Claus Dethlefsen [EMAIL PROTECTED] writes:
Thank you for the advice. I have now boiled my problem down to the
following:
How do I create fm2 from fm1 ?
fm1 - Y ~ 1 + tvar(x:A) + tvar(z) + u + tvar(B) + tvar(poly(v,3))
fm2 - Y ~ 1 + x:A + z + u + B + poly(v, 3)
Thus, how do I simply
1) I have constracted a function that returns an output, which runs in a while
( condition ){ run function }
loop. I would like to know if there is a way to get the outputs in different
windows, every time the function
runs, so as to compare easier the results.
Try windows().
But better
Please learn to wrap your emails at about 72 characters.
See below for other comments.
On Thu, 2004-12-16 at 08:29, vasilis pappas wrote:
Hello R users,
I have three questions and I would be grateful if someone could give me an
answer to each of these.
1) I have constracted a
Hi All,
I have read the article on lazy-loading in the September R news letter, and
think I have at least a vague grasp on what is happening.
Am I right in thinking that, assuming I were using the same packages, I
could copy the .rdb .rdx files from one installation of R (2.0.0) to
another?
I
Hi all,
I am currently trying to create a development environment
including PostgreSQL 8.0.0rc1, R 2.0.1 and PL/R on a system running Fedora
Cora 1.
So far, I have suceeded in setting up PostgreSQL and R as
a shared library - unfortunately I have not been able to link these
two spheres by adding
On 16 Dec 2004, Peter Dalgaard wrote:
Simon Pickering [EMAIL PROTECTED] writes:
Hi All,
I have read the article on lazy-loading in the September R news letter, and
think I have at least a vague grasp on what is happening.
Am I right in thinking that, assuming I were using the same
If R is run in interactive mode; i.e., interactive() == TRUE, whatever
function calls that produced R objects gets printed (by calling the
appropriate print() method; known as auto-printing), unless the object is
returned invisibly (i.e., wrapped in invisible()). As an example, if you
put
Brian D Ripley [EMAIL PROTECTED] writes:
On 16 Dec 2004, Peter Dalgaard wrote:
Simon Pickering [EMAIL PROTECTED] writes:
stuff more stuff
[...]
Take a look at cross-compiling (Windows under Linux). We have failed to
make lazy loading of base work under cross-compilation, but do
Dear Vasilis,
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of vasilis pappas
Sent: Thursday, December 16, 2004 3:30 AM
To: [EMAIL PROTECTED]
Subject: [R] 3 questions
. . .
2) In my function I make use of the Rcmdr package. But every
time I
Thank you Thomas for your answer. This is of course what I intend to do
(indeed, to use a tryCatch(), instead of I try(). However, I would like to
have a different behaviour depending if the synthax is incorrect ls()) for
instance, or incomplete ls( for instance. Indeed, exactly like the
Claus Dethlefsen dethlef at math.aau.dk writes:
:
: Thank you for the advice. I have now boiled my problem down to the
: following:
:
: How do I create fm2 from fm1 ?
:
: fm1 - Y ~ 1 + tvar(x:A) + tvar(z) + u + tvar(B) + tvar(poly(v,3))
: fm2 - Y ~ 1 + x:A + z + u + B + poly(v, 3)
:
: Thus,
Philippe Grosjean [EMAIL PROTECTED] writes:
Thank you Thomas for your answer. This is of course what I intend to do
(indeed, to use a tryCatch(), instead of I try(). However, I would like to
have a different behaviour depending if the synthax is incorrect ls()) for
instance, or incomplete ls(
I recently installed R version 2.01 for OS X (version 10.3.6). I now
get the following error message when I try to use the postscript
function:
Error in get(name.opt, envir = envir) : Object .PSenv not found
This did not happen in previous versions of R (i.e. 1.9). I do not get
this error
What kinds of terms do you have in mind for the non-linear parts? gam() in
both mgcv and gam will accommodate linear terms, so they ought to work, no?
Andy
From: Jin Shusong
Dear all,
Are there any packages can estimate the partial linear
model. Or any one can give me any suggestions.
I would like to have complete control over which plots and which
axes have labels in a lattice figure. I tried lots of vectors for the
alternating setting in scales, but none worked. Here is what I
would like to do for a 2 col x 3 row figure, where the x designates
a location I would like to
On Thursday 16 December 2004 09:58, Waichler, Scott R wrote:
I would like to have complete control over which plots and which
axes have labels in a lattice figure. I tried lots of vectors for
the alternating setting in scales, but none worked. Here is what I
would like to do for a 2 col x 3
If you mean R 2.0.1, your installation is broken. Here's a quick check of
where it should be:
ls(asNamespace(grDevices), all=TRUE)
[1] .PSenv .Quartzenv .X11env
[4] .__NAMESPACE__. .__S3MethodsTable__. .packageName
On Thu, 16 Dec 2004, Jeffrey Freedman
Being still unsatisfied with the CrossTable() function I modified the
code so that the function will create an output similar to the SPSS
procedure CROSSTABS. Most probably the code will not meet most R
programmers' standards, perhaps someone else is willing to optimize it.
Unfortunately, as
On Thu, 2004-12-16 at 17:45 +0100, Dirk Enzmann wrote:
Being still unsatisfied with the CrossTable() function I modified the
code so that the function will create an output similar to the SPSS
procedure CROSSTABS. Most probably the code will not meet most R
programmers' standards, perhaps
- Output delivery system (ODS): *Every* piece of SAS output is an
output object that can be captured as
a dataset, rendered in RTF, LaTeX, HTML, PDF, etc. with a relatively
simple mechanism (including graphs)
ods pdf file='mystuff.pdf'';
any sas stuff
ods pdf close;
R
Mike
nlsList from nlme library can fit nonlinear models for dataset grouped by
some specification, e.g. by specie in your case
Regards
Christian
-- Mensaje Original --
From: Mike Saunders [EMAIL PROTECTED]
To: R Help [EMAIL PROTECTED]
Date: Thu, 16 Dec 2004 10:40:00 -0500
Subject: [R] nls
Hello everyone,
I was wondering if someone could tell me what happens when you use
na.omit in the gls() function in library(nlme) when you assume a
correlation structure for the errors:
gls(Y ~ X1 + X2 + X3, data=sample.data, na.action=na.omit,
correlation=corARMA(p=1))
Is na.omit is an
When I generate levelplot figures with Postscript, the lines from
the underlying grid (i.e., the x and y in z ~ x* y)
show up as faint white lines in the output. If I have a dense grid,
the lines wash out the contour colors. I can avoid the problem if
I use png instead, but that brings up other
Attached is a file with the definition of a function (cnvrt.coords)
that
can just be sourced into R. This function will convert between the
different coordinate systems. The basic usage for your problem is:
1. draw first plot
2. convert the y-value for the top of your rectangle from the current
On Thursday 16 December 2004 12:57, Waichler, Scott R wrote:
When I generate levelplot figures with Postscript, the lines from
the underlying grid (i.e., the x and y in z ~ x* y)
show up as faint white lines in the output. If I have a dense grid,
the lines wash out the contour colors. I can
Hi
Waichler, Scott R wrote:
When I generate levelplot figures with Postscript, the lines from
the underlying grid (i.e., the x and y in z ~ x* y)
show up as faint white lines in the output. If I have a dense grid,
the lines wash out the contour colors. I can avoid the problem if
I use png
Hi,
If I try to read the codes of functions in e1071 package, it gives me following
error message.
library(e1071)
svm
function (x, ...)
UseMethod(svm)
environment: namespace:e1071
predict.svm
Error: Object predict.svm not found
Can someone help me on this how to read the codes of the
The predict method for class `svm' is hidden in a namespace. Try
getS3method(predict, svm)
-roger
Rajdeep Das wrote:
Hi,
If I try to read the codes of functions in e1071 package, it gives me following
error message.
library(e1071)
svm
function (x, ...)
UseMethod(svm)
environment:
One typical problem with gv is that some artifacts show up (which may
not be what you describe) when the display is anti-aliased. Try
turning that off (by pressing 'a') and see if that improves the
display.
If you produce PDF, it's possible to just turn off antialiasing for
line art,
On Thu, 16 Dec 2004, Claus Dethlefsen wrote:
Thank you for the advice. I have now boiled my problem down to the
following:
How do I create fm2 from fm1 ?
fm1 - Y ~ 1 + tvar(x:A) + tvar(z) + u + tvar(B) + tvar(poly(v,3))
fm2 - Y ~ 1 + x:A + z + u + B + poly(v, 3)
Thus, how do I simply remove
I am just wondering if there is an easy way to count
in a numeric vector how many numbers don't have
replicates.
For example,
a=c(1,1,2,2,3,4,5), how can I know there are three
numbers (3, 4 and 5) without replicates?
How about:
length(table(a)[table(a) == 1])
?
Ray Brownrigg
On Thu, 2004-12-16 at 13:40 -0800, Jun Ding wrote:
Hi,
I am just wondering if there is an easy way to count
in a numeric vector how many numbers don't have
replicates.
For example,
a=c(1,1,2,2,3,4,5), how can I know there are three
numbers (3, 4 and 5) without replicates?
Thank you!
Hi all -
I am running into a problem with the SVM() method when applying it to data sets
that have descriptors with zero variance. Here is the sequence of events:
1. I split my data set with 512 descriptors in a training and test set
2. I build an SVM model for the training set. Out of 512
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
From: Vito Muggeo [EMAIL PROTECTED]
Subject: R: [R] partial linear model
Date: Thu, 16 Dec 2004 17:25:35 +0100
Dear Jin,
if you mean `conditional linearity', (i.e. given the nonlinear parameter,
the model is linear) you can use nls() with algorithm = plinear. See ?nls
Alternatively, if your
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Peter Dalgaard
Sent: Thursday, December 16, 2004 5:43 PM
To: Ray Brownrigg
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [R] counting numbers without replicates in a vector
Ray
Apologies for adding to this discussion so late.
When the idea of a mascot was first raised, I
recalled how in describing (and spelling) R to
people in seminars, etc I would sometimes say,
in my best pirate voice, That's R, as in ARR!.
The connection to something or someone criminal
is
Marc Schwartz wrote:
On Fri, 2004-12-17 at 12:32 +1000, Andrew Ward wrote:
Apologies for adding to this discussion so late.
When the idea of a mascot was first raised, I
recalled how in describing (and spelling) R to
people in seminars, etc I would sometimes say,
in my best pirate voice, That's
Hello R users,
I have three questions and I would be grateful if someone could give me an
answer to each of these.
1) I have constracted a function that returns an output, which runs in a while(
condition ){ run function } loop. I would like to know if there is a way to get
the outputs
Thank you for the advice. I have now boiled my problem down to the
following:
How do I create fm2 from fm1 ?
fm1 - Y ~ 1 + tvar(x:A) + tvar(z) + u + tvar(B) + tvar(poly(v,3))
fm2 - Y ~ 1 + x:A + z + u + B + poly(v, 3)
Thus, how do I simply remove tvar( * ) from a formula? Do I have to write a
Dear useRs,
automatical building of contributed Windows binary packages for R-1.9.x
has been stopped.
The last known good versions of contributed packages are available in
the repository: These may be outdated versions, because new versions of
many packages already require R=2.0.0.
Upgrading to
Hello,
I need a similar behaviour as with the prompt: asking to complete incomplete
R command with eval(parse(text = ))
Is it a way to make the difference between an illegal and an incomplete R
command in a string?
For instance:
parse(text=ls())
expression(ls())
This is fine!
Hi Jens,
On 16-Dec-04 Jens Hainmueller wrote:
I am desperately trying to impute missing data using
'imp.mix' but always run into this yucky error message
to which I cannot find the solution.
It's the first time I am using mix and I'm trying really
hard to understand, but there's just this
Hi
I am running R 2.0 on Suse Linux 8.2. I get an error message when
loading a library:
Incorrect permissions to edit the package database,
/usr/lib/R/library/liblisting.Rda: save.locLib(locLibList, curLib)
However, when I look at that file, the user I am running R as has r and
w permissions
Hello All,
I'm getting the error message unknown (internal) error when evaluating
the following string
source('j:/tmp/test.r')
via the (D)COM server. The script test.r is run and everything works,
but Evaluate still returns this error. I can avoid the error by using
EvaluateNoReturn, but
Okay, well you could define a tvar function as follows
tvar - function(term) term
Then stick to fm1
X - model.matrix(fm1,keep.order=TRUE)
pAssign - attr(X, assign)
tvar.terms - terms( fm1, specials = tvar,keep.order=TRUE )
idx - attr(tvar.terms,specials)$tvar
if (attr(tvar.terms,response)) idx -
Philippe Grosjean wrote:
Hello,
I need a similar behaviour as with the prompt: asking to complete incomplete
R command with eval(parse(text = ))
Is it a way to make the difference between an illegal and an incomplete R
command in a string?
For instance:
parse(text=ls())
expression(ls())
This
Stefan Sobernig wrote:
I am currently trying to create a development environment
including PostgreSQL 8.0.0rc1, R 2.0.1 and PL/R on a system running Fedora
Cora 1.
So far, I have suceeded in setting up PostgreSQL and R as
a shared library - unfortunately I have not been able to link these
two
Just a quick question. Is there a way to easily specify factor levels in a
function definition within nls? For example, I am trying to fit a 3 parameter,
nonlinear Weibull function to tree height and I would like to have results by
species (or down the road a bit, by plot). I am hoping there
Hello everyone, this is my first post. Nice to meet all of you. I am
having some troubles using R in combination with PHP and MySQL. I
would appreciate any assistance very much! This is kind of long, so if
you'd like a shorter version let me know.
I am working on a project that takes a
On 16 Dec 2004, Peter Dalgaard wrote:
Philippe Grosjean [EMAIL PROTECTED] writes:
Thank you Thomas for your answer. This is of course what I intend to do
(indeed, to use a tryCatch(), instead of I try(). However, I would like to
have a different behaviour depending if the synthax is
Dear Jin,
if you mean `conditional linearity', (i.e. given the nonlinear parameter,
the model is linear) you can use nls() with algorithm = plinear. See ?nls
Alternatively, if your model has just one nonlinear parameter th, say, I
think you can write the objective function (for instance the
It's in the R FAQ. Try getAnywhere(predict.svm).
Andy
From: Rajdeep Das
Hi,
If I try to read the codes of functions in e1071 package, it
gives me following error message.
library(e1071)
svm
function (x, ...)
UseMethod(svm)
environment: namespace:e1071
predict.svm
Error:
Dear all,
Are there any packages can estimate the partial linear
model. Or any one can give me any suggestions.
Many thanks in advance.
Jin
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Hi,
I am just wondering if there is an easy way to count
in a numeric vector how many numbers don't have
replicates.
For example,
a=c(1,1,2,2,3,4,5), how can I know there are three
numbers (3, 4 and 5) without replicates?
Thank you!
Jun
=
__
Jun Ding wrote:
Hi,
I am just wondering if there is an easy way to count
in a numeric vector how many numbers don't have
replicates.
For example,
a=c(1,1,2,2,3,4,5), how can I know there are three
numbers (3, 4 and 5) without replicates?
How about using ?table:
tab - table(a)
unq -
On 12/16/04 13:40, Jun Ding wrote:
Hi,
I am just wondering if there is an easy way to count
in a numeric vector how many numbers don't have
replicates.
For example,
a=c(1,1,2,2,3,4,5), how can I know there are three
numbers (3, 4 and 5) without replicates?
Take a look at unique()
--
?duplicated and ?unique might be of interest to you ...
But I think an easier way is:
z-table(a)
length(z)-sum(z1)
This gives you the count.
names(z)[z==1] gives you the actual values
(The quotes can be removed by explicitly calling print with argument
quote=FALSE)
-- Bert Gunter
Genentech
table will probably do. The following is probably is what you want:
a - c(1,1,2,2,3,4,5)
a.tab - table (a)
a.tab
a
1 2 3 4 5
2 2 1 1 1
as.vector(which (a.tab == 1))
[1] 3 4 5
Cheers,
Yu
Jun Ding wrote:
Hi,
I am just wondering if there is an easy way to count
in a numeric vector how many
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