[R] (no subject)

2006-10-02 Thread John Kapsomenakis
Dear friends

I try to install R-project in SUSE 10.0 LINUX. I run the ./configure. The
last lines during the run is

checking readline/history.h usability... no
checking readline/history.h presence... no
checking for readline/history.h... no
checking readline/readline.h usability... no
checking readline/readline.h presence... no
checking for readline/readline.h... no
checking for rl_callback_read_char in -lreadline... no
checking for main in -lncurses... no
checking for main in -ltermcap... no
checking for main in -ltermlib... no
checking for rl_callback_read_char in -lreadline... no
checking for history_truncate_file... no
configure: error: --with-readline=yes (default) and headers/libs are not
available

I'm now hoping for some help

Thanks in advance.
john

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Re: [R] (installing on SUSE readline failure)

2006-10-02 Thread Roger Bivand
On Mon, 2 Oct 2006, John Kapsomenakis wrote:

 Dear friends

Please include an informative subject!

 
 I try to install R-project in SUSE 10.0 LINUX. 

Did you read the online version of the R Installation and Administration 
manual at:

http://cran.r-project.org/doc/manuals/R-admin.html

There you will find information in Appendix A about your problem. Please 
also check that you have the development RPMs installed as well as those 
providing readline as such. Appendix A does start with the reminder to:

Remember that some package management systems (such as RPM and deb) make 
a distinction between the user version of a package and the development 
version. The latter usually has the same name but with the extension 
`-devel' or `-dev': you need both versions installed.

 I run the ./configure. The last lines during the run is
 
 checking readline/history.h usability... no
 checking readline/history.h presence... no
 checking for readline/history.h... no
 checking readline/readline.h usability... no
 checking readline/readline.h presence... no
 checking for readline/readline.h... no
 checking for rl_callback_read_char in -lreadline... no
 checking for main in -lncurses... no
 checking for main in -ltermcap... no
 checking for main in -ltermlib... no
 checking for rl_callback_read_char in -lreadline... no
 checking for history_truncate_file... no
 configure: error: --with-readline=yes (default) and headers/libs are not
 available
 
 I'm now hoping for some help
 
 Thanks in advance.
 john
 
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-- 
Roger Bivand
Economic Geography Section, Department of Economics, Norwegian School of
Economics and Business Administration, Helleveien 30, N-5045 Bergen,
Norway. voice: +47 55 95 93 55; fax +47 55 95 95 43
e-mail: [EMAIL PROTECTED]

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Re: [R] How to repeat vectors ?

2006-10-02 Thread Tong Wang
Hi, 
Thanks you guys for all the help. I learned a lot from it.  
It looks using apply() is not an efficient way, since all it does is 
looping through 
each row(or col) , which would be slow for large matrix, right ? 

cheers

- Original Message -
From: Gabor Grothendieck [EMAIL PROTECTED]
Date: Saturday, September 30, 2006 4:54 am
Subject: Re: [R] How to repeat vectors ?
To: Tong Wang [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch

 Here are 4 approaches in order from most compact
 to least.  #1 only works for numeric matrices, # 2 is
 a shorter versio of your solution using rep.vec and # 3
 is from Alex's post and is likely what I would
 use in practice.
 
 m - matrix(1:4, 2) # test matrix
 
 # 1 - m must be numeric for this one to work
 kronecker(m, rep(1,2))
 
 # 2
 apply(m, 2, rep, each = 2) # 2
 
 # 3 - from Alex's post
 m[rep(1:nrow(m), each = 2),]
 
 # 4
 matrix(rbind(c(m), c(m)), nc = ncol(m))
 
 On 9/30/06, Tong Wang [EMAIL PROTECTED] wrote:
  I just figured out a way to do this:
   rep.vec - function(X,n)
 return(t(array(rep(X,n),c(length(X),n
Then,apply(MyMatrix, 2, rep.vec,2)
 
  Is there a better way ?  Is there an internal function to repeat 
 a vector or matrix ?
 
  Thanks a lot.
 
 
  - Original Message -
  From: Tong Wang [EMAIL PROTECTED]
  Date: Friday, September 29, 2006 11:23 pm
  Subject: How to repeat vectors ?
  To: r-help@stat.math.ethz.ch
 
   Hi,
  If I have a matrix  , say   a11   a12
 a21  a22
  Is there a routine to get:  a11  a12
   a11  a12
   a21   a22
   a21   a22
  
   Thanks a lot for any help.
  
   best
  
 
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 reproducible code.
 


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[R] bar chart with several lines

2006-10-02 Thread Marko Ekqvist
Hi,
I have been some problems with producing bar graph with r. Here is my
example data (link) and picture but I am not able to do that with r.
Please any kind of help is welcome

http://www.pasilankaista.com/~ekqvistmt/r/Page001.html

Kind Regards,
Marko

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Re: [R] RODBC ERROR on Rcmdr install

2006-10-02 Thread vittorio
Alle 22:55, venerdì 29 settembre 2006, John Fox ha scritto:
 As I understand it, RODBC isn't useful on non-Windows systems, since the
 necessary ODBC drivers aren't available. (Someone will correct me, I'm
 sure, if I don't have that entirely straight.) The RODBC package is used in
 the Rcmdr to read Excel and some other files under Windows; in the latest
 version of the Rcmdr, you won't even see this menu item in non-Windows
 systems.

As a matter of fact RODBC can be profitably used under *nix OS together with 
unixODBC to connect to many DBs.
I've been using RODBC with unixODBC on linux, freebsd and win xp  to connect 
smoothly to postgresql, mysql  and oracle (somewhat tricky to me under *nix, 
you need ** to buy ** a driver) and I know that connections are possible to 
many other *nix DBs under *nix itself. 

Ciao
Vittorio

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[R] [R-pkgs] Stineman interpolation package

2006-10-02 Thread halldor bjornsson
The package STINEPACK is now available on CRAN.

This package implements the stineman interpolation method, and is coded
entirely in R
(no Fortan or C libraries).  The interpolation method is very robust, and
does not yield
spurious oscillations near spikes or steps. The original article (Stineman
1980) describes
this method as consistently well behaved.

The interpolation is done in the stinterp routine, and depending on
arguments passed to it, this routine
may call other routines to estimate the slope of the interpolating function.
If the slope is known it can be
explicitly included in stinterp.

The interpolation method is described in an article by Russell W. Stineman
in the July 1980 issue of
Creative Computing with a note from the editor stating that while they were
not an academic journal
but once in a while something serious and original comes in adding that
this was apparently a
real solution to a well known problem.

According to Stineman, the interpolation procedure has the following
properties:

1. If values of the ordinates of the specified points change monotonically,
and the slopes of the
line segments joining the points change monotonically, then the
interpolating curve and its
slope will change monotonically.
2. If the slopes of the line segments joining the specified points change
monotonically, then the
slopes of the interpolating curve will change monotonically.
3. Suppose that the conditions in (1) or (2) are satisfied by a set of
points, but a small change
in the ordinate or slope at one of the points will result conditions (1) or
(2) being not longer
satisfied. Then making this small change in the ordinate or slope at a point
will cause no more
than a small change in the interpolating curve.

The method is based on rational interpolation with specially chosen rational
functions to satisfy the
above three conditions.

Slopes computed at the given points with the methods provided by the
'stinterp' function satisfy
Stineman's requirements. The original method suggested by Stineman
(method=scaledstineman,
the default, and stineman) result in lower slopes near abrupt steps or
spikes in the point sequence,
and therefore a smaller tendency for overshooting. The method based on a
second degree polynomial
(method=parabola) provides better approximation to smooth functions, but
it results in
in higher slopes near abrupt steps or spikes and can lead to some
overshooting where Stineman's
method does not. Both methods lead to much less tendency for 'spurious'
oscillations than traditional
interplation methods based on polynomials, such as splines (see the example
below).

Stineman states that The complete assurance that the procedure will never
generate 'wild' points
makes it attractive as a general purpose procedure.

This interpolation method has been implemented in Matlab and Python in
addition to R

An example follows:

library(stinepack)

# make a function with a sharp spike
x - seq(0,2*pi,by=pi/6)
y - sin(x)
y[3] - -1.5

# interpolate to a finer axis, try all three methods for estimating the
slope.
xo - seq(0,2*pi,by=pi/150)
y1 - stinterp(x,y,xo,method=sc)$y
y2 - stinterp(x,y,xo,method=st)$y
y3 - stinterp(x,y,xo,method=pa)$y

# compare with standard spline
ysp=spline(x,y,n=length(xo))

# plot the results
plot(x,y,ylim=c(-1.5,1.5))
points(xo,y1,cex=1/5,col=2)
points(xo,y2,cex=1/5,col=3)
points(xo,y3,cex=1/5,col=4)
points(ysp,cex=1/5,col=5)

legend(3, 1, c(Scaled Stineman, Stineman, Parabolic, Spline), col =
c(2,3,4,5),lty=1)


Sincerely,
Halldor
-- 
Halldór Björnsson
Deildarstj. Ranns.  Þróun
Veðursvið Veðurstofu Íslands

Halldór Bjornsson
Weatherservice R  D
Icelandic Met. Office

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[R] [R-pkgs] New package 'ade4TkGUI', a Tcl/Tk GUI for ade4

2006-10-02 Thread Jean Thioulouse
Dear R-Users,

ade4TkGUI is a new package available on CRAN. It implements a Tcl/Tk
graphical user interface (GUI) for the ade4 package.

Only the most basic functions of ade4 have a GUI in this first
version : classical one-table data analysis methods (PCA, COA,
MCA, PCO, etc.), one table with groups of rows (BGA, WGA, DA),
and two-tables analysis methods (Coinertia analysis, CCA, PCAIV).
http://pbil.univ-lyon1.fr/JTHome/ade4TkGUI.jpg

One of the benefits of using ade4TkGUI is the centralized graphical
display of the dudi objects created by ade4. A dudi is a list with
many components http://pbil.univ-lyon1.fr/ade4html/dudi.html
The GUI presents a window in which the user can click on dudi
components to get predefined graphical displays : 
http://pbil.univ-lyon1.fr/JTHome/coa1dudi.jpg

Another benefit is for complex functions, and particularly graphical
functions that have many parameters. For example, the s.class function
has 27 parameters : http://pbil.univ-lyon1.fr/ade4html/s.class.html
In this case, the GUI makes it much easier to try various graphical
options : http://pbil.univ-lyon1.fr/JTHome/s.class.jpg

ade4TkGUI also contains a factor map exploration function, written by
Stephane Dray. This function allows dynamic operations like zooming,
panning, and identification of points by searching on labels on the
factor maps : http://pbil.univ-lyon1.fr/JTHome/explore.jpg

Current version (ade4TkGUI_0.1-4) depends on ade4_1.4-2, and the
dynamic factor map exploration function depends on tkrplot. Future
versions will add GUIs for more advanced ade4 methods, like ktables
analysis methods, or spatial methods, and for more graphical functions.

All comments are welcome. Please use the adelist mailing list :
http://listes.univ-lyon1.fr/wws/info/adelist

Jean
-- 
Jean Thioulouse - Labo Biometrie et Biologie Evolutive, UMR CNRS 5558
Universite Lyon 1,  43 Boulevard du 11 Novembre 1918,  Bat. G. Mendel
69622 Villeurbanne Cedex,  France.   Tel/Fax : (33) 4 72 43 27 56   

   http://pbil.univ-lyon1.fr/JTHome.html

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Re: [R] Build error on Windows

2006-10-02 Thread Pankaj Savdekar
From: Duncan Murdoch [EMAIL PROTECTED]
Date: Sat, 30 Sep 2006 09:13:36 -0400

On 9/29/2006 5:41 PM, Pankaj Savdekar wrote:
Thanks for the quick reply.

On 9/29/2006 8:53 AM, Pankaj Savdekar wrote:
Hi,

I'm trying to build R-2.3.1 on windows, but make gives me following 
error while building pkg-base:
-- Making package base 
   adding build stamp to DESCRIPTION
make[4]: *** [frontmatter] Error 1
make[3]: *** [all] Error 2
make[2]: *** [pkg-base] Error 2
make[1]: *** [rpackage] Error 2
make: *** [all] Error 2

Please note that R.exe, Rterm.exe, Rgui.exe, RCmd.exe are build without 
any errors.

I have three questions, can anyone please help me to resolve it?
1. How to solve (or get more details) of the above mentioned error?
You need to look through the make files, to see what was happening. 
Reading the messages in reverse order:  make all called make rpackage 
and so on to make frontmatter.  The errors don't tell you which 
makefiles these are in, but the frontmatter target only occurs in 
src/gnuwin32/MakePkg.  You could try deleting the @ signs from the 
lines for that target to see exactly what was happening when the error 
was generated.

Yes I could figure out the source of 'frontmatter', but my problem is, 
there is no error message. I tried 'make -d' too. I tried removing '@', 
but no change.

I'd guess that this is happening because your build is messed up:  the 
base package is used in later build steps.  If you start from a clean 
checkout and just call make, you probably won't see this.

Is there any way to check what could have been wrong in building base 
package?

You could look at whatever command in the makefile failed, and try it 
outside of the makefile, try variations on it, etc.  I can't give more 
specific advice without more specific information on where the error 
happened.

Thanks, I could get the error after 'make distclean'. The error is
-- Making package base 
  adding build stamp to DESCRIPTION
Error in loadNamespace(name) : there is no package called 'tools'
Execution halted
make[4]: *** [frontmatter] Error 1
make[3]: *** [all] Error 2
make[2]: *** [pkg-base] Error 2
make[1]: *** [rpackage] Error 2
make: *** [all] Error 2

Surprisingly once this error come, if I do 'make' or 'make pkg-base', this 
error doesn't get displayed.

I tried including R-bin directory to 'PATH', setting R_HOME, R_LIBS 
environment variable, but it doesn't help. Do I need to set anyother 
environment variable to find proper tools directory. My library directory 
contents are as follows:
R-2.3.1
library
base
DESCRIPTION [file]
R
all.R [file]
base [file]
Rprofile [file]
tools
DESCRIPTION [file]
NAMESPACE [file]
libs
tools.dll [file]
R
all.R [file]
tools [file]
R.css [file]

If you're not used to working in Windows, remember that it is not like Unix 
in several ways.  In particular, you can't delete an open file, because 
it's considered an error for a file to exist unless it has a valid 
directory entry.  If you try to replace a file that is open, the 
replacement will fail, and that may lead to other errors later.

Duncan Murdoch

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[R] Geometric pattern matching with R?

2006-10-02 Thread Atte Tenkanen
Hi,

Is there some package or function for 2- or 3 -dimensional geometric pattern 
matching with R? It should be measure similarities between patterns in a fuzzy 
way, so not exact similarities are demanded.

Atte Tenkanen
University of Turku, Finland

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[R] Simple question on a function

2006-10-02 Thread Serguei Kaniovski
I would like to apply the following function to the rows of the matrix 
mat, so that freq[1],...,freq[4] are the four elements of each row.

min_chi2-function(freq){

obj-function(x){
(freq[1]-(1-x[1])*(1-x[2])-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[1]+
(freq[2]-(1-x[1])*x[2]+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[2]+
(freq[3]-x[1]*(1-x[2])+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[3]+
(freq[4]-x[1]*x[2]-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[4]
}

optim(c(0.1,0.1,0.1),obj,NULL,method=BFGS)$par
}

mat-matrix(c(0.4,0.1,0.1,0.4), byrow=TRUE, nrow=10, ncol=4)

Questions:
1. How to do this using the apply function?
2. Can opmit be used directly, i.e. without needing to define the 
function min_chi2?
3. How to pass the vector of initial conditions (c(0.1,0.1,0.1)) as an 
argument to apply?

The output should be a 10x3 matrix containing 0.5 0.5 0.6 in each row.

Thanks a lot,
Serguei
-- 
___

Austrian Institute of Economic Research (WIFO)

Name: Serguei Kaniovski P.O.Box 91
Tel.: +43-1-7982601-231 Arsenal Objekt 20
Fax:  +43-1-7989386 1103 Vienna, Austria
Mail: [EMAIL PROTECTED]

http://www.wifo.ac.at/Serguei.Kaniovski

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Re: [R] bar chart with several lines

2006-10-02 Thread David Barron
This should be enough to show how to do it:

 dta - read.table(clipboard,dec=,,row.names=NULL)
 r - barplot(dta$use,ylim=c(-80,60))
 lines(r,dta$x1,type=b,col=red,pch=20)
 lines(r,dta$x2,type=b,col=blue,pch=21)


On 01/10/06, Marko Ekqvist [EMAIL PROTECTED] wrote:
 Hi,
 I have been some problems with producing bar graph with r. Here is my
 example data (link) and picture but I am not able to do that with r.
 Please any kind of help is welcome

 http://www.pasilankaista.com/~ekqvistmt/r/Page001.html

 Kind Regards,
 Marko

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-- 
=
David Barron
Said Business School
University of Oxford
Park End Street
Oxford OX1 1HP

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[R] finding correlation between two matrices

2006-10-02 Thread sima fakheran
Dear all,
 
I would like to compare two distance matrices to find the correlation
between those and create a XY plot.could you please kindly help me and
let me know how I can do that using R.(Mantel test?).
 
Your help is very much appreciated!! Many thanks!
 
Regards,
Sima Fakheran
...
Sima Fakheran Esfahani
PhD Student
Institute of Environmental Sciences
University of Zurich
Winterthurerstrasse 190
8057 Zurich
Switzerland
Tel: +41 1 635 61 18
Fax:+41 1 635 57 11
email:[EMAIL PROTECTED]
 http://www.uwinst.unizh.ch www.uwinst.unizh.ch
 

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Re: [R] multilevel factor model in lmer

2006-10-02 Thread Doran, Harold
Dan:

lmer cannot currently be used for the 2PL. As you note, it is straightforward 
to estimate the 1PL, but the a-parameters present a current challenge. Doug 
mentioned to me the other day he is doing some work on this, so I have copied 
him on this reply.

Harold


-Original Message-
From: [EMAIL PROTECTED] on behalf of Dan Powers
Sent: Sun 10/1/2006 10:15 PM
To: 'R-Help'
Subject: [R] multilevel factor model in lmer
 

Hello --

I am curious if lmer can be used to fit a multilevel factor model such as a
two-parameter item response model. The one parameter model is
straightforward.  A two-factor model requires a set of factor loadings
multiplying a single random effect. For example, a logit model for the ith
subject responding correctly to the jth item (j=1,..,J) is

logit[p(ij)] = a1*item1(i) + ... +  aJ * itemJ(i) + 
 lambda1*item1(i)*u(i) + ... + lambdaJ*itemJ(i)*u(i) 

where the lambdas are factor loadings, with lambda1 fixed to 1.0 and
item1-itemJ are dummy variables for the items.

Thanks,
Dan
 
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Daniel A. Powers, Ph.D.
Department of Sociology
University of Texas at Austin
1 University Station A1700
Austin, TX  78712-0118
phone: 512-232-6335
fax:   512-471-1748
[EMAIL PROTECTED]

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Re: [R] finding correlation between two matrices

2006-10-02 Thread David Barron
Have you looked at the function mantel.rtest in the ade4 package?

On 02/10/06, sima fakheran [EMAIL PROTECTED] wrote:
 Dear all,

 I would like to compare two distance matrices to find the correlation
 between those and create a XY plot.could you please kindly help me and
 let me know how I can do that using R.(Mantel test?).

 Your help is very much appreciated!! Many thanks!

 Regards,
 Sima Fakheran
 ...
 Sima Fakheran Esfahani
 PhD Student
 Institute of Environmental Sciences
 University of Zurich
 Winterthurerstrasse 190
 8057 Zurich
 Switzerland
 Tel: +41 1 635 61 18
 Fax:+41 1 635 57 11
 email:[EMAIL PROTECTED]
  http://www.uwinst.unizh.ch www.uwinst.unizh.ch


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-- 
=
David Barron
Said Business School
University of Oxford
Park End Street
Oxford OX1 1HP

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Re: [R] multilevel factor model in lmer

2006-10-02 Thread Dimitris Rizopoulos
If you just want to fit the 2PL, without any covariates, then this can 
be currently handled by function ltm() in package ltm.

Best,
Dimitris


Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
 http://www.student.kuleuven.be/~m0390867/dimitris.htm


- Original Message - 
From: Doran, Harold [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; R-Help r-help@stat.math.ethz.ch
Cc: [EMAIL PROTECTED]
Sent: Monday, October 02, 2006 12:22 PM
Subject: Re: [R] multilevel factor model in lmer


 Dan:

 lmer cannot currently be used for the 2PL. As you note, it is 
 straightforward to estimate the 1PL, but the a-parameters present a 
 current challenge. Doug mentioned to me the other day he is doing 
 some work on this, so I have copied him on this reply.

 Harold


 -Original Message-
 From: [EMAIL PROTECTED] on behalf of Dan Powers
 Sent: Sun 10/1/2006 10:15 PM
 To: 'R-Help'
 Subject: [R] multilevel factor model in lmer


 Hello --

 I am curious if lmer can be used to fit a multilevel factor model 
 such as a
 two-parameter item response model. The one parameter model is
 straightforward.  A two-factor model requires a set of factor 
 loadings
 multiplying a single random effect. For example, a logit model for 
 the ith
 subject responding correctly to the jth item (j=1,..,J) is

 logit[p(ij)] = a1*item1(i) + ... +  aJ * itemJ(i) +
 lambda1*item1(i)*u(i) + ... + lambdaJ*itemJ(i)*u(i)

 where the lambdas are factor loadings, with lambda1 fixed to 1.0 and
 item1-itemJ are dummy variables for the items.

 Thanks,
 Dan

 =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
 Daniel A. Powers, Ph.D.
 Department of Sociology
 University of Texas at Austin
 1 University Station A1700
 Austin, TX  78712-0118
 phone: 512-232-6335
 fax:   512-471-1748
 [EMAIL PROTECTED]

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Re: [R] plotting

2006-10-02 Thread Anupam Tyagi
Dieter Menne dieter.menne at menne-biomed.de writes:

  Is there something in R that will display both observed values and their
  influence on calculated statistics?
 
 In general : yes. You may give the example in the lm documentation a first
 try, and then rephrase your question.

Thanks for the pointer. I found what I was looking for in lm.influence and
influence.measures. I was looking for Cook's Distance some other influence
measures. I guess I want to plot the fitted values, observations and influence
measures on the same plot. Anupam.

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[R] Arrowheads at line-ends

2006-10-02 Thread Dan Michael Olsen Heggø
Hi,

I'm quite new to R and I'm trying to do a simple plot with two lines,  
one upper and one lower. The problem is that the lines are reaching  
limiting values at x=0 for the upper line and x=1 for the lower.  
Thus, they are undefined at that values. I would like to indicate  
that with arrowheads. So I want a arrowhead at the left end of the  
upper line and a one at the right end at the lower line. I've managed  
to do this manually by drawing them with arrows, but this solution  
appears too be quite inflexible.

So my question to the more experienced R-users out there is if there  
is a smarter way to do this? Is there, for instance, any graphing  
property that automaticly insert arrowheads?

Here's the code of my manual solution:

xA - c(0.,0.0968,0.2340,0.4645,0.6115,0.8890,1.)
Va - c(69.016,69.769,70.775,72.456,73.280,73.564,73.921)
Vb - c(18.020,17.822,17.480,16.897,16.277,13.833,13.101)

plot(c(0,1), c(10,80),
type=n,
xlab=expression(x[aceton]),
ylab=Partielt molart volum,
bty=o,
xaxs=i, yaxs=i,
xaxp=c(0,1,10),
yaxp=c(10,80,20),
penel.first = grid(20,20,lty=1)
)
points(xA[2:7],Va[2:7], type=o, col=blue,pch=5,lend=1)
points(xA[1:6],Vb[1:6], type=o, col=darkgreen,pch=5)

arrows(xA[2],Va[2],xA[1],Va[1],col=blue)
arrows(xA[6],Vb[6],xA[7],Vb[7],col=darkgreen)

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[R] GLS models - bootstrapping

2006-10-02 Thread Lillian Sandeman
Hello,

I am have fitted GLS models to time series data.  Now I wish to bootstrap
this data to produce confidence intervals for the model.

However, because this is time series data, normal bootstrapping is not
applicable.  Secondly, 'tsboot' appears to only be useful for ar models -
and does not seem to be applicable to GLS models.

I have written code in R to randomly sample blocks of the data (as in
Davison  Hinkley's book - bootstrap methods and their application) and
use this resampling to re-run the model, but this does not seem to be the
correct approach since Confidence Intervals produced do not show the
underlying pattern (cycles) in the data [even when block length is
increased, it only picks up a little of this variation].

Any help as to how to proceed with this would be greatly appreciated, as I
cannot find anything applicable on the R pages.   Alternatively, if there
is another method to proceed with this (other than bootstrapping), I would
also be happy to try it.

Thankyou,

Lillian.

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Re: [R] Simple question on a function

2006-10-02 Thread Christoph Buser
Dear Serguei

There might be more efficient ways, but this should work:   

## Define function that you want to optimize. In your case I
## copied your code, but included freq as a second argument:
fun - function(x, freq)
{
  (freq[1]-(1-x[1])*(1-x[2])-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[1]+
(freq[2]-(1-x[1])*x[2]+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[2]+
  (freq[3]-x[1]*(1-x[2])+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[3]+
(freq[4]-x[1]*x[2]-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[4]
}

## Define mat with values for freq (your code)
mat-matrix(c(0.4,0.1,0.1,0.4), byrow=TRUE, nrow=10, ncol=4)

## Use apply on mat
apply(mat, 1, function(freq, start) optim(start, fun,
method=BFGS, freq = freq)$par, start = c(0.1,0.1,0.1))

You still can use t() to transpose the matrix if you want the
solutions by row instead of columns.


Please remark that in general optim returns a list, including
several arguments, e.g. convergence that indicates if optim has
converge.
Since you wanted a matrix I only returned optim(...)$par. This
might be dangerous since the additional information gets
lost. Maybe it is better to save the output in a list. You can
try:  

apply(mat, 1, function(freq, start) optim(start, fun,
method=BFGS, freq = freq), start = c(0.1,0.1,0.1))

to see the difference.

Hope this helps

Christoph

--

Credit and Surety PML study: visit our web page www.cs-pml.org

--
Christoph Buser [EMAIL PROTECTED]
Seminar fuer Statistik, LEO C13
ETH Zurich  8092 Zurich  SWITZERLAND
phone: x-41-44-632-4673 fax: 632-1228
http://stat.ethz.ch/~buser/
--


Serguei Kaniovski writes:
  I would like to apply the following function to the rows of the matrix 
  mat, so that freq[1],...,freq[4] are the four elements of each row.
  
  min_chi2-function(freq){
  
  obj-function(x){
  (freq[1]-(1-x[1])*(1-x[2])-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[1]+
  (freq[2]-(1-x[1])*x[2]+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[2]+
  (freq[3]-x[1]*(1-x[2])+x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[3]+
  (freq[4]-x[1]*x[2]-x[3]*sqrt(x[1]*(1-x[1])*x[2]*(1-x[2])))^2/freq[4]
  }
  
  optim(c(0.1,0.1,0.1),obj,NULL,method=BFGS)$par
  }
  
  mat-matrix(c(0.4,0.1,0.1,0.4), byrow=TRUE, nrow=10, ncol=4)
  
  Questions:
  1. How to do this using the apply function?
  2. Can opmit be used directly, i.e. without needing to define the 
  function min_chi2?
  3. How to pass the vector of initial conditions (c(0.1,0.1,0.1)) as an 
  argument to apply?
  
  The output should be a 10x3 matrix containing 0.5 0.5 0.6 in each row.
  
  Thanks a lot,
  Serguei
  -- 
  ___
  
  Austrian Institute of Economic Research (WIFO)
  
  Name: Serguei Kaniovski  P.O.Box 91
  Tel.: +43-1-7982601-231  Arsenal Objekt 20
  Fax:  +43-1-7989386  1103 Vienna, Austria
  Mail: [EMAIL PROTECTED]
  
  http://www.wifo.ac.at/Serguei.Kaniovski
  
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Re: [R] RODBC ERROR on Rcmdr install

2006-10-02 Thread John Fox
Dear Vittorio,

Thanks for the clarification. This raises two questions: (1) If a *nix
system has an ODBC driver, can one then read Excel, Access, and dBase data
sets via RODBC (which is what the Rcmdr menu item in question provides for)?
(2) If so, is there a way for me to detect whether unixODBC is present, or
would I have to rely, e.g., on a user-set option?

I'm moving this message to the r-devel list.

Regards,
 John


John Fox
Department of Sociology
McMaster University
Hamilton, Ontario
Canada L8S 4M4
905-525-9140x23604
http://socserv.mcmaster.ca/jfox 
 

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED] On Behalf Of vittorio
 Sent: Saturday, September 30, 2006 12:40 PM
 To: r-help@stat.math.ethz.ch
 Subject: Re: [R] RODBC ERROR on Rcmdr install
 
 Alle 22:55, venerdì 29 settembre 2006, John Fox ha scritto:
  As I understand it, RODBC isn't useful on non-Windows 
 systems, since 
  the necessary ODBC drivers aren't available. (Someone will 
 correct me, 
  I'm sure, if I don't have that entirely straight.) The 
 RODBC package 
  is used in the Rcmdr to read Excel and some other files 
 under Windows; 
  in the latest version of the Rcmdr, you won't even see this 
 menu item 
  in non-Windows systems.
 
 As a matter of fact RODBC can be profitably used under *nix 
 OS together with unixODBC to connect to many DBs.
 I've been using RODBC with unixODBC on linux, freebsd and win 
 xp  to connect smoothly to postgresql, mysql  and oracle 
 (somewhat tricky to me under *nix, you need ** to buy ** a 
 driver) and I know that connections are possible to many 
 other *nix DBs under *nix itself. 
 
 Ciao
 Vittorio
 
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Re: [R] How to dowload mod_R.so

2006-10-02 Thread Jeffrey Horner
khao_lek wrote:
 i don't know url address how to dowload mod_R.so for use R and Apache
 webserver.
 i'm want to try R on the web. 
 please tell me.

Please visit:

http://biostat.mc.vanderbilt.edu/RApacheProject

to download the latest release, and also read the paper near the end of 
the page.

Jeff

-- 
http://biostat.mc.vanderbilt.edu/JeffreyHorner

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[R] line plot through NA

2006-10-02 Thread rggefrm
Dear R-help list,

I hope I did not miss something obvious, because my question seems very 
simple, but I couln't figure out how to do it.

If I have the following data:
Day-c(1,2,3,4,5,6,7)
V-c(5,NA,10,30,45,NA,10)
than the line in plot

plot(V~Day, type=b)

will start with the 3rd value and stop stop at the 5th value because all NA 
are omitted. Is there now a parameter which can be added to the plot 
function so the line will start with with the first value and skip the NA 
values and can this than applied to xyplots.

Many thanks

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Re: [R] line plot through NA

2006-10-02 Thread David Barron
I assume you mean that you want the first point to be connected by a
straight line to the third, etc. because fisrt and sixth points are
shown on the plot.  If so, you can use the approx function:


plot(approx(Day,V,n=length(Day)), type=l)
points(Day,V)

On 02 Oct 2006 15:31:59 +0100, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
 Dear R-help list,

 I hope I did not miss something obvious, because my question seems very
 simple, but I couln't figure out how to do it.

 If I have the following data:
 Day-c(1,2,3,4,5,6,7)
 V-c(5,NA,10,30,45,NA,10)
 than the line in plot

 plot(V~Day, type=b)

 will start with the 3rd value and stop stop at the 5th value because all NA
 are omitted. Is there now a parameter which can be added to the plot
 function so the line will start with with the first value and skip the NA
 values and can this than applied to xyplots.

 Many thanks

 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



-- 
=
David Barron
Said Business School
University of Oxford
Park End Street
Oxford OX1 1HP

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[R] Problems with graphics

2006-10-02 Thread Christophe Nguyen
Dear all,
I am a SAS user, who's trying R. I am a little bit lost for graphics. 
What is the simplest way for plotting y as a function of x with one 
symbol (line or dot) for each level of a class variable z (for SAS 
langage= plot x*y=z). Can I add vertical bars for standard deviation 
stored in a  separate variable (say  ystd). Finally, is it possible to 
do all this with xyplot function arranging plots according to A and B 
factor: xyplot(y~x|A*B) with as many plots and symbol as there is levels 
in the z variable for each panel?
Thanks for the help.
Chris

-- 
___

Christophe NGUYEN

UMR 1220 INRA-ENITAB
Transfert sol-plante et cycle des éléments minéraux
dans les écosystèmes cultivés

Centre INRA de Bordeaux-Aquitaine
71, avenue Edouard Bourlaux, BP 81
33883 Villenave d'Ornon, FRANCE

Tel : 00 33 (0)5 57 12 25 07
Fax : 00 33 (0)5 57 12 25 15

email : [EMAIL PROTECTED]
page infoservice: http://www.bordeaux.inra.fr/tcem

__m°O°m

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Re: [R] line plot through NA

2006-10-02 Thread Peter Dalgaard
[EMAIL PROTECTED] writes:

 Dear R-help list,
 
 I hope I did not miss something obvious, because my question seems very 
 simple, but I couln't figure out how to do it.
 
 If I have the following data:
 Day-c(1,2,3,4,5,6,7)
 V-c(5,NA,10,30,45,NA,10)
 than the line in plot
 
 plot(V~Day, type=b)
 
 will start with the 3rd value and stop stop at the 5th value because all NA 
 are omitted. Is there now a parameter which can be added to the plot 
 function so the line will start with with the first value and skip the NA 
 values and can this than applied to xyplots.

AFAIK, this is not controlable via options or graphics parameters. So
the way forward would be to remove the points with missing data.
Here's one way:

plot(V~Day, type=b, data=na.omit(data.frame(V,Day)))

and another:

plot(V~Day, type=b, subset=complete.cases(V,Day))

and another (messes up axis labels, though)

s - complete.cases(V,Day)
plot(Day[s], V[s], type=b)



-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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[R] Barplot

2006-10-02 Thread Mohsen Jafarikia
Hello,

I have used the following data to draw my barplot:

BL LRQ

36.351.00   1.92
36.914.00   0.00
25.706.00   0.00
34.383.00   1.92
05.320.50   0.00

 BL-c(36.35, 36.91, 25.70, 34.38, 05.32)
LR-c(1.00, 4.00, 6.00, 3.00, 0.50)
Q-(1.92, 0.00, 0.00, 1.92, 0.00)

barplot(dt$LR, main='LR Value',  col='orange', border='black', space=0.05,
width=(dt$BL), xlab='Length', ylab='LR')

 axis(1)

I would like to do the following things that I don't know how to do it:

  1)  Writing the value of each 'BL' on my X axis.
2)  Writing the value of 'Q' on the bottom of  X axis.
3)  Draw a line on the bars which connects the 'LR' values.

 I appreciate your comments.

 Thanks,
Mohsen

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Re: [R] line plot through NA

2006-10-02 Thread Doran, Harold
Do you mean something like this:

 plot(approx(Day,V), type='l') 

 -Original Message-
 From: [EMAIL PROTECTED] 
 [mailto:[EMAIL PROTECTED] On Behalf Of 
 [EMAIL PROTECTED]
 Sent: Monday, October 02, 2006 10:32 AM
 To: r-help@stat.math.ethz.ch
 Subject: [R] line plot through NA
 
 Dear R-help list,
 
 I hope I did not miss something obvious, because my question 
 seems very simple, but I couln't figure out how to do it.
 
 If I have the following data:
 Day-c(1,2,3,4,5,6,7)
 V-c(5,NA,10,30,45,NA,10)
 than the line in plot
 
 plot(V~Day, type=b)
 
 will start with the 3rd value and stop stop at the 5th value 
 because all NA are omitted. Is there now a parameter which 
 can be added to the plot function so the line will start with 
 with the first value and skip the NA values and can this than 
 applied to xyplots.
 
 Many thanks
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
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[R] separation depending on equal contents in more than one field

2006-10-02 Thread Florian Jansen
Hi,

I have a dataframe:

(obs - data.frame(a=c(1,2,2,3,3,3), b=c(1,2,3,4,4,5), c=1:2))
attach(obs)

In reality its about 1 million rows.

Some of the datasets have same contents in col a and! b like row 4 and 5.
I want to do some calculations on col c within the duplicated rows and 
merge them afterwards:

layer - function(x) round((1-prod(1-x/100))*100,0)
(covnew - aggregate(c, list(a=a, b=b), layer))

This works fine, but not with 1 mill. rows because of memory space 
limitations.
So I thought to split the dataframe into the majority of unique rows on 
one hand and all duplicated rows on the other:

With
subset(obs, a %in% a[duplicated(a)])
and !a respectively this works fine for single column comparison.
This must be also possible for two column comparison, but I can`t get it.

Thanks
Florian

-- 
Dr. Florian Jansen
Geobotany  Nature Conservation
Institute for Botany and Landscape Ecology
Ernst-Moritz-Arndt-University
Grimmer Str. 88
17487 Greifswald - Germany
+49 (0)3834 86 4147

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Re: [R] multilevel factor model in lmer

2006-10-02 Thread Dan Powers
Harold and Dimitris --
Thanks very much. 
Cheers,
Dan


=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Daniel A. Powers, Ph.D.
Department of Sociology
University of Texas at Austin
1 University Station A1700
Austin, TX  78712-0118
phone: 512-232-6335
fax:   512-471-1748
[EMAIL PROTECTED]

-Original Message-
From: Dimitris Rizopoulos [mailto:[EMAIL PROTECTED] 
Sent: Monday, October 02, 2006 6:05 AM
To: Doran, Harold; [EMAIL PROTECTED]; R-Help
Cc: [EMAIL PROTECTED]
Subject: Re: [R] multilevel factor model in lmer

If you just want to fit the 2PL, without any covariates, then this can 
be currently handled by function ltm() in package ltm.

Best,
Dimitris


Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
 http://www.student.kuleuven.be/~m0390867/dimitris.htm


- Original Message - 
From: Doran, Harold [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; R-Help r-help@stat.math.ethz.ch
Cc: [EMAIL PROTECTED]
Sent: Monday, October 02, 2006 12:22 PM
Subject: Re: [R] multilevel factor model in lmer


 Dan:

 lmer cannot currently be used for the 2PL. As you note, it is 
 straightforward to estimate the 1PL, but the a-parameters present a 
 current challenge. Doug mentioned to me the other day he is doing 
 some work on this, so I have copied him on this reply.

 Harold


 -Original Message-
 From: [EMAIL PROTECTED] on behalf of Dan Powers
 Sent: Sun 10/1/2006 10:15 PM
 To: 'R-Help'
 Subject: [R] multilevel factor model in lmer


 Hello --

 I am curious if lmer can be used to fit a multilevel factor model 
 such as a
 two-parameter item response model. The one parameter model is
 straightforward.  A two-factor model requires a set of factor 
 loadings
 multiplying a single random effect. For example, a logit model for 
 the ith
 subject responding correctly to the jth item (j=1,..,J) is

 logit[p(ij)] = a1*item1(i) + ... +  aJ * itemJ(i) +
 lambda1*item1(i)*u(i) + ... + lambdaJ*itemJ(i)*u(i)

 where the lambdas are factor loadings, with lambda1 fixed to 1.0 and
 item1-itemJ are dummy variables for the items.

 Thanks,
 Dan

 =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
 Daniel A. Powers, Ph.D.
 Department of Sociology
 University of Texas at Austin
 1 University Station A1700
 Austin, TX  78712-0118
 phone: 512-232-6335
 fax:   512-471-1748
 [EMAIL PROTECTED]

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Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm

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[R] Help with lrm function in package Design

2006-10-02 Thread WWei
Hi, there,

I am having trouble using 'lrm' function in package 'Design'. Basically, 
the ' . ' after ' ~ ' wouldn't  work. Here are some sample codes:

 temp - 
data.frame(a=c(rep(0,3),rep(1,3)),b=rnorm(6),c=c('a','b','c','a','b','c'))
 lrm(a~.,data=temp)
Error in terms.formula(formula, specials = strat) : 
'.' in formula and no 'data' argument

This code worked before but I can't remember the exact version number. Is 
there something being changed in the new version of lrm? If so, how to 
specify all other variables in the formula then?

Thanks in advance,

Auston


 version
   _ 
platform   i386-pc-mingw32 
arch   i386 
os mingw32 
system i386, mingw32 
status 
major  2 
minor  3.1 
year   2006 
month  06 
day01 
svn rev38247 
language   R 
version.string Version 2.3.1 (2006-06-01)



Auston Wei
Research Statistical Analyst
Division of Quantitative Science
The University of Texas MD Anderson Cancer Center
Tel: 713-563-4281
Email: [EMAIL PROTECTED]
[[alternative HTML version deleted]]

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[R] qvalue

2006-10-02 Thread alex lam \(RI\)

Dear colleagues,

This is not strictly a R question, but I hope it is ok to ask on the
list.
I fed a vector of p-values from about 20 million anova tests to the
package q-value and obtained this output:

 qsummary(asso_p.qvalue)

Call:
qvalue(p = asso_p.vec)

pi0:1

Cumulative number of significant calls:

1e-04 0.001  0.01 0.025   0.050.1   1
p-value  22711  59067 262103 551316 1013241 1936797 20048103
q-value   3554   5211   9275  12807   16951   24557 20048103

I can see that there are many hits with very small q-values ,say q
0.001, so to use that as cut off I have 5211 significant hits and can
expect ~ 5 false postives. But my pi0 is 1. Does it mean that all my
tests are true null and there are no significant results?

Thanks for your help.
Alex 
 

Alex Lam
PhD student
Department of Genetics and Genomics
Roslin Institute (Edinburgh)
Roslin
Midlothian EH25 9PS

Phone +44 131 5274471
Web   http://www.roslin.ac.uk

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Re: [R] Help with lrm function in package Design

2006-10-02 Thread Uwe Ligges
This is a bug in the Design package, please report it to its maintainer.

Uwe Ligges



[EMAIL PROTECTED] wrote:
 Hi, there,
 
 I am having trouble using 'lrm' function in package 'Design'. Basically, 
 the ' . ' after ' ~ ' wouldn't  work. Here are some sample codes:
 
 temp - 
 data.frame(a=c(rep(0,3),rep(1,3)),b=rnorm(6),c=c('a','b','c','a','b','c'))
 lrm(a~.,data=temp)
 Error in terms.formula(formula, specials = strat) : 
 '.' in formula and no 'data' argument
 
 This code worked before but I can't remember the exact version number. Is 
 there something being changed in the new version of lrm? If so, how to 
 specify all other variables in the formula then?
 
 Thanks in advance,
 
 Auston
 
 
 version
_ 
 platform   i386-pc-mingw32 
 arch   i386 
 os mingw32 
 system i386, mingw32 
 status 
 major  2 
 minor  3.1 
 year   2006 
 month  06 
 day01 
 svn rev38247 
 language   R 
 version.string Version 2.3.1 (2006-06-01)
 
 
 
 Auston Wei
 Research Statistical Analyst
 Division of Quantitative Science
 The University of Texas MD Anderson Cancer Center
 Tel: 713-563-4281
 Email: [EMAIL PROTECTED]
   [[alternative HTML version deleted]]
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

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R-help@stat.math.ethz.ch mailing list
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] qvalue

2006-10-02 Thread Uwe Ligges


alex lam (RI) wrote:
 Dear colleagues,
 
 This is not strictly a R question, but I hope it is ok to ask on the
 list.
 I fed a vector of p-values from about 20 million anova tests to the
 package q-value and obtained this output:
 
 qsummary(asso_p.qvalue)
 
 Call:
 qvalue(p = asso_p.vec)
 
 pi0:1
 
 Cumulative number of significant calls:
 
 1e-04 0.001  0.01 0.025   0.050.1   1
 p-value  22711  59067 262103 551316 1013241 1936797 20048103
 q-value   3554   5211   9275  12807   16951   24557 20048103
 
 I can see that there are many hits with very small q-values ,say q
 0.001, so to use that as cut off I have 5211 significant hits and can
 expect ~ 5 false postives. But my pi0 is 1. Does it mean that all my
 tests are true null and there are no significant results?

Well, yes, at least under H0 you would expect the above results in such 
a case.
Concluding without further information that *all* are non-significant is 
impossible, though. This requires some interpretation depending on where 
the tests some from...

Uwe Ligges



 Thanks for your help.
 Alex 
  
 
 Alex Lam
 PhD student
 Department of Genetics and Genomics
 Roslin Institute (Edinburgh)
 Roslin
 Midlothian EH25 9PS
 
 Phone +44 131 5274471
 Web   http://www.roslin.ac.uk
 
 __
 R-help@stat.math.ethz.ch mailing list
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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[R] Quantitative Position with Constellation

2006-10-02 Thread Tzamouranis,Yannis C
Content listed in R-Help and R-Finance

We have a couple of openings in the Risk Management Group of
Constellation Commodities and specifically in the Deal Review Team which
examines, analyzes and models structured transactions.  Brief
description follows.  If interested, please email me at
[EMAIL PROTECTED] with questions and a resume.

Regards,

Yannis Tzamouranis
-
Summary of Responsibilities, Essential Duties  Expectations:
 The Quantitative Analyst/Associate, Risk Management is responsible for:


*   Work within the Structured Deal analysis group to understand,
value and place risk metrics around new deals of some complexity, size
and risk; examine how they have been modeled by origination, how they
will be booked into the trading systems and how they are modified over
time.
*   Help in the valuation of financial and physical trading
instruments and derivatives.
*   Independently create models (usually Monte Carlos) to value
deals and confirm risk models created by the front office or Strategists
*   Develop models in support of various other risk management
functions
*   Develop new risk metrics for management to better understand the
risk /return tradeoffs of complex deals.  
*   Study the impact of hedging strategies, stress tests, critical
exposures, risks interacting across various regions and commodities.

Qualifications (Experience, Competencies, Skills, Education):
Ph.D. (in hard sciences or engineering) or Masters degree required in
technical field, e.g., computational finance, mathematics, physics,
economics, statistics or engineering. Some experience in energy is a
plus.  A good subset of the following skills and experience (with the
capability to eventually learn and cover all the areas below) is
desired: 

*   Advanced knowledge of mathematics and statistics, especially the
mathematical framework underlying the valuation and risk management of
futures, options and other derivatives. 
*   A thorough working knowledge of options valuation as it relates
to energy markets, especially North American gas markets. 
*   Advanced modeling and support of system operation, risk
management, and valuation systems. 
*   A well developed understanding of the fundamentals of various
North American power or gas markets and instruments.
*   Good knowledge of R (or SPLUS) and Visual Basic are desired.
SAS, Matlab and C++ are welcomed as are other programming languages.
Extensive experience in Microsoft Excel is also a must.
 This e-mail and any attachments are confidential, may contain legal, 
 professional or other privileged information, and are intended solely for 
 the addressee.  If you are not the intended recipient, do not use the 
 information in this e-mail in any way, delete this e-mail and notify the 
 sender. CEG-IP1

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] Help with lrm function in package Design

2006-10-02 Thread WWei
Thanks a lot. Will do.

Auston

Auston Wei
Research Statistical Analyst
Division of Quantitative Science
The University of Texas MD Anderson Cancer Center
Tel: 713-563-4281
Email: [EMAIL PROTECTED]





Uwe Ligges [EMAIL PROTECTED]
Sent by: [EMAIL PROTECTED]
10/02/2006 11:47 AM



 

To:
[EMAIL PROTECTED]
cc:
r-help@stat.math.ethz.ch




Subject:
Re: [R] Help with lrm function in package Design



This is a bug in the Design package, please report it to its maintainer.

Uwe Ligges



[EMAIL PROTECTED] wrote:
 Hi, there,
 
 I am having trouble using 'lrm' function in package 'Design'. Basically, 

 the ' . ' after ' ~ ' wouldn't  work. Here are some sample codes:
 
 temp - 
 
data.frame(a=c(rep(0,3),rep(1,3)),b=rnorm(6),c=c('a','b','c','a','b','c'))
 lrm(a~.,data=temp)
 Error in terms.formula(formula, specials = strat) : 
 '.' in formula and no 'data' argument
 
 This code worked before but I can't remember the exact version number. 
Is 
 there something being changed in the new version of lrm? If so, how to 
 specify all other variables in the formula then?
 
 Thanks in advance,
 
 Auston
 
 
 version
_ 
 platform   i386-pc-mingw32 
 arch   i386 
 os mingw32 
 system i386, mingw32 
 status 
 major  2 
 minor  3.1 
 year   2006 
 month  06 
 day01 
 svn rev38247 
 language   R 
 version.string Version 2.3.1 (2006-06-01)
 
 
 
 Auston Wei
 Research Statistical Analyst
 Division of Quantitative Science
 The University of Texas MD Anderson Cancer Center
 Tel: 713-563-4281
 Email: [EMAIL PROTECTED]
[[alternative HTML version deleted]]
 
 __
 R-help@stat.math.ethz.ch mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

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[[alternative HTML version deleted]]

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Re: [R] separation depending on equal contents in more than one field

2006-10-02 Thread jim holtman
One way is to 'split' the indices of the rows to determine which ones
to use.  For example from the data give, I got the following:

 split(seq(nrow(obs)), list(obs$a, obs$b), drop=T)
$`1.1`
[1] 1

$`2.2`
[1] 2

$`2.3`
[1] 3

$`3.4`
[1] 4 5

$`3.5`
[1] 6

You can then use this resulting list and find all entries with more
than one value and use this to do your calculations.

On 10/2/06, Florian Jansen [EMAIL PROTECTED] wrote:
 Hi,

 I have a dataframe:

 (obs - data.frame(a=c(1,2,2,3,3,3), b=c(1,2,3,4,4,5), c=1:2))
 attach(obs)

 In reality its about 1 million rows.

 Some of the datasets have same contents in col a and! b like row 4 and 5.
 I want to do some calculations on col c within the duplicated rows and
 merge them afterwards:

 layer - function(x) round((1-prod(1-x/100))*100,0)
 (covnew - aggregate(c, list(a=a, b=b), layer))

 This works fine, but not with 1 mill. rows because of memory space
 limitations.
 So I thought to split the dataframe into the majority of unique rows on
 one hand and all duplicated rows on the other:

 With
 subset(obs, a %in% a[duplicated(a)])
 and !a respectively this works fine for single column comparison.
 This must be also possible for two column comparison, but I can`t get it.

 Thanks
 Florian

 --
 Dr. Florian Jansen
 Geobotany  Nature Conservation
 Institute for Botany and Landscape Ecology
 Ernst-Moritz-Arndt-University
 Grimmer Str. 88
 17487 Greifswald - Germany
 +49 (0)3834 86 4147

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 R-help@stat.math.ethz.ch mailing list
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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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Re: [R] Barplot

2006-10-02 Thread Marc Schwartz (via MN)
On Mon, 2006-10-02 at 11:14 -0400, Mohsen Jafarikia wrote:
 Hello,
 
 I have used the following data to draw my barplot:
 
 BL LRQ
 
 36.351.00   1.92
 36.914.00   0.00
 25.706.00   0.00
 34.383.00   1.92
 05.320.50   0.00
 
  BL-c(36.35, 36.91, 25.70, 34.38, 05.32)
 LR-c(1.00, 4.00, 6.00, 3.00, 0.50)
 Q-(1.92, 0.00, 0.00, 1.92, 0.00)
 
 barplot(dt$LR, main='LR Value',  col='orange', border='black', space=0.05,
 width=(dt$BL), xlab='Length', ylab='LR')
 
  axis(1)
 
 I would like to do the following things that I don't know how to do it:
 
   1)  Writing the value of each 'BL' on my X axis.
 2)  Writing the value of 'Q' on the bottom of  X axis.
 3)  Draw a line on the bars which connects the 'LR' values.
 
  I appreciate your comments.
 
  Thanks,
 Mohsen


I'm not sure if I am getting this completely correct, but is this what
you want?


BL - c(36.35, 36.91, 25.70, 34.38, 5.32)
LR - c(1.00, 4.00, 6.00, 3.00, 0.50)
Q - c(1.92, 0.00, 0.00, 1.92, 0.00)


# Get the bar midpoints in 'mp'
mp - barplot(LR, main='LR Value',  col='orange', border='black',
  space=0.05, width=(BL), xlab='Length', ylab='LR')

# Write the LR and Q values below the bar midpoints
mtext(1, at = mp, text = sprintf(%.1f, LR), line = 1)
mtext(1, at = mp, text = sprintf(%.1f, Q), line = 0)

# Now connect the LR values across the bars
lines(mp, LR)


See ?barplot, ?mtext, ?sprintf and ?lines

HTH,

Marc Schwartz

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[R] How can I generate this numbers

2006-10-02 Thread Ricardo Rios
Hi wizards, I need to know how can I generate this numbers

I have n numbers N1,N2 , Nn  , but  Nn = 1- sum(N1+N2+...+Nn-1) and
sum(N1+N2+..Nn)=1
and N1,N2,..Nn  with 0N1 .

Does somebody know how to generate it ? Some distribution or algorithm.

Thanks in advance.








-- 
Web Page
http://www.geocities.com/ricardo_rios_sv/index.html

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Re: [R] How can I generate this numbers

2006-10-02 Thread Rolf Turner

This sounds so simple it must be a homework problem, no?

cheers,

Rolf Turner
[EMAIL PROTECTED]

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[R] X-axis labels in histograms drawn by the truehist function

2006-10-02 Thread Ravi Varadhan
 

Hi,

 

I had sent this email last week, but received no reply.  So, I am resending
it - please excuse me for the redundant email.

 

I have a simple problem that I would appreciate getting some tips.  I am
using the truehist function within an apply call to plot multiple
histograms.  I can't figure out how to get truehist to use the column names
of the matrix as the labels for the x-axis of the histograms.  

 

Here is a simple example:

 

library(MASS)  # this contains the truehist function

X - matrix(runif(4000),ncol=4)

colnames(X) - c(X1,X2,X3,X4)

par(mfrow=c(2,2))

apply(X, 2, function(x)truehist(x))

 

In this example, I would like the x-labels of the histograms to be X1,
X2, etc.

 

Any help is appreciated.

 

Best,

Ravi

 


---

Ravi Varadhan, Ph.D.

Assistant Professor, The Center on Aging and Health

Division of Geriatric Medicine and Gerontology 

Johns Hopkins University

Ph: (410) 502-2619

Fax: (410) 614-9625

Email: [EMAIL PROTECTED]

Webpage:  http://www.jhsph.edu/agingandhealth/People/Faculty/Varadhan.html

 




 


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Re: [R] X-axis labels in histograms drawn by the truehist function

2006-10-02 Thread Marc Schwartz (via MN)
On Mon, 2006-10-02 at 14:58 -0400, Ravi Varadhan wrote:
  
 Hi,
 
  
 
 I had sent this email last week, but received no reply.  So, I am resending
 it - please excuse me for the redundant email.
 
  
 
 I have a simple problem that I would appreciate getting some tips.  I am
 using the truehist function within an apply call to plot multiple
 histograms.  I can't figure out how to get truehist to use the column names
 of the matrix as the labels for the x-axis of the histograms.  
 
  
 
 Here is a simple example:
 
  
 
 library(MASS)  # this contains the truehist function
 
 X - matrix(runif(4000),ncol=4)
 
 colnames(X) - c(X1,X2,X3,X4)
 
 par(mfrow=c(2,2))
 
 apply(X, 2, function(x)truehist(x))
 
  
 
 In this example, I would like the x-labels of the histograms to be X1,
 X2, etc.
 
  
 
 Any help is appreciated.
 
  
 
 Best,
 
 Ravi

Ravi,

Gabor did reply:

https://stat.ethz.ch/pipermail/r-help/2006-September/114019.html

HTH,

Marc Schwartz

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Re: [R] Barplot

2006-10-02 Thread Mohsen Jafarikia
Thanks for your response. I just have two more questions:
1) I don't know how to write the titles of the LR and Q behind their
lines of values (at the bottom of the graph). I tried to write like
   … text = sprintf(LR%.1f, LR)...
  but it writes 'LR' behind all values while I only want it once at the
beginning of the line while all the LR and Q values are still in the mid
points of bars.

2) I would like a line which connects the mid points of each bar to be
like a density function (or regression) line which is not sharp like what I
have now. I tried to write density in the code but it tells Error in
xy.coords(x, y) : 'x' and 'y' lengths differ
 I appreciate any comment about these questions

Thanks,
Mohsen


On 10/2/06, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:

 On Mon, 2006-10-02 at 11:14 -0400, Mohsen Jafarikia wrote:
  Hello,
 
  I have used the following data to draw my barplot:
 
  BL LRQ
 
  36.351.00   1.92
  36.914.00   0.00
  25.706.00   0.00
  34.383.00   1.92
  05.320.50   0.00
 
   BL-c(36.35, 36.91, 25.70, 34.38, 05.32)
  LR-c(1.00, 4.00, 6.00, 3.00, 0.50)
  Q-(1.92, 0.00, 0.00, 1.92, 0.00)
 
  barplot(dt$LR, main='LR Value',  col='orange', border='black', space=
 0.05,
  width=(dt$BL), xlab='Length', ylab='LR')
 
   axis(1)
 
  I would like to do the following things that I don't know how to do it:
 
1)  Writing the value of each 'BL' on my X axis.
  2)  Writing the value of 'Q' on the bottom of  X axis.
  3)  Draw a line on the bars which connects the 'LR' values.
 
   I appreciate your comments.
 
   Thanks,
  Mohsen


 I'm not sure if I am getting this completely correct, but is this what
 you want?


 BL - c(36.35, 36.91, 25.70, 34.38, 5.32)
 LR - c(1.00, 4.00, 6.00, 3.00, 0.50)
 Q - c(1.92, 0.00, 0.00, 1.92, 0.00)


 # Get the bar midpoints in 'mp'
 mp - barplot(LR, main='LR Value',  col='orange', border='black',
  space=0.05, width=(BL), xlab='Length', ylab='LR')

 # Write the LR and Q values below the bar midpoints
 mtext(1, at = mp, text = sprintf(%.1f, LR), line = 1)
 mtext(1, at = mp, text = sprintf(%.1f, Q), line = 0)

 # Now connect the LR values across the bars
 lines(mp, LR)


 See ?barplot, ?mtext, ?sprintf and ?lines

 HTH,

 Marc Schwartz





-- 
Mohsen Jafarikia
Department of Animal and Poultry Science
University of Guelph
Phone: (519) 824-4120 ext.58353

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[R] sweave2html only for Linux users ?

2006-10-02 Thread Laurent Rhelp
Dear R-List,

I would like to convert my rnw files written with Sweave from LaTeX 
to html. I discovered on the list the following link : 
http://biostat.mc.vanderbilt.edu/twiki/bin/view/Main/SweaveConvert

Is this document only for linux users or I can use it with windose XP ?

Thanks

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Re: [R] X-axis labels in histograms drawn by the truehist function

2006-10-02 Thread Ravi Varadhan
Thank you, Marc and Gabor.  I apologize for having missed Gabor's reply.

Best regards,
Ravi.


---

Ravi Varadhan, Ph.D.

Assistant Professor, The Center on Aging and Health

Division of Geriatric Medicine and Gerontology 

Johns Hopkins University

Ph: (410) 502-2619

Fax: (410) 614-9625

Email: [EMAIL PROTECTED]

Webpage:  http://www.jhsph.edu/agingandhealth/People/Faculty/Varadhan.html

 





-Original Message-
From: Marc Schwartz (via MN) [mailto:[EMAIL PROTECTED] 
Sent: Monday, October 02, 2006 3:25 PM
To: Ravi Varadhan
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] X-axis labels in histograms drawn by the truehist
function

On Mon, 2006-10-02 at 14:58 -0400, Ravi Varadhan wrote:
  
 Hi,
 
  
 
 I had sent this email last week, but received no reply.  So, I am
resending
 it - please excuse me for the redundant email.
 
  
 
 I have a simple problem that I would appreciate getting some tips.  I am
 using the truehist function within an apply call to plot multiple
 histograms.  I can't figure out how to get truehist to use the column
names
 of the matrix as the labels for the x-axis of the histograms.  
 
  
 
 Here is a simple example:
 
  
 
 library(MASS)  # this contains the truehist function
 
 X - matrix(runif(4000),ncol=4)
 
 colnames(X) - c(X1,X2,X3,X4)
 
 par(mfrow=c(2,2))
 
 apply(X, 2, function(x)truehist(x))
 
  
 
 In this example, I would like the x-labels of the histograms to be X1,
 X2, etc.
 
  
 
 Any help is appreciated.
 
  
 
 Best,
 
 Ravi

Ravi,

Gabor did reply:

https://stat.ethz.ch/pipermail/r-help/2006-September/114019.html

HTH,

Marc Schwartz

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[R] R function to compute kappa statistics for two vector

2006-10-02 Thread Philip He
Dear R-user,

Did anybody know how to calculate the kappa statistics of two vectors for
the agreement? for example:

a-c(0,1,0,0,1,0)

b-c(0,1,1,0,0,1)

I know the percent of agreement is 3/6, but how to get the kappa?

[[alternative HTML version deleted]]

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[R] Problem with rbinom

2006-10-02 Thread Alexander Geisler
Hello!

I have the following problem: I calculate a variable called pd in Excel, 
save it as pd.txt, so that it looks like the following:

pd
0.070568471
0.011275136
0.006892258
0.028592432
0.028489582
0.01881913
0.035426606
0.011517305

There were 4857 cases in pd.txt.

After that I start R and load the data through the following command:
daten - read.table(pd.txt, header=T)

Then I want to execute the function rbinom:

rbinom(4857,1,daten)

I get the following error message:
Fehler in rbinom(n, size, prob) : ungültige Argumente
(error in rbinom(n, size, prob) : bad arguments

The problem is daten, because if I excecute rbinom(4857,1,0.5), then it 
works.

So, I have no idea, what the problem could be.

Alex

-- 
Alexander Geisler * Moserhofgasse 36/1 * A-8010 Graz
StV Technische Mathematik | FakV TMTP
email: [EMAIL PROTECTED] | [EMAIL PROTECTED]
phone: +43 650 / 811 61 90

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Re: [R] R function to compute kappa statistics for two vector

2006-10-02 Thread Bruno L. Giordano
Kappa() in library vcd
kappa2() in library irr
ckappa() in library psy
cohen.kappa() in library concord..

Bruno
- Original Message - 
From: Philip He [EMAIL PROTECTED]
To: R-help@stat.math.ethz.ch
Cc: Rebecca Ding [EMAIL PROTECTED]
Sent: Monday, October 02, 2006 5:53 PM
Subject: [R] R function to compute kappa statistics for two vector


 Dear R-user,

 Did anybody know how to calculate the kappa statistics of two vectors for
 the agreement? for example:

 a-c(0,1,0,0,1,0)

 b-c(0,1,1,0,0,1)

 I know the percent of agreement is 3/6, but how to get the kappa?

 [[alternative HTML version deleted]]

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


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Re: [R] sweave2html only for Linux users ?

2006-10-02 Thread Greg Snow


Another approach is to use the Sweave driver in the R2HTML package and
work directly with HTML rather than converting.

Hope this helps,


-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
 

-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Laurent Rhelp
Sent: Monday, October 02, 2006 3:25 PM
To: R-help@stat.math.ethz.ch
Subject: [R] sweave2html only for Linux users ?

Dear R-List,

I would like to convert my rnw files written with Sweave from LaTeX
to html. I discovered on the list the following link : 
http://biostat.mc.vanderbilt.edu/twiki/bin/view/Main/SweaveConvert

Is this document only for linux users or I can use it with windose XP ?

Thanks

__
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http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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Re: [R] R function to compute kappa statistics for two vector

2006-10-02 Thread Peter Dalgaard
Philip He [EMAIL PROTECTED] writes:

 Dear R-user,
 
 Did anybody know how to calculate the kappa statistics of two vectors for
 the agreement? for example:
 
 a-c(0,1,0,0,1,0)
 
 b-c(0,1,1,0,0,1)
 
 I know the percent of agreement is 3/6, but how to get the kappa?

Multiple packages appear to have versions of Cohen's Kappa:

   irr, concord, psy, vcd, e1071

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] Problem with rbinom

2006-10-02 Thread Greg Snow
Using read.table creates a data frame that you store in dataen, rbinom wants a 
vector not a data frame, so try:

 rbinom(4857,1,dataen$pd) 

Or 

 rbinom(4857,1,dataen[[1]])

Hope this helps, 


-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
 

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Alexander Geisler
Sent: Monday, October 02, 2006 4:01 PM
To: r-help@stat.math.ethz.ch
Subject: [R] Problem with rbinom

Hello!

I have the following problem: I calculate a variable called pd in Excel, save 
it as pd.txt, so that it looks like the following:

pd
0.070568471
0.011275136
0.006892258
0.028592432
0.028489582
0.01881913
0.035426606
0.011517305

There were 4857 cases in pd.txt.

After that I start R and load the data through the following command:
daten - read.table(pd.txt, header=T)

Then I want to execute the function rbinom:

rbinom(4857,1,daten)

I get the following error message:
Fehler in rbinom(n, size, prob) : ungültige Argumente (error in rbinom(n, size, 
prob) : bad arguments

The problem is daten, because if I excecute rbinom(4857,1,0.5), then it works.

So, I have no idea, what the problem could be.

Alex

--
Alexander Geisler * Moserhofgasse 36/1 * A-8010 Graz StV Technische Mathematik 
| FakV TMTP
email: [EMAIL PROTECTED] | [EMAIL PROTECTED]
phone: +43 650 / 811 61 90

__
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Re: [R] How can I generate this numbers

2006-10-02 Thread Ricardo Rios
Hi Rolf Turner, I have a  statistical model, it model need this
numbers for calculate the probability. This numbers must be random.

For example I need that
magicfunction(3)
[1] 0.3152460 0.5231614 0.1615926
magicfunction(3)
[1]  0.6147933 0.3122999  0.0729068

but the argument of the function is arbitrary , does somebody
know if exist this function in R?









On 10/2/06, Rolf Turner [EMAIL PROTECTED] wrote:

 This sounds so simple it must be a homework problem, no?

 cheers,

 Rolf Turner
 [EMAIL PROTECTED]



-- 
Web Page
http://www.geocities.com/ricardo_rios_sv/index.html

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Re: [R] fMultivar rollMax question

2006-10-02 Thread Diethelm Wuertz
Omar Lakkis wrote:

I am using fMultivar under R 2.2.1 on a Debian linux box. Could
someone, please, explain to me why there are two trailing NAs in the
last statement in the code beow?


  

library(fMultivar)
x - 1:20
rollMax(x, n=3)


 [1]  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19 20
  

rollMax(x, n=2)


 [1]  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19 20
  

rollMax(x, n=1)


 [1]  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19 20 NA NA
  


The rolling functions were build for n  1, which is unfortunately not 
mentioned in the
help page. For n=1 you can just call: apply(x, 1, max)

If we want rolling functions which also work for n=1 we have to modify the
code in the following way:

replace in the function rollFun() the following lines

for (i in 2:n) {
   start = start + 1
   end = end + 1
m = cbind(m, x[start:end])
   }

with

if (n  1) {
for (i in 2:n) {
start = start + 1
end = end + 1
m = cbind(m, x[start:end])
}
} else if (n == 1) {
m = matrix(m)
}


Regards DW




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Re: [R] How can I generate this numbers

2006-10-02 Thread Rolf Turner
Ricardo Rios wrote:

 Hi Rolf Turner, I have a  statistical model, it model need this
 numbers for calculate the probability. This numbers must be random.
 
 For example I need that
 magicfunction(3)
 [1] 0.3152460 0.5231614 0.1615926
 magicfunction(3)
 [1]  0.6147933 0.3122999  0.0729068
 
 but the argument of the function is arbitrary , does somebody
 know if exist this function in R?

As far as I know, no such function exists in R, but
it would be totally trivial to write one, if that's
what you really want.

However the question you pose makes little sense to me.  If
you really have a ``statisical model'' then there must be
some marginal distribution for each of the probabilities (I
*assume* They are probabilities) going into the sequence
which you wish to sum to 1.

You mention no such distribution.

To generate such a sequence with an arbitray marginal
distribution is so trivial that it does not bear discussing.

If you really can't see how to do this, then you probably
shouldn't be messing about with ``statistical models''.

You did not explicitly deny that this is a homework problem.

I still suspect that it is.

cheers,

Rolf Turner

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[R] install packages question

2006-10-02 Thread Leeds, Mark \(IED\)
I am at a new job where my sys admin installed R in linux and it does
run when I log in as a user.  I am on linux 2.1.2 but i'm not sure if
it''s redhat etc ( but i doubt this matters for my question ).
 
The alias put in my .envfile ( for the kshell ) is
 
R =
/ms/dev/fsf/R/2.0.0/install/.exec/ia32.linux.2.4.lib6/lib/R/bin/exec/R
 
and my R_HOME is
/ms/dev/fsf/R/2.0.0/install/.exec/ia32.linux.2.4.lib6/lib/R
 
So now, I am trying to install specific packages ( I can't use
install.packages because my linux doesn't have an internet connection )
, I think I found the right documentation 
( pg 16 of R installation and administration ) and I set my R_LIBS
varaible appropriately  but my  R CMD INSTALL command is not working. It
just drops the  CMD and gives ARGUMENT CMD __ignored__ )  and invokes R
by itself.  I also tried R CMD BATCH testfile and similarly it dropped
the CMD and the BATCH and just invoked R also
 
Does anyone know what I need to change ( probably in my .envfile ) so
that R knows what these commands mean ?  I am familar with installing R
( binary ) and various packages 
on windows but I am very unfamilar with Linux.
 
I think if I can get this fixed, I might be able to install the specific
packages I need because the instructions on pg 16 are clear. Thanks a
lot.


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Re: [R] How can I generate this numbers

2006-10-02 Thread Ben Bolker
Ricardo Rios alfilnegro.sv at gmail.com writes:

 
 Hi Rolf Turner, I have a  statistical model, it model need this
 numbers for calculate the probability. This numbers must be random.
 
 For example I need that
 magicfunction(3)
 [1] 0.3152460 0.5231614 0.1615926
 magicfunction(3)
 [1]  0.6147933 0.3122999  0.0729068
 
 but the argument of the function is arbitrary , does somebody
 know if exist this function in R?
 
 On 10/2/06, Rolf Turner rolf at erdos.math.unb.ca wrote:
 
  This sounds so simple it must be a homework problem, no?
 
  cheers,
 
  Rolf Turner
  rolf at math.unb.ca
 

  Hmmm.  You're basically asking for random probabilities of
a composition.  There are many possible distributions (and it's
hard to imagine that it doesn't matter which one you choose,
or what it's parameters are!
you may need to think about this some more), e.g. additive
log ratio or Dirichlet.  Dirichlet (the multivariate analogue
of the beta distribution) is most common and simplest, although
not very flexible.  rdirichlet() exists in several different
packages: try RSiteSearch(rdirichlet).

(actually, for what you're looking for

magicfunction - function(n) {
   r - runif(n)
   r/sum(r)
}

should satisfy your needs -- you can substitute any non-negative
probability distribution for runif -- but, again, you may need
to think more about what you're doing ...)

  good luck
Ben Bolker

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Re: [R] How can I generate this numbers

2006-10-02 Thread roger koenker
Try:

  rsimplex - function(n){
u - diff(sort(runif(n)))
c(u,1-sum(u))
}

On Oct 2, 2006, at 5:43 PM, Rolf Turner wrote:

 Ricardo Rios wrote:

 Hi Rolf Turner, I have a  statistical model, it model need this
 numbers for calculate the probability. This numbers must be random.

 For example I need that
 magicfunction(3)
 [1] 0.3152460 0.5231614 0.1615926
 magicfunction(3)
 [1]  0.6147933 0.3122999  0.0729068

 but the argument of the function is arbitrary , does somebody
 know if exist this function in R?

   As far as I know, no such function exists in R, but
   it would be totally trivial to write one, if that's
   what you really want.

   However the question you pose makes little sense to me.  If
   you really have a ``statisical model'' then there must be
   some marginal distribution for each of the probabilities (I
   *assume* They are probabilities) going into the sequence
   which you wish to sum to 1.

   You mention no such distribution.

   To generate such a sequence with an arbitray marginal
   distribution is so trivial that it does not bear discussing.

   If you really can't see how to do this, then you probably
   shouldn't be messing about with ``statistical models''.

   You did not explicitly deny that this is a homework problem.

   I still suspect that it is.

   cheers,

   Rolf Turner

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 guide.html
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[R] Kendall for Copula

2006-10-02 Thread marta dilascio
Somebody know what is the package in which I can find the association measures 
(like Kendall's Tau and Spearman's Rho) for a copula object (bivariate 
copulas)??
   
  Thanks a lot.
   
  Marta Di Lascio

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[R] a question regarding 'lrm'

2006-10-02 Thread Tao Shi
Hi List,

I don't understand why 'lrm' doesn't recognize the '~.' formula.  I'm pretty 
sure it was working before. Please see below:

I'm using R2.3.0, WinXP, Design 2.0-12

thanks,
...Tao

 dat - data.frame(y=factor(rep(1:2,each=50)), x1=rnorm(100), x2=rnorm(100), 
 x3=rnorm(100))
 lrm(y~., data=dat, x=T, y=T)
Error in terms.formula(formula, specials = strat) : 
'.' in formula and no 'data' argument
 lrm(y~x1+x2+x3, data=dat, x=T, y=T)

Logistic Regression Model

lrm(formula = y ~ x1 + x2 + x3, data = dat, x = T, y = T)


Frequencies of Responses
 1  2 
50 50 

   Obs  Max Deriv Model L.R.   d.f.  P  CDxy
  Gamma 
   100  1e-08   3.61  3 0.3066  0.594  0.187
  0.188 
 Tau-a R2  Brier 
 0.095  0.047  0.241 

  Coef S.E.   Wald Z P 
Intercept -0.05224 0.2071 -0.25  0.8009
x1-0.30699 0.1952 -1.57  0.1159
x2 0.08093 0.2171  0.37  0.7093
x3 0.21450 0.2247  0.95  0.3398

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[R] RGL 'front' upwards default in rendering image

2006-10-02 Thread Joe Byers
The documentation for surface3d and rgl.surface in the package RGL states
'surface3d' always draws the surface with the `front' upwards
  (i.e. towards higher 'z' values).  This can be used to render the
  top and bottom differently; see 'rgl.material' and the example
  below.

Is there a way to override this default?  I have search all the related 
methods help and the documents on RGL's website.

Thanx
Joe

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Re: [R] RGL 'front' upwards default in rendering image

2006-10-02 Thread Duncan Murdoch
Joe Byers wrote:
 The documentation for surface3d and rgl.surface in the package RGL states
 'surface3d' always draws the surface with the `front' upwards
   (i.e. towards higher 'z' values).  This can be used to render the
   top and bottom differently; see 'rgl.material' and the example
   below.

 Is there a way to override this default?  I have search all the related 
 methods help and the documents on RGL's website.
There are lots of ways to override it:  as the docs say, rgl.surface is 
more flexible than surface3d, and you can draw triangles or quads 
arbitrarily.  What sort of thing do you want to do?

Duncan Murdoch

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[R] help: Error: cannot allocate vector of size 12079 Kb

2006-10-02 Thread Baoqiang Cao
Dear All,

I'm running the latest R on WinXP by using Rgui.exe 
--max-mem-size=3Mb . After read in a huge data file to a data 
matrix, I tried to get a subset of the data matrix but failed with:
Error: cannot allocate vector of size 12079 Kb
Any tips to get out of it?

If helps,
  memory.limit()
[1] 3145728000
  memory.size()
[1] 842735624

Thanks!

Best,
  Cao

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