#%28def._%28%28quote._~23~25kernel%29._dynamic-require%29%29
> > If the module exports _provided_ as syntax,
> > then a use of the binding is expanded and
> > evaluated in a fresh namespace to which
> > the module is attached, which means that
> > the module is vi
Hello list,
In the following program, racket thinks foo2, and foo3 are bound to
syntax. Is this expected behavior?
-- File: go.rkt
#lang racket
(module p racket
(provide (all-defined-out))
(define (foo0 a b)
(+ a b))
(define (foo1 a b [c 3])
(+ a b c))
(define (foo2 a b [c 3] #
e without
> knowing what file it's in -- `namespace-require`, unlike `require`, is
> a just a function and doesn't know anything about where it is in the
> source code. So you need to use something like `(quote-module-path)`
> that knows where it is.
>
> Sam
>
> On
ocation)
>
> (module food racket
> (provide apple)
> (define apple "pie"))
>
> (parameterize ([current-namespace (make-base-namespace)])
> (namespace-require (quote-module-path food))
> (eval 'apple))
>
> On Sun, Oct 29, 2017 at 12:19 P
Hello list,
I am trying to do namespace-require to a submodule, racket complains about
unknown module, as below:
$ cat go.rkt
#lang racket
(module food racket
(provide apple)
(define apple "pie"))
(parameterize ([current-namespace (make-base-namespace)])
(namespace-require ''food)
(
Hello list,
I am wondering how to expand a BSL program into the Racket _core language_?
Let's say a simple program:
(define (id x) x)
Thanks.
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