-mail address!
Edwin
I think this is LinkedIn, as I have gotten a number of more or less spam
notifications like this when the person involved had no idea they were sent.
Jim
On 09/20/2010 07:31 PM, elaine kuo wrote:
Dear List,
I ran a regression model using lm and produced a regression line using
abline.
The line ranges from -20 to 20 in x axis,
and the section I only want is from -20 to 0.
Please kindly advise any function in abline () to set the range of
Textures are currently not possible in ggplot2. Because grid does not
support them.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Hi
r-help-boun...@r-project.org napsal dne 17.09.2010 17:02:29:
On 9/16/10 5:00 PM, Rolf Turner wrote:
On 17/09/2010, at 8:51 AM, Duke wrote:
Hi Duncan,
On 9/16/10 3:47 PM, Duncan Murdoch wrote:
On 16/09/2010 3:40 PM, Duke wrote:
Hi all,
I am writing a function (fun.R),
Dear List,
I am familier with binary models, however i am now trying to get predictions
from a ordinal model and have a question.
I have a data set made up of 12 categorical predictors, the response variable
is classed as 1,2,3,4,5,6, this relates to threat level of the species ( on the
IUCN
Jake Kami jakejkami at gmail.com writes:
dear list,
i am running a within-design ANOVA with 4 factors (4,4,2 and 2 levels each).
the last one is a time factor comprising two different treatment timepoints.
i fit a mixed-effects model using lme and apply the anova function to the
outcome.
Unger Kristian k.unger at imperial.ac.uk writes:
I would like to select probes (affy expression set) of genes that are
cancer-related. Conventionally the decision whether a gene is
cancer-related or not is made by looking up the literature. Since this
is not possible for all genes on the
Hi,
I have a function that takes close to 60 seconds to run. In this time, the R
interface freezes and I have to wait for it to complete. Is there anyway the
function can run in the background while I continue to use the interface? It
could send me a signal when it completed.
Hi!
I'm trying to read individual files from a ZIP archive, using the unz()
function. Some of the files contain non-ASCII characters and I'd like to avoid
unpacking them in a temporary directory.
My problem is that unz() seems to ignore the encoding=latin1 option I need to
read the non-ASCII
Dear List,
I am using plot for homework.
The x-axis covered from 0 to 80, with 4 intervals.
However, the plot only showed 0, 40, 80.
20 and 60 disappeared.
Please kindly advise how to show 0, 20, 40, 60, 80 for the axis interval.
Thank you.
Elaine
[[alternative HTML version deleted]]
Hi,
The list is not made for helping students with their homeworks.
I will just tell you this: there are graphic parameters for every single
detail on a plot. Take a look at ?par
Ivan
Le 9/20/2010 15:44, elaine kuo a écrit :
Dear List,
I am using plot for homework.
The x-axis covered
On 20/09/2010 9:44 AM, elaine kuo wrote:
Dear List,
I am using plot for homework.
You should ask your instructor or teaching assistant for help on homework.
Duncan Murdoch
The x-axis covered from 0 to 80, with 4 intervals.
However, the plot only showed 0, 40, 80.
20 and 60 disappeared.
Have a look at ?axis
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
team Biometrics
You sent a private note about this which I just took the time to answer.
Please send only one note, and please post my reply to you to r-help.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
Duncan Murdoch murdoch.duncan at gmail.com writes:
On 20/09/2010 9:44 AM, elaine kuo wrote:
Dear List,
I am using plot for homework.
You should ask your instructor or teaching assistant for help on homework.
Duncan Murdoch
The x-axis covered from 0 to 80, with 4 intervals.
Dear all,
I'm performing a t-test on two normal distributions with identical mean
standard deviation, and repeating this tests a very large number of times to
describe an representative p value distribution in a null case. As a part of
this, the program bins these values in 10 evenly distributed
A few comments; sorry I don't have time for any more.
- Combining categories is almost always a bad idea
- It can be harder to discriminate more categories but that's only because the
task is more difficult
- Split-sample validation is not reliable unless you have say 10,000 samples to
begin
On 20/09/2010 9:54 AM, A wrote:
Dear all,
I'm performing a t-test on two normal distributions with identical mean
standard deviation, and repeating this tests a very large number of times to
describe an representative p value distribution in a null case. As a part of
this, the program bins
On Sep 20, 2010, at 15:50 , Frank Harrell wrote:
You sent a private note about this which I just took the time to answer.
Please send only one note, and please post my reply to you to r-help.
I have been annoyed by this at times as well. However, I have come to suspect
that it is actually
C.H. chainsawtiney at gmail.com writes:
http://r-forge.r-project.org/projects/tuner/
On Mon, Sep 20, 2010 at 8:35 AM, Deb Midya debmidya at yahoo.com wrote:
[snip]
1. Is there any R-package or if any to compose music?
2. Is there any R-package or if any to analyse music?
A petlyakov at gmail.com writes:
Dear all,
[snip]
Here are two key parts of my code to show what functions I'm working with:
#Calculating the p values
while(inumtests){
Group1-rnorm(6,-0.0065,0.0837)
Group2-rnorm(6,-0.0065,0.0837)
PV-t.test(Group1,Group2)$p.value
On 20-Sep-10 13:54:56, A wrote:
Dear all,
I'm performing a t-test on two normal distributions with identical
mean standard deviation, and repeating this tests a very large
number of times to describe an representative p value distribution
in a null case. As a part of this, the program bins
A few comments; sorry I don't have time for any more.
- Combining categories is almost always a bad idea
- It can be harder to discriminate more categories but that's only because the
task is more difficult
- Split-sample validation is not reliable unless you have say 10,000 samples to
begin
Mango Solutions announce a public training course in ADVANCED R on the 6th and
7th October 2010 in London.
This 2 day course is suitable for people with a working knowledge of R who
want to extend their knowledge to take advantage of the fuller capabilities of
R. Ideally, attendees should
On Mon, 20 Sep 2010, Duncan Murdoch wrote:
On 20/09/2010 9:54 AM, A wrote:
Dear all,
I'm performing a t-test on two normal distributions with identical mean
standard deviation, and repeating this tests a very large number of times
to
describe an representative p value distribution in a null
Thanks Peter. I think you're right.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
http://r.789695.n4.nabble.com/predict-lrm-Design-package-tp2546894p2547146.html
Sent from the R help mailing list archive at Nabble.com.
I am creating a Slovak translation of an interactive website (
http://mazamascience.com/OilExport/index_sk.html ) and am running into
problems with R's lack of support for the caron found in the following
letters: Ä/Ä, Å /Å¡ and Ž/ž.
I am using R 2.6.1 running on a recent version of CentOS.
Hi, I am trying to reconcile anova table in R (summary(lm)) with individual
t.test.
datafilename=http://personality-project.org/R/datasets/R.appendix1.data;
data.ex1=read.table(datafilename,header=T) #read the data into a table
summary(lm(Alertness~Dosage,data=data.ex1))
gives:
Call:
Hello
Dne Po 20. září 2010 10:28:54 Jonathan Callahan napsal(a):
I am creating a Slovak translation of an interactive website (
http://mazamascience.com/OilExport/index_sk.html ) and am running into
problems with R's lack of support for the caron found in the following
letters: Ä/Ä, Å /Å¡
On Sep 20, 2010, at 11:53 AM, Jabez Wilson wrote:
Hi, I am trying to reconcile anova table in R (summary(lm)) with
individual t.test.
datafilename=http://personality-project.org/R/datasets/R.appendix1.data
data.ex1=read.table(datafilename,header=T) #read the data into a
table
On Mon, 20 Sep 2010, Jabez Wilson wrote:
Hi, I am trying to reconcile anova table in R (summary(lm)) with individual
t.test.
datafilename=http://personality-project.org/R/datasets/R.appendix1.data;
data.ex1=read.table(datafilename,header=T) #read the data into a table
Now that is a more useful reply than Why do you assume there is one?. Thanks
a lot Ravi!
--- On Fri, 9/17/10, Ravi Varadhan rvarad...@jhmi.edu wrote:
From: Ravi Varadhan rvarad...@jhmi.edu
Subject: RE: [R] Is there a bisection method in R?
To: 'Peter Dalgaard' pda...@gmail.com, 'Gregory
I have a 2x50 matrix and would like to round all the elements to 2
decimal places. Can any one help?
Thanks,
Raphael
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Look at the functions dummy.coef, model.tables, and se.contrasts, they may help
with what you want. You can also look at the multcomp package for another
approach.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
Hi Raphael,
mat - matrix(rnorm(100), ncol = 2)
round(mat, 2)
for documentation see ?round
Cheers,
Josh
On Mon, Sep 20, 2010 at 9:21 AM, Raphael Fraser
raphael.fra...@gmail.com wrote:
I have a 2x50 matrix and would like to round all the elements to 2
decimal places. Can any one help?
Call for Papers:
R/Finance 2011: Applied Finance with R
April 29 and 30, 2011
Chicago, IL, USA
The third annual R/Finance conference for applied finance using R will
be held this spring in Chicago, IL, USA on April 29 and 30, 2011. The
two-day conference will cover topics including portfolio
On Sep 20, 2010, at 12:25 PM, Joshua Wiley wrote:
Hi Raphael,
mat - matrix(rnorm(100), ncol = 2)
round(mat, 2)
for documentation see ?round
Thanks, Josh. I was having trouble a couple of minutes ago remembering
this. Getting old, I guess. In constructing my thanks to Josh I tested:
On Sep 20, 2010, at 18:15 , Gregory Gentlemen wrote:
Now that is a more useful reply than Why do you assume there is one?.
Thanks a lot Ravi!
Well, maybe, but you can NOT expect that someone will go out of THEIR way to
solve YOUR problem every time. Sometimes they will and sometimes they
Fair enough. I didn't intend to offend anyone. Please accept my apologies.
Greg
--- On Mon, 9/20/10, peter dalgaard pda...@gmail.com wrote:
From: peter dalgaard pda...@gmail.com
Subject: Re: [R] Is there a bisection method in R?
To: Gregory Gentlemen gregory_gentle...@yahoo.ca
Cc: Ravi Varadhan
Look at the clip function for one approach. You specify the clipping region,
then do abline and it only shows up in the region specified.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
I am glad, Greg, you did this. Peter is one of the backbones behind R, and
has made enormous contributions to it. He deserves to be treated with
respect.
More to the point, Peter's comments are perfectly reasonable. People are
motivated by different factors to go to extra lengths to help
Suppose I have a data frame, such as the one below:
tmp - data.frame(index = gl(2,20), foo = rnorm(40))
And further assume it is sorted by index and then by the variable foo.
tmp - tmp[order(tmp$index, tmp$foo) , ]
Now, I want to grab the first N rows of tmp for each index. In the end, what I
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))=5)
- Phil Spector
Statistical Computing Facility
Very nice, Phil. Thank you.
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Monday, September 20, 2010 1:28 PM
To: Doran, Harold
Cc: R-help
Subject: Re: [R] Sorting and subsetting
Harold -
Two ways that come to mind:
1)
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of randomizing those with life-threatening
disease to relatively ineffective SOC when new biologically
Hi Harold,
I thought of one way to do this, but maybe (probably) there is a faster way:
tmp - data.frame(index = gl(3,20), foo = rnorm(60))
subset.first.x.elements - function(INDEX, num.of.elements = 5)
{
t.INDEX - table(factor(INDEX, levels = unique(INDEX)))
running.indexes -
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
spec...@stat.berkeley.edu wrote:
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))=5)
3) do.call(rbind, by(tmp, tmp$index, .Primitive([), 1:5,
Dear All,
Does anyone know if there is any R implementation of the Lempel-Ziv
entropy estimator?
I searched for it in the entropy contributed package, but unsuccessfully.
Cheers
Lorenzo
__
R-help@r-project.org mailing list
On 09/20/2010 07:16 PM, Doran, Harold wrote:
tmp1 - tmp1[1:5,]
tmp2 - tmp2[1:5,]
result - rbind(tmp1, tmp2)
Does anyone see a way to subset and subsequently bind without a loop?
do.call(rbind,lapply(split(tmp,tmp$index),head,5))
indexfoo
1.11 1 -1.5124909
1.10 1
On 9/17/2010 4:39 PM, Phil Spector wrote:
Soyeon -
I think scan() (combined with matrix and data.frame) is the easiest way.
Suppose your text file is called data.txt. Then
data.frame(matrix(scan('data.txt'),byrow=TRUE,ncol=14))
should give you what you want.
- Phil Spector
Statistical
On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
spec...@stat.berkeley.edu wrote:
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))=5)
3)
Thank you Peter for your explanation of relationship between aov and lme. It
makes perfect sense.
When you said you might have computed the average of all 8
measurements on each animal and computed a 1-way ANOVA for treatment effect,
would this be the case for balanced design, or it is also
On Sep 20, 2010, at 2:01 PM, David Winsemius wrote:
On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
spec...@stat.berkeley.edu wrote:
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2)
Richard Tan asked a very similar question last week
('get top n rows group by a column from a dataframe').
You could use ave() to make a sequence-number-within-group
vector and choose rows with a small enough value there:
tmp[ave(integer(nrow(tmp)), tmp$index, FUN=seq_along)=N, ]
If there are
Dear All,
I have data which contains 14 variables. And I have to regress one of
variables on each variable (simple 13 linear regressions)
I try to make a loop and store only R-squared
colnames(boston)
[1] CRIMZN INDUS CHASNOX RM AGE
[8] DIS RAD TAX PTRATIO
Dear All,
I am trying to use ode solver rk4 to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object dIN not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls())
library(odesolve)
# The ODE system
On Mon, 20 Sep 2010, Bert Gunter wrote:
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of randomizing those with life-threatening
disease to relatively
On Mon, Sep 20, 2010 at 11:15 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Sep 20, 2010, at 2:01 PM, David Winsemius wrote:
On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
spec...@stat.berkeley.edu wrote:
Harold -
Two ways that
Try this:
lapply(names(boston), function(x)summary(update(lm(MEDV ~ 1, boston), ~
get(x
On Mon, Sep 20, 2010 at 2:03 PM, Soyeon Kim yunni0...@gmail.com wrote:
Dear All,
I have data which contains 14 variables. And I have to regress one of
variables on each variable (simple 13 linear
Hi Soyeon,
Here are a few options:
## Use get() to find the predictor
r - rep(0, 13)
for(i in 1: 13) {
r[i] - summary(lm(MEDV ~ get(name[i]), data = boston))$r.squared
}
## Use as.formula(paste()) to construction the model
for(i in 1: 13) {
r[i] - summary(lm(as.formula(paste(MEDV ~ , name[i],
Dear All,
I am trying to use ode solver rk4 to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object dIN not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls())
library(odesolve)
# The ODE system
On Sep 20, 2010, at 2:28 PM, Charles C. Berry wrote:
On Mon, 20 Sep 2010, Bert Gunter wrote:
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of
interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of
I was just reading about the merge sort algorithm last night (BTW, here
is a fun link http://www.youtube.com/watch?v=t8g-iYGHpEA). There are
some interesting similarities in this context. Here's a recursive method
for bisection:
bisectMatt - function(fn, lo, hi, tol = 1e-7, ...) {
flo -
On 09/20/2010 08:09 PM, array chip wrote:
Thank you Peter for your explanation of relationship between aov and lme. It
makes perfect sense.
When you said you might have computed the average of all 8
measurements on each animal and computed a 1-way ANOVA for treatment effect,
would this
On 09/20/2010 08:01 PM, David Winsemius wrote:
indexfoo
1.6 1 -3.0267759
1.7 1 -1.3725536
1.19 1 -1.1476048
1.16 1 -1.0963967
1.2 1 -1.0684793
2.29 2 -1.6601486
2.21 2 -1.2633632
2.22 2 -0.9875626
2.38 2 -0.9515301
2.30 2
Thank you Peter and Ben for your comments.
John
- Original Message
From: Peter Dalgaard pda...@gmail.com
To: array chip arrayprof...@yahoo.com
Cc: r-help@r-project.org; r-sig-mixed-mod...@r-project.org
Sent: Mon, September 20, 2010 12:28:43 PM
Subject: Re: [R] lmer() vs. lme() gave
Hello,
Which would be the command to change the size of the legend.
I checked at the help and I found out something about TEXT.WIDTH, but I am
not sure if is what I want.
Any help!
Thanks in advance,
Marcio
--
View this message in context:
On 20/09/2010 3:07 PM, Tianchan Niu wrote:
Dear All,
I am trying to use ode solver rk4 to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object dIN not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls())
Clearly inferior treatments are unethical.
Donald Berry at MD Anderson in Houston TX and Jay Kadane at Carnegie
Mellon have been working on more ethical designs within the Bayesian
framework. In particular, response adaptive designs reduce the assignment
to and continuation of patients on
Thank you all
On Mon, Sep 20, 2010 at 12:53 PM, Zoppoli, Gabriele (NIH/NCI) [G]
zoppo...@mail.nih.gov wrote:
see help(round)
Gabriele Zoppoli, MD
Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University
of Genova, Genova, Italy
Guest Researcher, LMP, NCI, NIH, Bethesda
sampleSize - 20
shape.true - 1.82
scale.true - 987
sampWB - rweibull(sampleSize, shape=shape.true, scale=scale.true)
print(sampWB)
censidx - sample(1:length(sampWB), length(sampWB)*0.3)
Censored.data - sampWB[censidx]
noncensidx - defines the rest values of the vector which is not included at
Anan -
If you actually want the indices, you can use
seq_along(sampWB)[-censidx]
If you want the values themselves, then use
sampWB[-censidx]
- Phil Spector
Statistical Computing Facility
Please I need some help using R to
analyze my data. What I
would like to do is to repeat the same basic process (e.g. linear regression
between wood density and distance from pith) for at least 240 data
subsets
within the main data-frame. Within the main data-frame, these data subsets will
be
Base graphics, ggplot2 or lattice? You need to be more specific. A
reproducible example to illustrate your problem would be helpful.
Dennis
On Mon, Sep 20, 2010 at 1:07 PM, Mestat mes...@pop.com.br wrote:
Hello,
Which would be the command to change the size of the legend.
I checked at the
If you assume that the variance is the same in all your subsets,
you can do an lm analysis with your subset classification as a factor.
You could also analyze the interaction between factors
and between factors and your numeric independent variable.
You also should consider repeated measurement
From: Oyomoare Osazuwa-Peters oyomo...@yahoo.com
Subject: Re: [R] Help!
To: Erich Neuwirth erich.neuwi...@univie.ac.at
Date: Monday, September 20, 2010, 5:16 PM
Thanks for responding to my request for help.
I understand what you mean about the repeated measurements methods for the two
cores.
You could do most of this with the function lmList in the nlme package, but
since you want both plots and summaries, you might as well do it in a more
flexible loop.
How about something like this:
Code:
## This makes a single factor to define your groups
BCI - within(BCI,
VojtÄch,
Thanks for responding. I should be clear that the web pages and server all
support UTF-8 quite well.
I am asking about using slavic letters with the caron/hacek symbol in R *
plots*. Reading old messages I see that this has been a problem in past
years. Can you -- or anyone else --
On Mon, 20 Sep 2010, Jonathan Callahan wrote:
Can you -- or anyone else -- point me to some plots in R that have
Czech, Slovak or Polish text on them? That would be the proof that it is
possible. Then I would still need to figure out why my version fails to
print this text properly.
I have
Awesome! Can you tell me what version of R you are using and what operating
system? R does use system fonts, doesn't it? Perhaps I just don't have the
correct fonts installed -- I'm on CentOS.
Jon
2010/9/20 Thomas Lumley tlum...@u.washington.edu
On Mon, 20 Sep 2010, Jonathan Callahan wrote:
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