We don't have any of the information asked for in the posting guide,
such as your version of R, reproducible example
But please try R-patched, since this might be
• download.file() could leave the destination file open if the URL
was not able to be opened. (PR#14414)
(If you
Dear all,
this looks pretty much a standard problem, but I couldn't find a
satisfying and understandable solution.
(A) Given a data frame (or matrix), e.g.
x - data.frame(A=c(1, 2, 2), B=c(4, 5, 5))
and a row of this data frame, e.g.
r - c(2, 5)
I need to find one row
Mirko,
Here is a solution - I am sure other R mentors would find a more efficient
one
x - data.frame(A=c(1, 2, 2), B=c(4, 5, 5))
x - rbind(x,x)
r - c(2,5)
(rowfind=apply(x,1,FUN=function(row,add){isTRUE(all.equal(row,add,check.attributes
= FALSE))},add=r))
1 2 3 4 5 6
FALSE TRUE TRUE
this problem seems to only exist in R 2.12.0 but not in R 2.11.1.
any ideas? a bug?
--
dr. katharina manderscheid
soziologisches seminar
universität luzern
kasernenplatz 3
6000 luzern 7
tel. ++41 41 228 4657
web:
rows - which(apply(mapply(x, r, FUN===), MARGIN=1, FUN=all));
/H
On Thu, Nov 25, 2010 at 1:59 AM, Luedde, Mirko mirko.lue...@sap.com wrote:
Dear all,
this looks pretty much a standard problem, but I couldn't find a
satisfying and understandable solution.
(A) Given a data frame (or matrix),
Ziad,
Also you didn't mention which version of SAS and which modules.
In case you are working with 9.2 and have at disposal IML, you can have a
look at
http://support.sas.com/documentation/cdl/en/imlsstat/63545/HTML/default/viewer.htm#statr_toc.htm
Eric
2010/11/24 ziad.elmou...@tnsglobal.com
Hi all, thank you for quick help.
Any ideas on (better) efficiency
(with other data types)?
Best, Mirko
-Ursprüngliche Nachricht-
Von: henrik.bengts...@gmail.com [mailto:henrik.bengts...@gmail.com] Im Auftrag
von Henrik Bengtsson
Gesendet: Donnerstag, 25. November 2010 11:25
An:
Try this:
which((apply(x, 1, toString) %in% toString(r)))
On Thu, Nov 25, 2010 at 7:59 AM, Luedde, Mirko mirko.lue...@sap.com wrote:
Dear all,
this looks pretty much a standard problem, but I couldn't find a
satisfying and understandable solution.
(A) Given a data frame (or matrix), e.g.
On 25/11/2010 5:38 AM, pilchat wrote:
Dear all,
I am running a MCMC on my data, and I want to plot the results of the
simulation. I want to dedicate a page in the PS file for each element in
my sample, and in each page I need to plot 8 quadrants.
In attachment you find my first attemp (just
I have a file 4lmetc.Rnw, intended for inclusion in a LaTeX document,
that starts:
\SweaveOpts{engine=R, keep.source=TRUE}
\SweaveOpts{eps=FALSE, prefix.string=snArt/4lmetc}
The attempt to process the file through Sweave generates the error:
Sweave(4lmetc)
Writing to file 4lmetc.tex
Processing
I got a question about using a GLZ with categorical x categorical data.
Below there is a data set I want to know the influence of treatments (CONT,
and LPS2H LPS24H) on the categories of pigmentation of the right testis of
an amphibian. From these data, I used the function glm with binomial family
On 25/11/2010 6:34 AM, John Maindonald wrote:
I have a file 4lmetc.Rnw, intended for inclusion in a LaTeX document,
that starts:
I think this may have been fixed in the patched version. Could you give
it a try to confirm? If not, please send me a simplified version of the
file, and I'll
Hi,
I am running the RODBC examples form the help guide. I am trying to
UPDATE a table in an Access data base but I am having an error.
library(RODBC)
library(termstrc)
path = getwd()
setwd(getwd())
dbName = data.mdb
pathdbname = paste(path,/,dbName,sep=)
accesChannel =
I manage to achieve similar results with a Cox model as follows but I don't
really understand why we have to take the inverse of the linear prediction with
the Cox model and why we do not need to divide by the number of days in the
year
anymore?
Am I getting a similar result out of pure luck?
Thank you for all your answers.
I've looked at RODBC but it seems that you have to declare the database with
the administration tools before using it . With RMySQL, you can do it
directly in the R-script which is very convenient for me as I regularly
treat new databases.
For those who already
My small brain is having trouble getting to grips with lme()
I wonder if anyone can help me correctly set the random = argument
to lme() for this kind of setup with (I think) 9 variance/covariance
components ...
Study.1 Study.2 ...
Study.10
Dear all,
I am fitting a time series using the following command:
Ts.arima-arima(x,c(2,1,2)) where x is a time series.
What the function returns is perfectly fine but I was wondering if I could
access to the t-stat of the coefficients I got from the arima function.
Any help would be
On Thu, Nov 25, 2010 at 4:59 AM, Luedde, Mirko mirko.lue...@sap.com wrote:
Dear all,
this looks pretty much a standard problem, but I couldn't find a
satisfying and understandable solution.
(A) Given a data frame (or matrix), e.g.
x - data.frame(A=c(1, 2, 2), B=c(4, 5, 5))
and a
I've seen it, but not reliably enough to reproduce.
The issue is that there isn't really support for '\r' (CR) in Rgui,
and so it was sometimes getting junk characters.
However, I think that this is probably fixed in R-patched = r53662,
so please try an update in a day or two.
On Mon, 22
( I'm top posting for clarity, hotmail decided not to original
text and I'm not going to even try to outguess it LOL)
I have a non-definitive negative answer : I found two
packages but it isn't obvious either expose anything
related to lifting. I haven't worked with these lately
and so not
jt306 wrote:
Is it possible to create a contour plot with the isolines labeled. I know
you can do this with Matlab. Argh!
I tried creating a filled contour plot, then using par(new=T), followed by
overlaying the contour plot on top. However, the placement of the filled
contour plot
If you usre filled.contour, then use contour() as a part of the function
supplied as the axis parameter, you can correctly overlay contours on
the colour contour plot.
Steve e
-Original Message-
From: Fiona Berryman f.berry...@wlv.ac.uk
To: r-help@r-project.org
Sent: 11/25/2010
Hi R-floks:
Working in geoRglm, it shows me, according to AIC criterion, that the
non-spacial model describes the process in a better way. It's the first time
that I'm facing up to.
These are my results:
OP2003Seppos.AICnonsp-OP2003Seppos.AICsp
#[1] -4
On Nov 25, 2010, at 7:27 AM, Ben Rhelp wrote:
I manage to achieve similar results with a Cox model as follows but
I don't
really understand why we have to take the inverse of the linear
prediction with
the Cox model
Different parameterization. You can find expanded answer(s) in the
On 2010-11-24 22:24, Roslina Zakaria wrote:
Hi Jorge,
I tried but still it does not work. Thank you for your time.
Jorge's code works perfectly well.
If you prefer lines() over plot(, add = TRUE),
then use lines():
plot( ecdf(rnorm(15, sd=3)), verticals=TRUE, col=black)
On Nov 25, 2010, at 2:00 AM, jsntxt wrote:
http://r.789695.n4.nabble.com/file/n3058505/file.csv file.csv
Hi, Rusers
I have a problem in making a rcspline.plot with a Hmisc package.
My data is in the upload attachment.
My programme as follows:
library(Hmisc)
Hello R-help,
Please cc me on all responses, as I only receive summary emails from
this list.
I'm wondering if anybody has any tips on how to accomplish this
efficiently. I have a list of matrices, and I'm trying to get the mean
of the [i,j]'th element of each matrix in a list.
So if I
try this:
Reduce(+, x) / length(x)
Best,
Dimitris
On 11/25/2010 3:42 PM, statmobile wrote:
Hello R-help,
Please cc me on all responses, as I only receive summary emails from
this list.
I'm wondering if anybody has any tips on how to accomplish this
efficiently. I have a list of matrices,
On 11/25/2010 09:44 AM, Dimitris Rizopoulos wrote:
try this:
Reduce(+, x) / length(x)
Thanks Dimitris, that's very slick, I was unaware of this Reduce function.
The issue, is that I actually wanted to do a trimmed mean, and if things
prove possible even the median.
Is there a way to apply
Hi David,
Thank you for your reply. See below for more information.
From: David Winsemius
On Nov 25, 2010, at 7:27 AM, Ben Rhelp wrote:
I manage to achieve similar results with a Cox model as follows but I don't
really understand why we have to take the inverse of the linear
Hi:
You could try something like this:
For illustration, I'll use a data frame that was presented in a recent post
to the ggplot2 group. The poster wanted regressions by individual, but you
can add more than one grouping variable to the code I show below. It uses
the plyr package.
library(plyr)
On 2010-11-25 07:06, statmobile wrote:
On 11/25/2010 09:44 AM, Dimitris Rizopoulos wrote:
try this:
Reduce(+, x) / length(x)
Thanks Dimitris, that's very slick, I was unaware of this Reduce function.
The issue, is that I actually wanted to do a trimmed mean, and if things
prove possible
hey guys,
I am working on a function to make a duplicated value unique. For example,
the original vector would be like : a = c(2,1,1,3,3,3,4)
I'll like to transform it into:
a.nodup = 2, 1.01, 1.02, 3.01, 3.02, 3.03, 4
basically, find the duplicates and assign a unique value by adding a small
Dear R users,
I am trying to move the xlab string on my xyplot, without success, I would
like it to shifted down, would one of you know a way ?
Thanks for reading
Colin
--
View this message in context:
http://r.789695.n4.nabble.com/moving-xlabels-in-lattice-tp3059092p3059092.html
Sent from
I am trying to get some idea of the power of the Spearman's Rank correlation
I have carried out. Is there a way I can calculate power post-hoc? I know
that confidence intervals are preferred by many people, but how do I
generate those for a Spearman's?
Thanks
Lewis Dean
[[alternative
Hi folks,
I need to search the dataset on data with name on heading;
Run conc density
I look at ??help.search and could not resolve;
help.search(pattern, fields = c(alias, concept, title)
What shall I replace pattern?
I suppose replacing alias, concept, title with Run, conc, density ?
On Nov 25, 2010, at 10:00 AM, statquant2 wrote:
Dear R users,
I am trying to move the xlab string on my xyplot, without success,
I would
like it to shifted down, would one of you know a way ?
A quick and dirty way would be to stick a \n in front of your x-label.
--
David Winsemius, MD
Dear all,
I am fitting a time series using the following command:
Ts.arima-arima(x,c(2,1,2)) where x is a time series.
What the function returns is perfectly fine but I was wondering if I could
access to the t-stat of the coefficients I got from the arima function.
Any help would be
Hi Colin,
I wish I could do the same with a persp plot, since the labels overlap
the ticks and the annotations. Unfortunately, I don't know the answer to
your question, but I'll stay tuned on this thread.
Good luck
Gaetano
On 11/25/2010 04:00 PM, statquant2 wrote:
Dear R users,
I am
one way is the following:
a - c(2,1,1,3,3,3,4)
d - unlist(sapply(rle(a)$length, function (x)
if (x 1) seq(0.01, by = 0.01, len = x) else 0))
a + d
I hope it helps.
Best,
Dimitris
On 11/25/2010 3:49 PM, randomcz wrote:
hey guys,
I am working on a function to make a duplicated value
Hello all,
I would like some R function that can translate a string to a URL encoding
(see here: http://www.w3schools.com/tags/ref_urlencode.asp)
Is it implemented? (I wasn't able to find any reference to it)
Thanks,
Tal
Contact
Hi:
On Thu, Nov 25, 2010 at 3:53 AM, Diogo B. Provete dbprov...@gmail.comwrote:
I got a question about using a GLZ with categorical x categorical data.
Below there is a data set I want to know the influence of treatments (CONT,
and LPS2H LPS24H) on the categories of pigmentation of the right
?URLencode
On Thu, Nov 25, 2010 at 3:53 PM, Tal Galili tal.gal...@gmail.com wrote:
Hello all,
I would like some R function that can translate a string to a URL encoding
(see here: http://www.w3schools.com/tags/ref_urlencode.asp)
Is it implemented? (I wasn't able to find any reference to it)
Le 25/11/10 16:53, Tal Galili a écrit :
Hello all,
I would like some R function that can translate a string to a URL encoding
(see here: http://www.w3schools.com/tags/ref_urlencode.asp)
Is it implemented? (I wasn't able to find any reference to it)
Thanks,
Tal
Perhaps ?URLencode
--
Romain
On Nov 25, 2010, at 10:50 AM, Samuel Le wrote:
Dear all,
I am fitting a time series using the following command:
Ts.arima-arima(x,c(2,1,2)) where x is a time series.
What the function returns is perfectly fine but I was wondering if I
could access to the t-stat of the coefficients I
Thank you for your kind comments.
I tried different algorithms such as BFGS, CG, and so on. However, the
choice of algorithms was not effective on reducing computation time.
Instead, your second suggestion of coding the gradient of minimization
function was a little bit successful to reduce
Try this:
d - data()
ne - new.env()
data(list = grep(\\(, d$results[,'Item'], value = TRUE, invert = TRUE),
envir = ne)
out - eapply(ne, names)
names(which(lapply(lapply(out, '%in%', c(Run, conc, density)), sum) ==
3))
On Thu, Nov 25, 2010 at 1:38 PM, Stephen Liu sati...@yahoo.com wrote:
Hi
On 2010-11-25 07:00, statquant2 wrote:
Dear R users,
I am trying to move the xlab string on my xyplot, without success, I would
like it to shifted down, would one of you know a way ?
Thanks for reading
Colin
Have a look at the possible height adjustments with
Hi, I'm estimating a loglogistic aft (accelerated failure time) model, just a
simple plain vanilla one (without time dependent covariates), I'm comparing
the results that I obtain between aftreg (eha package) and survreg(surv
package). If I don't use any covariate the results are identical , if I
If the input vector t is known to be ordered
(or if you only care about runs of duplicated
values, not all duplicated values) the following
is pretty quick
nodup3 - function (t) {
t + (sequence(rle(t)$lengths) - 1)/100
}
If you don't know if the the input will be ordered
then ave() will do
On Nov 25, 2010, at 10:08 AM, Ben Rhelp wrote:
Hi David,
Thank you for your reply. See below for more information.
From: David Winsemius
On Nov 25, 2010, at 7:27 AM, Ben Rhelp wrote:
I manage to achieve similar results with a Cox model as follows
but I don't
really understand why
On 11/25/10 7:53 AM, Tal Galili wrote:
Hello all,
I would like some R function that can translate a string to a URL encoding
(see here: http://www.w3schools.com/tags/ref_urlencode.asp)
Is it implemented? (I wasn't able to find any reference to it)
I expect there are several
Hi Robert:
It appears to me that you have a split-plot structure, so let me see if I
have it right.
The 'whole-plot' experiment looks like a replicated randomized block design
- the studies are the blocks, the treatments A and B are the whole-plot
treatments, each of which is assigned randomly
Hi:
Package sos is a wonderful tool for this sort of question...
library(sos)
findFn('lifting wavelet transform')
It returned nine possible matches in two packages, adlift and nlt.
HTH,
Dennis
On Wed, Nov 24, 2010 at 8:46 PM, assaedi76 assaedi76 assaed...@yahoo.comwrote:
Hi R users
Thanks
Thank you so much :)
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__
R-help@r-project.org mailing list
I hit the send button on my second reply before I intended to. Since
then I have noticed that the question I thought you were asking is not
at all a good match to the Subject line of your message. There is a
type =lp in predict.coxph and that is the linear predictor, although
it is not a
Dear R users,
There is a error message when I run the following code. It is used to load
microarray data and use the top 1000 genes for training svm to classify test
set .
library(e1071)
Loading required package: class
f=read.table(F:\\lab\\
microarray analysis\\VEH LPS\\exprs.txt,
Date: Thu, 25 Nov 2010 06:49:19 -0800
From: rando...@gmail.com
To: r-help@r-project.org
Subject: [R] help: program efficiency
hey guys,
I am working on a function to make a duplicated value unique. For example,
the original vector would be
UCLA Statistics is hosting three meetup groups that are either straight R (361
members)
or R-related (GRASS, which interacts directly with R, and GPGPU, which will look
at interfacing R with OpenMP, GCD, OpenCL, CUDA, ...)
http://www.meetup.com/LAarea-R-usergroup
I have a vector of values -1, 0, 1, say
a - c(0, 1, 0, 1, 1, -1, -1, -1, 0, -1, -1)
I want to create a vector of the cumulative sum of this, but I need to set a
maximum and minimum value for the cumsum, for example:
max_value - 2
min_value - -2
the expected result would be (0, 1,
Hi all,
Since roxygen is a great help to document R packages, I am wondering
if there exists an approach to go back from the raw Rd files to
roxygen-documentation? E.g. turn \author{Somebody} into @author
Somebody. This sounds ridiculous, but I believe it helps in the long
term for me to maintain
Dear all,
I am pretty new to R only having an introduction course, so please bare with
me. I am doing my PhD at The Max Planck Institute of Immunobiology where I
am analyzing some calorimetry data from some mice.
I have a spreadsheet consisting of measurements of the respiratory exchange
rate
Try this:
ac - cumsum(a)
ifelse(ac 2, max_value, ifelse(ac -2, min_value, ac))
On Thu, Nov 25, 2010 at 6:44 PM, henrique henri...@allianceasset.com.brwrote:
I have a vector of values -1, 0, 1, say
a - c(0, 1, 0, 1, 1, -1, -1, -1, 0, -1, -1)
I want to create a vector of the
On 2010-11-25 02:25, Manderscheid Katharina wrote:
this problem seems to only exist in R 2.12.0 but not in R 2.11.1.
any ideas? a bug?
Duncan *did* say that he was using R 2.12.0. So that's not likely
to be the problem. Most of the time, when users claim that a
problem exists in a new
Since today is American Thanksgiving, I want to thank:
(a) R-core for all of their efforts to produce what is, IMHO,
the best statistical software around, not simply for the
convenience of doing more, better, quicker, but also
because it changes the landscape in the way one
Thank you Duncan, Romain and Gustavo for referring me to both:
URLencode
and
curlEscape
I see that both functions work great for English, but fail to provide with
the proper translation for Hebrew characters.
For example, the word
ש×××
(Peace, in Hebrew)
Should be this:
ditto. Spencer Graves
On 11/25/2010 1:20 PM, Dennis Murphy wrote:
Since today is American Thanksgiving, I want to thank:
(a) R-core for all of their efforts to produce what is, IMHO,
the best statistical software around, not simply for the
convenience of doing more, better,
I'll second that.
Paul Hurley.
On 25/11/10 21:25, Spencer Graves wrote:
ditto. Spencer Graves
On 11/25/2010 1:20 PM, Dennis Murphy wrote:
Since today is American Thanksgiving, I want to thank:
(a) R-core for all of their efforts to produce what is, IMHO,
the best statistical
Hello,
I am trying to import a phylogenetic tree from Mesquite into R. When I use
the read.nexus command I get the following message:
Warning message:
In matrix(x, ncol = 2, byrow = TRUE) :
data length [589] is not a sub-multiple or multiple of the number of rows
[295]
A phylo object is
The following fit does not make sense to me, please, correct me if I have a
logical error.
moddowsn
Call:
coxph(formula = Surv(start, stop, resp) ~ sn + matfac2, data = coxsn1,
method = efron)
coef exp(coef) se(coef) z p
sn2 0.0497 1.051 0.02030 2.450
res - function(x) resid(x)
ds_test$u - do.call(c, llply(mods, res))
I'd be a little careful with this, because there's no guarantee the
results will by ordered in the same way as the input (and I'd also
prefer ds_test$u - unlist(llply(mods, res)) or ds_test$u -
laply(mods, res))
In your case,
Hi,
I am not sure if it is more robust than a discriminant function but it is
certainly capable if differentiating between species based on morphology. I
used 12 measurements in my fish.
What did your PCA results show?
Unfortunately I haven't got round to publishing my data yet but I can
Hi Peter and Jorge,
Finally, it works. Thank you for your guidance.
## CDF plots
par(mar=c(4,4,2,1.2),oma=c(0,0,0,0),xaxs=i, yaxs=i)
plot(ecdf(dt1),verticals=TRUE, horizontals=TRUE,pch=46,do.p=FALSE, col.hor=1,
col.vert=1,lwd=2,)
lines(ecdf(dt2),verticals=TRUE,
On Nov 25, 2010, at 5:16 PM, Bond, Stephen wrote:
The following fit does not make sense to me, please, correct me if I
have a logical error.
moddowsn
Call:
coxph(formula = Surv(start, stop, resp) ~ sn + matfac2, data = coxsn1,
method = efron)
coef exp(coef) se(coef)
On 25/11/2010 3:45 PM, Yihui Xie wrote:
Hi all,
Since roxygen is a great help to document R packages, I am wondering
if there exists an approach to go back from the raw Rd files to
roxygen-documentation? E.g. turn \author{Somebody} into @author
Somebody. This sounds ridiculous, but I believe it
It would be something like this (might have to change the syntax a bit)
bin_ave=0;
while (i lenth(time)){
bin_ave[k]=mean(time(i:i+6));
k=k+1;
i=i+6;
}
if your data is in a table format replace time with mytable$time.
hope this helps,
Sachin
p.s. sorry about corporate
On Thu, Nov 25, 2010 at 3:44 PM, henrique henri...@allianceasset.com.br wrote:
I have a vector of values -1, 0, 1, say
a - c(0, 1, 0, 1, 1, -1, -1, -1, 0, -1, -1)
I want to create a vector of the cumulative sum of this, but I need to set a
maximum and minimum value for the cumsum, for
Hello Group,
I am trying out RQuantLib on a 64bit Win 7 machine. But running into
installation errors
install.packages(RQuantLib)
Warning in install.packages(RQuantLib) :
argument 'lib' is missing: using
'C:\Users\Tester\Documents/R/win64-library/2.11'
Warning: unable to access index for
Does this do it;
pmin(2, pmax(-2, cumsum(a)))
[1] 0 1 1 2 2 2 1 0 0 -1 -2
On Thu, Nov 25, 2010 at 3:44 PM, henrique henri...@allianceasset.com.br wrote:
I have a vector of values -1, 0, 1, say
a - c(0, 1, 0, 1, 1, -1, -1, -1, 0, -1, -1)
I want to create a vector of the
Since roxygen is a great help to document R packages, I am wondering
if there exists an approach to go back from the raw Rd files to
roxygen-documentation? E.g. turn \author{Somebody} into @author
Somebody. This sounds ridiculous, but I believe it helps in the long
term for me to maintain R
try this:
# create times 9 minutes apart
time - seq(as.POSIXct('2010-11-25 00:00'), by = '9 min', length = 480)
mySamp - data.frame(time = time, value = sample(1:100, length(time), TRUE))
# add column to split by hour
mySamp$hour - format(mySamp$time, '%Y-%m-%d %H:30')
# compute the mean
Hi Kevin
Here is one way:
yourData - c(0.730, 0.732, 0.743, 0.757,0.781, 0.731,
0.830, 0.832, 0.843, 0.857, 0.881, 0.831)
nrGroups - 2
lengthGroups - 6
tapply(yourData, factor(rep(c(1,nrGroups), each = lengthGroups)), mean)
and you will have to adjust the number of groups and if necessary
Hi Henrique,
Lot of thanks for your advice which is a little complicate to me. It involves
multiple R commands:
d - data()
ne - new.env()
data(list = grep(\\(, d$results[,'Item'], value = TRUE, invert = TRUE),
envir
= ne)
out - eapply(ne, names)
names(which(lapply(lapply(out, '%in%',
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Hi R-users,
I have a list
mylist - list(c(0.79, 0.92, 0.91, 0.86, 0.96, 0.96, 0.95, 0.94, 0.99),
c(0.28, 0.45, 0.59, 0.69, 0.80, 0.87, 0.95, 0.94, 0.98), c(0.29, 0.39,
0.59, 0.69, 0.68, 0.80, 0.93, 0.95, 0.98))
Is there a way to find the index of the list element that contains the
Hello Lorezo,
Try this...
order(sapply(mylist, min))[1]
Michael
On 26 November 2010 11:23, Lorenzo Cattarino l.cattar...@uq.edu.au wrote:
Hi R-users,
I have a list
mylist - list(c(0.79, 0.92, 0.91, 0.86, 0.96, 0.96, 0.95, 0.94, 0.99),
c(0.28, 0.45, 0.59, 0.69, 0.80, 0.87, 0.95,
On 26 November 2010 at 07:05, Santosh Srinivas wrote:
| Hello Group,
|
| I am trying out RQuantLib on a 64bit Win 7 machine. But running into
| installation errors
The error message is about as clear as it can get:
| install.packages(RQuantLib)
|
| Warning in install.packages(RQuantLib) :
|
Hi Ted,
Regarding your examples, is it possible to get a smooth line for the density
which overlap with the histogram?
Regards,
Roslina
From: ted.hard...@wlandres.net ted.hard...@wlandres.net
To: r-help@r-project.org
Sent: Fri, November 12, 2010 6:42:31 AM
Awesome! Thanks a lot!
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Thu, Nov 25, 2010 at 8:09 PM, Hadley Wickham had...@rice.edu wrote:
Since roxygen is a great help to
Hi folks,
Win7 64bit
I tried to save DNase, a data set on database, as .txt file for future use with
load.
I can't do it on fly;
save(DNase, file=C:/Users/satimis/Documents/aaa.txt)
load(file=C:/Users/satimis/Documents/aaa.txt)
aaa
Error: object 'aaa' not found
aaa.txt
Error: object
On Nov 25, 2010, at 10:45 PM, Stephen Liu wrote:
Hi folks,
Win7 64bit
I tried to save DNase, a data set on database, as .txt file for
future use with
load.
I can't do it on fly;
save(DNase, file=C:/Users/satimis/Documents/aaa.txt)
load(file=C:/Users/satimis/Documents/aaa.txt)
aaa
Hi David,
But you didn't try:
DNase# which was after all the name of the object you saved.
Sorry I don't follow.
I can't do it with following steps:
DNase
save(DNase, file=C:/Users/satimis/Documents/dnase.txt)
load(file=C:/Users/satimis/Documents/dnase.txt)
dnase
Error: object
Yes, that has fixed the problem. (2010-11-24 r53659)
Thanks.
John Maindonald email: john.maindon...@anu.edu.au
phone : +61 2 (6125)3473fax : +61 2(6125)5549
Centre for Mathematics Its Applications, Room 1194,
John Dedman Mathematical Sciences Building (Building 27)
Australian
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