You can do the same thing by wrapping the electrodes in foil with a
little salt water or vinegar...any conductive liquid.
What that does is make a battery effect that strips a layer off the silver
by ionization and deposits it on the aluminum.
That's how the silver bandaids work...the silver ions released sterilize
the wound.
You don't need aluminum to reverse current clean electrodes.
I don't know why sulphur would be a problem unless you live down wind of a
coal power plant or something and leave your distilled water, or electrodes
open to the air for a long time.
The black stuff that forms on electrodes is silver oxide, not sulphur
oxides "tarnish".
There is no need to do anything but wipe it off and switch electrode
positions to change the polarity now and then.
Ode
At 08:18 PM 9/13/2011 -0400, you wrote:
Asif Nathekar <[email protected]> wrote:
> Hi Mike, Just to clarify you mentioned that to clean the silver
> electrodes, use the voltage from the generator and the aluminium
> strip should be the anode or positive and the silver should be on
> the cathode or negative.
> If I have understood this won't that release the aluminium from
> the strip? Thanks.
> Excuse me if the question shows my lack of knowledge. I am an
> electronics hobbyist not big on chemistry!.
Hi Asif,
You ask a very good question. I definitely want to invite you to
join the SilverCell forum soon when it is ready.
You can use just about any voltage or current source you have
available, for example, a simple 9 volt battery works fine. Unlike a
3 nines, the Desulfurizing process is self-limiting and won't run
away on you.
The aluminum foil is the positive electrode or anode, and both your
silver electrodes connect to the negative terminal or cathode.
Your question about aluminum ions is extremely astute. I did not
expect anyone would ask that.
The reactions at the cathode are simple and easy to describe. I will
do that in the web version of this paper.
The reactions at the anode are completely different. They could
drive a saint to sin.
The literature is very confused about what happens at the anode. I
find most of the available equations are incorrect, so I have come
up with my own explanation that fits the available facts.
Unlike silver, copper, zinc, or steel, aluminum will not donate
aluminum ions to the solution. It is so reactive it immediately
forms aluminum oxide, which is insoluble.
So I believe all the reactions at the aluminum anode are as if the
aluminum were completely inert. Then the main things that happen
involve the hydrogen ions that are released as a product of the
liberation of oxygen at the anode. I will formalize the equations
and present them in the web version of the paper.
Very Good question!
Thanks,
Mike Monett
SilverCell
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