Thanks Bob, if the silver wire is 14 gauge (14 gauge = 0.064") 14 gauge = about 1/8 of an inch
the equalization would be 3.1416 x (0.064) x 7 (inches of wetted area) measured on only one of the two silver wires. equals = 1.4070 ma if a bend the negative silver wire so there is 14 inches of wet area (negative = cathode the one that gives up the silver ??!!??) 3.1416 x 0.064 x 14 = 1.7496 ma then all I need is to find a LM 117 / LM 317 that can limit a 54 VDC to 1.75 ma and place that inline on the negative side wire. correct?? thanks for the help, much appreciated ed -----Original Message----- From: Robert Berger [mailto:[email protected]] Sent: Friday, April 25, 2003 2:35 PM To: [email protected] Subject: Re: CS>RE: Current limitation Ed, Most venders set their current limit to 1 ma per sqin. Area= 3.1416 x wired diameter in inches x wet length. "Ole Bob" --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.474 / Virus Database: 272 - Release Date: 4/18/2003 -- The silver-list is a moderated forum for discussion of colloidal silver. Instructions for unsubscribing may be found at: http://silverlist.org To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
