Hi everyone,
I am using eigen() to extract the 2 major eigenpairs from a large real
square symmetric matrix. The procedure is already rather efficient, but
becomes somehow slow for real time needs with moderately large matrices
(few thousand lines).
The R implementation statically extracts all
Hello,
I don´t manage to address the results I get from modFit(). Would be really
nice if you could help me to do so.
This is my loop:
for (i in 1:10) {
CO2 - CO2.list[[i]]
#Beobachtungen
Obs - data.frame(x=t=numeric(),y=Respi=numeric())
Obs - cbind(CO2[,1],CO2[,3])
colnames(Obs) - c(x,y)
Dear R help.
Hello.
I want to fit the model of FIGARCH on TimeSeries data.
So I need to use the code of garchOxFit.
I don't know how to estimate FIGARCH model.
Please let me know which package I need and
what is procedure of estimating FIGARCH by R.
I think I need this code!
gt;
Hi all,
I want to plot a facet plot with column names as x and column values as y.
One plot for each row. here is part of my dataset:
Gene T0h T0.25h T0.5h T1h T2h T3h T6h T12h T24h T48h NM_001001130 68 95
56 43 66 62 68 90 63 89 NM_001001144 0 1 4 0 1 1 1 4 1 2 NM_001001152 79
129 52 50
On 30/01/2013 21:23, Yuan, Rebecca wrote:
Hello all,
When I tried to install fSeries in R, I got the following error messages:
install.packages(fSeries,dependencies=T)
Warning message:
package 'fSeries' is not available (for R version 2.15.2)
Is this package changing/merging to another
On 31/01/2013 06:50, Jeff Newmiller wrote:
Put the directory name into the filename string. The syntax for doing that is somewhat OS dependent, but for most cases
you can use / as the separator. You really should Google file path and your OS and learn how to
do this, because it is broadly
Hi
or use prop.table
barplot(prop.table(table(stop)))
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rui Barradas
Sent: Wednesday, January 30, 2013 4:01 PM
To: Naser Jamil
Cc: R help
Subject: Re: [R]
Â
See
Â
Dean
Fantazzini (2011) Fractionally Integrated Models for Volatility: A Review -
Empirical Appendix: Some Examples with R Interfaced with the Ox Package G@RCH,
Moscow
School of Economics; National Research University Higher School of Economics
Hello,
R is good at handling XML, but in this case I would rather do the first
step with an XSLT transformation, e.g. with Saxon, possibly to a CSV
file.
HTH,
Gabriele
-Original Message-
From: Anika Masters [mailto:anika.mast...@gmail.com]
Sent: Tuesday, January 29, 2013 3:01 AM
To:
Hi Robin,
You didn't provide the list with a clear structure of your data, but I hope I
understood it properly. If not, it'd be easy for you to adapt what follows.
I guess your data looks like this:
Gene T0h T0.25h T0.5h T1h T2h T3h T6h T12h T24h T48h
1 NM_001001130 68
Dear useRs,
With the following set of command i managed to create the copula density
library(MASS) library(evd) X-matrix(sample(1:3000), ncol=2)
U=cbind(rank(X[,1])/(nrow(X)+1),rank(X[,2])/(nrow(X)+1))
mat1=kde2d(U[,1],U[,2],n=150)
Hi Anika,
Have you looked at or tried the XML package? I've not used it for XBRL
in particular, but have used it very successfully to parse other kinds
of xml data.
Best,
Ista
On Wed, Jan 30, 2013 at 7:19 PM, Anika Masters anika.mast...@gmail.com wrote:
Has anyone explored pulling XBRL
Have you looked in the package 'copula'?
Regards,
José
José Iparraguirre
Chief Economist
Age UK
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of eliza botto
Sent: 31 January 2013 11:13
To: r-help@r-project.org
Subject: [R] lower
I'm not sure, but would recommend not to.
--
Marcio
www.dsr.inpe.br/~mello
On 31/01/2013 04:26, Ortiz, John wrote:
Dear list,
Can I use a character to set the name of a R package? like this (-)
for example (sdp-R)
Thanks,
John
__
On 13-01-31 1:26 AM, Ortiz, John wrote:
Dear list,
Can I use a character to set the name of a R package? like this (-)
for example (sdp-R)
I can't quite parse your question, but I think the answer is in the
Writing R Extensions manual, section 1.1 Package Structure.
Duncan Murdoch
Dear Beatriz,
There are several problems that combine to make the computation unstable: the
small size of the numbers, the small ratio of the largest to the smallest
value, the extreme negative skew of the data, and the outliers at the low end.
Because of the small ratio of max(x) to min(x),
hi: the irlba package does what you're looking for.
On Thu, Jan 31, 2013 at 3:32 AM, Pierrick Bruneau pbrun...@gmail.comwrote:
Hi everyone,
I am using eigen() to extract the 2 major eigenpairs from a large real
square symmetric matrix. The procedure is already rather efficient, but
becomes
Dear R community,
I do know, that an R function is constructing a copy of any object passed as
argument into a function. I program on a larger S4 project for a package, and I
arrived at a point where I have to think a little harder on implementation
style (especially to spare users complex
I am curious why one would want risk ratios. Unlike odds ratios, they are
not interpretable without reference to the base risk. For example a risk
ratio of 2 cannot possibly apply to anyone with a starting risk exceeding
1/2.
I think it is most helpful to use one of the existing nomograms to
OK, i' look at this. Thank you :-)
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
On Thu, Jan 31, 2013 at 11:52 AM, Simon Zehnder szehn...@uni-bonn.de wrote:
Dear R community,
I do know, that an R function is constructing a copy of any object passed as
argument into a function. I program on a larger S4 project for a package, and
I arrived at a point where I have to think
it lets you do:
(a~b~c) = foo()
Mistook. should be:
(a~b~c) %=% foo()
because it defines the %=% operator.
Barry
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Thu, Jan 31, 2013 at 3:00 PM, Simon Zehnder szehn...@uni-bonn.de wrote:
Hi Barry,
this actually a good idea, to put them together! Probably even creating an
object containing both of them. Haven't thought about it before.
Hadley W asked for implementations of 'unstructuring assignments'
On Thu, Jan 31, 2013 at 6:52 AM, Simon Zehnder szehn...@uni-bonn.de wrote:
Dear R community,
I do know, that an R function is constructing a copy of any object passed as
argument into a function. I program on a larger S4 project for a package, and
I arrived at a point where I have to think
Hello: I need to create a six barplots from data that looks pretty close to
what appears below. There are two grouping variables (age and gender) and three
dependent variables for each grouping variables. I'm not really familiar with
trellis graphics, perhaps there is something that can do
Dear Patrick,
This is indeed a nice post to address the three dot issues.
It is definitely much clearer to me now
Thanks!
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
On Thu, Jan 31, 2013 at 10:29 AM, Weijia Wang wwang@gmail.com wrote:
Hi,
I have a new question about subsetting in R.
Say we have this data frame:
PT_ID Blood_Pressure OBS_TYPE
92 1900 90.0 DBP
94 1900 90.0 DBP
174 2900 140.0 SBP
176
Thanks Bert for your example.
I wouldn't say that I understand why everything happens the way it does,
but at least I now know what happens!
I think I now need to use it and try around!
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000
Dear useRs,
What is the syntax to obtain survival curves for single strata on many subjects?
I have a model based on Surv(time,response) object, so there is a single row
per subject and no start,stop and no switching of strata.
The newdata has many subjects and each subject has a strata and
*RMS Short Course 2013*
Frank E. Harrell, Jr., Ph.D., Professor and Chair
Department of Biostatistics, Vanderbilt University School of Medicine
*March 4, 5 6, 2013*
8:00am - 4:30pm
Student Life Center Board of Trust Room
Vanderbilt University
Nashville Tennessee USA
See
I am currently using the relaimpo package to estimate the relative
importance of regressors (N= 4000):
m1 - lm(y ~ x1+x2+x3+x4+x5+, data=data)
calc.relimp(m1, rela=TRUE)
m2=boot.relimp(m1, boot = 500, rela=TRUE, type=lmg)
booteval.relimp(m2)
plot(booteval.relimp(m2))
In a new dataset with 3
Simon,
I think this is what you are looking for.
###Random Data
crime - sample(c('agree' ,'disagree'), replace=TRUE, size=100)
guns - sample(c('agree','disagree'), replace=TRUE, size=100)
climate - sample(c('agree', 'disagree'), replace=TRUE, size=100)
gender - sample(c('male','both' ,'female'),
Hello everyone.
I am trying to use rgenoud in a parallel environment.
While making some tests, I noticed that rgenoud seems not to be using the
cluster created by makeCluster, doing all the computation in the main node.
Following is the example:
ncores - 5
cl - makeCluster(rep('localhost',
Hello,
Maybe the following will help.
layout(matrix(c(1,2,3,0,4,5,6), c(1,6)))
Note the zero. It reserves space but no graph is put there.
There is an error in your code, you plot twice guns/gender. I think the
second is meant to be guns/age.
Also, you can do those 6 barplot instructions
Dear Barry,
thank you very much for this information. This looks pretty interesting!
Best
Simon
On Jan 31, 2013, at 4:09 PM, Barry Rowlingson b.rowling...@lancaster.ac.uk
wrote:
it lets you do:
(a~b~c) = foo()
Mistook. should be:
(a~b~c) %=% foo()
because it defines the %=%
Dear Listers,
can anyone help me, please.
Since several days i try to figure out, how to assign values, vectors,
functions etc to variables with dynamically generated names inside of
functions.
Sometimes I succeed, but the success is rather arbitrary, it seems. up to
now i don't fully
Hi Barry,
this actually a good idea, to put them together! Probably even creating an
object containing both of them. Haven't thought about it before.
Best
Simon
On Jan 31, 2013, at 3:49 PM, Barry Rowlingson b.rowling...@lancaster.ac.uk
wrote:
On Thu, Jan 31, 2013 at 11:52 AM, Simon Zehnder
Thanks a lot ! I'm going to try this very soon.
As the package seems general purpose (ie not dedicated to real symmetric
matrices), I hope it remains more efficient than the eigen function
parametrized for symmetric matrices.
Pierrick Bruneau
CRP Gabriel Lippmann
On Thu, Jan 31, 2013 at 2:51
Well, since no one has responded
Please use ?dput to provide data in your posts.
There are likely zillions of way to go about this. Following is one
way based on ?duplicated that I think works, but I make no claims for
either elegance or efficiency. Others may do lots better. But maybe it
dd - # from dput()
structure(list(ColA = c(92L, 94L, 174L, 176L, 180L, 268L, 268L
), PT_ID = c(1900L, 1900L, 2900L, 2900L, 3900L, 3900L, 3900L),
Blood_Pressure = c(90, 90, 140, 130, 120, 150, 90), OBS_TYPE =
structure(c(1L,
1L, 2L, 2L, 2L, 2L, 1L), .Label = c(DBP, SBP), class =
I am a beginner in R.
I wrote a function to read a data frame from a file and then split it
into certain number of data frames and write each one of them in a
separate txt file.
the function is working perfectly for the first four files the it
gives me files contain one column of NA values.
On Thu, Jan 31, 2013 at 10:51 AM, Weijia Wang wwang@gmail.com wrote:
On Thu, Jan 31, 2013 at 10:29 AM, Weijia Wang wwang@gmail.com wrote:
Hi,
I have a new question about subsetting in R.
Say we have this data frame:
PT_ID Blood_Pressure OBS_TYPE
92 1900 90.0
Hi,
May be this helps:
#dd
res-data.frame(Include=with(subset(dd,OBS_TYPE == SBP Blood_Pressure =
140|OBS_TYPE==DBP
Blood_Pressure=90),apply(tapply(Blood_Pressure,list(PT_ID,OBS_TYPE),length)=2,1,any,na.rm=T)))
res
# Include
#1900 TRUE
#2900 FALSE
#3900 FALSE
A.K.
-
Your example is not reproducible. See
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
I would guess you have tabs at the ends of your lines in the input file. This
is a fairly common problem when you muck with data in Excel.
To find these problems
Hello there,
Can anyone point me to the code for logLik of an nls object? I found the
code for logLik of an lm but could not find exactly what function is used
for calculating the logLik of nls function?
I am using the nls to fit the following model to data -
Model 1: y ~ Ae^(-mx) + Be^(-nx) +c
methods(logLik) ## for S3 methods
stats:::logLik.nls
### and look at the code!
-- Bert
On Thu, Jan 31, 2013 at 12:06 PM, Diviya Smith diviya.sm...@gmail.com wrote:
Hello there,
Can anyone point me to the code for logLik of an nls object? I found the
code for logLik of an lm but could not
Is there a way to start multiple instances of R in an automated manner?
Since I'm not sure that question makes tons of sense, here's my scenario:
I have a number of data updates that need to be completed on an ongoing
basis with the data pulled from and then stored to another location. The
?parallel::parallel
Only one gui, multiple cores working at once.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
You could always just run something like
system(path/to/R/RScript myfile.R)
from within R.
But this also sounds like something that the parallel package may be
helpful with to use your 8 cores to speed up your update process.
On Thu, Jan 31, 2013 at 2:12 PM, Brigid Mooney bkmoo...@gmail.com
On 31.01.2013 14:12, Duncan Murdoch wrote:
On 13-01-31 1:26 AM, Ortiz, John wrote:
Dear list,
Can I use a character to set the name of a R package? like this (-)
for example (sdp-R)
I can't quite parse your question, but I think the answer is in the
Writing R Extensions manual, section
I've got a data.frame I'm trying to insert into a database table in an
ms sql server instance using RODBC. When I save a table using
nothing but character and numeric columns things work fine. However,
when I attempt to add another column of type POSIXct to the data.frame
and redefine the table
On 01/25/2013 10:07 AM, Rosario Garcia Gil wrote:
Hello
I am using library(spatstat). I managed to test of the random distribution of a
collection of sampled trees in the forest. But what I want now is to test if
their diameter is randomly distributed across the forest, for example the
I don't see what's missing in my statements to add rows to a data frame
and someone else will probably see what needs to be added to the statements.
The data frame has this structure (without any data):
$ PHYLUM : chr
$ SUBPHYLUM : chr
$ SUPERCLASS : chr
$ CLASS : chr
$
On Thu, 31 Jan 2013, Rich Shepard wrote:
I don't see what's missing in my statements to add rows to a data frame
and someone else will probably see what needs to be added to the statements.
Found the problem: a FUBAR'd R session.
Rich
__
Use rms instead.
MW
On Jan 31, 2013, at 10:09 PM, Gabriela Agostini gabrielaagostin...@gmail.com
wrote:
Hi!
I need to work whir Desing Package.
I used
library(Design)
but the following error is displayed on the console
library(Design, lib.loc=C:/Program
On Thu, Jan 31, 2013 at 3:55 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
I don't see what's missing in my statements to add rows to a data frame
and someone else will probably see what needs to be added to the statements.
The data frame has this structure (without any data):
$
Hi list,
I keep on getting this rand word come up on my console. It shows up
maybe one out 20 times I type in R console. I don't understand why it is
coming up?
mean(variables)
[1] -0.41
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand
rand mean(variables)
Hi:
Apologies for asking the following question. As this may sound very basic and
stupid for this forum , I honestly do not know how to solve it and I do not
have a teacher who can help me understand.
I have list of genes (200) that are involved in a particular process and I call
this as a
Better would have been to have been following the Mac SIG mailing
list. Had you been reading that list you would have known that this
was investigated and fixed in the most recent release of the Mac GUI.
--
David.
On Jan 31, 2013, at 9:49 PM, C W wrote:
Hi list,
I keep on getting this
-
Hi every body,
i am using D_f_norm function from library stat in R
i am using it to find the standard deviation of the output of a function
'calculate_Z0' that has one of it is inputs as a random variable 'W' , with a
standard deviation 'Sigm3LER', when i change the mean of this random
Hello,
I have a question about modelling via glm. I have a dataset (see dput)
that looks like as if it where poisson distributed (actually I would
appreciate that) but it isnt because mean unequals var.
mean (x)
[1] 901.7827
var (x)
[1] 132439.3
Anyway, I tried to model it via poisson and
Hi every body,
i am using D_f_norm function from library stat in R
i am using it to find the standard deviation of the output of a function
'calculate_Z0' that has one of it is inputs as a random variable 'W' , with a
standard deviation 'Sigm3LER', when i change the mean of this random variable
Hi
Another possibility following on from Rich's example and to
demonstrate what lattice can do with the latticeExtra package
library(lattice)
library(latticeExtra)
useOuterStrips(
barchart(Freq ~ Var1 | topic + category, groups=Var2, data=opinion,
stack=TRUE,
layout=c(3,2),
dear experts,
i hv tried to put a different weights for regression using MM-estimator by
using the command:
lmrob(y ~ x, weights = w2rdf)
where weights are uniquely derived. somehow, R gives me Error - Weights
are not yet implemented for this estimator.
In S-plus, similar command lmRobMM(y~x,
I have the following data frame:
foo
w x y z
n 1.51550092 1.4337572 1.2791624 1.1771230
q 0.09977303 0.8173761 1.6123402 0.1510737
r 1.17083866 1.2469347 0.8712135 0.8488029
What I want to do is to change it into :
newdf
1 nw 1.51550092
2 q w
I did not closely follow the Mac SIG, but I will look into it now. Thanks
for pointing it out.
Mike
On Thu, Jan 31, 2013 at 11:16 PM, David Winsemius dwinsem...@comcast.netwrote:
Better would have been to have been following the Mac SIG mailing list.
Had you been reading that list you would
Hi all,
In my plotCI function, the argument x is chosen to be seq(0.05, 0.95,
by=0.05).
However, when I make the plot, the plot has the x coordinate goes 1:19.
Does anyone know how to make the x coordinate to be (0,0.5, 0.1, ...,
0.95).
Thank you.
Hanna
[[alternative HTML
Hello All,
I have a data with two columns. In one column it is date and in another
column it is flow data.
I was able to read the data as date and flow data. I used the following
code:
creek - read.csv(creek.csv)
library(ggplot2)
creek[1:10,]
colnames(creek) - c(date,flow)
creek$date -
Dear list,
I'm just getting started learning how to use remote supercomputers for
execution of parallelized code. I got a lot of initial help from this
http://stackoverflow.com/questions/14553357/parallelizing-on-a-supercomputer-and-then-combining-the-parallel-results-r
previous post, as well
Hello,
One possibility is:
creek - read.csv(creek.csv)
colnames(creek) - c(date,flow)
creek$date - as.Date(creek$date, %m/%d/%Y)
creek - within(creek, year - format(date, '%Y'))
with(creek, aggregate(flow, by=list(year=year), summary))
HTH,
Pascal
Le 01/02/2013 16:32, Janesh Devkota a
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