[EMAIL PROTECTED] wrote:
I have created a list of matrices using sapply or lapply and wish to
extract each of the matrices as a matrix. Some of them are 2x2, 3x3, etc.
I can do this one at a time as:
M1-as.matrix(D[[1]])
How can repeat this process for an unknown number of entries in
I have created a list of matrices using sapply or lapply and wish to extract
each of the matrices as a matrix. Some of them are 2x2, 3x3, etc.
I can do this one at a time as:
M1-as.matrix(D[[1]])
How can repeat this process for an unknown number of entries in the list? In
other words, how
You get the number of list elements with length(D),
the dimensions of M1 with dim(M1)
see help with:
?dim
?length
Hope this helps...
I have created a list of matrices using sapply or lapply and wish to
extract each of the matrices as a matrix. Some of them are 2x2, 3x3, etc.
I can do this
If they are already a matrix in the list, then you don't have to use
'as.matrix'; you can just say:
M1 - D[[1]]
Now the question is, what do you mean by how do you index M1? Do you
want to go through the list applying a function to each matrix? If
so, then just 'lapply'. For example, to get
Hello,
in using vector() we can create a vector and fill in like this
v - vector()
v - c(v,2)
v - c(v,c(5,10,23))
but I wanna know if it's possible to do the same with the list I don't fond how?
Can you help me?
Thanks.
'c' also works with lists:
a=list(1,2,3)
b=list(1,2,3)
c(a,b)
[[1]]
[1] 1
[[2]]
[1] 2
[[3]]
[1] 3
[[4]]
[1] 1
[[5]]
[1] 2
[[6]]
[1] 3
On 7/18/07, elyakhlifi mustapha [EMAIL PROTECTED] wrote:
Hello,
in using vector() we can create a vector and fill in like this
v - vector()
v -
hello,
I wanna know how to create a list of list if it's possible and if it isn't
possible how to do without.
thanks.
_
[[alternative HTML version deleted]]
There's no special method, just create a list in the usual way. For example:
l1-list(a=letters[1:5],b=letters[6:10])
l1
$a
[1] a b c d e
$b
[1] f g h i j
l2-list(c=LETTERS[1:5],d=LETTERS[6:10])
l2
$c
[1] A B C D E
$d
[1] F G H I J
l3-list(l1,l2)
l3
[[1]]
[[1]]$a
[1] a b c d e
[[1]]$b
dissection of
uncertainties, a surgery of suppositions. ~M.J.Moroney
-Oorspronkelijk bericht-
Van: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Namens elyakhlifi mustapha
Verzonden: woensdag 6 juni 2007 10:59
Aan: R-help@stat.math.ethz.ch
Onderwerp: [R] list
hello,
I wanna know how
--- elyakhlifi mustapha [EMAIL PROTECTED]
wrote:
hello,
I wanna know how to create a list of list if it's
possible and if it isn't possible how to do without.
thanks.
Why? The question is not clear and could mean several
things. Can you explain a bit?
Hello R-ologists,
Imagine you have a list list like so:
list
[[1]]
[1] IPI00776145.1 IPI00776187.1
[[2]]
[1] Something IPI00807764.1 IPI00807887.1
[[3]]
[1] IPI00807764.1
[[4]]
[1] Somethingelse
What I need to achieve is a filtered list list2 like so:
list2
[[1]]
[1] IPI00776145.1
[[2]]
3:33 PM
Subject: [R] List filtration
Hello R-ologists,
Imagine you have a list list like so:
list
[[1]]
[1] IPI00776145.1 IPI00776187.1
[[2]]
[1] Something IPI00807764.1 IPI00807887.1
[[3]]
[1] IPI00807764.1
[[4]]
[1] Somethingelse
What I need to achieve is a filtered list list2
On Thu, 2007-02-22 at 15:33 +0100, Johannes Graumann wrote:
Hello R-ologists,
[snip]
So:
- if sublist-entry 1 start with ^IPI make it the list-entry.
- otherwise chose the first ^IPI sublist-entry present.
- delete the list-entry if not ^IPI sublist-entry present.
One way to do it would
Graumann [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Thursday, February 22, 2007 3:33 PM
Subject: [R] List filtration
Hello R-ologists,
Imagine you have a list list like so:
list
[[1]]
[1] IPI00776145.1 IPI00776187.1
[[2]]
[1] Something IPI00807764.1 IPI00807887.1
[[3]]
[1
Hi Folks,
I need to extract the list of all my data frame objects. With objects() I can
list all objects and was hoping to use something like the following:
objects()[is.data.frame(objects())] to extracts all my objects that are data
frame...
What am I doing wrong?
Thanks - Tim
try something like the following (untested):
objs - ls()
sapply(objs, function(obj) inherits(get(obj), data.frame))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35,
Hi,
Sorry for the question, I know it should be basic knowledge but I'm
struggling for two hours now.
How do I select only the first entry of each list member and ignore the
rest?
So for
$121_at
-113691170
$1255_g_at
42231151
$1316_at
35472685 35472588
Is this what you want?
x - list(a=1:3, b=30:34, c=40:35)
x
$a
[1] 1 2 3
$b
[1] 30 31 32 33 34
$c
[1] 40 39 38 37 36 35
lapply(x,'[', 1)
$a
[1] 1
$b
[1] 30
$c
[1] 40
unlist(lapply(x,'[', 1))
a b c
1 30 40
On 9/29/06, Benjamin Otto [EMAIL PROTECTED] wrote:
Hi,
Sorry for the
You need one of the apply family of functions.
?sapply
tmp - list(a=1:2, b=3:5, c=5, dd=numeric(0), e=1:8)
sapply(tmp, function(x) x[1])
a b c dd e
1 3 5 NA 1
__
R-help@stat.math.ethz.ch mailing list
Does this do what you want?
x - list(1,2,3:7,8,9:10)
sapply(x, function(xx) xx[1])
[1] 1 2 3 8 9
-- Tony Plate
Benjamin Otto wrote:
Hi,
Sorry for the question, I know it should be basic knowledge but I'm
struggling for two hours now.
How do I select only the first entry
Hi, I have a situation where I have a list of lists. Each list can
contain elements of different types (but each one will be a scalar) say
of double, integer or character.
However the elements of each list are always in the same order:
x - list('a', 1, 2)
y - list('b', 3, 4)
z - list('c', 5, 6)
On Fri, 2006-08-18 at 16:44 -0400, Rajarshi Guha wrote:
Hi, I have a situation where I have a list of lists. Each list can
contain elements of different types (but each one will be a scalar) say
of double, integer or character.
However the elements of each list are always in the same order:
I am working with a large data set of arrivals, for each day I have
aggregated the arrivals into hrs (1-24) via: apply(x,2,table). On some days
there are zero arrivals during some hours of the day, this leaves me with
(I believe) a list of vectors of differnt lengths (see below).
[[4]]
1 2 3
, 2006 5:22 PM
Subject: [R] list to balanced array
I am working with a large data set of arrivals, for each day I have
aggregated the arrivals into hrs (1-24) via: apply(x,2,table). On
some days
there are zero arrivals during some hours of the day, this leaves me
with
(I believe) a list
Sorry, but your posting is being returned to you.
The list is temporarily restricted.
If your post is substantive, dealing with SSSI issues, it will be
forwarded to the list. If it is intended as private email, it
will be forwarded accordingly.
If you wish to subscribe to SSSITALK, send a
Hello,
I discussed the following problem on the great useR conference with
several people and wonder if someone of you knows a more elegant (or
more common ?) solution than the one below.
The problem:
I have several sets of interrelated functions which should be compared.
The
Martin Morgan wrote:
Here's another way:
makeSolver - function() {
f1 - function(x, K) K - x
f2 - function(x, r, K) r * x * f1(x, K)
function() f1(3,4) + f2(1,2,3)
}
solverB - makeSolver()
solverB()
makeSolver (implicitly) creates an environment, installs f1 and f2
into it,
Hi,
this is probably the easiest thing to do but I manage
not finding the answer:
I have a list with matrices of exact same format and
headers. Now I would like to transform the list into
an normal array. What is the proper way to do this?
as.array changes the entire format and right now I
only
: [R] List to Array
Hi,
this is probably the easiest thing to do but I manage
not finding the answer:
I have a list with matrices of exact same format and
headers. Now I would like to transform the list into
an normal array. What is the proper way to do this?
as.array changes the entire
Please supply some test data and the expected answer
since its not clear what is desired here.
On 4/5/06, Werner Wernersen [EMAIL PROTECTED] wrote:
Hi,
this is probably the easiest thing to do but I manage
not finding the answer:
I have a list with matrices of exact same format and
headers.
Werner Wernersen pensterfuzzer at yahoo.de writes:
Hi,
this is probably the easiest thing to do but I manage
not finding the answer:
I have a list with matrices of exact same format and
headers. Now I would like to transform the list into
an normal array. What is the proper way to do
On 4/5/06, Ben Bolker [EMAIL PROTECTED] wrote:
Werner Wernersen pensterfuzzer at yahoo.de writes:
Hi,
this is probably the easiest thing to do but I manage
not finding the answer:
I have a list with matrices of exact same format and
headers. Now I would like to transform the list
Oh yes, I should give an example:
m - matrix(1:6,nrow=3)
L - list(m,m)
Output of L:
[[1]]
[,1] [,2]
[1,]14
[2,]25
[3,]36
[[2]]
[,1] [,2]
[1,]14
[2,]25
[3,]36
I would like to transform L to and array looking like
this:
, , 1
[,1]
Grothendieck [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Wednesday, April 05, 2006 3:55 PM
Subject: Re: [R] List to Array
Oh yes, I should give an example:
m - matrix(1:6,nrow=3)
L - list(m,m)
Output of L:
[[1]]
[,1] [,2]
[1,]14
[2,]25
[3,]36
[[2
/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
- Original Message -
From: Werner Wernersen [EMAIL PROTECTED]
To: Gabor Grothendieck [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Wednesday, April 05, 2006 3:55 PM
Subject: Re: [R] List to Array
Oh yes, I
: Wednesday, April 05, 2006 3:55 PM
Subject: Re: [R] List to Array
Oh yes, I should give an example:
m - matrix(1:6,nrow=3)
L - list(m,m)
Output of L:
[[1]]
[,1] [,2]
[1,]14
[2,]25
[3,]36
[[2]]
[,1] [,2]
[1,]14
[2
Hello,
I have a list (mode and class are list) in R that is many elements long and of
the form:
length(list)
[1] 5778
list[1:4]
$ID1
[1] num1
$ID2
[1] num2 num3
$ID3
[1] num4
$ID4
[1] NA
I'd like to convert the $ID2 value to be in one element rather than in two. It
shows up as c(\num2\,
LD == Liz Dem [EMAIL PROTECTED] writes:
LD I have a list (mode and class are list) in R that is many elements long
and of the form:
length(list)
LD [1] 5778
list[1:4]
LD $ID1
LD [1] num1
LD $ID2
LD [1] num2 num3
LD $ID3
LD [1] num4
LD $ID4
LD
Thx for the hint...
the div - factor(c(1,1,1,2,2)) did exactly what I was expecting...
Stéphane.
Le Mardi 31 Janvier 2006 15:50, Gabor Grothendieck a écrit :
Your post seems to be messed up but I will assume you have a
5 column data frame and the questino is how to run f on the first
three
Hi,
I would like to perform computations on some variables belonging to the same
dataframe. For instance my data frame has the following shape:
toto1 toto2 toto3 toto4 toto5
1 1 2 3 4 5
2 6 7 8 9 10
I would like to
Your post seems to be messed up but I will assume you have a
5 column data frame and the questino is how to run f on the first
three columns and separately on the last two. I think the
easiest is just the following where I have used the builtin iris
data set where I have assumed that the
This worked great but I'm a bit confused about how to access the names
(keys?) of a list in a loop, and why this is failing for me:
I want to cross the entries in mylist (like entry0001) with the
columns of a dataframe ginput:
$entry0001
[1] AB0032 CF32134 DF34334
$entry0002
[1] AB0033
On 27 Jan 2006, [EMAIL PROTECTED] wrote:
But mylist$entrylabel is not working inside the loop.
'$' doesn't evaluate its argument. You want mylist[[entrylabel]].
I haven't been able to found my way with R lists, maybe because I'm
comparing them with perl's hashes.
R lists do have names, but
Hi all,
I have a file of this kind:
entry0001:AB0032,CF32134,DF34334
entry0002:AB0033
entry0003:AB0032,CF32134,DF34334,DD343434,DD34222
entry0004:AB0032,CF32134
And I would like to read it into something like a hash, so that I can
then loop over it by keys and values.
I wonder which would be
The following might be what you want (replace clipboard with your
filename):
mylist - strsplit(readLines(clipboard), :)
nm - sapply(mylist, [, 1)
mylist - lapply(mylist, [, -1)
names(mylist) - nm
mylist - lapply(mylist, function(s) strsplit(s, ,)[[1]])
mylist
$entry0001
[1] AB0032 CF32134
This also depends on which field you are interested in, for example
MEDSTATS (http://tinyurl.com/bwha8)
ED-STATS (http://lists.psu.edu/archives/edstat-l.html)
and a few more http://tinyurl.com/a8wo4
Regards, Adai
On Fri, 2005-09-30 at 07:32 -0500, Marc Schwartz wrote:
On Thu, 2005-09-29
Indeed.
I was not aware of the additional non-usenet statistics Google Groups.
Some familiar names on the MEDSTATS list... :-)
Thanks Adai.
Marc
On Sat, 2005-10-01 at 18:17 +0100, Adaikalavan Ramasamy wrote:
This also depends on which field you are interested in, for example
MEDSTATS
Dear All,
How can I can to know a mail list , to speak about
exclusively statistic. Thanks.
__
Espacio para todos tus mensajes, antivirus y antispam ¡gratis!
__
R-help@stat.math.ethz.ch mailing list
There is some discussion and data sources of the volume of email on
the list in:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/27532.html
On 9/30/05, José Raul Capablanca [EMAIL PROTECTED] wrote:
Dear All,
How can I can to know a mail list , to speak about
exclusively statistic. Thanks.
José Raul Capablanca wrote:
Dear All,
How can I can to know a mail list , to speak about
exclusively statistic. Thanks.
Hola Jose,
If you mean a list devoted exclusively to statistics
(Si desea una lista solo para la statistica)
http://www.jiscmail.ac.uk/lists/allstat.html
(y una lista
On 30-Sep-05 Jim Lemon wrote:
José Raul Capablanca wrote:
Dear All,
How can I can to know a mail list , to speak about
exclusively statistic. Thanks.
Hola Jose,
If you mean a list devoted exclusively to statistics
(Si desea una lista solo para la statistica)
On Thu, 2005-09-29 at 23:47 -0500, José Raul Capablanca wrote:
Dear All,
How can I can to know a mail list , to speak about
exclusively statistic. Thanks.
If you have access to Usenet either via an NNTP server or via Google
Groups, there are three principal groups for general statistics
In this simple function, how can I pass strings for index and column names
to the function? I've posted this type of question before and received no
response.
Maybe this example will be easier to understand and troubleshoot.
ds - function(myds, vec) {myds[[vec]]*2}
ds1 - c(X=list(1:10),
[EMAIL PROTECTED] wrote:
In this simple function, how can I pass strings for index and column names
to the function? I've posted this type of question before and received no
response.
Maybe this example will be easier to understand and troubleshoot.
ds - function(myds, vec)
I'm not sure how to best explain what I am after but here goes. I have a data
frame with 2 geographical factors. One is the major region the other is the
component regions.
I am trying to process all the regions at the same time without using for. So
I need (think, I do) a list of matrices
-Help (E-mail)
Subject: [R] List of tables rather than an extra dimension in
the table
or (l)apply(xtabs)
I'm not sure how to best explain what I am after but here
goes. I have a data frame with 2 geographical factors. One is
the major region the other is the component regions.
I am
)
{
set.seed(j+1+(i-1)*6)
r-rnorm(1)
ss-ss+r
}
list(ss=ss)
}
}
check.1-z1(3)
check.1
the results is:
$ss
[1] -0.01516304
what i want is something that looks like this:
j=1
$ss
[1] -2.213343
j=2
$ss
[1] -2.904235
j=3
$ss
[1] -0.01516304
i know that i could use
such that there are no loops. but lets leave the
loops in for now.)
z1-function(w)
{
for (i in 1:w)
{
set.seed(i+6)
ss-0
for (j in 1:5)
{
set.seed(j+1+(i-1)*6)
r-rnorm(1)
ss-ss+r
}
list(ss=ss)
}
}
check.1-z1(3)
check.1
)
{
set.seed(j+1+(i-1)*6)
r-rnorm(1)
ss-ss+r
}
list(ss=ss)
}
}
check.1-z1(3)
check.1
the results is:
$ss
[1] -0.01516304
what i want is something that looks like this:
j=1
$ss
[1] -2.213343
j=2
$ss
[1] -2.904235
j=3
$ss
[1] -0.01516304
i know that i could use
)
ss-ss+r
}
list(ss=ss)
}
}
check.1-z1(3)
check.1
the results is:
$ss
[1] -0.01516304
what i want is something that looks like this:
j=1
$ss
[1] -2.213343
j=2
$ss
[1] -2.904235
j=3
$ss
[1] -0.01516304
i know that i could use the print command. (see z2)
z2
Re-Hello frederic,
Don't worry, i have the same english speaking problem, here is what i
suggest :
n - natScan()
natScan - function(){
cat(\n)
cat(Give me a natural (everything after the '.' will be ignored)\n)
n - scan(,
On Mon, 27 Dec 2004 03:18:53 -0800 (PST)
Frederic renaud [EMAIL PROTECTED] wrote:
Hello
I've another question :-)
I would like to transform a list to a integer.
I must be sure that the number entered by the user is
an integer! Thus, I've made :
repeat{
cat(Effectif des populations
Hello all,
As a general programming question I can't seem to figure out how to make
a list of lists in R.
As matrices won't work as they have to be rectangular.
I am sure that there is an easy solution but...
the specific situation is this:
- I have created a Tukey confidence interval table and
From: Karla Sartor
Hello all,
As a general programming question I can't seem to figure out
how to make
a list of lists in R.
As matrices won't work as they have to be rectangular.
I am sure that there is an easy solution but...
the specific situation is this:
- I have created a
Is the following more like what you want:
a=c(1,1,1,1,1) # generate the first list
b=c(2,2,2)# generate a second list
d=list(a,b)# make a list of a and b
(
e=c(d,a)
)
[[1]]
[1] 1 1 1 1 1
[[2]]
[1] 2 2 2
[[3]]
[1] 1
[[4]]
[1] 1
Hi all,
there is environment-list coercion, i.e. as.list.environment.
Is there any list-environment coercion?
thank you.
--
Valery.
__
[EMAIL PROTECTED] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 09, 2004 4:56 PM
Subject: [R] list - environment coercion
Hi all,
there is environment-list coercion, i.e. as.list.environment.
Is there any list-environment coercion?
thank you.
--
Valery.
__
[EMAIL PROTECTED
Greetings R community,
I am curious about the following behaviour: if I define a factor, and
then store a subset of it in a list, the stored version seems to drop
levels that were not included in the subset. E.g. ..
mask - c(T, F)
grp.1 - factor(c(1,2))
list(grp.1)
[[1]]
[1] 1 2
Levels: 1 2
Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Andrew Robinson
Sent: Tuesday, November 09, 2004 19:44 PM
To: R-Help Discussion
Cc: Andrew Robinson
Subject: [R] List seems to drop empty levels of factors when containing
them
Greetings R community,
I am curious about
Andrew Robinson wrote:
Greetings R community,
I am curious about the following behaviour: if I define a factor, and
then store a subset of it in a list, the stored version seems to drop
levels that were not included in the subset. E.g. ..
mask - c(T, F)
grp.1 - factor(c(1,2))
list(grp.1)
[[1]]
PM
To: R-Help Discussion
Cc: Andrew Robinson
Subject: [R] List seems to drop empty levels of factors when containing
them
Greetings R community,
I am curious about the following behaviour: if I define a factor, and
then store a subset of it in a list, the stored version seems to drop
Sorry if this is a question more on regular expressions. I am dealing
with several files which have been badly named. For example the files
are given either the extensions txt, TXT or Txt. I wish to select all
those files ending with 'txt' ignoring case.
Here is how I would do it in bash (Redhat
On Thu, 4 Nov 2004, Adaikalavan Ramasamy wrote:
Sorry if this is a question more on regular expressions. I am dealing
with several files which have been badly named. For example the files
are given either the extensions txt, TXT or Txt. I wish to select all
those files ending with 'txt'
Thanks to Sundar Dorai-Raj, Prof. Ripley and Berton Gunter for the
solution. I think I will take Prof. Ripley's suggestion and stick with
my initial solution for code readability but I am sure the regexp stuff
will come handy next time.
On Thu, 2004-11-04 at 15:10, Prof Brian Ripley wrote:
On
Hi
Is there any function to get the name of the components of a given list
object?
ok.
[[alternative HTML version deleted]]
__
[EMAIL PROTECTED] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
names() is what you want, if i understand your question correctly.
cheers,
robert
-Original Message-
From: Leonardo L Miceli [mailto:[EMAIL PROTECTED]
Sent: Friday, October 29, 2004 3:22 PM
To: [EMAIL PROTECTED]
Subject: [R] R list
Hi
Is there any function to get the name
Yes, names().
Andy
From: Leonardo L Miceli
Hi
Is there any function to get the name of the components of a
given list
object?
ok.
[[alternative HTML version deleted]]
__
[EMAIL PROTECTED] mailing list
What about names() ?
Giovanni
Date: Fri, 29 Oct 2004 11:21:35 -0300
From: Leonardo L Miceli [EMAIL PROTECTED]
Sender: [EMAIL PROTECTED]
Cc:
Precedence: list
Hi
Is there any function to get the name of the components of a given list
object?
ok.
[[alternative HTML
It seems to me that \concept{} is simply another code for My keyword is
your search term. I do not consider myself to be one of the better
informed users of R, yet the frequency with which I resort to a full text
search is less than once a month. For such an infrequent task, I find it no
problem
PROTECTED]
Sent: Friday, September 10, 2004 5:26 AM
To: Jonathan Baron
Cc: Adaikalavan Ramasamy; John Fox; R-help; 'Berton Gunter'
Subject: Re: [R] Proposal for New R List: Criticism? Comments?
On Fri, 10 Sep 2004, Jonathan Baron wrote:
On 09/10/04 03:54
-Original Message-
From: Martin Maechler [mailto:[EMAIL PROTECTED]
Sent: Friday, September 17, 2004 7:57 AM
To: John Fox
Cc: 'R-help'
Subject: RE: [R] Proposal for New R List: Criticism? Comments?
Hi John et al.
I'm coming late to this thread (because of vacation),
JohnF
On 09/10/04 03:54, Adaikalavan Ramasamy wrote:
There is another issue to be considered. Currently you need to have the
relevant packages installed before help.search() bring it up. My work
around this is to install all available packages just in case the
function I need is nestled in some
On Fri, 10 Sep 2004, Jonathan Baron wrote:
On 09/10/04 03:54, Adaikalavan Ramasamy wrote:
There is another issue to be considered. Currently you need to have the
relevant packages installed before help.search() bring it up. My work
around this is to install all available packages just in case
, September 10, 2004 5:26 AM
To: Jonathan Baron
Cc: Adaikalavan Ramasamy; John Fox; R-help; 'Berton Gunter'
Subject: Re: [R] Proposal for New R List: Criticism? Comments?
On Fri, 10 Sep 2004, Jonathan Baron wrote:
On 09/10/04 03:54, Adaikalavan Ramasamy wrote:
There is another issue
Just finished updating and installing new packages from CRAN and
BioConductor (including annotation data) and am happy to say that my R
has just exceeded the 1 GB mark.
On Fri, 2004-09-10 at 10:11, Jonathan Baron wrote:
On 09/10/04 03:54, Adaikalavan Ramasamy wrote:
There is another issue to
Folks:
I would like to propose a new R list, tentatively labeled r-contents. I wish
to briefly explain the purpose and format here and solicit public comments,
pro or con, so feel free to criticize or suggest a better name and other
improvements or alternatives.
R presently consists of a suite
I think that a lot of posts on r-help are exactly of the form you
suggest: How do I do X? Answer: Use Y. (Or maybe, Use Y.
And next time RTFM. But so what. The answer is still there.)
Often, when the answer is not of that form, the question is
unclear. In other cases, the questioner is
AM
To: [EMAIL PROTECTED]
Subject: [R] Proposal for New R List: Criticism? Comments?
Folks:
I would like to propose a new R list, tentatively labeled
r-contents. I wish to briefly explain the purpose and format
here and solicit public comments, pro or con, so feel free to
criticize
White, Charles E WRAIR-Wash DC wrote:
It is frustrating to see the labels I want in the dimensions of a list but not be able to extract those labels into titles for plots generated from component objects. If someone could set me straight, I would appreciate it. For your amusement, I have provided
My goal is more efficient code for something I anticipate doing a lot.
My example code from my first message works because I insert a seemingly
redundant recording of Dose Treatment in the list generated in the
by command. Since Dose Treatment are already recorded in the
dimensions of the list,
It is frustrating to see the labels I want in the dimensions of a list but not be able
to extract those labels into titles for plots generated from component objects. If
someone could set me straight, I would appreciate it. For your amusement, I have
provided an example of the Byzantine code I
R-help,
I have a list of several data frames.
I want to compute the rowSums of the columns of these data frames but first one.
Something like this
lapply(my.list,rowSums)
Thank you
Luis Ridao Cruz
Fiskirannsóknarstovan
Nóatún 1
P.O. Box 3051
FR-110 Tórshavn
Faroe
From: Luis Rideau Cruz
R-help,
I have a list of several data frames.
I want to compute the rowSums of the columns of these data
frames but first one.
Something like this
lapply(my.list,rowSums)
You're almost there:
lapply(my.list, function(x)
Luis Rideau Cruz wrote:
R-help,
I have a list of several data frames.
I want to compute the rowSums of the columns of these data frames but first one.
... but first data.frame or but first column?
but first data.frame:
lapply(my.list[-1], rowSums)
but first column:
lapply(my.list, function(x)
Hi all,
I have the folowing frame(there are more columns than shown),
1 2 34 5
Year Total TusWhi Norw
1994 1.00 1830 0 355
1995 1.00 0 00
1995 1.00 0
Message -
From: Luis Rideau Cruz [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, July 27, 2004 2:22 PM
Subject: [R] list problem
Hi all,
I have the folowing frame(there are more columns than shown),
1 2 34 5
Year Total Tus
Message -
From: Luis Rideau Cruz [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, July 27, 2004 2:22 PM
Subject: [R] list problem
Hi all,
I have the folowing frame(there are more columns than shown),
1 2 34 5
Year Total
how can I get a list of all S3-methods (of a package)
such that I know which functions to include in the S3method()
in the NAMESPACE-file?
Maybe separated by generic=T/F.
thx
Meinhard Ploner
Vienna
__
[EMAIL PROTECTED] mailing list
Meinhard Ploner wrote:
how can I get a list of all S3-methods (of a package)
such that I know which functions to include in the S3method()
in the NAMESPACE-file?
Maybe separated by generic=T/F.
thx
Meinhard Ploner
Vienna
Since one you does not register S3 methods (except for the Namespace
file),
Meinhard Ploner wrote:
how can I get a list of all S3-methods (of a package)
such that I know which functions to include in the S3method()
in the NAMESPACE-file?
Maybe separated by generic=T/F.
thx
Meinhard Ploner
Vienna
Since one you does not register S3 methods (except for the Namespace
file),
1 - 100 of 121 matches
Mail list logo
