> There is another problem as well. The chemistry of silver
> indicates that any silver ions in the blood will quickly plate out
> on any silver particles in the blood, which do not register as
> ions. He does not confirm that the ions do not make it into the
> blood, we know from those who get argyria from silver compounds
> they do, but rather that when taken with colloidal particles are
> quickly plated out on the particles which are in the blood.
>Marshall
Marshall,
There is no such chemistry of silver that will allow silver ions to
plate out on silver particles. Your claim is false.
Here's why:
1. In conventional LVDC silver electrolysis, a silver ion that
reaches the cathode can accept an electron and be converted back
into an atom. The equation is:
Ag(+) + e(-) --> Ag
However, one of the most fundamental laws in chemistry is any
chemical process must be charge balanced, and the result must be
neutral.
2. In order for the ion to plate out at the cathode, another ion
must enter the solution. The only place this can occur is at the
anode, and the result is another silver ion releases an electron and
enters the solution. The equation is:
Ag - e(-) --> Ag(+)
The overall effect is a silver atom is transferred from the anode to
the cathode. This wastes an electron, and results in no change in
the conductance of the solution. This is why I developed the
conductance method of terminating the brew at or just before the
ions reach the opposite electrodes. The section is "Analysing the CS
Process", at:
http://www.pstca.com/silversol/theory/analysis.htm
3. The above process cannot work in the blood. There is no source of
electrons to neutralize the charge on the ion, and there is no
positively-charged silver anode to release another silver ion into
the solution to keep the charge balanced. There is also no battery
connecting the two electrodes to supply the EMF necessary for the
reaction to occur.
4. If for some reason a silver ion landed on a silver particle, the
entire particle would take on a positive charge in accordance with
the charge balance rule. This will repel any further ions from the
particle and stop any further plateout.
However, for your claim to work, the ions have to ignore the charge
buildup and continue releasing their charge to the particle. The
particle would develop a high voltage like these two ladies who are
touching a high voltage conductor:
http://izismile.com/img/img2/20090406/tesla_20.jpg
5. If your claim was true, the silver electrolysis process could not
work. When a silver particle gives up an electron and leaves the
anode, the nearest silver particle is the anode. Since your claim
requires the ion to ignore the positive charge on the anode, the
silver ion would have no choice but to return to the anode and plate
out. This obviously does not happen.
6. If your claim was true, the ion selective electrode would not
work in any solution that contained silver particles. All the ions
would plate out and there would be nothing left to measure. This
obviously does not happen.
Marshall, your remarkable and profound ignorance of the basic laws
of chemistry, physics, logic, and common sense is amusing.
But I'm afraid the conclusions you draw would be very confusing to
newcomers. I recommend that any of your claims should be checked
very carefully by independent means.
Mike M.
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