@Bob Use a magnetic shield to divert muons and other charged particles. I describe it here
https://www.lenr-forum.com/forum/index.php/Thread/2862-A-Simple-LENR-Magnetic-Radiation-Shield/?postID=15183#post15183 [image: Inline image 1] On Sun, Mar 13, 2016 at 10:56 AM, Bob Higgins <[email protected]> wrote: > Muonic decay in the reactor is an interesting prospect that I would like > to read more about. However, I don't think the muons, electrons, or > protons are going to escape the reactor in any large number due to the > mass/cm^2 they would have to traverse to get out. Muons are no more likely > to penetrate the reactor walls than electrons or protons of the same > energy. The reason that muons are an issue with the lead in the > scintillator shield is that the cosmogenic muons have a typical energy of > 2GeV - probably 1000x that of what could be created inside the reactor. > The penetration is directly related to the energy of the muon. > > Certainly some in-the-cave vs. out-of-the-cave measurements are in order, > but can't easily be done while the experiment is running. > > On Fri, Mar 11, 2016 at 7:45 AM, Jones Beene <[email protected]> wrote: > >> Bob, >> >> >> >> There is simply too little nickel. If looking for bremsstrahlung, and in >> the absence of gamma - a possible source of high speed electrons would be >> muon decay. >> >> >> >> At least this would be true in a situation like the glow-tube, where >> dense hydrogen would be expected to form. >> >> >> >> If the counts are higher inside the lead cave, compared to outside >> (bare), it is very likely that the source is muonic from the reactor, not >> cosmic - and the target is lead. >> >> >> >> *From:* Bob Higgins >> >> >> >> I don't know if other Vorts thought of this already... but I had a minor >> epiphany regarding the radiation that MFMP measured in GS5.2. We >> identified this radiation tentatively as bremsstrahlung. This has certain >> implications. Bremsstrahlung requires that the high speed electrons impact >> on a high atomic mass element so as to be accelerated/decelerated quickly >> to produce the radiation. It could be that the stainless steel can that >> contained the fuel was an important component in seeing the >> bremsstrahlung. Without the can, there would still be the Ni for the >> electrons to hit, but the Ni is covered with light atomic mass Li. If the >> electrons were to strike alumina (no fuel can present), I don't think there >> would be nearly as much bremsstrahlung because alumina is comprised of >> light elements. >> >> >> >> Thus, the stainless steel can for the fuel may be an important component >> for seeing the bremsstrahlung. >> >> Bob Higgins >> > >
