OK If you change the limits like some do with the Peltier elements using
500C input then you can get higher COP's due to the higher entry level.
(and just ignore the heating of the input...)
Heat pumps we use in houses are certified - Europe for 0..35C, not for
10..35C - as we live pretty
*Sorry a heatpump (HP) cannot have a COP 30 or 60*
Sorry but they can, I gave you the links.
The math also supports this.
No, you are right that a regular small house-hold heatpumps operating at
100% power over the rated temperature differential will top out currently
at about a heating COP of
Sorry a heatpump (HP) cannot have a COP 30 or 60. Assume a COP of 5 for
a single step HP as we have it today in a reasonably good probe heat
pump. (mine has 5.5 for heating)
You can neither simply multiply or add the COP's as you must provide
e.g. 20x the basic energy to fill the reservoir
Oh I missed the end:
"Heatpumps are reverse Carnot engines and have a much higher COP in respect
to heat gained but *not to current gained!!!"*
Current?
I'm not sure what you mean by this, you might be talking about the volume
of thermal energy moved, or you might be talking about the
Not sure why but this isn't forming into proper paragraphs...
*"Youtube physics usually is self satisfaction of people that have no clue
of the simplest things. So I almost never watch this garbage."*
The video is covering the work of a company cascading heat pumps.
As such the temperature
Youtube physics usually is self satisfaction of people that have no clue
of the simplest things. So I almost never watch this garbage.
A heatpump is not a Carnot process as *you obviously supply additional
energy*! You must calculate in the Carnot conversion rate of energy
gained -->
After 200 years (1824) the second law of thermodynamics is disproven.
https://en.wikipedia.org/wiki/Carnot%27s_theorem_(thermodynamics)
Simply Carnot argues that if the efficiency of a reversible heat engine was
variable based on how it is made or the gases etc, then the second law of
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