You seem to have got it covered Roger.
I might just add that the oxygen reaction at the anode is unlikely to
proceed at low voltages, as silver is oxidised at a much lower
potential.

Ivan.

----- Original Message -----
From: <[email protected]>
To: <[email protected]>
Sent: Saturday, 24 March 2001 06:08
Subject: Re: CS>Solubility of silver in water.


> In a message dated 3/23/01 11:16:13 AM EST, [email protected]
writes:
>
> << Subj:     Re: CS>Solubility of silver in water.
>  Date:  3/23/01 11:16:13 AM EST
>  From:  [email protected] (Del or Elmay Crow)
>  Reply-to:  [email protected]
>  To:    [email protected]
>
>  Sorry, but you guys are confusing me.  The thing you are dealing with
is a
>  change of energy levels.The silver is still silver.  There is
supposedly no
>  metal exchanged between the annode and cathode.  All you could expect
is
>  that the water is changed to accomodate this.  Bubbles of hydrogen at
one
>  side, oxegen at the other plus the water electron-cloud structure
change to
>  possibly up to 105degrees.   None of us can measure this stuff, let
alone
>  imagine it!!! >>
>
> Del: I think what you have to keep in mind is when ~27 volts are
applied
> across silver electrodes in pure water, certain oxidation/reduction
reactions
> are possible.
>
> Let's look at the anode where oxidation takes place. At the voltage
stated,
> these are the reactions that MAY take place,
>
> (1) Ag -------> [Ag+] + 1e
> (2) 1/2O2(g) + 2[H+] -----> H2O + 1e
> (3) 2[OH-] -----> H2O + 1/2O2 + 1e
>
>
> And for the cathode, the following reactions MAY take place,
>
> (4) [Ag+] + 1e -------> Ag
> (5) [H+] + 1e --------> 1/2H2(g)
> (6) H2O + 1e --------> 1/2O2(g) + 2[H+]
>
> Now, the way I remember how to proceed, and it has been a very long
time
> since I did these calculations, is to examine the standard electrode
> potential for each reaction. The reaction that has the smallest
absolute
> electrode potential will proceed under STANDARD conditions, that is.
In this
> case, however, water is essentially the electrolyte (at least in the
> beginning of CS electrolysis) so we can use the standard electrode
potential
> directly to determine which of the "water reactions" will proceed, and
since
> water is in abundance, that reaction will set the maximum potential at
that
> electrode. Now, here's where silver enters the picture: If silver can
be
> oxidized at the anode at the maximum electrode potential (dictated by
one of
> the water reactions), silver ions will be produced. Similarly at the
cathode,
> if silver ions can be reduced at the maximum electrode potential
(dictated by
> one of the water reactions) then metallic silver will be produced
(from the
> silver ions generated at the anode). Perhaps, Ivan (or anyone else
versed in
> electrochemistry) can fill in the blanks with regard to which of these
water
> reactions will prevail at the anode and cathode, and/or whether or not
I made
> any boo boos. Roger



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