On Wed, 6 Oct 2010, Peter Langfelder wrote:
you should close files that you do not use anymore. the maximum number
of open files is likely 4000 or so. Use close(file) before you open
the next one.
He/she said he did that, and as the limit on open connections is 128,
that cannot be the sole
Hi
r-help-boun...@r-project.org napsal dne 07.10.2010 07:16:01:
Hi,
With a vector like:
x = c (22, 23, 22.5, 0,0,24, 0, 23.2, 23.5, 0,0,0, 26)
How can I replace the 0's with the previous last value without looping
through the vector ?
Change your zeroes to NA values
x[x==0]-NA
Alternatively,
see rowQuantiles() in the matrixStats package.
/Henrik
On Wed, Oct 6, 2010 at 10:34 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
Hi,
This should do it, for details, see ?apply
a - matrix(rnorm(1),100,100)
t(apply(a, 1, quantile, probs = c(.3, .5)))
Basically you
No, because I thought something that might be easier.
If you see the image again you might notice that the proportions I am
looking for might also be found by using the hypotenuse which is the same
(as all squares are triangles) by finding the adjacent. The adjacent are
easier to be found by
Hi,
I've just seen yesterday on ?plotmath the operator %notin%.
This could also work I guess.
Ivan
Le 10/7/2010 07:41, bill.venab...@csiro.au a écrit :
Try !(group %in% C(A, ...))
A slightly cuter way is to define your own operator.
`%ni%`- Negate(`%in%`)
letters[1:3] %ni% letters[3:5]
Um... if that makes sense for the analysis that you're trying to do
then that's great. I had assumed that you were using the term
integral in its usual sense, ie. area under the curve.
Michael
On 7 October 2010 18:52, alaios ala...@yahoo.com wrote:
No, because I thought something that might be
Hey Duncan,
Thank so much for the site. Quite helpful. Containing everything and
informing me that raster has got no older version.
I have also installed the new R version and I am fine.
Regards
Ogbos
On 5 October 2010 15:11, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 05/10/2010 9:00 AM,
hi all,
how do I filter a dataframe.
What I am looking for is something like:
data-data.frame(matrix(c(2,2,1,2,2,2,2,2,3),byrow=TRUE,ncol=3))
subset(data, subset=(X3==3 X2==2 X1==2))
thanks
--
View this message in context:
On 2010-10-06 13:24, Erik Iverson wrote:
Hello,
You can use ddply from the very useful plyr package to do this.
There must be a way using base R functions, but plyr is
worth looking into in my opinion.
install.packages(plyr)
library(plyr)
ddply(myData, .(class, group, name),
Hi,
Try this:
subset(data, subset=(X3==3 X2==2 X1==2))
X1 X2 X3
3 2 2 3
First, you have numerical values, so don't quote them.
Second, take a look at ? to understand the difference between and .
HTH,
Ivan
Le 10/7/2010 10:43, behave a écrit :
hi all,
how do I filter a dataframe.
Dont know if this is the right forum for this but here we go.
Trying to figure out where I should put the Rserv.conf file in windows,
anyone have any idea?
//Joel
--
View this message in context:
http://r.789695.n4.nabble.com/Rserve-config-tp2966394p2966394.html
Sent from the R help mailing
Thanks, works perfectly
--
View this message in context:
http://r.789695.n4.nabble.com/filter-data-frame-tp2966377p2966398.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
On Wed, 6 Oct 2010, PeterB wrote:
Thanks, Christian. This is really helpful.
I was not aware of that equality, but now I can see it. I think you mean the
inner sum over all distances in the distance matrix (for that cluster),
which means that each distance is counted twice (which is why we
I'm attempting to learn how to use the debug function to find the values of
some variables. I've found a couple of documents describing the basics and
they show examples that the debugger returns
Browse[1]
but for some reason when I follow the examples I get
Browse[2]
What is the 2
On 07/10/2010 4:10 AM, Ivan Calandra wrote:
Hi,
I've just seen yesterday on ?plotmath the operator %notin%.
This could also work I guess.
No, that's just a way to encode the symbol for not an element of.
It's not actually an operator that works outside of plotmath (though you
could make
On 07/10/2010 6:09 AM, Maas James Dr (MED) wrote:
I'm attempting to learn how to use the debug function to find the values of
some variables. I've found a couple of documents describing the basics and
they show examples that the debugger returns
Browse[1]
but for some reason when I follow
Dear all,
I am a new user in r and I am facing some problems with the quantile regression
specification. I have two matrix (mresultb and mresultx) with nrow=1000 and
ncol=nsim, where I specify (let's say) nsim=10. Hence, the columns in my matrix
represents each simulation of a determined
Hello everyone
I have problem with axis labels on graphs, I have my code as below:
plot(0,0,xlim=c(1,ncol(PA)),ylim=c(1,nrow(PA)),main=Stratigraphic
Range,xlab=Time
Bins,ylab=Taxa,cex.axis=1.5,cex.lab=2,cex.main=2.5,mgp=c(5,1.5,0),xaxt=n)
text(1:(length(strat_name)), y= 0, adj=1,
I am trying to install 64 bit R on Linux. But I got the following error -
rpm -i R-core-2.10.0-2.fc11.x86_64.rpm
warning: R-core-2.10.0-2.fc11.x86_64.rpm: Header V3 DSA signature: NOKEY,
key ID 97d3544e
error: Failed dependencies:
/bin/bash is needed by R-core-2.10.0-2.fc11.x86_64
R version 2.8.1 (2008-12-22) on Linux 64-bit
I am trying to run 'rulefit' function (Rule based Learning Ensembles). but I
got the following error -
rulefit(x,y)
Warning: This program is an suid-root program or is being run by the root
user.
The full text of the error or warning message cannot
On 10/07/2010 09:29 PM, Martin Hughes wrote:
Hello everyone
I have problem with axis labels on graphs, I have my code as below:
plot(0,0,xlim=c(1,ncol(PA)),ylim=c(1,nrow(PA)),main=Stratigraphic
Range,xlab=Time
Bins,ylab=Taxa,cex.axis=1.5,cex.lab=2,cex.main=2.5,mgp=c(5,1.5,0),xaxt=n)
Hi,
We are a group of student working on a Java project on a Windows System.
For our project, we need to embed R into Java.
We have read about Rserve, but the single threaded JRI would be enough
for our system.
Actually we were able to install rJava in R through
install.packages(rJava), but
The problem is that I can see a matrix with the coefficients, but not with the
coefficients of all the simulations.
look at the codes now:
set.seed(180185)
nsim - 10
mresultx - matrix(-99, nrow=1000, ncol=nsim)
mresultb - matrix(-99, nrow=1000, ncol=nsim)
for (i in 1:nsim){
# make a
Hi,
Your code is of the form
for (i in 1:nsim) {
## Do something that generates variable qf05
M - coeff(qf05)
}
This means that you are overwriting the variable M at each iteration and
so when the loop has finished you only have the coefficients from the
last simulation. There are lots of
On Oct 7, 2010, at 6:40 AM, Julia Lira wrote:
Dear all,
I am a new user in r and I am facing some problems with the quantile
regression specification. I have two matrix (mresultb and mresultx)
with nrow=1000 and ncol=nsim, where I specify (let's say) nsim=10.
Hence, the columns in my
Hi Julia,
In addition to Martyn's answer and David's friendly post I'd just add
that it's not a good idea to call a variable c since the function of
that name is so often used in R.
Michael
On 7 October 2010 22:28, Martyn Byng martyn.b...@nag.co.uk wrote:
Hi,
Your code is of the form
for
Hello to all R users,
I use R for a year now and am dealing with geometric morphometrics of deer
skulls. Yes, I am a biologist and my math skills are just beginning to brush
up. To cut to the chase...
I have two groups in my data (males and females) and my data is in a simple
vector
Hi,
I have the following problem:
I have a list of entries with vehicles going from some places to others and
the time that they need.
e.g.
Vehicle Start End Time
1A B5
2A C4
3A C3
4B A6
5B
Thank you all for the explanation!
Best,
Julia
Date: Thu, 7 Oct 2010 22:37:32 +1100
Subject: Re: [R] quantile regression
From: michael.bedw...@gmail.com
To: martyn.b...@nag.co.uk
CC: julia.l...@hotmail.co.uk; r-help@r-project.org
Hi Julia,
In addition to Martyn's answer and
Dear All,
I have just installed a new version of R (Version R-2.11.0) and did install
other packages such as raster with ease. However, I could not start the
plotting device x11(). I remembered that somewhere at the stage of
installation, an error occurred : 'configure: error: --with-x=yes
You can also use sqldf:
require(sqldf)
sqldf(select class, `group`, name, avg(height)
+ from myData
+ group by class, 'group', name)
class group name avg(height)
1 0 B Jane58.5
2 0 A Tom62.5
3 1 A Enzo66.5
4 1 B Mary
On Oct 7, 2010, at 7:39 AM, paulideali...@aol.com wrote:
Hello to all R users,
I use R for a year now and am dealing with geometric morphometrics
of deer skulls. Yes, I am a biologist and my math skills are just
beginning to brush up. To cut to the chase...
I have two groups in my
Try this:
with(DF, tapply(Time, list(Start, End), mean))
On Thu, Oct 7, 2010 at 8:40 AM, sugimoto iey...@sugimoto.at wrote:
Hi,
I have the following problem:
I have a list of entries with vehicles going from some places to others and
the time that they need.
e.g.
Vehicle Start End Time
Dear all,
I am looking for an R package that fits multivariate gaussian or
non-gaussian longitudinal outcomes.
I am especially interested to non-gaussian outcomes since the outcomes I've
got are discrete (some are binomial and some are count data).
Many thanks in advance,
Abderrahim
Hey,
Just decided to install the latest version of R and the device is supported.
Thanks
Ogbos
On 7 October 2010 13:49, ogbos okike ogbos.ok...@gmail.com wrote:
Dear All,
I have just installed a new version of R (Version R-2.11.0) and did install
other packages such as raster with ease.
On Oct 7, 2010, at 3:50 AM, noclue_ wrote:
I am trying to install 64 bit R on Linux. But I got the following error -
rpm -i R-core-2.10.0-2.fc11.x86_64.rpm
warning: R-core-2.10.0-2.fc11.x86_64.rpm: Header V3 DSA signature: NOKEY,
key ID 97d3544e
error: Failed dependencies:
Dimitri,
1. The grid will always be on the background. You can use geom_vline() and
geom_hline() to draw horizontal and vertical lines at the positions that you
want them.
2. Note that you must 'stack' the data yourself. Geom_area() just plots a
polygon with 0 as one of the boundaries. When
Windows 7, R-2.11.1 and R-2.12.0beta
When I do
file.info(list.files(getwd()))
I get what I expect, a dataframe with a lot of variables,
especially isdir, which tells me if the named object
is a file or a directory.
In the result of
file.info(list.files(paste(R.home(),library,sep=/)))
all
On Oct 7, 2010, at 6:48 AM, abderrahim youssef wrote:
Dear all,
I am looking for an R package that fits multivariate gaussian or
non-gaussian longitudinal outcomes.
I am especially interested to non-gaussian outcomes since the outcomes I've
got are discrete (some are binomial and some are
Try with full.names = TRUE argument in list.files:
file.info(list.files(paste(R.home(),library,sep=/), full.names = TRUE))
On Thu, Oct 7, 2010 at 9:37 AM, Erich Neuwirth
erich.neuwi...@univie.ac.atwrote:
Windows 7, R-2.11.1 and R-2.12.0beta
When I do
file.info(list.files(getwd()))
I get
On 07/10/2010 8:37 AM, Erich Neuwirth wrote:
Windows 7, R-2.11.1 and R-2.12.0beta
When I do
file.info(list.files(getwd()))
I get what I expect, a dataframe with a lot of variables,
especially isdir, which tells me if the named object
is a file or a directory.
In the result of
Dear list, I want to plot several variables with splom and in the main
diagonal, instead of the variable names, I'd like to plot an histogram of
corresponding variables. Searching I did not find the correct syntax, only
some tips in an old post in the list, but this comments help to plot only
HI,
It's not clear to me exactly what you did.
On Thu, Oct 7, 2010 at 7:49 AM, ogbos okike ogbos.ok...@gmail.com wrote:
Dear All,
I have just installed a new version of R (Version R-2.11.0) and did install
other packages such as raster with ease. However, I could not start the
plotting device
Hey Ista,
I am just learning a bit of installation. Trying my hands on various things
I see on the web. Some proved helpful whereas I am not sure of others.
I didn't compile R from source. Just downloaded R-2.10.0 and tried to
install. The error message I referred to was there when I did
Dear all,
I write to you because there seems to be something I'm just not 'getting' in
the way R lets you construct a new package. Google and this mailing list's
archive don't seem to have the answer to my specific case so I signed up and
mailed the question myself.
So I've written this function
On Oct 7, 2010, at 9:04 AM, Alejo C.S. wrote:
Dear list, I want to plot several variables with splom and in the main
diagonal, instead of the variable names, I'd like to plot an
histogram of
corresponding variables. Searching I did not find the correct
syntax, only
some tips in an old
I am new to R. I thing this will be simple, but I don't yet know my way
around.
I am generating character strings from the system clock that represent
integers, and I want to convert them to integer values. Strtoi works
well, except when there are leading zeros on the string. Could
If I have a list:
list = c(~garch(1,1), ~arma(1,1)) and I run
typeof(list[1]), the output is a list object. But I want each element in the
list to be a language object. How do I transform these list objects to
language objects?
--
View this message in context:
On 07/10/2010 10:06 AM, Mipam Bruining wrote:
Dear all,
I write to you because there seems to be something I'm just not 'getting' in
the way R lets you construct a new package. Google and this mailing list's
archive don't seem to have the answer to my specific case so I signed up and
mailed
obj - c(~garch(1,1), ~arma(1,1))
typeof(obj[[1]])
Use doble '[' indeed of '['
On Thu, Oct 7, 2010 at 10:50 AM, lord12 trexi...@yahoo.com wrote:
If I have a list:
list = c(~garch(1,1), ~arma(1,1)) and I run
typeof(list[1]), the output is a list object. But I want each element in
the
list
On Oct 7, 2010, at 9:57 AM, E. Paul Wileyto wrote:
I am new to R. I thing this will be simple, but I don't yet know my
way around.
I am generating character strings from the system clock that
represent integers, and I want to convert them to integer values.
Strtoi works well, except
Hi,
Think I might be misunderstanding what you want, because ...
t = 123
as.integer(t)
[1] 123
anyway
t = 123
substr(t,regexpr([^0],t),nchar(t))
[1] 123
seems to trim the leading 0's
Martyn
-Original Message-
From: r-help-boun...@r-project.org
I am trying to use auto.arima to fit a univariate time series and do forecast.
This is an imaginary data on monthly outcomes of 2 years and I want to forecast
the outcome for next 12 months of next year.
data Data1;
input RR;
datalines;
12
14
17
15
13
15
15
14
15
14
16
15
15
18
16
16
15
14
15
Hi folks,
I'm trying to get these call-tip things to work in Tinn-R. I expect them
to be somewhat like Microsoft's Intellisense? Anyways, I copy-pasted the
recommended Rprofile.site and adjusted it to fit the location of my
Tinn-R.exe... It looks like this:
I would like to thank you for spending your time to reply to my post.
So far I checked the links provided.
What is still missing is to find some information how local and global
variables work in R. Do you know any link for that? (checked the book but
from the table of contents is not clear if
Dear David, it works just perfect. Thanks a lot for the help
Sincerely,
Alejo
2010/10/7 David Winsemius dwinsem...@comcast.net
On Oct 7, 2010, at 9:04 AM, Alejo C.S. wrote:
Dear list, I want to plot several variables with splom and in the main
diagonal, instead of the variable names,
I am trying to use auto.arima to fit a univariate time series and do forecast.
This is an imaginary data on monthly outcomes of 2 years and I want to forecast
the outcome for next 12 months of next year.
data Data1;
input RR;
datalines;
12
14
17
15
13
15
15
14
15
14
16
15
15
18
16
16
15
14
15
On Oct 7, 2010, at 11:00 AM, alaios wrote:
I would like to thank you for spending your time to reply to my post.
So far I checked the links provided.
What is still missing is to find some information how local and global
variables work in R. Do you know any link for that? (checked the
book
Thanks... As I mentioned, I am new to R, and as.integer was not
what I stumbled onto. I looked up string conversion in the reference
manual, and strtoi is what came up.
P
On 10/7/2010 10:35 AM, David Winsemius wrote:
On Oct 7, 2010, at 9:57 AM, E. Paul Wileyto wrote:
I am new to R. I
So I copy and pasted my function to the R startup file. However, in my
function, I change directories. When I run the function in Eclipse, I get a
message in the console, Cannot change working directory. Why is this?
--
View this message in context:
Hi The reshape suggestions works great on my previous data, but I am unable
to make is work on the new dataset. It actually works but only gives me the
output of single row, instead of 96 rows.
The dataset has two control groups control 1 and control 2, two disease
groups viz disease 1 and
Hello all,
I am trying to use the micEcon 'insertRow' function inside a function
I have written. For example:
insert_row_test - function(m){
insertRow(m,nrow(m)+1,v=0,rName=test)
}
However, when I try to call the 'insert_row_test' function (after
loading the micEcon package), it does not
Hi, R function aggregate can only take summary stats functions, can I
aggregate text columns? For example, for the dataframe below,
a - rbind(data.frame(id=1, name='Tom',
hobby='fishing'),data.frame(id=1, name='Tom',
hobby='reading'),data.frame(id=2, name='Mary',
Esteemed UseRs and DevelopeRs,
Just coming to terms with the very attractive proportional venn
gernator, venneuler(), but would like to customize a few things.
Is it possible to-
-suppress all circle labels?
-suppress only certain circle labels?
-print specific text strings at specified
try this using sqldf:
a
id name hobby
1 1 Tom fishing
2 1 Tom reading
3 2 Mary reading
4 3 John boating
5 2 Mary running
require(sqldf)
sqldf('select name, group_concat(hobby) hobby from a group by id',
method='raw')
name hobby
1 Tom fishing,reading
2 Mary
Try adding a statement at the beginning of your function:
require(micEcon)
See if that helps.
Andrew Miles
Department of Sociology
Duke University
On Oct 7, 2010, at 11:47 AM, Alison Callahan wrote:
Hello all,
I am trying to use the micEcon 'insertRow' function inside a function
I have
Hi Alison,
By default, a function in R creates a copy of the variable that you
pass into it. insertRow() looks to be unusual in that it actually
changes the variable you pass into the function.
So if you run your insert_row_test(x), the function will create a copy
of x, insert a row into it
Hello,
I gave a list of 2 x 2 matrices called matlist. I have about 5000 2 x 2
matrices. I would like to count how many of each 2 x 2 unique matrix I have.
So I am thinking that I need a list of the unique 2 x 2 matrices and their
counts. Can anyone help.
--
Thanks,
Jim.
[[alternative
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Petr PIKAL
Sent: Thursday, October 07, 2010 12:13 AM
To: rivercode
Cc: r-help@r-project.org
Subject: [R] Odp: Vector replace 0 elements without using a loop
Hi
Or:
data.frame( hobs= tapply(a$hobby, list( a$name), c))
hobs
Tom fishing, reading
Mary reading, running
John boating
Note Jim's gives you the names as columns while this has them as
rownames. Further differences : my version has the column as lists
whereas Jim's
I guess the best answer to your question depends on the specifics of the
implementation, but, i think if I were in your situation and I wanted to be
able to call a function foo found in file foo.R every time a user
clicked a button, i'd just
source(path to foo.R)
which just parses the
Hi List.
I've to perform a sequence of conditional sampling without repetition from a
very simple data frame.
It contains the samples and people names (which picked the sample).
Something like this (but much more longer):
Sample
Picker
4ME1B2 B
Ana
4ME1C1 B
Ana
4ME1D2 C
Ana
I may or may not have the most elegant solution to this problem, but if it
were me, I would probably put them all in a list and then
unique_matrix_list - unique(list_of_matrix)
# number of unique matricies:
length(unique_matrix_list)
# count the number of each matrix,
for (m in
Dear R users,
I would like to fit a glm with Poisson distribution and log link with a known
dispersion parameter. I do not want to estimate the dispersion parameter. I
know what it is, so I simply want to fix it at a constant for this and other
models to follow. My simple, no covariate
On Thu, 7 Oct 2010, Huso, Manuela wrote:
Dear R users,
I would like to fit a glm with Poisson distribution and log link with a known
dispersion parameter. I do not want to estimate the dispersion parameter. I
know what it is, so I simply want to fix it at a constant for this and other
I think that R/S's biggest advantage is in the ways you can store data. It
does not force you to fit your data to a single spreadsheet like table, but
rather encourages you to think about your data and find the correct way to
store it. Lists and objects are a great advantage for keeping
Hello,
I have data in the following form
age sex Int.Prev.Est.1 Int.Prev.Est.2 Int.Prev.Est.3
Int.Prev.Est.4 Int.Prev.Est.5
93110 93 0 23.75482 57.86592 9.755003
4.343534 4.280714
93610 93 1 53.36475 39.47247 4.381618
1.622119 1.159044
Try this:
aggregate(hobby ~ id + name, a, FUN = toString)
On Thu, Oct 7, 2010 at 12:52 PM, Tan, Richard r...@panagora.com wrote:
Hi, R function aggregate can only take summary stats functions, can I
aggregate text columns? For example, for the dataframe below,
a -
For your specific question, Jim's answer of staxlab is the best, but for
general placing of text or other graphics elements relative to figure, plot, or
device look at the grconvertX and grconvertY functions.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
Actually, I rechecked the paging and thought about it more, and realized the
windows was French and therefore, the , was the decimal separator and not the
thousand separator. So the paging was staying around 6 (not 6000) most of
the time and hitting the 100 other times. It looks a little bit
Richard -
Yes, you certainly can use aggregate to acheive what you want:
aggregate(a$hobby,a['name'],paste,collapse=' ')
name x
1 Tom fishing reading
2 Mary reading running
3 John boating
- Phil Spector
Hi Kari,
On Thu, Oct 7, 2010 at 12:05 PM, Karl Brand k.br...@erasmusmc.nl wrote:
Esteemed UseRs and DevelopeRs,
Just coming to terms with the very attractive proportional venn gernator,
venneuler(), but would like to customize a few things.
Is it possible to-
Say v is a VennDiagram:
Thank you!
Richard
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, October 07, 2010 12:08 PM
To: Tan, Richard
Cc: r-help@r-project.org
Subject: Re: [R] aggregate text column by a few rows
try this using sqldf:
a
id name hobby
1 1 Tom fishing
2
Dear R users,
I am wondering about the following results:
p.adjust(c(0.05,0.05,0.05),fdr)
[1] 0.05 0.05 0.05
p.adjust(c(0.05,0.04,0.03),fdr)
[1] 0.05 0.05 0.05
Why does p.adjust(..., fdr) not adjust p-values, if they are constant?
Does somebody have an explanation or can point to a reference?
Dear fellows,
I've been working this problem for a day and still can't see where the
problem is. I really appreciate if anyone can help me out.
My data is like:
V1V2 v3
1 a 1.3
1 a 1.5
1 b 2.0
1 a 2.3
1 a 3.4
1 c 5.5
1
Nevermind about the previous post. However, I in the retest sample code, I
can run my own function in the command line. But, say I am creating a GUI
and I want the user to enter the model parameters. How do I, within the java
code, explicity call my unique function without going to the console?
Dear Sirs,
I was hoping you can help me, I am quite desperate in finding a
solution for my problem! I have looked everywhere on the net and tried
hundreds of codes, but I am still not anywhere close to the solution.
I am quite new to R, so please excuse if this seems simple:
I am trying to
Try this:
reshape(UK.INT, direction = 'long', varying = list(grep(Int.Prev.Est,
names(UK.INT
On Thu, Oct 7, 2010 at 2:05 PM, stefan.d...@gmail.com stefan.d...@gmail.com
wrote:
Hello,
I have data in the following form
age sex Int.Prev.Est.1 Int.Prev.Est.2 Int.Prev.Est.3
On Thu, Oct 7, 2010 at 1:05 PM, stefan.d...@gmail.com
stefan.d...@gmail.com wrote:
Hello,
I have data in the following form
age sex Int.Prev.Est.1 Int.Prev.Est.2 Int.Prev.Est.3
Int.Prev.Est.4 Int.Prev.Est.5
93110 93 0 23.75482 57.86592 9.755003
4.343534
Hi, Josh,
What we are doing is, we have a microarray data set with 2000 genes and
roughly 60 samples split 2:1 cancer:normal. So we essentially have one
binary response and 2000 continuous predictors. We want to use this to
develop an ensemble-based classifier method in which the members of
This is correct. Wikipedia is not bad, and provides some references.
Another web page:
http://courses.ttu.edu/isqs6348-westfall/images/6348/BonHolmBenHoch.htm
http://courses.ttu.edu/isqs6348-westfall/images/6348/BonHolmBenHoch.htm
Jeremy
On 7 October 2010 10:37, will.ea...@gmx.net wrote:
Hi,
I have a data set of 47 columns. I would like to create a boxplot for each
column, each boxplot of a different colour.
So I created a vector col1. This vector has a subset of the colors
returned by color()- red, cyan, green etc.
Now I use the command: boxplot(dataset, col= col1) expecting to
On Oct 7, 2010, at 2:21 PM, Barth B. Riley wrote:
Dear list
I would like to compute a Mantel-Haenszel chi-square in which the
matching variable is a continuous variable. The MH chi-square is
used to assess the relationship between two categorical variables at
each level or strata
Anjan -
I think you'll need to give us more information -- I can't
reproduce the problem. For example,
dat = data.frame(matrix(rnorm(47000),100,47))
cols = sample(colors(),47)
boxplot(dat,col=cols)
doesn't repeat any of the colors in cols.
-
Thank you so much for your reply, Z. Of course, you are correct about the
overdispersion not affecting parameter estimation. But my goal is comparison
of several models using QAIC and the dispersion parameter enters the QAIC
calculation. I suppose I could calculate the QAIC of all models
Hi Everyone,
In follow up to my previous question, I wrote some code that correctly makes a
confusion matrix as I need it. However, it only works when the numbers are
between 1 and n. If the possible outcomes are between 0 and n, then I can't
reference row 0 of the matrix and the code breaks.
On Oct 7, 2010, at 12:01 PM, Christian Goelz wrote:
Dear Sirs,
I was hoping you can help me, I am quite desperate in finding a
solution for my problem! I have looked everywhere on the net and tried
hundreds of codes, but I am still not anywhere close to the solution.
I am quite new to R, so
Huso, Manuela manuela.huso at oregonstate.edu writes:
Thank you so much for your reply, Z. Of course, you are correct about
the overdispersion not affecting
parameter estimation. But my goal is comparison of several models
using QAIC and the dispersion
parameter enters the QAIC
On 2010-10-07 12:09, Phil Spector wrote:
Is this what you're looking for?
dat = read.table(textConnection('V1V2 v3
+ 1 a 1.3
+ 1 a 1.5
+ 1 b 2.0
+ 1 a 2.3
+ 1 a 3.4
+ 1 c 5.5
+ 1 d 6.0
+ 1 a 7.0
+
Dear David,
Thank you for your prompt response.
I understand that this may seem like an simple problem to you, but I have never
done this before, so please excuse the mistakes along the line!
May I revise the code according to your suggestion and, should I have further
problems, ask you for
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