i am trying to figure out the pearson residuals in a lm model:
vl.lm - lm(VL ~ GSS)
resid (vl.lm, ¡§pearson¡¨)
but when i tried other types of residuals such as working, deviance,
etc...they give me the exact numbers...is there anything wrong with what i am
trying to do?
thanks!
Quotes from messages about Solaris 9 are not necessarily applicable to
AIX, and in omitting the context you have misrepresented me.
Please do bear in mind the `moral rights' on quoting given at
http://www.jiscmail.ac.uk/help/policy/copyright.htm
(Perhaps such a reference is needed in the posting
On Sat, 26 Feb 2005, Oli wrote:
i am trying to figure out the pearson residuals in a lm model:
vl.lm - lm(VL ~ GSS)
resid (vl.lm, ¡§pearson¡¨)
but when i tried other types of residuals such as working, deviance,
etc...they give me the exact numbers...is there anything wrong with what
i am trying
Hi Folks,
While I was browsing in the R-help archives yesterday,
I got curious about the time series of the sizes of
the monthly archives in MB.
This turned out to have an unexpected feature or two,
which I leave to readers to explore for themselves.
I'm now wondering at what point in time we
I think
1) You have the units wrong: these appear to be the figures quoted for KB
of compressed files, and the compression is nothing like 1024:1.
2) This is not `a series' unless you add a time base, e.g. via a call
to ts().
Surely subscribers are aware that they do not get many MB/day and
Maybe argument 'fill' of read.table is the solution.
The default value is FALSE in read.table and, therefore, any line not
having the same number of fields as the first line (not skipped) will
make problems. If set to TRUE, as in read.delim and read.csv, lines
with less number of fields get
On 26-Feb-05 Prof Brian Ripley wrote:
I think
1) You have the units wrong: these appear to be the figures
quoted for KB of compressed files, and the compression is
nothing like 1024:1.
Sorry, yes, you are correct: it is KB and not MB (a slip of the
eye on my part).
2) This is not `a
Ted.Harding at nessie.mcc.ac.uk writes:
:
: Hi Folks,
:
: While I was browsing in the R-help archives yesterday,
: I got curious about the time series of the sizes of
: the monthly archives in MB.
:
: This turned out to have an unexpected feature or two,
: which I leave to readers to explore
Tilo Blenk wrote:
Maybe argument 'fill' of read.table is the solution.
The default value is FALSE in read.table and, therefore, any line not
having the same number of fields as the first line (not skipped) will
make problems. If set to TRUE, as in read.delim and read.csv, lines with
less number
Hello,
Is there a way to get plot.summary.Design() to plot the variable labels instead
of the variable name on the y axis of the confidence interval plot generated? I
am using R2.0.1 on windows xp.
Osman
[[alternative HTML version deleted]]
Prof Brian Ripley wrote:
I think
1) You have the units wrong: these appear to be the figures quoted for
KB of compressed files, and the compression is nothing like 1024:1.
2) This is not `a series' unless you add a time base, e.g. via a call to
ts().
Surely subscribers are aware that they do
On 26-Feb-05 Uwe Ligges wrote:
So let's be immensely unfair and do some speculation ...
Assuming 1000MB/month means a compressed archive file of (very)
*roughly* 250MB.
Looking at the data with linear models,
lm(sqrt(MB) ~ monthindex)
seems not to be the worst model (removing the
My apologies -- I had believed that by linking the source message I
had made the detailed context available. I will be more careful in
the future to correctly give full context.
Paul
-Original Message-
From: Prof Brian Ripley [mailto:[EMAIL PROTECTED]
Sent: Saturday, February 26,
I am new to R. Having come from SPSS and SAS to this program, I know
that my problem is
reshaping from long to wide. How would I go about reshaping data frame
(A) so that
information for each record is contained on one row. I am aware of the
R reshape
function, but I am uncertain of how to
I have a dataframe with names in the first column and wait times
between decisions in the second column. Since individuals make
multiple decisions, I want the average for each individual. For
example, the data might look like this
namewtime
jo 1
jo 2
jo
?tapply
Bendix Carstensen
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of thomas hills
Sent: Saturday, February 26, 2005 6:17 PM
To: r-help@stat.math.ethz.ch
Subject: [R] averaging within columns
I have a dataframe with names in the first
On Sat, 26 Feb 2005, Matthew Pharr wrote:
but I am uncertain of how to instruct R to reshape the data
set because I
need to move var1 (var1 is a survey question) out wide while placing
the values of var2 (var2 is the answer to the survey question) under
the correct survey question. Thank
Hello Thomas,
The function aggregate will do the job.
Marc Mamin
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
On Fri, 18 Feb 2005, Romain Francois wrote:
Hello Sander,
That's a good idea and i am up to it.
Right now i am in an exam period, so it's not really the better time,
give me a couple of weeks and i will come up with a specific format of R
files to submit to me that i could post-process to
Spencer Graves wrote:
I agree with Thomas and Georg: A 40 minute intro should be mostly
Marketing and very little how to.
I think you'll have a more effective sales job if you target, say,
4 examples averaging 5 slides each plus some general overview, max 25-30
slides. If I had
In addition to other suggestions made, note also count.fields().
cat(10 9 17 # First of 7 lines, 11 13 1 6, 9 14 16,
+ 12 15 14, 8 15 15, 9 13 12, 7 14 18,
+ file=oneBadRow.txt, sep=\n)
nfields - count.fields(oneBadRow.txt)
nfields
[1] 3 4 3 3 3 3 3
table(nfields) ## Use with many
I have used \input in my .Snw file and it works fine.
- Mohamed
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Gorjanc Gregor
Sent: February 23, 2005 10:50 AM
To: r-help@stat.math.ethz.ch
Subject: [R] Sweave and \input or \include LaTeX commands
Imagine this situation:
% --- a.Rnw start ---
\documentclass{book}
\usepackage{Sweave}
\begin{document}
% some toy example
print=TRUE=
x - 1:10
@
% now we input additional file
\input{a1}
% and lets look again at x
print=TRUE=
x
@
\end{document}
% --- a.Rnw end ---
% --- a1.Rnw start ---
If this were supported it should have a different command than the
latex one or else one would not be able to do it at the latex level.
One might want to do it at the latex level rather than the Sweave
level in the case that one wants to have a vignette pass R CMD CHECK
but the vignette depends
In R 2.0.1 under Windows 2000, at least in some cases, as.POSIXct
adds one to the date:
March1.1959.POSIXct - as.POSIXct(1959-03-01)
March1.1959.POSIXlt - as.POSIXlt(1959-03-01)
(Mar2.59 - as.Date(March1.1959.POSIXct))
[1] 1959-03-02
as.Date(March1.1959.POSIXlt)
[1] 1959-03-01
Spencer Graves spencer.graves at pdf.com writes:
:
: In R 2.0.1 under Windows 2000, at least in some cases, as.POSIXct
: adds one to the date:
:
: March1.1959.POSIXct - as.POSIXct(1959-03-01)
: March1.1959.POSIXlt - as.POSIXlt(1959-03-01)
:
: (Mar2.59 - as.Date(March1.1959.POSIXct))
:
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