----- Original Message ----- From: <[email protected]> > > Ivan: My reasoning was that since ~27 volts are applied across the > electrodes, electrochemical water reactions will dominate the individual > electrode reactions. So which of these water electrochemical reactions will > set the potential at each electrode at least at the beginning of CS > production? Roger
Roger, Usually the reaction which requires the least energy proceeds to exhaustion before others, requiring more energy, proceed. In this case the reduction potential of silver is 0.80V Hydrogen is 0.83V (including over-voltage) Oxygen is 1.42V (including over-voltage) Over-voltage is the extra energy required to rip the water molecules out of solution. So at the beginning of electrolysis the evolution of hydrogen gas sets the energy required for the reaction to proceed, and silver ions enter the water at the anode in preference to production of O2. As the reaction proceeds and silver ions reach the cathode, they will be reduced in preference to H2. Regards Ivan. --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.237 / Virus Database: 115 - Release Date: 07/03/2001 -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: [email protected] -or- [email protected] with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
