----- Original Message -----
From: "Marshall Dudley" <[email protected]>

Ivan (thats me) wrote:

> > We have been down this road before.
> > I believe that the reason you could not get a reaction with HCl and
most
> > importantly with HNO is because you already have ionic silver, that
is
> > clumps of silver ions. You can't ionise something that is already
> > ionised.
>
> OK, I can buy that.  So you are now saying that the HCl in the stomach
does
> not react with CS?

No, the H+ ions will not react with silver, metal or ion, but the Cl-
anion will react with the silver metal forming silver chloride. Now that
I think about it, I'm not sure that the product will be disassociated as
I noted below.

> > I do believe that particles of metalic silver will be ionised in the
> > acid stomach environment, and that clumps of ions will be broken
apart,
> > but I doubt that at low pH that silver will combine with Cl- to form
the
> > silver cloride molecule, much in the same way that silver nitrate in
> > solution is not combined in molecules but exists as free silver ions
and
> > free nitrate ions.
>
> But we are talking about CS, which are charged clumps.  If they don't
have a
> charge, they drop out of the colloid, and will not be drunk.

Not necessarily, a particle does not need to be charged to remain
suspended, just of colloidal dimension.

> If the clumps do become ionized (how they got there I have no idea
since
> they will not be present in CS that has had any time to settle), they
then
> become charged, and thus identical to CS particles.  So you are saying
that
> there is no reaction, but it will break the particles apart into the
atoms?

If the clumps are not there it doesn't matter then, of clumps that are
there the attraction among positvely charged atoms in those clumps would
be much lessened in an acid, which is high in H+ ions.

> This comes back to my original experiment, where I cannot get the CS
to lose
> its tyndall when added to HCL or nirtic acid. I do not see any action
taking
> place.  Does this not imply that the particles are NOT being broken
down?

Yes, that would imply that the particles are not being broken apart, but
it also implies quite large particle to begin with. As silver readilly
reacts with dilute nitric acid I cannot understand why this should be so
in this instance, with HCl perhaps the silver chloride is of the same
particle size.

> Also if you take CS and add an acid to it, it tends to aggregate and
the
> particles become larger, not smaller.  This has been discussed here
several
> times before.  It is a problem with mixing with aloe vera, which I
have
> found has to be neutralized with baking soda first to make stable.  I
know
> what mechanism makes them aggregate.  What mechanism do you propose
that
> would mke them do the opposite?

Well, I have never thought it was the acidity of the Aloe that caused
clumping, but rather that it was one or some of the myriade of other
compounds of which aloe is composed, and I have found that if such a
mixture is shielded from light, it has a longer life span. By adding
baking soda, you are changing the chemical composition of the aloe and
are perhaps preventing the silver from reacting with the compounds it
originally did.

> Marshall

Ivan.


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