It’s right there for all to see hidden behind the Cheshire Cat’s grin!
From: David Roberson [mailto:dlrober...@aol.com]
Sent: Monday, March 14, 2016 11:07 AM
To: vortex-l@eskimo.com
Subject: Re: [Vo]: Bremsstrahlung experimental note
Can you point out the location of the mouse in Rossi's
Can you point out the location of the mouse in Rossi's patent?
Dave
-Original Message-
From: Axil Axil <janap...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Sun, Mar 13, 2016 3:34 pm
Subject: Re: [Vo]: Bremsstrahlung experimental note
Something is
Something is getting out of the LENR reactor. The mouse is stimulating the
cat in Rossi's reactor clustering scheme. The some emission of the mouse is
producing the LENR reaction inside the Cat type reactor.
That emission only exits the Mouse when the power to the heater coils of
the Mouse is
Muons with less than about 4MeV are not going to escape the reactor.
Cosmic muons are average 2GeV. No magnetic field that I could generate is
going to significantly deflect either of these.
On Sun, Mar 13, 2016 at 11:39 AM, Axil Axil wrote:
> @Bob
>
> Use a magnetic shield
@Bob
Use a magnetic shield to divert muons and other charged particles.
I describe it here
https://www.lenr-forum.com/forum/index.php/Thread/2862-A-Simple-LENR-Magnetic-Radiation-Shield/?postID=15183#post15183
[image: Inline image 1]
On Sun, Mar 13, 2016 at 10:56 AM, Bob Higgins
From: Bob Higgins
Ø Muonic decay in the reactor is an interesting prospect that I would like to
read more about. However, I don't think the muons, electrons, or protons are
going to escape the reactor in any large number due to the mass/cm^2 they would
have to traverse to get out. Muons
Muonic decay in the reactor is an interesting prospect that I would like to
read more about. However, I don't think the muons, electrons, or protons
are going to escape the reactor in any large number due to the mass/cm^2
they would have to traverse to get out. Muons are no more likely to
Why does the burst last for just a second even when excess heat is
produced after the radiation burst?
On Fri, Mar 11, 2016 at 4:25 PM, wrote:
> In reply to Bob Cook's message of Fri, 11 Mar 2016 09:34:55 -0800:
> Hi,
> [snip]
>>The effectiveness of the SS can at stopping
In reply to Bob Cook's message of Fri, 11 Mar 2016 09:34:55 -0800:
Hi,
[snip]
>The effectiveness of the SS can at stopping any high energy electrons that
>cause Bremsstrahlung would depend upon the thickness of the can (or alumina)
>and the energy of the incident electrons. I think the loss of
The seconds long MFMP X-ray burst is smooth and demonstrates no
resonance energy peaks caused by the interaction of electrons with
matter. The MFMP burst is strictly a release of photons in a random
energy distribution.
A Landau distribution is what we are seeing in the MFMP radiation
plot. It is
Electrons may have nothing to do with the x-ray radiation.
The radiation could be produced by photon based quasiparticles.
The LENR reaction might start with Surface Plasmon Polaritons
initiated nuclear reactions and then after thermalization, the decay
of those SPPs. When the SPPs decay, they
The effectiveness of the SS can at stopping any high energy electrons that
cause Bremsstrahlung would depend upon the thickness of the can (or alumina)
and the energy of the incident electrons. I think the loss of energy per
scattering event is proportional to Z ^2 for the nucleus that is
Bob,
There is simply too little nickel. If looking for bremsstrahlung, and in the
absence of gamma - a possible source of high speed electrons would be muon
decay.
At least this would be true in a situation like the glow-tube, where dense
hydrogen would be expected to form.
If the
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